SINUSOIDAL OSCILLATOR
 An oscillator is an electronic circuit that produces a periodic
signal.
 Sinusoidal Oscillator produces sine wave as output.
 It converts the input energy from a DC source into an AC output
energy of a periodic signal.
 This periodic signal will be having a specific frequency and
amplitude.
SINUSOIDAL OSCILLATOR
□ The loop gain Avβ of oscillator must be greater than or equal to unity.
□ The total phase shift of a sinusoidal oscillator must be either 00 or 3600
RC Phase Shift Oscillator
unit 3.pptx
unit 3.pptx
The negative sign indicates a phase shift of 180°
Thus circuit will work as an oscillator which will produce a sinusoidal waveform if the
gain is 29 and total phase shift around a loop is 360°.
audio frequency range i.e. about 20 Hz up to 100 kHz.
At this Frequency
RC PHASE SHIFT OSCILLATOR
 The op-amp is operating in inverting mode.
 It provides a phase shift of 1800.
 Each RC section provides a phase shift of 600.
 The circuit provides a total phase shift of 3600 at some
frequency.
 The output frequency of a RC phase shift oscillator is
f=1/(2ΠRC√6)
 The gain Av of an inverting amplifier should be greater than or
equal to -29,
 □ i.e., −Rf/R1≥−29
WIEN BRIDGE OSCILLATOR
 Op-amp is operating in Non-inverting mode.
 it provides a phase shift of 00
 So, the feedback network present in the above circuit should not
provide any phase shift.
 Have to balance the bridge in such a way that there should not
be any phase shift.
 So, the above circuit provides a total phase shift of 00 at some
frequency.
 The output frequency of Wien bridge oscillator is f=1/2ΠRC
 The gain Av of the non-inverting amplifier should be greater than
or equal to 3
 □ i.e.,1+Rf/R1≥3
WIEN BRIDGE OSCILLATOR
To satisfy Barkhausen criterion that Aβ ≥ 1 it is necessary that the gain of the
noninverting op-amp amplifier must be minimum 3.
R1, R2 and C1, C2 are not equal R1, R2 and C1, C2 are equal
Peak Detector
 Compute the peak value of the input.
 Circuit follows the voltage peak and stores the highest value on
capacitor.
 When Vi>Vc , diode D forward biased and he circuits acts asvoltage
follower.
 When Vi<Vc , Diode D reverse biasedand the capacitor holds the
charge .
Peak Detector
 Capacitor voltage can be reset by connecting low leakage MOSFET
switch across the capacitor.
Positive Clipper
 Clipping level is determined by Vref
 Portion of output voltage Vo > Vref is clipped off.
Positive Clipper
Negative Clipper
 Clipping level is determined by Vref
 Portion of output voltage Vo < Vref isclipped off.
Negative Clipper
Clamper
 DC inserter or dc restorer
 Output is clamped to adesired dc level
 If dc level is positive – positive clamper
 If dc level is negative – negative clamper
 Clamper circuit with variable positive dc voltage applied at the +
terminal is shown
Clamper
Clamper
 For positive Vref ,the V’ispositive , hence Diode D forward biased,
circuit acts asvoltage follower
 Vo = +Vref
 Vi = Vm.Sin(wt)
 During negative half cycle of Vi, diode D conducts
 Capacitor gets charged through diode D to negative peak voltage of Vm
Clamper
 For positive half cycle of Vi, D is reverse biased.
 Capacitor retains at voltage of Vm.
 SinceVi is in series with C, the output voltage is equal
to Vi+Vm.
 Total output voltage = Vi+Vm+Vref
Clamper
Sample and Hold Circuit
 Samples an input signal and holds on to its last sampled value
until next sample.
 The n-channel E-MOSFET acts aswitch controlled by Vc.
 Vi to be sampled is applied to the drain of MOSFET and Vc is
applied to its gate.
 When Vc is positive, MOSFET turns ON and capacitor charges
to instantaneous value of Vi
Sampleand Hold Circuit
⚫ When Vc is Zero, E-MOSFET turns OFF
⚫ Capacitor faces high input impedance of A2.
⚫ Capacitor holds the voltage across it.
Sampleand Hold Circuit
 Sample period Ts – Voltage across the capacitor is equal to
input Voltage.
 Hold period TH – capacitor voltage ished constant.
 Frequency of the Vc should be higher than input.
 Atleast It should be twice that of the frequency of input
signal
Sampleand Hold Circuit

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unit 3.pptx

  • 1. SINUSOIDAL OSCILLATOR  An oscillator is an electronic circuit that produces a periodic signal.  Sinusoidal Oscillator produces sine wave as output.  It converts the input energy from a DC source into an AC output energy of a periodic signal.  This periodic signal will be having a specific frequency and amplitude.
  • 2. SINUSOIDAL OSCILLATOR □ The loop gain Avβ of oscillator must be greater than or equal to unity. □ The total phase shift of a sinusoidal oscillator must be either 00 or 3600
  • 3. RC Phase Shift Oscillator
  • 6. The negative sign indicates a phase shift of 180° Thus circuit will work as an oscillator which will produce a sinusoidal waveform if the gain is 29 and total phase shift around a loop is 360°. audio frequency range i.e. about 20 Hz up to 100 kHz. At this Frequency
  • 7. RC PHASE SHIFT OSCILLATOR  The op-amp is operating in inverting mode.  It provides a phase shift of 1800.  Each RC section provides a phase shift of 600.  The circuit provides a total phase shift of 3600 at some frequency.  The output frequency of a RC phase shift oscillator is f=1/(2ΠRC√6)  The gain Av of an inverting amplifier should be greater than or equal to -29,  □ i.e., −Rf/R1≥−29
  • 9.  Op-amp is operating in Non-inverting mode.  it provides a phase shift of 00  So, the feedback network present in the above circuit should not provide any phase shift.  Have to balance the bridge in such a way that there should not be any phase shift.  So, the above circuit provides a total phase shift of 00 at some frequency.  The output frequency of Wien bridge oscillator is f=1/2ΠRC  The gain Av of the non-inverting amplifier should be greater than or equal to 3  □ i.e.,1+Rf/R1≥3 WIEN BRIDGE OSCILLATOR
  • 10. To satisfy Barkhausen criterion that Aβ ≥ 1 it is necessary that the gain of the noninverting op-amp amplifier must be minimum 3. R1, R2 and C1, C2 are not equal R1, R2 and C1, C2 are equal
  • 11. Peak Detector  Compute the peak value of the input.  Circuit follows the voltage peak and stores the highest value on capacitor.  When Vi>Vc , diode D forward biased and he circuits acts asvoltage follower.  When Vi<Vc , Diode D reverse biasedand the capacitor holds the charge .
  • 12. Peak Detector  Capacitor voltage can be reset by connecting low leakage MOSFET switch across the capacitor.
  • 13. Positive Clipper  Clipping level is determined by Vref  Portion of output voltage Vo > Vref is clipped off.
  • 15. Negative Clipper  Clipping level is determined by Vref  Portion of output voltage Vo < Vref isclipped off.
  • 17. Clamper  DC inserter or dc restorer  Output is clamped to adesired dc level  If dc level is positive – positive clamper  If dc level is negative – negative clamper  Clamper circuit with variable positive dc voltage applied at the + terminal is shown
  • 19. Clamper  For positive Vref ,the V’ispositive , hence Diode D forward biased, circuit acts asvoltage follower  Vo = +Vref  Vi = Vm.Sin(wt)  During negative half cycle of Vi, diode D conducts  Capacitor gets charged through diode D to negative peak voltage of Vm
  • 20. Clamper  For positive half cycle of Vi, D is reverse biased.  Capacitor retains at voltage of Vm.  SinceVi is in series with C, the output voltage is equal to Vi+Vm.  Total output voltage = Vi+Vm+Vref
  • 22. Sample and Hold Circuit  Samples an input signal and holds on to its last sampled value until next sample.  The n-channel E-MOSFET acts aswitch controlled by Vc.  Vi to be sampled is applied to the drain of MOSFET and Vc is applied to its gate.  When Vc is positive, MOSFET turns ON and capacitor charges to instantaneous value of Vi
  • 23. Sampleand Hold Circuit ⚫ When Vc is Zero, E-MOSFET turns OFF ⚫ Capacitor faces high input impedance of A2. ⚫ Capacitor holds the voltage across it.
  • 24. Sampleand Hold Circuit  Sample period Ts – Voltage across the capacitor is equal to input Voltage.  Hold period TH – capacitor voltage ished constant.  Frequency of the Vc should be higher than input.  Atleast It should be twice that of the frequency of input signal