Unsymmetrical Fault
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1) The document describes an experiment to perform unsymmetrical fault analysis on a power system model by calculating fault currents (If) for different types of faults including single line-to-ground (1LG), line-to-line (LL), double line-to-ground (2LG), and three-phase faults. 2) The user inputs the fault location (zf) and fault type, and the code calculates the appropriate fault currents based on the system impedance values and voltage (Ea). 3) For a 1LG fault at zf=0, the code outputs the fault current as If = -115.4667∠-90°.
![EXPERIMENT – 6
OBJECT: -To perform unsymmetrical fault analysis.
CODE
clc
clearall
z1=.2i
z2=.2i
z0=.05i
Ea=1
a=-.5+.866i
Ib=17.32
zf=input('Please Enter the value of zf');
k=input('Enter 1 for 1LG, Enter 2 for LL, Enter 3 for 2LG Enter 4 for 3phase
fault');
switch(k)
case 1
Ia=(3*Ea/(z1+z2+z0+3*zf));
If=Ia*Ib
case 2
Ia1=(Ea/z1+z2+zf);
Ia2=((a*a-a)*Ia1);
If=Ia2*Ib
case 3
Ia3=(Ea/z1+(z2*(z0+3*zf)/(z2+z0+3*zf)));
Ia4=(-(Ea-Ia3*z1)/(z0+3*zf));
Ia5=3*Ia4;
If=Ia5*Ib
case 4
Ia6=Ea/z1;
If=Ia6*Ib
end
[Theta,rho]=cart2pol(real(If),imag(If))
a=Theta*180/pi
i=[rho a]](https://image.slidesharecdn.com/experiment6-140313220018-phpapp02/85/Unsymmetrical-Fault-1-320.jpg)
Unsymmetrical Fault
- 1. EXPERIMENT – 6 OBJECT: -To perform unsymmetrical fault analysis. CODE clc clearall z1=.2i z2=.2i z0=.05i Ea=1 a=-.5+.866i Ib=17.32 zf=input('Please Enter the value of zf'); k=input('Enter 1 for 1LG, Enter 2 for LL, Enter 3 for 2LG Enter 4 for 3phase fault'); switch(k) case 1 Ia=(3*Ea/(z1+z2+z0+3*zf)); If=Ia*Ib case 2 Ia1=(Ea/z1+z2+zf); Ia2=((a*a-a)*Ia1); If=Ia2*Ib case 3 Ia3=(Ea/z1+(z2*(z0+3*zf)/(z2+z0+3*zf))); Ia4=(-(Ea-Ia3*z1)/(z0+3*zf)); Ia5=3*Ia4; If=Ia5*Ib case 4 Ia6=Ea/z1; If=Ia6*Ib end [Theta,rho]=cart2pol(real(If),imag(If)) a=Theta*180/pi i=[rho a]
- 2. RESULT:- z1 =0 + 0.2000i z2 =0 + 0.2000i z0 = 0 + 0.0500i Ea =1 a = -0.5000 + 0.8660i Ib =17.3200 Please Enter the value of zf0 Enter 1 for 1LG, Enter 2 for LL, Enter 3 for 2LG Enter 4 for 3phase fault1 If =0 -1.1547e+002i Theta =-1.5708 rho = 115.4667 a = -90 i = 115.4667 -90.0000