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Ā 
COORDINATE EQUATION PROBLEMS: PROCESS 1 EXAMPLES: a) Given the coordinate equation  7 = (x-5)² + (y+6)², change it to the form  0 = x² + y² + dx + ey + f .  b) Given the coordinate equation  18 = (x+3)² + (y-4)², change it to the form  0 = x² + y² + dx + ey + f .
Solution to a) : Solution to b): PROCESS 1 SOLUTIONS:
PROCESS 2 EXAMPLES: c) Given the centre (-4,7), and the radius √26, write the coordinate equation.  d) Given the centre (9,-2), and the radius √54, write the coordinate equation.
Solution to c) : Solution to d) : PROCESS 2 SOLUTIONS:
PROCESS 3 EXAMPLE: Given theĀ centre (4,-9), and theĀ point (10,-3), write the coordinate equation.
PROCESS 3 SOLUTION:
PROCESS 4 EXAMPLE: Given the centre (7,12), and the area 21  , write the coordinate equation.
PROCESS 4 SOLUTION:
PERPENDICULAR DISTANCE PROBLEMS: PROCESS 1 EXAMPLE: Given theĀ point P(3,5) and the line 12x + 4y +3 = 0, find the perpendicular distance.
PROCESS 1 SOLUTION:
PROCESS 2 EXAMPLE: Given theĀ point P(2,5) and the line 3x + 5y = 8, find the perpendicular distance.
PROCESS 2 SOLUTION:
PROCESS 3 EXAMPLE: Given the lines -4y + x + 9 = 0 and y - 5x = 12, find the perpendicular distance.
PROCESS 3 SOLUTION:
LINEAR EQUATION SYSTEM  PROBLEM: Solve by Graphing Example: Given this system : Solve graphically.    y = x² y = 6 - x²
Solve by Graphing solution: y = x²    x | y   -1   1         --->         P(-1,1)   0   0         --->          P(0,0)   1   1         --->          P(1,1)   2   4         --->          P(2,4)   3   9         --->          P(3,9)   4   16       --->          P(4,16)   5   25       --->          P(5,25)   6   36       --->          P(6,36)
y = 6 - x²     y = - x²  + 6    x | y   -1   5         --->        P(-1,5)   0   6         --->        P(0,6)   1   5         --->        P(1,5)   2   2         --->        P(2,2)   3   -3        --->        P(3,-3)   4   -10      --->        P(4,-10)   5   -19      --->        P(5,-19)   6   -30      --->        P(6,30)
(-1¾, 3) (1¾, 3) The Solutions are  (-1¾, 3)  and  (1¾, 3) .
Solve by Substitution Example: Given this system : Solve using substitution.Ā Ā   Ā   12x - 4y =Ā 9 Ā Ā  y + 4x  = 18
Solve by Substitution solution:
Solve by Elimination Example: Given this system : Ā   4x + y =Ā 30 Ā Ā   -2xĀ + 2y = 10  Solve using elimination.Ā Ā 
Solve by Elimination solution:
BIBLIOGRAPHY: http://www.univie.ac.at/future.media/moe/fplotter/fplotter.html

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Analytic Geometry

  • 2. COORDINATE EQUATION PROBLEMS: PROCESS 1 EXAMPLES: a) Given the coordinate equationĀ  7 = (x-5)² + (y+6)², change itĀ to the form Ā 0 = x² + y² + dx + ey + f . b) Given the coordinate equationĀ  18 = (x+3)² + (y-4)², change itĀ to the form Ā 0 = x² + y² + dx + ey + f .
  • 3. Solution to a) : Solution to b): PROCESS 1 SOLUTIONS:
  • 4. PROCESS 2 EXAMPLES: c) Given theĀ centre (-4,7), and the radius √26, write the coordinate equation. d) Given theĀ centre (9,-2), and the radius √54, write the coordinate equation.
  • 5. Solution to c) : Solution to d) : PROCESS 2 SOLUTIONS:
  • 6. PROCESS 3 EXAMPLE: Given theĀ centre (4,-9), and theĀ point (10,-3), write the coordinate equation.
  • 8. PROCESS 4 EXAMPLE: Given theĀ centre (7,12), and theĀ area 21  , write the coordinate equation.
  • 10. PERPENDICULAR DISTANCE PROBLEMS: PROCESS 1 EXAMPLE: Given theĀ point P(3,5) and the line 12x + 4y +3 = 0, find the perpendicular distance.
  • 12. PROCESS 2 EXAMPLE: Given theĀ point P(2,5) and the line 3x + 5y = 8, find the perpendicular distance.
  • 14. PROCESS 3 EXAMPLE: Given the lines -4y + x + 9 = 0 and y - 5x = 12, find the perpendicular distance.
  • 16. LINEAR EQUATION SYSTEM PROBLEM: Solve by Graphing Example: Given this system : Solve graphically.Ā Ā  y = x² y = 6 - x²
  • 17. Solve by Graphing solution: y = x² Ā Ā  x | yĀ Ā  -1Ā Ā  1Ā Ā Ā Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā Ā Ā Ā P(-1,1) Ā Ā 0Ā  Ā 0Ā Ā Ā Ā Ā Ā Ā Ā  --->Ā Ā Ā Ā Ā Ā Ā Ā Ā  P(0,0) Ā Ā 1Ā  1Ā Ā Ā Ā Ā Ā Ā Ā  --->Ā Ā Ā Ā Ā Ā Ā Ā Ā  P(1,1) Ā Ā 2Ā Ā  4Ā Ā Ā Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā Ā Ā Ā  P(2,4) Ā  3Ā Ā  9Ā Ā Ā Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā Ā Ā Ā  P(3,9) Ā  4Ā Ā  16Ā Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā Ā Ā Ā  P(4,16) Ā  5Ā Ā  25Ā Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā Ā Ā Ā  P(5,25) 6Ā Ā  36Ā Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā Ā Ā Ā  P(6,36)
  • 18. y = 6 - x² y = - x² + 6 Ā Ā  x | yĀ Ā  -1Ā Ā  5Ā Ā Ā Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā Ā Ā P(-1,5) Ā Ā 0Ā  Ā 6Ā Ā Ā Ā Ā Ā Ā Ā  --->Ā Ā Ā Ā Ā Ā Ā Ā P(0,6) Ā Ā 1Ā  5Ā Ā Ā Ā Ā Ā Ā Ā  --->Ā Ā Ā Ā Ā Ā Ā Ā P(1,5) Ā Ā 2Ā Ā  2Ā Ā Ā Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā  P(2,2) Ā  3Ā Ā  -3Ā Ā Ā Ā Ā Ā Ā  --->Ā Ā Ā Ā Ā Ā Ā  P(3,-3) Ā  4Ā Ā  -10Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā Ā  P(4,-10) Ā  5Ā Ā  -19Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā Ā  P(5,-19) 6Ā Ā  -30Ā Ā Ā Ā Ā Ā --->Ā Ā Ā Ā Ā Ā Ā  P(6,30)
  • 19. (-1¾, 3) (1¾, 3) The Solutions are (-1¾, 3) and (1¾, 3) .
  • 20. Solve by Substitution Example: Given this system : Solve using substitution.Ā Ā  Ā  12x - 4y =Ā 9 Ā Ā  y + 4x = 18
  • 22. Solve by Elimination Example: Given this system : Ā  4x + y =Ā 30 Ā Ā  -2xĀ + 2y = 10 Solve using elimination.Ā Ā 
  • 23. Solve by Elimination solution: