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Chapter 2
Part II: Motion in Two Dimensions
(‫)الحركة في بعدين‬
Motion in Two Dimensions


Using + or – signs is not always sufficient to fully
describe motion in more than one dimension







Vectors can be used to more fully describe motion
Will look at vector nature of quantities in more detail

Still interested in displacement, velocity, and
acceleration
Will serve as the basis of multiple types of motion in
future chapters
Position and Displacement




The position of an
object is describedrby
its position vector, r
The displacement of
the object is defined as
the change in its
position

r r r
 ∆r ≡ r − r
f
i
General Motion Ideas
 In

two- or three-dimensional kinematics,
everything is the same as in one-dimensional
motion except that we must now use full
vector notation


Positive and negative signs are no longer
sufficient to determine the direction
Average Velocity






The average velocity is the ratio of the displacement
to the time interval for the displacement
r
r
∆r
vavg ≡
∆t
The direction of the average velocity is the direction
of the displacement vector
The average velocity between points is independent
of the path taken


This is because it is dependent on the displacement, also
independent of the path
Instantaneous Velocity


The instantaneous
velocity is the limit of the
average velocity as Δt
approaches zero
r
r
r
∆r dr
v ≡ lim
=
dt
∆t →0 ∆t


As the time interval
becomes smaller, the
direction of the
displacement approaches
that of the line tangent to the
curve
Instantaneous Velocity, cont
 The

direction of the instantaneous velocity
vector at any point in a particle’s path is along
a line tangent to the path at that point and in
the direction of motion
 The magnitude of the instantaneous velocity
vector is the speed


The speed is a scalar quantity
Average Acceleration
 The

average acceleration of a particle as it
moves is defined as the change in the
instantaneous velocity vector divided by the
time interval during which that change
occurs.

r
aavg

r r
r
v f − v i ∆v
≡
=
tf − t i
∆t
Average Acceleration, cont


As a particle moves,
the direction of the
change in velocity is
found by vector
subtraction r
r r

∆v = vf − v i



The average
acceleration is a vector
quantity directed along

r
∆v
Instantaneous Acceleration
 The

instantaneous acceleration is the limiting
r
value of the ratio ∆v ∆t as Δt approaches
zero
r
r

r
∆v dv
a ≡ lim
=
dt
∆t →0 ∆t



The instantaneous equals the derivative of the
velocity vector with respect to time
Producing An Acceleration
 Various

changes in a particle’s motion may
produce an acceleration



The magnitude of the velocity vector may change
The direction of the velocity vector may change




Even if the magnitude remains constant

Both may change simultaneously
Kinematic Equations for TwoDimensional Motion






When the two-dimensional motion has a constant
acceleration, a series of equations can be
developed that describe the motion
These equations will be similar to those of onedimensional kinematics
Motion in two dimensions can be modeled as two
independent motions in each of the two
perpendicular directions associated with the x and y
axes


Any influence in the y direction does not affect the motion
in the x direction
Kinematic Equations, 2
 Position

r vector for a particle moving in the xy
i
j
plane r = x ˆ + yˆ
 The velocity vector can be found from the
position vector
r
r dr
v=
= vxˆ + vy ˆ
i
j
dt


Since acceleration is constant, we can also find
an expression for the velocity as a function of
r
r r
time: v f = v i + at
Kinematic Equations, 3
 The

position vector can also be expressed as
a function of time:



r r r
r
1 at 2
rf = ri + v i t +
2
This indicates that the position vector is the sum
of three other vectors:




The initial position vector
The displacement resulting from the initial velocity
The displacement resulting from the acceleration
Kinematic Equations, Graphical
Representation of Final Velocity




The velocity vector can
be represented by its
components
r
vf is generally not along
r
therdirection of either v i
or a
Kinematic Equations, Graphical
Representation of Final Position






The vector
representation of the
position vector
r
rf is generally not along
r
the same direction as v i
r
or as a
r
r
vf and rf are generally
not in the same
direction
Graphical Representation
Summary




Various starting positions and initial velocities
can be chosen
Note the relationships between changes
made in either the position or velocity and the
resulting effect on the other
Projectile Motion (‫حركة‬
‫)المقذوفات‬
 An

object may move in both the x and y
directions simultaneously
 The form of two-dimensional motion we will
deal with is called projectile motion
Assumptions of Projectile
Motion (‫الفتراضات من حركة‬
‫)المقذوفات‬
 The

free-fall acceleration is constant over the
range of motion (‫تسارع السقوط الحر ثابت في مدى‬

‫)الحركة‬




It is directed downward
This is the same as assuming a flat Earth over the
range of the motion
It is reasonable as long as the range is small
compared to the radius of the Earth

 The

effect of air friction (‫ )احتكاك الهواء‬is
negligible
 With these assumptions, an object in
projectile motion will follow a parabolic path
Projectile Motion Diagram
(‫)مخطط لحركة القذيفة‬
Analyzing Projectile Motion



Consider the motion as the superposition of the
motions in the x- and y-directions
The actual position at any time is given by:
r r r
r
1 gt 2
rf = ri + v i t +
2



The initial velocity can be expressed in terms of its
components




The x-direction has constant velocity




vxi = vi cos θ and vyi = vi sin θ
ax = 0

The y-direction is free fall


ay = -g
Effects of Changing Initial
Conditions


The velocity vector
components depend on
the value of the initial
velocity




Change the angle and
note the effect
Change the magnitude
and note the effect
Analysis Model
 The

analysis model is the superposition of
two motions




Motion of a particle under constant velocity in the
horizontal direction
Motion of a particle under constant acceleration in
the vertical direction


Specifically, free fall
Projectile Motion Vectors



r r r
r
1 gt 2
rf = ri + v i t +
2
The final position is the
vector sum of the initial
position, the position
resulting from the initial
velocity and the
position resulting from
the acceleration
Projectile Motion –
Implications
 The

y-component of the velocity is zero at the
maximum height of the trajectory
 The acceleration stays the same throughout
the trajectory
Range and Maximum Height of
a Projectile






When analyzing projectile
motion, two
characteristics are of
special interest
The range, R, is the
horizontal distance of the
projectile
The maximum height the
projectile reaches is h
Height of a Projectile, equation
 The

maximum height of the projectile can be
found in terms of the initial velocity vector:
v i2 sin2 θ i
h=
2g

 This

equation is valid only for symmetric
motion
Range of a Projectile, equation
 The

range of a projectile can be expressed in
terms of the initial velocity vector:
2
v i sin 2θ i
R=
g

 This

is valid only for symmetric trajectory
More About the Range of a
Projectile
Range of a Projectile, final
 The

maximum range occurs at θi = 45o

 Complementary

angles will produce the

same range




The maximum height will be different for the two
angles
The times of the flight will be different for the two
angles
Projectile Motion – Problem
Solving Hints


Conceptualize




Categorize





Establish the mental representation of the projectile moving
along its trajectory
Confirm air resistance is neglected
Select a coordinate system with x in the horizontal and y in
the vertical direction

Analyze



If the initial velocity is given, resolve it into x and y
components
Treat the horizontal and vertical motions independently
Projectile Motion – Problem
Solving Hints, cont.


Analysis, cont








Analyze the horizontal motion using constant velocity
techniques
Analyze the vertical motion using constant acceleration
techniques
Remember that both directions share the same time

Finalize




Check to see if your answers are consistent with the
mental and pictorial representations
Check to see if your results are realistic
Non-Symmetric Projectile
Motion







Follow the general rules
for projectile motion
Break the y-direction into
parts
 up and down or
 symmetrical back to
initial height and then
the rest of the height
Apply the problem solving
process to determine and
solve the necessary
equations
May be non-symmetric in
other ways
Uniform Circular Motion
(‫) الحركة الدائرية المنتظمة‬






Uniform circular motion occurs when an object
moves in a circular path with a constant speed
The associated analysis motion is a particle in
uniform circular motion
An acceleration exists since the direction of the
motion is changing




This change in velocity is related to an acceleration

The velocity vector is always tangent to the path of
the object
Changing Velocity in Uniform
Circular Motion


The change in the
velocity vector is due to
the change in direction



The vector diagram
r
r
r
shows vf = v i + ∆v
Centripetal Acceleration
(‫) التسارع المركزي‬
 The

acceleration is always perpendicular to
the path of the motion
 The acceleration always points toward the
center of the circle of motion
 This acceleration is called the centripetal
acceleration
Centripetal Acceleration, cont


The magnitude of the centripetal acceleration vector
is given by

v2
aC =
r


The direction of the centripetal acceleration vector is
always changing, to stay directed toward the center
of the circle of motion
Period (‫)الزمن الدوري‬
 The

period, T, is the time required for one
complete revolution
 The speed of the particle would be the
circumference of the circle of motion divided
by the period
 Therefore, the period is defined as
2π r
T ≡
v
Tangential Acceleration
(‫) التسارع المماسي‬




The magnitude of the velocity could also be changing
In this case, there would be a tangential acceleration
The motion would be under the influence of both
tangential and centripetal accelerations


Note the changing acceleration vectors
Total Acceleration (‫التسارع‬
‫)الكلي‬
 The

tangential acceleration causes the
change in the speed of the particle
 The radial acceleration comes from a change
in the direction of the velocity vector
Total Acceleration, equations


dv
The tangential acceleration: at =
dt



v2
ar
The radial acceleration(‫− = :)التسارع الشعاعي‬aC = −
r



The total acceleration:

a = a +a
2
r

2
t



Magnitude



Direction
 Same as velocity vector if v is increasing, opposite if v is
decreasing
Relative Velocity (‫السرعة‬
‫)النسبية‬





Two observers moving relative to each other
generally do not agree on the outcome of an
experiment
However, the observations seen by each are related
to one another
A frame of reference can described by a Cartesian
coordinate system for which an observer is at rest
with respect to the origin
Different Measurements,
example






Observer A measures
point P at +5 m from
the origin
Observer B measures
point P at +10 m from
the origin
The difference is due to
the different frames of
reference being used
Different Measurements,
another example





The man is walking on the
moving beltway
The woman on the beltway
sees the man walking at his
normal walking speed
The stationary woman sees
the man walking at a much
higher speed




The combination of the
speed of the beltway and
the walking

The difference is due to the
relative velocity of their
frames of reference
Relative Velocity, generalized




Reference frame SA is
stationary
Reference frame SB is
moving to the right
r
relative to SA at v AB




r
This also means that SA
v
moves at – BA relative to
SB

Define time t = 0 as that
time when the origins
coincide
Notation
 The

first subscript represents what is being
observed
 The second subscript represents who is
doing the observing
r
 Example v
AB


The velocity of A as measured by observer B
Relative Velocity, equations


The positions as seen from the two reference
frames are related through the velocity

r
r
r
 r
PA = rPB + v BA t



The derivative of the position equation will give the
velocity equation
r
r
r




uPA = uPB + vBA

r
u
is the velocity of the particle P measured by observer A
r PA
u
is the velocity of the particle P measured by observer B
PB
These are called the Galilean transformation
equations
Acceleration in Different
Frames of Reference
 The

derivative of the velocity equation will
give the acceleration equation
 The acceleration of the particle measured by
an observer in one frame of reference is the
same as that measured by any other
observer moving at a constant velocity
relative to the first frame.

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Chapter2 b

  • 1. Chapter 2 Part II: Motion in Two Dimensions (‫)الحركة في بعدين‬
  • 2. Motion in Two Dimensions  Using + or – signs is not always sufficient to fully describe motion in more than one dimension     Vectors can be used to more fully describe motion Will look at vector nature of quantities in more detail Still interested in displacement, velocity, and acceleration Will serve as the basis of multiple types of motion in future chapters
  • 3. Position and Displacement   The position of an object is describedrby its position vector, r The displacement of the object is defined as the change in its position r r r  ∆r ≡ r − r f i
  • 4. General Motion Ideas  In two- or three-dimensional kinematics, everything is the same as in one-dimensional motion except that we must now use full vector notation  Positive and negative signs are no longer sufficient to determine the direction
  • 5. Average Velocity    The average velocity is the ratio of the displacement to the time interval for the displacement r r ∆r vavg ≡ ∆t The direction of the average velocity is the direction of the displacement vector The average velocity between points is independent of the path taken  This is because it is dependent on the displacement, also independent of the path
  • 6. Instantaneous Velocity  The instantaneous velocity is the limit of the average velocity as Δt approaches zero r r r ∆r dr v ≡ lim = dt ∆t →0 ∆t  As the time interval becomes smaller, the direction of the displacement approaches that of the line tangent to the curve
  • 7. Instantaneous Velocity, cont  The direction of the instantaneous velocity vector at any point in a particle’s path is along a line tangent to the path at that point and in the direction of motion  The magnitude of the instantaneous velocity vector is the speed  The speed is a scalar quantity
  • 8. Average Acceleration  The average acceleration of a particle as it moves is defined as the change in the instantaneous velocity vector divided by the time interval during which that change occurs. r aavg r r r v f − v i ∆v ≡ = tf − t i ∆t
  • 9. Average Acceleration, cont  As a particle moves, the direction of the change in velocity is found by vector subtraction r r r ∆v = vf − v i  The average acceleration is a vector quantity directed along r ∆v
  • 10. Instantaneous Acceleration  The instantaneous acceleration is the limiting r value of the ratio ∆v ∆t as Δt approaches zero r r r ∆v dv a ≡ lim = dt ∆t →0 ∆t  The instantaneous equals the derivative of the velocity vector with respect to time
  • 11. Producing An Acceleration  Various changes in a particle’s motion may produce an acceleration   The magnitude of the velocity vector may change The direction of the velocity vector may change   Even if the magnitude remains constant Both may change simultaneously
  • 12. Kinematic Equations for TwoDimensional Motion    When the two-dimensional motion has a constant acceleration, a series of equations can be developed that describe the motion These equations will be similar to those of onedimensional kinematics Motion in two dimensions can be modeled as two independent motions in each of the two perpendicular directions associated with the x and y axes  Any influence in the y direction does not affect the motion in the x direction
  • 13. Kinematic Equations, 2  Position r vector for a particle moving in the xy i j plane r = x ˆ + yˆ  The velocity vector can be found from the position vector r r dr v= = vxˆ + vy ˆ i j dt  Since acceleration is constant, we can also find an expression for the velocity as a function of r r r time: v f = v i + at
  • 14. Kinematic Equations, 3  The position vector can also be expressed as a function of time:   r r r r 1 at 2 rf = ri + v i t + 2 This indicates that the position vector is the sum of three other vectors:    The initial position vector The displacement resulting from the initial velocity The displacement resulting from the acceleration
  • 15. Kinematic Equations, Graphical Representation of Final Velocity   The velocity vector can be represented by its components r vf is generally not along r therdirection of either v i or a
  • 16. Kinematic Equations, Graphical Representation of Final Position    The vector representation of the position vector r rf is generally not along r the same direction as v i r or as a r r vf and rf are generally not in the same direction
  • 17. Graphical Representation Summary   Various starting positions and initial velocities can be chosen Note the relationships between changes made in either the position or velocity and the resulting effect on the other
  • 18. Projectile Motion (‫حركة‬ ‫)المقذوفات‬  An object may move in both the x and y directions simultaneously  The form of two-dimensional motion we will deal with is called projectile motion
  • 19. Assumptions of Projectile Motion (‫الفتراضات من حركة‬ ‫)المقذوفات‬  The free-fall acceleration is constant over the range of motion (‫تسارع السقوط الحر ثابت في مدى‬ ‫)الحركة‬    It is directed downward This is the same as assuming a flat Earth over the range of the motion It is reasonable as long as the range is small compared to the radius of the Earth  The effect of air friction (‫ )احتكاك الهواء‬is negligible  With these assumptions, an object in projectile motion will follow a parabolic path
  • 20. Projectile Motion Diagram (‫)مخطط لحركة القذيفة‬
  • 21. Analyzing Projectile Motion   Consider the motion as the superposition of the motions in the x- and y-directions The actual position at any time is given by: r r r r 1 gt 2 rf = ri + v i t + 2  The initial velocity can be expressed in terms of its components   The x-direction has constant velocity   vxi = vi cos θ and vyi = vi sin θ ax = 0 The y-direction is free fall  ay = -g
  • 22. Effects of Changing Initial Conditions  The velocity vector components depend on the value of the initial velocity   Change the angle and note the effect Change the magnitude and note the effect
  • 23. Analysis Model  The analysis model is the superposition of two motions   Motion of a particle under constant velocity in the horizontal direction Motion of a particle under constant acceleration in the vertical direction  Specifically, free fall
  • 24. Projectile Motion Vectors   r r r r 1 gt 2 rf = ri + v i t + 2 The final position is the vector sum of the initial position, the position resulting from the initial velocity and the position resulting from the acceleration
  • 25. Projectile Motion – Implications  The y-component of the velocity is zero at the maximum height of the trajectory  The acceleration stays the same throughout the trajectory
  • 26. Range and Maximum Height of a Projectile    When analyzing projectile motion, two characteristics are of special interest The range, R, is the horizontal distance of the projectile The maximum height the projectile reaches is h
  • 27. Height of a Projectile, equation  The maximum height of the projectile can be found in terms of the initial velocity vector: v i2 sin2 θ i h= 2g  This equation is valid only for symmetric motion
  • 28. Range of a Projectile, equation  The range of a projectile can be expressed in terms of the initial velocity vector: 2 v i sin 2θ i R= g  This is valid only for symmetric trajectory
  • 29. More About the Range of a Projectile
  • 30. Range of a Projectile, final  The maximum range occurs at θi = 45o  Complementary angles will produce the same range   The maximum height will be different for the two angles The times of the flight will be different for the two angles
  • 31. Projectile Motion – Problem Solving Hints  Conceptualize   Categorize    Establish the mental representation of the projectile moving along its trajectory Confirm air resistance is neglected Select a coordinate system with x in the horizontal and y in the vertical direction Analyze   If the initial velocity is given, resolve it into x and y components Treat the horizontal and vertical motions independently
  • 32. Projectile Motion – Problem Solving Hints, cont.  Analysis, cont     Analyze the horizontal motion using constant velocity techniques Analyze the vertical motion using constant acceleration techniques Remember that both directions share the same time Finalize   Check to see if your answers are consistent with the mental and pictorial representations Check to see if your results are realistic
  • 33. Non-Symmetric Projectile Motion     Follow the general rules for projectile motion Break the y-direction into parts  up and down or  symmetrical back to initial height and then the rest of the height Apply the problem solving process to determine and solve the necessary equations May be non-symmetric in other ways
  • 34. Uniform Circular Motion (‫) الحركة الدائرية المنتظمة‬    Uniform circular motion occurs when an object moves in a circular path with a constant speed The associated analysis motion is a particle in uniform circular motion An acceleration exists since the direction of the motion is changing   This change in velocity is related to an acceleration The velocity vector is always tangent to the path of the object
  • 35. Changing Velocity in Uniform Circular Motion  The change in the velocity vector is due to the change in direction  The vector diagram r r r shows vf = v i + ∆v
  • 36. Centripetal Acceleration (‫) التسارع المركزي‬  The acceleration is always perpendicular to the path of the motion  The acceleration always points toward the center of the circle of motion  This acceleration is called the centripetal acceleration
  • 37. Centripetal Acceleration, cont  The magnitude of the centripetal acceleration vector is given by v2 aC = r  The direction of the centripetal acceleration vector is always changing, to stay directed toward the center of the circle of motion
  • 38. Period (‫)الزمن الدوري‬  The period, T, is the time required for one complete revolution  The speed of the particle would be the circumference of the circle of motion divided by the period  Therefore, the period is defined as 2π r T ≡ v
  • 39. Tangential Acceleration (‫) التسارع المماسي‬    The magnitude of the velocity could also be changing In this case, there would be a tangential acceleration The motion would be under the influence of both tangential and centripetal accelerations  Note the changing acceleration vectors
  • 40. Total Acceleration (‫التسارع‬ ‫)الكلي‬  The tangential acceleration causes the change in the speed of the particle  The radial acceleration comes from a change in the direction of the velocity vector
  • 41. Total Acceleration, equations  dv The tangential acceleration: at = dt  v2 ar The radial acceleration(‫− = :)التسارع الشعاعي‬aC = − r  The total acceleration: a = a +a 2 r 2 t  Magnitude  Direction  Same as velocity vector if v is increasing, opposite if v is decreasing
  • 42. Relative Velocity (‫السرعة‬ ‫)النسبية‬    Two observers moving relative to each other generally do not agree on the outcome of an experiment However, the observations seen by each are related to one another A frame of reference can described by a Cartesian coordinate system for which an observer is at rest with respect to the origin
  • 43. Different Measurements, example    Observer A measures point P at +5 m from the origin Observer B measures point P at +10 m from the origin The difference is due to the different frames of reference being used
  • 44. Different Measurements, another example    The man is walking on the moving beltway The woman on the beltway sees the man walking at his normal walking speed The stationary woman sees the man walking at a much higher speed   The combination of the speed of the beltway and the walking The difference is due to the relative velocity of their frames of reference
  • 45. Relative Velocity, generalized   Reference frame SA is stationary Reference frame SB is moving to the right r relative to SA at v AB   r This also means that SA v moves at – BA relative to SB Define time t = 0 as that time when the origins coincide
  • 46. Notation  The first subscript represents what is being observed  The second subscript represents who is doing the observing r  Example v AB  The velocity of A as measured by observer B
  • 47. Relative Velocity, equations  The positions as seen from the two reference frames are related through the velocity r r r  r PA = rPB + v BA t  The derivative of the position equation will give the velocity equation r r r   uPA = uPB + vBA r u is the velocity of the particle P measured by observer A r PA u is the velocity of the particle P measured by observer B PB These are called the Galilean transformation equations
  • 48. Acceleration in Different Frames of Reference  The derivative of the velocity equation will give the acceleration equation  The acceleration of the particle measured by an observer in one frame of reference is the same as that measured by any other observer moving at a constant velocity relative to the first frame.