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Defining a Linear Inequality in
Two Variables
What you’ll learn:
1. Review the definition of inequality.
2. Translate real-life situation to linear
inequality
Think critically and
divergently!
A Working Student’s
Schedule
Manuel has two part time jobs, one
paying Php 30 per hour and another
paying Php 35 per hour. He must earn
at least Php 825 per week to pay his
expenses while attending college night
classes.
Write an inequality that shows the various ways
he can schedule his time to achieve his goal.
Let x = the no. of hours Manuel works
on
the first job
y = the no. of hours Manuel works
on
the second job
The hourly
rate on the
first job
no. of
hours
worked
on the
first job
The hourly
rate on the
second job
no. of hours
worked on
the second
job
Php
825
 
 is at
least
30   
35
x y  825
825
35
30 
 y
x
825
35
30 
 y
x
The inequality obtained is an example of a linear inequa
In two variables.
A linear inequality in two variables can be
written in one of four forms:
C
By
Ax 
 C
By
Ax 

C
By
Ax 
 C
By
Ax 

where A, B and C represent real numbers and A and B
Are not both zero.
Symbols used in inequality.




Greater than
Less than
Greater than or equal to ; at least
Less than or equal to ; at most
An ordered pair (x, y), is a solution of an
inequality in two variables if a true statement
results when variables in the inequality are replaced
by the coordinates of the ordered pair.
So, let us determine whether each ordered pair is a
solution of the given inequality…
Example 1:
Determine whether each ordered pair is a solution of
825
35
30 
 y
x
a. (6, 15)
b. (10, 15)
c. (12, 16)
SOLUTIONS:
a. (6,
15)
825
35
30 
 y
x
825
)
15
(
35
)
6
(
30 

Substitute 6 for x
and 15 for y .
825
525
180 

825
705  FALSE
Hence, (6, 15) is NOT a solution of the inequality.
SOLUTIONS:
b. (10, 15)
825
35
30 
 y
x
825
)
15
(
35
)
10
(
30 

Substitute 10 for x
and 15 for y .
825
525
300 

825
825  TRUE
Hence, (10, 15) is a solution of the inequality.
SOLUTIONS:
c. (12, 16)
825
35
30 
 y
x
825
)
16
(
35
)
12
(
30 

Substitute 12 for x
and 16 for y .
825
560
360 

825
920  TRUE
Hence, (12, 16) is a solution of the inequality.
Example 2:
Determine whether each ordered pair is a solution of
3
2
5 
 y
x
a. (-1, 0)
b. (1, 2)
c. (2, 1/2)
SOLUTIONS:
a. (-1, 0)
Substitute -1 for x
and 0 for y .
TRUE
Hence, (-1, 0) is a solution of the inequality.
3
2
5 
 y
x
3
)
0
(
2
)
1
(
5 


3
0
5 


3
5 

SOLUTIONS:
b. (1, 2)
Substitute 1 for x
and 2 for y .
TRUE
Hence, (1, 2) is a solution of the inequality.
3
2
5 
 y
x
3
)
2
(
2
)
1
(
5 

3
4
5 

3
1
SOLUTIONS:
c. (2, 1/2)
Substitute 2 for x
and 1/2 for y .
FALSE
Hence, (2, 1/2) is NOT a solution of the inequality.
3
2
5 
 y
x
3
)
2
/
1
(
2
)
2
(
5 

3
1
10 

3
9 
ACTIVITY:
1. Determine whether each ordered pair is a solution o
10
3
4 
 y
x
a. (1, 2)
b. (3, 1)
c. (-1/4, -2)
ACTIVITY:
2. Determine whether each ordered pair is a solution o
6
5
3 
 y
x
a. (-1, -2)
b. (1, 2)
c. (-5, 0)
ANSWERS:
1. Determine whether each ordered pair is a solution o
10
3
4 
 y
x
a. (1, 2)
b. (3, 1)
c. (-1/4, -2)
SOLUTION
NOT SOLUTION
SOLUTION
ANSWERS:
2. Determine whether each ordered pair is a solution o
6
5
3 
 y
x
a. (-1, -2)
b. (1, 2)
c. (-5, 0)
NOT SOLUTION
SOLUTION
NOT SOLUTION
Thank you
for watching 

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Defining Linear Inequalities in Two Variables Q2.ppt

  • 1. Defining a Linear Inequality in Two Variables
  • 2. What you’ll learn: 1. Review the definition of inequality. 2. Translate real-life situation to linear inequality Think critically and divergently!
  • 3. A Working Student’s Schedule Manuel has two part time jobs, one paying Php 30 per hour and another paying Php 35 per hour. He must earn at least Php 825 per week to pay his expenses while attending college night classes. Write an inequality that shows the various ways he can schedule his time to achieve his goal.
  • 4. Let x = the no. of hours Manuel works on the first job y = the no. of hours Manuel works on the second job The hourly rate on the first job no. of hours worked on the first job The hourly rate on the second job no. of hours worked on the second job Php 825    is at least 30    35 x y  825 825 35 30   y x
  • 5. 825 35 30   y x The inequality obtained is an example of a linear inequa In two variables. A linear inequality in two variables can be written in one of four forms: C By Ax   C By Ax   C By Ax   C By Ax   where A, B and C represent real numbers and A and B Are not both zero.
  • 6. Symbols used in inequality.     Greater than Less than Greater than or equal to ; at least Less than or equal to ; at most
  • 7. An ordered pair (x, y), is a solution of an inequality in two variables if a true statement results when variables in the inequality are replaced by the coordinates of the ordered pair. So, let us determine whether each ordered pair is a solution of the given inequality…
  • 8. Example 1: Determine whether each ordered pair is a solution of 825 35 30   y x a. (6, 15) b. (10, 15) c. (12, 16)
  • 9. SOLUTIONS: a. (6, 15) 825 35 30   y x 825 ) 15 ( 35 ) 6 ( 30   Substitute 6 for x and 15 for y . 825 525 180   825 705  FALSE Hence, (6, 15) is NOT a solution of the inequality.
  • 10. SOLUTIONS: b. (10, 15) 825 35 30   y x 825 ) 15 ( 35 ) 10 ( 30   Substitute 10 for x and 15 for y . 825 525 300   825 825  TRUE Hence, (10, 15) is a solution of the inequality.
  • 11. SOLUTIONS: c. (12, 16) 825 35 30   y x 825 ) 16 ( 35 ) 12 ( 30   Substitute 12 for x and 16 for y . 825 560 360   825 920  TRUE Hence, (12, 16) is a solution of the inequality.
  • 12. Example 2: Determine whether each ordered pair is a solution of 3 2 5   y x a. (-1, 0) b. (1, 2) c. (2, 1/2)
  • 13. SOLUTIONS: a. (-1, 0) Substitute -1 for x and 0 for y . TRUE Hence, (-1, 0) is a solution of the inequality. 3 2 5   y x 3 ) 0 ( 2 ) 1 ( 5    3 0 5    3 5  
  • 14. SOLUTIONS: b. (1, 2) Substitute 1 for x and 2 for y . TRUE Hence, (1, 2) is a solution of the inequality. 3 2 5   y x 3 ) 2 ( 2 ) 1 ( 5   3 4 5   3 1
  • 15. SOLUTIONS: c. (2, 1/2) Substitute 2 for x and 1/2 for y . FALSE Hence, (2, 1/2) is NOT a solution of the inequality. 3 2 5   y x 3 ) 2 / 1 ( 2 ) 2 ( 5   3 1 10   3 9 
  • 16. ACTIVITY: 1. Determine whether each ordered pair is a solution o 10 3 4   y x a. (1, 2) b. (3, 1) c. (-1/4, -2)
  • 17. ACTIVITY: 2. Determine whether each ordered pair is a solution o 6 5 3   y x a. (-1, -2) b. (1, 2) c. (-5, 0)
  • 18. ANSWERS: 1. Determine whether each ordered pair is a solution o 10 3 4   y x a. (1, 2) b. (3, 1) c. (-1/4, -2) SOLUTION NOT SOLUTION SOLUTION
  • 19. ANSWERS: 2. Determine whether each ordered pair is a solution o 6 5 3   y x a. (-1, -2) b. (1, 2) c. (-5, 0) NOT SOLUTION SOLUTION NOT SOLUTION