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Exceptions to Mendel’s Laws:

             Co-dominance
             Incomplete Dominance
             Multiple Alleles
             Lethal Genes

               Test Cross
B=brown
                                                b= blue
Test Cross:

 designed  to reveal the genotype of an organism that
  exhibits the dominant trait
  –   Brown eyes might be BB or Bb… how can we tell??
 cross the organism with an individual expressing the
  recessive trait….bb

 What    will this tell us?
Johnny has brown eyes… what is his genotype?


Complete the Punnett Squares:
The Results:

 -if
    all the offspring of the cross show the
  dominant trait (brown eyes), then the parent
  must be homozygous for the dominant allele

 -ifboth phenotypes appear among the offspring
  then the parent must have been heterozygous for
  the trait
Proving the genotype:

 Ifyou are asked to prove a genotype of an
  individual (with a dominant trait), use a
  testcross
 Cross the unknown genotype with an individual
  who is homozygous recessive
Exceptions to mendel's laws
Co-dominance:

 Two alleles of a gene are clearly expressed in
 the phenotype (equally)
  –   Ex. Roan colour in cattle – coat has both red and
      white hairs in it
  –   AB blood type in humans - IA & IB alleles are present
Punnett Square – Roan Cattle

 •In certain cattle, the hair colour can be red- RR, white- R’R’, or
 roan- RR’
     •Cross a red bull with a white cow
     •Cross an offsrping from the F1 generation with a white cow
Incomplete Dominance:

 Two  alleles of a gene appear to be blended
 into the phenotype
  –   Red snapdragons X white snapdragons = pink!
Multiple Alleles:
Polygenic Inheritance

 Some genes have 3 or more alleles BUT you
 can only have two alleles for a trait
  –   Ex. Skin color or height in humans
  –   Human blood types ABO
  –   There are 4 phenotypes A, B, AB & O produced from
      3 alleles IA-dominant, IB – dominant, & i - recessive
Exceptions to mendel's laws
Coat Colour in Rabbits

Four phenotypes and four alleles
Allelic series is C > cch > ch > c (which is most dominant)

Coat Color Phenotype          Genotype
Full Color                    CC, Ccch, Cch, Cc
Chinchilla                    cchcch, cchch, cchc
Himalayan                     chch, chc
Albino                        cc
Punnett Square – Blood Groups:

 Show     a cross between a person who has
    heterozygous A type blood & a person who has
    homozygous B type blood.
IAi x IBIB                         Genotypes:


                                Phenotypes:
Lethal Genes:

 Somegenes are lethal when present in the
 homozygous condition (dominant or recessive)
  –   Ex. In chickens, when an embryo contains two
      copies of the recessive gene known as creeper, the
      embryo dies inside the eggshell.
        Chicks   that are heterozygous for the gene survive
  –   In mice, yellow coat colour is dominant to grey
        Mice   that have YY (pure yellow) coat colour do not survive
Example with Mouse Coat Colour

 Yellow is dominant to grey
 Cross hybrid yellow mice Yy x Yy


                                        Resulting offspring:
                                         2 yellow to 1 grey
                                       One genotype is missing



        Somehow the YY genotype is lethal
  The 2:1 ratio is the typical ratio for a lethal gene.
Answers to samples:




A •child’s phenotype is O, the genotype must be ii (recessive)
      •father (A) and mother (B) must both carry the recessive
      allele
      •Father’s genotype IAi and mother’s genotype IBi
B




                                       C Chance of having an
                                          AB type baby is
                                                25%
a) The offspring occur in three types, classified as long, round
    and oval (intermediate), suggesting incomplete dominance
         • Long (L) Round (L’) Oval (LL’) - heterozygous
Test this idea…. LL’ x LL’ Gives a ratio of 1 long to 2 oval to 1
                                         round radishes.
                           b) (LL x LL), all the offspring will be
                                            long.
                         c) (L’L’ x L’L’), all the offspring will be
                                           round.
A)  Since ¼ of the eggs don’t hatch – lethal gene
      Crested (C) and non-crested (c) then both parents would have to
       be Cc ( eg. Cc x Cc)
                                      All the eggs with CC genotype would
                                                     not hatch
                                     Viable offspring would hatch in a ratio
                                           of 2 crested to 1 non-crested
                                   B) Cc x cc


                                    Ratio: 1Cc to 1 cc
                                    1 crested to 1 non
A)      Bull’s genotype RR, Cow’s genotype R’R’
                                B)        RR’ x R’R’




     All of the offspring have RR’
      genotype and will be roan      Ratio of 2 roan to 2 white calves

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Exceptions to mendel's laws

  • 1. Exceptions to Mendel’s Laws: Co-dominance Incomplete Dominance Multiple Alleles Lethal Genes Test Cross
  • 2. B=brown b= blue Test Cross:  designed to reveal the genotype of an organism that exhibits the dominant trait – Brown eyes might be BB or Bb… how can we tell??  cross the organism with an individual expressing the recessive trait….bb  What will this tell us?
  • 3. Johnny has brown eyes… what is his genotype? Complete the Punnett Squares:
  • 4. The Results:  -if all the offspring of the cross show the dominant trait (brown eyes), then the parent must be homozygous for the dominant allele  -ifboth phenotypes appear among the offspring then the parent must have been heterozygous for the trait
  • 5. Proving the genotype:  Ifyou are asked to prove a genotype of an individual (with a dominant trait), use a testcross  Cross the unknown genotype with an individual who is homozygous recessive
  • 7. Co-dominance:  Two alleles of a gene are clearly expressed in the phenotype (equally) – Ex. Roan colour in cattle – coat has both red and white hairs in it – AB blood type in humans - IA & IB alleles are present
  • 8. Punnett Square – Roan Cattle •In certain cattle, the hair colour can be red- RR, white- R’R’, or roan- RR’ •Cross a red bull with a white cow •Cross an offsrping from the F1 generation with a white cow
  • 9. Incomplete Dominance:  Two alleles of a gene appear to be blended into the phenotype – Red snapdragons X white snapdragons = pink!
  • 10. Multiple Alleles: Polygenic Inheritance  Some genes have 3 or more alleles BUT you can only have two alleles for a trait – Ex. Skin color or height in humans – Human blood types ABO – There are 4 phenotypes A, B, AB & O produced from 3 alleles IA-dominant, IB – dominant, & i - recessive
  • 12. Coat Colour in Rabbits Four phenotypes and four alleles Allelic series is C > cch > ch > c (which is most dominant) Coat Color Phenotype Genotype Full Color CC, Ccch, Cch, Cc Chinchilla cchcch, cchch, cchc Himalayan chch, chc Albino cc
  • 13. Punnett Square – Blood Groups:  Show a cross between a person who has heterozygous A type blood & a person who has homozygous B type blood. IAi x IBIB Genotypes: Phenotypes:
  • 14. Lethal Genes:  Somegenes are lethal when present in the homozygous condition (dominant or recessive) – Ex. In chickens, when an embryo contains two copies of the recessive gene known as creeper, the embryo dies inside the eggshell.  Chicks that are heterozygous for the gene survive – In mice, yellow coat colour is dominant to grey  Mice that have YY (pure yellow) coat colour do not survive
  • 15. Example with Mouse Coat Colour  Yellow is dominant to grey  Cross hybrid yellow mice Yy x Yy Resulting offspring: 2 yellow to 1 grey One genotype is missing Somehow the YY genotype is lethal The 2:1 ratio is the typical ratio for a lethal gene.
  • 16. Answers to samples: A •child’s phenotype is O, the genotype must be ii (recessive) •father (A) and mother (B) must both carry the recessive allele •Father’s genotype IAi and mother’s genotype IBi B C Chance of having an AB type baby is 25%
  • 17. a) The offspring occur in three types, classified as long, round and oval (intermediate), suggesting incomplete dominance • Long (L) Round (L’) Oval (LL’) - heterozygous Test this idea…. LL’ x LL’ Gives a ratio of 1 long to 2 oval to 1 round radishes. b) (LL x LL), all the offspring will be long. c) (L’L’ x L’L’), all the offspring will be round.
  • 18. A)  Since ¼ of the eggs don’t hatch – lethal gene  Crested (C) and non-crested (c) then both parents would have to be Cc ( eg. Cc x Cc) All the eggs with CC genotype would not hatch Viable offspring would hatch in a ratio of 2 crested to 1 non-crested B) Cc x cc Ratio: 1Cc to 1 cc 1 crested to 1 non
  • 19. A) Bull’s genotype RR, Cow’s genotype R’R’ B) RR’ x R’R’ All of the offspring have RR’ genotype and will be roan Ratio of 2 roan to 2 white calves