Free Fall & Projectiles 2
0 likes536 views
This document discusses free fall and projectile motion. It defines free fall as an object falling under the influence of gravity alone and a projectile as an object with both vertical and horizontal motion components. The vertical motion is affected only by gravity, while the horizontal motion is independent. Both an object and apple dropped from the same height will hit the ground at the same time, regardless of their mass. An example is worked out to calculate the minimum velocity needed to jump over a 1.5m high stair set that is 2m long.
1 of 6
More Related Content
What's hot (20)
Ad
Viewers also liked (20)
Ad
Similar to Free Fall & Projectiles 2 (20)
More from zglazenburg (20)
Recently uploaded (20)
Free Fall & Projectiles 2
- 1. Definitions Free Fall- An action where an object subjected to the effects of gravity Projectile- Object falling under the influence of gravity only.
- 2. Things To Know When an object is free falling, the acceleration is 9.81 m/s^2 towards the center of the earth. When a projectile is moving with a forward velocity there is a vertical component as well as a horizontal component. This results in a two step equation to find the unknown values.
- 3. More Things to know The Horizontal component (x) and the vertical component (y) are independent from each other. Near the surface of earth the acceleration do to gravity is 9.81m/s^2 Objects at the same altitude fall at the same rate no matter what their masses are.
- 4. Stair Set Example Louie is going to jump a stair set with a height of 1.5m and length 2m We must figure out the minimum velocity he must travel at in order to clear the stairs. We will also drop an apple at the same time from the same exact same height if done correctly they will hit the ground at the same time, even though Louie has a greater mass.
- 5. Our Knowns Vertical Component Vi=0 d=1.5 m a=g=9.81m/s^2 t=? Formula d=Vi(t)+1/2(at)^2 Horizontal Component v=? d=2 m t=? V=d/t
- 6. Calculations Y component 1.5m = 0(t)+1/2(9.81m/s^2)t^2 1.5m = 4.9m/s^2(t^2) 1.5m/(4.9m/s^2) = t^2 sqrt(.306s^2) = sqrt(t^2) .5532s = t X component V=2m/.5532s 3.6m/s=V