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Revision Session
Indefinite Integration
©2021, BYJU'S. All rights reserved
Sub-Topic
Number of Questions
Integration by Substitution 21
Integration of Special Functions
Integration by Parts 6
Integration by Partial Fraction 2
MAIN ADVANCED
1
0
0
0
PAST 10 YEARS JEE MAIN & JEE ADVANCED ANALYSIS (2012-2021)
JEE MAIN : 65 Papers, 41 Questions JEE ADVANCED : 20 Papers, 1 Question
12
©2021, BYJU'S. All rights reserved
JEE Main Aug 2021
If
Then the value of 𝑎4 + 𝑏5 is ___.
If ‫׬‬ tan 𝑥 + cot 𝑥 𝑑𝑥 = 𝑎 tan−1 tan 𝑥−1
𝑏 tan 𝑥
+ 𝑐.
©2021, BYJU'S. All rights reserved
JEE Main Aug 2021
If න
𝑑𝑥
𝑥2 + 𝑥 + 1 2
= 𝑎 tan−1
2𝑥 + 1
3
+ 𝑏
2𝑥 + 1
𝑥2 + 𝑥 + 1
+ 𝐶, 𝑥 > 0,
where 𝑐 is a constant of integration, then the value of 9( 3𝑎 + 𝑏)
is equal to ____.
©2021, BYJU'S. All rights reserved
JEE Main Jul 2021
න
𝑒𝑥
2 − 𝑥2
1 − 𝑥 1 − 𝑥2
𝑑𝑥
Evaluate
a 𝑒𝑥 1+𝑥
1−2𝑥
+ 𝑐 b 𝑒𝑥 1+𝑥
1−𝑥
+ 𝑐
c 𝑒𝑥 1−𝑥
1+𝑥
+ 𝑐 d 𝑒𝑥 1+𝑥
1−𝑥
2
+ 𝑐
©2021, BYJU'S. All rights reserved
JEE Main Mar 2021
The integral is equal
to ____. (where 𝐶 is a constant of integration)
a 1
2
sin 2𝑥 − 1 2 + 5 + 𝐶
b 1
2
cos 2𝑥 + 1 2 + 5 + 𝐶
c 1
2
cos 2𝑥 − 1 2 + 5 + 𝐶
d 1
2
sin 2𝑥 + 1 2 + 5 + 𝐶
න
2𝑥 − 1 cos 2𝑥 − 1 2 + 5
4𝑥2 − 4𝑥 + 6
𝑑𝑥
©2021, BYJU'S. All rights reserved
a 1
2
sin 2𝑥 − 1 2 + 5 + 𝐶
b 1
2
cos 2𝑥 + 1 2 + 5 + 𝐶
c 1
2
cos 2𝑥 − 1 2 + 5 + 𝐶
d 1
2
sin 2𝑥 + 1 2 + 5 + 𝐶
න
2𝑥 − 1 cos 2𝑥 − 1 2 + 5
4𝑥2 − 4𝑥 + 6
𝑑𝑥
©2021, BYJU'S. All rights reserved
JEE Main Aug 2021
න sin−1
2𝑥 + 2
4𝑥2 + 8𝑥 + 13
𝑑𝑥 = 𝐴 tan−1
2𝑥 + 2
3
+ 𝐵 ln 4𝑥2
+ 8𝑥 + 13 + 𝐶
If
a
3
2
𝑥 + 1 , −3 b 3
2
𝑥 + 1 , −6
c 𝑥 + 1, −3 d (𝑥 + 1, −6)
(where 𝐶 is a constant of integration), then the ordered pair 𝐴, 4𝐵 is
equal to ____.
©2021, BYJU'S. All rights reserved
න sin−1
2𝑥 + 2
4𝑥2 + 8𝑥 + 13
𝑑𝑥 = 𝐴 tan−1
2𝑥 + 2
3
+ 𝐵 ln 4𝑥2
+ 8𝑥 + 13 + 𝐶
a
3
2
𝑥 + 1 , −3
b 3
2
𝑥 + 1 , −6
c 𝑥 + 1, −3
d (𝑥 + 1, −6)
©2021, BYJU'S. All rights reserved
JEE Main Feb 2021
න
cos 𝑥 − sin 𝑥
8 − sin 2𝑥
𝑑𝑥 = 𝑎 sin−1
sin 𝑥 + cos 𝑥
𝑏
+ 𝐶
a −1, 3 b (3, 1) c 1,3 d 1, −3
(where 𝐶 is a constant of integration), then the ordered pair (𝑎, 𝑏) is
equal to ____.
©2021, BYJU'S. All rights reserved
න
cos 𝑥 − sin 𝑥
8 − sin 2𝑥
𝑑𝑥 = 𝑎 sin−1
sin 𝑥 + cos 𝑥
𝑏
+ 𝐶
a −1, 3
b (3, 1)
c 1,3
d 1, −3
©2021, BYJU'S. All rights reserved
JEE Main Feb 2021
න
1 − 5 sin2
𝑥
cos5 𝑥 sin2 𝑥
𝑑𝑥 =
𝑓 𝑥
cos5 𝑥
+ 𝐶
Then find the value of 𝑓
3𝜋
4
.
. (where 𝐶 is a constant of integration),
©2021, BYJU'S. All rights reserved
Let 𝑓
𝑥−4
𝑥+2
= 2𝑥 + 1, 𝑥 ∈ ℝ − 1, −2 , then ‫׬‬ 𝑓 𝑥 𝑑𝑥 is equal to :
(where 𝐶 is the constant of integration)
JEE Main 2018
a 12 ln 1 − 𝑥 − 3𝑥 + 𝐶
c 12 ln 1 − 𝑥 + 3𝑥 + 𝐶
b −12 ln 1 − 𝑥 − 3𝑥 + 𝐶
d −12 ln 1 − 𝑥 + 3𝑥 + 𝐶
©2021, BYJU'S. All rights reserved
𝑓
𝑥 − 4
𝑥 + 2
= 2𝑥 + 1
a 12 ln 1 − 𝑥 − 3𝑥 + 𝐶
c 12 ln 1 − 𝑥 + 3𝑥 + 𝐶
b −12 ln 1 − 𝑥 − 3𝑥 + 𝐶
d −12 ln 1 − 𝑥 + 3𝑥 + 𝐶
©2021, BYJU'S. All rights reserved
If ,
then is:
JEE Main Mar 2021
𝑓 𝑥 = න
5𝑥8
+ 7𝑥6
𝑥2 + 1 + 2𝑥7 2 𝑑𝑥, 𝑥 ≥ 0 , 𝑓 0 = 0 and 𝑓 1 =
1
𝑘
the value of 𝑘
©2021, BYJU'S. All rights reserved
‫׬‬
𝑒3 ln 2𝑥+5𝑒2 ln 2𝑥
𝑒4 ln 𝑥+5𝑒3 ln 𝑥−7𝑒2 ln 𝑥 𝑑𝑥
If ‫׬‬
𝑒3 ln 2𝑥+5𝑒2 ln 2𝑥
𝑒4 ln 𝑥+5𝑒3 ln 𝑥−7𝑒2 ln 𝑥 𝑑𝑥 , 𝑥 > 0, is equal to: (where 𝑐 is integration constant)
JEE Main Feb 2021
a
b
c
d
ln |𝑥2 + 5𝑥 − 7| + 𝑐
1
4
ln |𝑥2
+ 5𝑥 − 7| + 𝑐
4 ln |𝑥2
+ 5𝑥 − 7| + 𝑐
ln |𝑥2 + 5𝑥 − 7| + 𝑐
©2021, BYJU'S. All rights reserved
‫׬‬
𝑒3 ln 2𝑥+5𝑒2 ln 2𝑥
𝑒4 ln 𝑥+5𝑒3 ln 𝑥−7𝑒2 ln 𝑥 𝑑𝑥
a
b
c
d
ln |𝑥2 + 5𝑥 − 7| + 𝑐
1
4
ln |𝑥2 + 5𝑥 − 7| + 𝑐
4 ln |𝑥2 + 5𝑥 − 7| + 𝑐
ln |𝑥2
+ 5𝑥 − 7| + 𝑐
Let 𝐼 =
©2021, BYJU'S. All rights reserved
If ‫׬‬
1
4
𝑥−1 3 𝑥+2 5
𝑑𝑥 , 𝑥 > 0, is equal to: (where 𝑐 is integration constant)
JEE Main Aug 2021
a 3
4
𝑥+2
𝑥−1
5
4
+ 𝑐
c 3
4
𝑥+2
𝑥−1
1
4
+ 𝑐
b 4
3
𝑥−1
𝑥+2
5
4
+ 𝑐
d 4
3
𝑥−1
𝑥+2
1
4
+ 𝑐
‫׬‬
1
4
𝑥−1 3 𝑥+2 5
𝑑𝑥
©2021, BYJU'S. All rights reserved
‫׬‬
1
4
𝑥−1 3 𝑥+2 5
𝑑𝑥
Let 𝐼 =
a 3
4
𝑥+2
𝑥−1
5
4
+ 𝑐
c 3
4
𝑥+2
𝑥−1
1
4
+ 𝑐
b 4
3
𝑥−1
𝑥+2
5
4
+ 𝑐
d 4
3
𝑥−1
𝑥+2
1
4
+ 𝑐
©2021, BYJU'S. All rights reserved
JEE Main Jan 2020
If ‫׬‬
cos 𝑥
sin3 𝑥 1+sin6 𝑥
2
3
𝑑𝑥 (where 𝑐 is integration
constant) then 𝜆𝑓
𝜋
3
a −
9
8
b
9
8
c 2 d −2
= 𝑓 𝑥 1 + sin6
𝑥 1/𝜆
+ 𝑐,
‫׬‬
cos 𝑥
sin3 𝑥 1+sin6 𝑥
2
3
𝑑𝑥
©2021, BYJU'S. All rights reserved
‫׬‬
cos 𝑥
sin3 𝑥 1+sin6 𝑥
2
3
𝑑𝑥
a −
9
8
b
9
8
c 2
d −2
©2021, BYJU'S. All rights reserved
JEE Main Jan 2020
If ‫׬‬
𝑑𝑥
𝑥+4
8
7 𝑥−3
6
7
, 𝑥 > 0, is equal to: (where 𝑐 is integration constant)
a −
𝑥−3
𝑥+4
−
1
7
+ 𝑐
c 𝑥−3
𝑥+4
1
7
+ 𝑐
b 1
2
𝑥−3
𝑥+4
3
7
+ 𝑐
d −1
13
𝑥−3
𝑥+4
−
13
7
+ 𝑐
‫׬‬
𝑑𝑥
𝑥+4
8
7 𝑥−3
6
7
©2021, BYJU'S. All rights reserved
‫׬‬
𝑑𝑥
𝑥+4
8
7 𝑥−3
6
7
Let 𝐼 =
a −
𝑥−3
𝑥+4
−
1
7
+ 𝑐
c 𝑥−3
𝑥+4
1
7
+ 𝑐
b 1
2
𝑥−3
𝑥+4
3
7
+ 𝑐
d −1
13
𝑥−3
𝑥+4
−
13
7
+ 𝑐
©2021, BYJU'S. All rights reserved
JEE Main Jan 2020
If ‫׬‬
𝑑𝜃
cos2 𝜃 tan 2𝜃+sec 2𝜃
= 𝜆 tan 𝜃 + 2 ln 𝑓 𝜃 + 𝑐, (where 𝑐 is integration
constant) then the ordered pair 𝜆, 𝑓 𝜃 is equal to:
a −1, 1 − tan 𝜃 b −1, 1 + tan 𝜃
c 1, 1 + tan 𝜃 d −1, 1 − tan 𝜃
‫׬‬
𝑑𝜃
cos2 𝜃 tan 2𝜃+sec 2𝜃
= 𝜆 tan 𝜃 + 2 ln 𝑓 𝜃 + 𝑐
©2021, BYJU'S. All rights reserved
‫׬‬
𝑑𝜃
cos2 𝜃 tan 2𝜃+sec 2𝜃
= 𝜆 tan 𝜃 + 2 ln 𝑓 𝜃 + 𝑐
a −1, 1 − tan 𝜃
b −1, 1 + tan 𝜃
c 1, 1 + tan 𝜃
d −1, 1 − tan 𝜃
©2021, BYJU'S. All rights reserved
JEE Main Apr 2019
a 𝑥 − 𝛼 and ln sin 𝑥 − 𝛼
Let 𝛼 ∈ 0,
𝜋
2
be fixed. If the ‫׬‬
tan 𝑥+tan 𝛼
tan 𝑥−tan 𝛼
𝑑𝑥 = 𝐴 𝑥 cos 2𝛼 + 𝐵 𝑥 sin 2𝛼 + 𝑐,
(where 𝑐 is integration constant) then the functions 𝐴(𝑥) and 𝐵(𝑥) are
respectively:
b 𝑥 + 𝛼 and ln sin 𝑥 − 𝛼
c 𝑥 − 𝛼 and ln cos 𝑥 − 𝛼 d 𝑥 + 𝛼 and ln sin 𝑥 + 𝛼
©2021, BYJU'S. All rights reserved
‫׬‬
tan 𝑥+tan 𝛼
tan 𝑥−tan 𝛼
𝑑𝑥 = 𝐴 𝑥 cos 2𝛼 + 𝐵 𝑥 sin 2𝛼 + 𝑐
a 𝑥 − 𝛼 and ln sin 𝑥 − 𝛼
b 𝑥 + 𝛼 and ln sin 𝑥 − 𝛼
c 𝑥 − 𝛼 and ln cos 𝑥 − 𝛼
d 𝑥 + 𝛼 and ln sin 𝑥 + 𝛼
a 𝑥 − 𝛼 and ln sin 𝑥 − 𝛼
b 𝑥 + 𝛼 and ln sin 𝑥 − 𝛼
©2021, BYJU'S. All rights reserved

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Indefinite integration.pdf

  • 2. Sub-Topic Number of Questions Integration by Substitution 21 Integration of Special Functions Integration by Parts 6 Integration by Partial Fraction 2 MAIN ADVANCED 1 0 0 0 PAST 10 YEARS JEE MAIN & JEE ADVANCED ANALYSIS (2012-2021) JEE MAIN : 65 Papers, 41 Questions JEE ADVANCED : 20 Papers, 1 Question 12 ©2021, BYJU'S. All rights reserved
  • 3. JEE Main Aug 2021 If Then the value of 𝑎4 + 𝑏5 is ___. If ‫׬‬ tan 𝑥 + cot 𝑥 𝑑𝑥 = 𝑎 tan−1 tan 𝑥−1 𝑏 tan 𝑥 + 𝑐. ©2021, BYJU'S. All rights reserved
  • 4. JEE Main Aug 2021 If න 𝑑𝑥 𝑥2 + 𝑥 + 1 2 = 𝑎 tan−1 2𝑥 + 1 3 + 𝑏 2𝑥 + 1 𝑥2 + 𝑥 + 1 + 𝐶, 𝑥 > 0, where 𝑐 is a constant of integration, then the value of 9( 3𝑎 + 𝑏) is equal to ____. ©2021, BYJU'S. All rights reserved
  • 5. JEE Main Jul 2021 න 𝑒𝑥 2 − 𝑥2 1 − 𝑥 1 − 𝑥2 𝑑𝑥 Evaluate a 𝑒𝑥 1+𝑥 1−2𝑥 + 𝑐 b 𝑒𝑥 1+𝑥 1−𝑥 + 𝑐 c 𝑒𝑥 1−𝑥 1+𝑥 + 𝑐 d 𝑒𝑥 1+𝑥 1−𝑥 2 + 𝑐 ©2021, BYJU'S. All rights reserved
  • 6. JEE Main Mar 2021 The integral is equal to ____. (where 𝐶 is a constant of integration) a 1 2 sin 2𝑥 − 1 2 + 5 + 𝐶 b 1 2 cos 2𝑥 + 1 2 + 5 + 𝐶 c 1 2 cos 2𝑥 − 1 2 + 5 + 𝐶 d 1 2 sin 2𝑥 + 1 2 + 5 + 𝐶 න 2𝑥 − 1 cos 2𝑥 − 1 2 + 5 4𝑥2 − 4𝑥 + 6 𝑑𝑥 ©2021, BYJU'S. All rights reserved
  • 7. a 1 2 sin 2𝑥 − 1 2 + 5 + 𝐶 b 1 2 cos 2𝑥 + 1 2 + 5 + 𝐶 c 1 2 cos 2𝑥 − 1 2 + 5 + 𝐶 d 1 2 sin 2𝑥 + 1 2 + 5 + 𝐶 න 2𝑥 − 1 cos 2𝑥 − 1 2 + 5 4𝑥2 − 4𝑥 + 6 𝑑𝑥 ©2021, BYJU'S. All rights reserved
  • 8. JEE Main Aug 2021 න sin−1 2𝑥 + 2 4𝑥2 + 8𝑥 + 13 𝑑𝑥 = 𝐴 tan−1 2𝑥 + 2 3 + 𝐵 ln 4𝑥2 + 8𝑥 + 13 + 𝐶 If a 3 2 𝑥 + 1 , −3 b 3 2 𝑥 + 1 , −6 c 𝑥 + 1, −3 d (𝑥 + 1, −6) (where 𝐶 is a constant of integration), then the ordered pair 𝐴, 4𝐵 is equal to ____. ©2021, BYJU'S. All rights reserved
  • 9. න sin−1 2𝑥 + 2 4𝑥2 + 8𝑥 + 13 𝑑𝑥 = 𝐴 tan−1 2𝑥 + 2 3 + 𝐵 ln 4𝑥2 + 8𝑥 + 13 + 𝐶 a 3 2 𝑥 + 1 , −3 b 3 2 𝑥 + 1 , −6 c 𝑥 + 1, −3 d (𝑥 + 1, −6) ©2021, BYJU'S. All rights reserved
  • 10. JEE Main Feb 2021 න cos 𝑥 − sin 𝑥 8 − sin 2𝑥 𝑑𝑥 = 𝑎 sin−1 sin 𝑥 + cos 𝑥 𝑏 + 𝐶 a −1, 3 b (3, 1) c 1,3 d 1, −3 (where 𝐶 is a constant of integration), then the ordered pair (𝑎, 𝑏) is equal to ____. ©2021, BYJU'S. All rights reserved
  • 11. න cos 𝑥 − sin 𝑥 8 − sin 2𝑥 𝑑𝑥 = 𝑎 sin−1 sin 𝑥 + cos 𝑥 𝑏 + 𝐶 a −1, 3 b (3, 1) c 1,3 d 1, −3 ©2021, BYJU'S. All rights reserved
  • 12. JEE Main Feb 2021 න 1 − 5 sin2 𝑥 cos5 𝑥 sin2 𝑥 𝑑𝑥 = 𝑓 𝑥 cos5 𝑥 + 𝐶 Then find the value of 𝑓 3𝜋 4 . . (where 𝐶 is a constant of integration), ©2021, BYJU'S. All rights reserved
  • 13. Let 𝑓 𝑥−4 𝑥+2 = 2𝑥 + 1, 𝑥 ∈ ℝ − 1, −2 , then ‫׬‬ 𝑓 𝑥 𝑑𝑥 is equal to : (where 𝐶 is the constant of integration) JEE Main 2018 a 12 ln 1 − 𝑥 − 3𝑥 + 𝐶 c 12 ln 1 − 𝑥 + 3𝑥 + 𝐶 b −12 ln 1 − 𝑥 − 3𝑥 + 𝐶 d −12 ln 1 − 𝑥 + 3𝑥 + 𝐶 ©2021, BYJU'S. All rights reserved
  • 14. 𝑓 𝑥 − 4 𝑥 + 2 = 2𝑥 + 1 a 12 ln 1 − 𝑥 − 3𝑥 + 𝐶 c 12 ln 1 − 𝑥 + 3𝑥 + 𝐶 b −12 ln 1 − 𝑥 − 3𝑥 + 𝐶 d −12 ln 1 − 𝑥 + 3𝑥 + 𝐶 ©2021, BYJU'S. All rights reserved
  • 15. If , then is: JEE Main Mar 2021 𝑓 𝑥 = න 5𝑥8 + 7𝑥6 𝑥2 + 1 + 2𝑥7 2 𝑑𝑥, 𝑥 ≥ 0 , 𝑓 0 = 0 and 𝑓 1 = 1 𝑘 the value of 𝑘 ©2021, BYJU'S. All rights reserved
  • 16. ‫׬‬ 𝑒3 ln 2𝑥+5𝑒2 ln 2𝑥 𝑒4 ln 𝑥+5𝑒3 ln 𝑥−7𝑒2 ln 𝑥 𝑑𝑥 If ‫׬‬ 𝑒3 ln 2𝑥+5𝑒2 ln 2𝑥 𝑒4 ln 𝑥+5𝑒3 ln 𝑥−7𝑒2 ln 𝑥 𝑑𝑥 , 𝑥 > 0, is equal to: (where 𝑐 is integration constant) JEE Main Feb 2021 a b c d ln |𝑥2 + 5𝑥 − 7| + 𝑐 1 4 ln |𝑥2 + 5𝑥 − 7| + 𝑐 4 ln |𝑥2 + 5𝑥 − 7| + 𝑐 ln |𝑥2 + 5𝑥 − 7| + 𝑐 ©2021, BYJU'S. All rights reserved
  • 17. ‫׬‬ 𝑒3 ln 2𝑥+5𝑒2 ln 2𝑥 𝑒4 ln 𝑥+5𝑒3 ln 𝑥−7𝑒2 ln 𝑥 𝑑𝑥 a b c d ln |𝑥2 + 5𝑥 − 7| + 𝑐 1 4 ln |𝑥2 + 5𝑥 − 7| + 𝑐 4 ln |𝑥2 + 5𝑥 − 7| + 𝑐 ln |𝑥2 + 5𝑥 − 7| + 𝑐 Let 𝐼 = ©2021, BYJU'S. All rights reserved
  • 18. If ‫׬‬ 1 4 𝑥−1 3 𝑥+2 5 𝑑𝑥 , 𝑥 > 0, is equal to: (where 𝑐 is integration constant) JEE Main Aug 2021 a 3 4 𝑥+2 𝑥−1 5 4 + 𝑐 c 3 4 𝑥+2 𝑥−1 1 4 + 𝑐 b 4 3 𝑥−1 𝑥+2 5 4 + 𝑐 d 4 3 𝑥−1 𝑥+2 1 4 + 𝑐 ‫׬‬ 1 4 𝑥−1 3 𝑥+2 5 𝑑𝑥 ©2021, BYJU'S. All rights reserved
  • 19. ‫׬‬ 1 4 𝑥−1 3 𝑥+2 5 𝑑𝑥 Let 𝐼 = a 3 4 𝑥+2 𝑥−1 5 4 + 𝑐 c 3 4 𝑥+2 𝑥−1 1 4 + 𝑐 b 4 3 𝑥−1 𝑥+2 5 4 + 𝑐 d 4 3 𝑥−1 𝑥+2 1 4 + 𝑐 ©2021, BYJU'S. All rights reserved
  • 20. JEE Main Jan 2020 If ‫׬‬ cos 𝑥 sin3 𝑥 1+sin6 𝑥 2 3 𝑑𝑥 (where 𝑐 is integration constant) then 𝜆𝑓 𝜋 3 a − 9 8 b 9 8 c 2 d −2 = 𝑓 𝑥 1 + sin6 𝑥 1/𝜆 + 𝑐, ‫׬‬ cos 𝑥 sin3 𝑥 1+sin6 𝑥 2 3 𝑑𝑥 ©2021, BYJU'S. All rights reserved
  • 21. ‫׬‬ cos 𝑥 sin3 𝑥 1+sin6 𝑥 2 3 𝑑𝑥 a − 9 8 b 9 8 c 2 d −2 ©2021, BYJU'S. All rights reserved
  • 22. JEE Main Jan 2020 If ‫׬‬ 𝑑𝑥 𝑥+4 8 7 𝑥−3 6 7 , 𝑥 > 0, is equal to: (where 𝑐 is integration constant) a − 𝑥−3 𝑥+4 − 1 7 + 𝑐 c 𝑥−3 𝑥+4 1 7 + 𝑐 b 1 2 𝑥−3 𝑥+4 3 7 + 𝑐 d −1 13 𝑥−3 𝑥+4 − 13 7 + 𝑐 ‫׬‬ 𝑑𝑥 𝑥+4 8 7 𝑥−3 6 7 ©2021, BYJU'S. All rights reserved
  • 23. ‫׬‬ 𝑑𝑥 𝑥+4 8 7 𝑥−3 6 7 Let 𝐼 = a − 𝑥−3 𝑥+4 − 1 7 + 𝑐 c 𝑥−3 𝑥+4 1 7 + 𝑐 b 1 2 𝑥−3 𝑥+4 3 7 + 𝑐 d −1 13 𝑥−3 𝑥+4 − 13 7 + 𝑐 ©2021, BYJU'S. All rights reserved
  • 24. JEE Main Jan 2020 If ‫׬‬ 𝑑𝜃 cos2 𝜃 tan 2𝜃+sec 2𝜃 = 𝜆 tan 𝜃 + 2 ln 𝑓 𝜃 + 𝑐, (where 𝑐 is integration constant) then the ordered pair 𝜆, 𝑓 𝜃 is equal to: a −1, 1 − tan 𝜃 b −1, 1 + tan 𝜃 c 1, 1 + tan 𝜃 d −1, 1 − tan 𝜃 ‫׬‬ 𝑑𝜃 cos2 𝜃 tan 2𝜃+sec 2𝜃 = 𝜆 tan 𝜃 + 2 ln 𝑓 𝜃 + 𝑐 ©2021, BYJU'S. All rights reserved
  • 25. ‫׬‬ 𝑑𝜃 cos2 𝜃 tan 2𝜃+sec 2𝜃 = 𝜆 tan 𝜃 + 2 ln 𝑓 𝜃 + 𝑐 a −1, 1 − tan 𝜃 b −1, 1 + tan 𝜃 c 1, 1 + tan 𝜃 d −1, 1 − tan 𝜃 ©2021, BYJU'S. All rights reserved
  • 26. JEE Main Apr 2019 a 𝑥 − 𝛼 and ln sin 𝑥 − 𝛼 Let 𝛼 ∈ 0, 𝜋 2 be fixed. If the ‫׬‬ tan 𝑥+tan 𝛼 tan 𝑥−tan 𝛼 𝑑𝑥 = 𝐴 𝑥 cos 2𝛼 + 𝐵 𝑥 sin 2𝛼 + 𝑐, (where 𝑐 is integration constant) then the functions 𝐴(𝑥) and 𝐵(𝑥) are respectively: b 𝑥 + 𝛼 and ln sin 𝑥 − 𝛼 c 𝑥 − 𝛼 and ln cos 𝑥 − 𝛼 d 𝑥 + 𝛼 and ln sin 𝑥 + 𝛼 ©2021, BYJU'S. All rights reserved
  • 27. ‫׬‬ tan 𝑥+tan 𝛼 tan 𝑥−tan 𝛼 𝑑𝑥 = 𝐴 𝑥 cos 2𝛼 + 𝐵 𝑥 sin 2𝛼 + 𝑐 a 𝑥 − 𝛼 and ln sin 𝑥 − 𝛼 b 𝑥 + 𝛼 and ln sin 𝑥 − 𝛼 c 𝑥 − 𝛼 and ln cos 𝑥 − 𝛼 d 𝑥 + 𝛼 and ln sin 𝑥 + 𝛼 a 𝑥 − 𝛼 and ln sin 𝑥 − 𝛼 b 𝑥 + 𝛼 and ln sin 𝑥 − 𝛼 ©2021, BYJU'S. All rights reserved