LarCalc10_ch04_sec1.pptLarCalc10_ch04_sec1.ppt

Integration
Copyright © Cengage Learning. All rights reserved.

Antiderivatives and
Indefinite Integration
Copyright © Cengage Learning. All rights reserved.

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 Write the general solution of a differential equation and
use indefinite integral notation for antiderivatives.
 Use basic integration rules to find antiderivatives.
 Find a particular solution of a differential equation.
Objectives

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Antiderivatives
To find a function F whose derivative is f(x) = 3x2, you
might use your knowledge of derivatives to conclude that
The function F is an antiderivative of f .

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Antiderivatives
Note that F is called an antiderivative of f, rather than the
antiderivative of f. To see why, observe that
are all derivatives of f (x) = 3x2. In fact, for any constant C,
the function F(x)= x3 + C is an antiderivative of f.

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Using Theorem 4.1, you can represent the entire family of
antiderivatives of a function by adding a constant to a known
antiderivative.
For example, knowing that Dx [x2] = 2x, you can represent the
family of all antiderivatives of f(x) = 2x by
G(x) = x2 + C Family of all antiderivatives of f(x) = 2x
where C is a constant. The constant C is called the constant
of integration.
Antiderivatives

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The family of functions represented by G is the general
antiderivative of f, and G(x) = x2 + C is the general
solution of the differential equation
G'(x) = 2x. Differential equation
A differential equation in x and y is an equation that
involves x, y, and derivatives of y.
For instance, y' = 3x and y' = x2 + 1 are examples of
differential equations.
Antiderivatives

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Example 1 – Solving a Differential Equation
Find the general solution of the differential equation y' = 2.
Solution:
To begin, you need to find a function whose derivative is 2.
One such function is
y = 2x. 2x is an antiderivative of 2.
Now, you can use Theorem 4.1 to conclude that the
general solution of the differential equation is
y = 2x + C. General solution

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Example 1 – Solution
The graphs of several functions of the form y = 2x + C
are shown in Figure 4.1.
Figure 4.1
cont’d

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Notation for Antiderivatives

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When solving a differential equation of the form
it is convenient to write it in the equivalent differential form
The operation of finding all solutions of this equation is
called antidifferentiation (or indefinite integration) and is
denoted by an integral sign ∫.

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The general solution is denoted by
The expression ∫f(x)dx is read as the antiderivative of f with
respect to x. So, the differential dx serves to identify x as
the variable of integration. The term indefinite integral is a
synonym for antiderivative.

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Basic Integration Rules
The inverse nature of integration and differentiation can be
verified by substituting F'(x) for f(x) in the indefinite
integration definition to obtain
Moreover, if ∫f(x)dx = F(x) + C, then

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These two equations allow you to obtain integration
formulas directly from differentiation formulas, as shown in
the following summary.

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Basic Integration Rules cont’d

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Example 2 – Applying the Basic Integration Rules
Describe the antiderivatives of 3x.
Solution:
So, the antiderivatives of 3x are of the form where
C is any constant.

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In Example 2, note that the general pattern of integration is
similar to that of differentiation.

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Initial Conditions and Particular
Solutions

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Initial Conditions and Particular Solutions
You have already seen that the equation y = ∫f(x)dx has
many solutions (each differing from the others by a
constant).
This means that the graphs of any two antiderivatives of f
are vertical translations of each other.

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For example, Figure 4.2 shows the
graphs of several antiderivatives
of the form
for various integer values of C.
Each of these antiderivatives is a solution
of the differential equation
Figure 4.2

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In many applications of integration, you are given enough
information to determine a particular solution. To do this,
you need only know the value of y = F(x) for one value of x.
This information is called an initial condition.
For example, in Figure 4.2, only one curve passes through
the point (2, 4).
To find this curve, you can use the general solution
F(x) = x3 – x + C General solution
and the initial condition
F(2) = 4 Initial condition

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By using the initial condition in the general solution, you
can determine that
F(2) = 8 – 2 + C = 4
which implies that C = –2.
So, you obtain
F(x) = x3 – x – 2. Particular solution

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Find the general solution of
and find the particular solution that satisfies the initial
condition F(1) = 0.
Solution:
To find the general solution, integrate to obtain
Example 8 – Finding a Particular Solution

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Example 8 – Solution
Using the initial condition F(1) = 0, you
can solve for C as follows.
So, the particular solution, as shown
in Figure 4.3, is
cont’d
Figure 4.3

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