Lec 14-Instruction Set Architecture.pptx

Advanced Computer Arch.
Lecture 14
Instruction Set Architecture

Readings
 Von Neumann Model of LC-3, and MIPS
 P&P, Chapters 4 & 5
 P&P, Appendices A and C (ISA and microarchitecture of LC-3)
 Ebook 5, Ch 1, ISA (1.2) , CISC (1.4)
2

LC-3: A von Neumann Machine
3
Control signals
Data
ALU: 2 inputs, 1 output
Memory Data
Register
Memory Address
Register
16-bit
addressable
Keyboard
KBDR (data), KBSR (status)
Monitor (Display)
DDR (data), DSR (status)
8 General Purpose
Registers (GPR)
Finite State Machine
(for Generating Control Signals)
Instruction
Register
Program
Counter
ALU operation
GateALU
Clock

Stored Program & Sequential Execution
 Instructions and data are stored in memory
 Typically the instruction length is the word length
 The processor fetches instructions from memory sequentially
 Fetches one instruction
 Decodes and executes the instruction
 Continues with the next instruction
 The address of the current instruction is stored in the program counter
(PC)
 If word-addressable memory, the processor increments the PC by 1 (in LC-
3)
 If byte-addressable memory, the processor increments the PC by the
instruction length in bytes (4 in MIPS)
 In MIPS the OS typically sets the PC to 0x00400000 (start of a program)
4

 A sample MIPS program
 4 instructions stored in consecutive words in memory
 No need to understand the program now. We will get back to
it
A Sample Program Stored in Memory
5
.
.
.
Instructions
8 C 0 A 0 0 2 0
0 2 3 2 8 0 2 0
2 2 6 8 F F F 4
0 1 6 D 4 0 2 2
.
.
.
00400000
00400004
00400008
0040000C
.
.
.
Byte Address
.
.
.
lw $t2, 32($0)
add $s0, $s1, $s2
addi $t0, $s3, -12
sub $t0, $t3, $t5
MIPS assembly
0x8C0A0020
0x02328020
0x2268FFF4
0x016D4022
Machine code (encoded
instructions)
← PC

The Instruction
 An instruction is the most basic unit of computer
processing
 Instructions are words in the language of a computer
 Instruction Set Architecture (ISA) is the vocabulary
 The language of the computer can be written as
 Machine language: Computer-readable representation (that is,
0’s and 1’s)
 Assembly language: Human-readable representation
 We will study LC-3 instructions and MIPS instructions
 Principles are similar in all ISAs (x86, ARM, RISC-V, …)
6

The Instruction: Opcode & Operands
 An instruction is made up of two parts
 Opcode and Operands
 Opcode specifies what the instruction does
 Operands specify who the instruction is to do it to
 Both are specified in instruction format (or instr.
encoding)
 An LC-3 instruction consists of 16 bits (bits [15:0])
 Bits [15:12] specify the opcode  16 distinct opcodes in LC-
3
 Bits [11:0] are used to figure out where the operands are
7

Instruction Types
 There are three main types of instructions
 Operate instructions
 Execute operations in the ALU
 Data movement instructions
 Read from or write to memory
 Control flow instructions
 Change the sequence of execution
 Let us start with some example instructions
8

An Example Operate Instruction
 Addition
 add: mnemonic to indicate the operation to perform
 b, c: source operands
 a: destination operand
 a b + c
←
9
a = b + c; add a, b, c
High-level code Assembly

Registers
 We map variables to registers
10
add a, b, c b = R1
c = R2
a = R0
Assembly LC-3 registers
b = $s1
c = $s2
a = $s0
MIPS registers

 Addition
From Assembly to Machine Code in LC-3
11
ADD R0, R1, R2
LC-3 assembly
Field Values
Machine Code (Instruction
Encoding)
0x1042
Machine Code, in short (hexadecimal)
1 0 1 0 00 2
OP DR SR1 SR2
0 0 0 1 0 0 0 0 0 1 0 0 0 0 1 0
OP DR SR1 SR2
15 14 13 12 11 10 9 8 7 6 2 1 0
5 4 3

Instruction Format (or Encoding)
 LC-3 Operate Instruction Format
 OP = opcode (what the instruction does)
 E.g., ADD = 0001
 Semantics: DR SR1 + SR2
←
 E.g., AND = 0101
 Semantics: DR SR1 AND SR2
←
 SR1, SR2 = source registers
 DR = destination register 12
OP DR SR1 0 00 SR2
4 bits 3 bits 3 bits 3 bits
15 14 13 12 11 10 9 8 7 6 2 1 0
5 4 3

 Addition
From Assembly to Machine Code in MIPS
13
0 17 18 16 0 32
op rs rt rd shamt funct
add $s0, $s1, $s2
MIPS assembly
Field Values
0x02328020
000000 10001 10010 10000 00000 100000
op rs rt rd shamt funct
Machine Code (Instruction
Encoding)
15 11 10 6 0
5
16
20
21
25
26
31
rd ← rs + rt

Instruction Format: R-Type in MIPS
 MIPS R-type Instruction Format
 3 register operands
 0 = opcode
 rs, rt = source registers
 rd = destination register
 shamt = shift amount (only shift operations)
 funct = operation in R-type instructions
14
0 rs rt rd shamt funct
6 bits 5 bits 5 bits 5 bits 5 bits 6 bits

Reading Operands from Memory
 With operate instructions, such as addition, we tell the
computer to execute arithmetic (or logic) computations
in the ALU
 We also need instructions to access the operands from
memory
 Load them from memory to registers
 Store them from registers to memory
 Next, we see how to read (or load) from memory
 Writing (or storing) is performed in a similar way, but we
will talk about that later
15

Reading Word-Addressable Memory
 Load word
 load: mnemonic to indicate the load word operation
 A: base address
 i: offset
 E.g., immediate or literal (a constant)
 a: destination operand
 Semantics: a Memory[A + i]
← 16
a = A[i]; load a, A, i
High-level code Assembly

Load Word in LC-3 and MIPS
 LC-3 assembly
 MIPS assembly (assuming word-addressable)
17
a = A[2]; LDR R3, R0, #2
High-level code LC-3 assembly
R3 Memory[R0 + 2]
←
a = A[2]; lw $s3, 2($s0)
High-level code MIPS assembly
$s3 Memory[$s0 + 2]
←
These instructions use a particular addressing mode
(i.e., the way the address is calculated), called base+offset

Load Word in Byte-Addressable MIPS
 MIPS assembly
 Byte address is calculated as: word_address *
bytes/word
 4 bytes/word in MIPS
 If LC-3 were byte-addressable (i.e., LC-3b), 2 bytes/word
18
a = A[2]; lw $s3, 8($s0)
High-level code MIPS assembly
$s3 Memory[$s0 + 8]
←

 LC-3
 MIPS
Instruction Format With Immediate
19
6 3 0 2
OP DR BaseR offset6
LDR R3, R0, #2
LC-3 assembly
Field Values
35 16 19 8
op rs rt imm
lw $s3, 8($s0)
MIPS assembly
Field Values
I-Type
15 0
16
20
21
25
26
31
5 0
6
8
9
11
12
15

Instruction (Processing) Cycle
20

How Are These Instructions Executed?
 By using instructions, we can speak the language of the
computer
 Thus, we now know how to tell the computer to
 Execute computations in the ALU by using, for instance, an
addition
 Access operands from memory by using the load word instruction
 But, how are these instructions executed on the computer?
 The process of executing an instruction is called is the instruction
cycle (or, instruction processing cycle)
21

The Instruction Cycle
 The instruction cycle is a sequence of steps or phases, that an
instruction goes through to be executed
 FETCH
 DECODE
 EVALUATE ADDRESS
 FETCH OPERANDS
 EXECUTE
 STORE RESULT
 Not all instructions require the six phases
 LDR does not require EXECUTE
 ADD does not require EVALUATE ADDRESS
 Intel x86 instruction ADD [eax], edx is an example of instruction with
six phases
22

After STORE RESULT, a New FETCH
 FETCH
 DECODE
 FETCH OPERANDS
 EXECUTE
 STORE RESULT
23

FETCH
 The FETCH phase obtains the instruction from memory
and loads it into the Instruction Register (IR)
 This phase is common to every instruction type
 Complete description
 Step 1: Load the MAR with the contents of the PC, and
simultaneously increment the PC
 Step 2: Interrogate memory. This results in the instruction
being placed in the MDR by memory
 Step 3: Load the IR with the contents of the MDR
24

FETCH in LC-3
25
Step 1: Load
MAR and
increment PC
Step 2: Access
memory
Step 3: Load IR
with the
content of MDR

DECODE
 The DECODE phase identifies the instruction
 Also generates the set of control signals to process the
identified instruction in later phases of the instruction
cycle
 Recall the decoder (from Lecture 5)
 A 4-to-16 decoder identifies which of the 16 opcodes is
going to be processed
 The input is the four bits IR[15:12]
 The remaining 12 bits identify what else is needed to
process the instruction 26

DECODE in LC-3
27
DECODE
identifies the
instruction to
be processed
Also generates
the set of
control signals
to process the
instruction

Recall: Decoder
 “Input pattern detector”
 n inputs and 2n
outputs
 Exactly one of the outputs is 1 and all the rest are 0s
 The output that is logically 1 is the output
corresponding to the input pattern that the logic circuit
is expected to detect
 Example: 2-to-4 decoder
28

Recall: Decoder (II)
 The decoder is useful in determining how to interpret a
bit pattern
29
A = 1
0
B = 0
0
1
0
 It could be the
address of a location
in memory, that the
processor intends to
read from
 It could be an
instruction in the
program and the
processor needs to
decide what action to
take (based on
instruction opcode)

To Come: Full State Machine for LC-3b
30
https://safari.ethz.ch/digitaltechnik/spring2022/lib/exe/fetch.php?media=pp-appendixc.pdf
Decode State

EVALUATE ADDRESS
 The EVALUATE ADDRESS phase computes the address of
the memory location that is needed to process the
instruction
 This phase is necessary in LDR
 It computes the address of the data word that is to be read
from memory
 By adding an offset to the content of a register
 But not necessary in ADD
31

EVALUATE ADDRESS in LC-3
32
LDR calculates
the address by
adding a
register and an
immediate
ADD

FETCH OPERANDS
 The FETCH OPERANDS phase obtains the source operands
needed to process the instruction
 In LDR
 Step 1: Load MAR with the address calculated in EVALUATE
ADDRESS
 Step 2: Read memory, placing source operand in MDR
 In ADD
 Obtain the source operands from the register file
 In some microprocessors, operand fetch from register file can
be done at the same time the instruction is being decoded
33

FETCH OPERANDS in LC-3
34
LDR loads MAR
(step 1), and
places the
results in MDR
(step 2)

EXECUTE
 The EXECUTE phase executes the instruction
 In ADD, it performs addition in the ALU
 In XOR, it performs bitwise XOR in the ALU
 …
35

EXECUTE in LC-3
36
ADD adds SR1
and SR2

STORE RESULT
 The STORE RESULT phase writes the result to the
designated destination
 Once STORE RESULT is completed, a new instruction
cycle starts (with the FETCH phase)
37

STORE RESULT in LC-3
38
ADD loads ALU
Result into DR

STORE RESULT in LC-3
39
LDR loads
MDR into DR

 FETCH
 DECODE
 FETCH OPERANDS
 EXECUTE
 STORE RESULT
40

Changing the Sequence of Execution
 A computer program executes in sequence (i.e., in
program order)
 First instruction, second instruction, third instruction and
so on
 Unless we change the sequence of execution
 Control instructions allow a program to execute out of
sequence
 They can change the PC by loading it during the EXECUTE
phase
 That wipes out the incremented PC (loaded during the
FETCH phase)
41

Jump in LC-3
 Unconditional branch or jump
 LC-3
 BaseR = Base register
 PC R2 (Register identified by BaseR)
←
 Variations
 RET: special case of JMP where BaseR = R7
 JSR, JSRR: jump to subroutine
42
JMP R2
1100 000 000000
4 bits
BaseR
3 bits
This is register
addressing mode

Jump in MIPS
 Unconditional branch or jump
 MIPS
 2 = opcode
 target = target address
 PC PC
← ✝
[31:28] | sign-extend(target) * 4
 Variations
 jal: jump and link (function calls)
 jr: jump register
43
2 target
6 bits 26 bits
j target
J-Type
jr $s0
j uses pseudo-
direct addressing
mode
✝
This is the incremented PC
jr uses register
addressing mode

PC UPDATE in LC-3
44
JMP loads
SR1 into PC

Control of the Instruction Cycle
 State 1
 The FSM asserts GatePC and LD.MAR
 It selects input (+1) in PCMUX and
asserts LD.PC
 State 2
 MDR is loaded with the instruction
 State 3
 The FSM asserts GateMDR and LD.IR
 State 4
 The FSM goes to next state
depending on opcode
 State 63
 JMP loads register into PC
 Full state diagram in Patt&Pattel,
Appendix C
45
This is an FSM Controlling the LC-3 Processor

 FETCH
 DECODE
 FETCH OPERANDS
 EXECUTE
 STORE RESULT
46

LC-3 and MIPS
Instruction Set Architectures
47

The Instruction Set
 It defines opcodes, data types, and addressing modes
 ADD and LDR have been our first examples
48
ADD
1 0 1 0 00 2
OP DR SR1 SR2
6 3 0 4
OP DR BaseR offset6
LDR
Register mode
Base+offset mode

The Instruction Set Architecture
 The ISA is the interface between what the software commands and what
the hardware carries out
 The ISA specifies
 The memory organization
 Address space (LC-3: 216
, MIPS: 232
)
 Addressability (LC-3: 16 bits, MIPS: 8 bits)
 Word- or Byte-addressable
 The register set
 8 registers (R0 to R7) in LC-3
 32 registers in MIPS
 The instruction set
 Opcodes
 Data types
 Addressing modes
 Length and format of instructions
49
Microarchitecture
ISA
Program
Algorithm
Problem
Circuits
Electrons

Opcodes
 A large or small set of opcodes could be defined
 E.g, HP Precision Architecture: an instruction for A*B+C
 E.g, x86 ISA: multimedia extensions (MMX), later SSE and
AVX
 E.g, VAX ISA: opcode to save all information of one program
prior to switching to another program
 Tradeoffs are involved. Examples:
 Hardware complexity vs. software complexity
 Latency of simple vs. complex instructions
 In LC-3 and in MIPS there are three types of opcodes
 Operate
 Data movement
 Control 51

MIPS Instruction Types
54
opcode
6-bit
rs
5-bit
rt
5-bit
immediate
16-bit
I-type
R-type
0
6-bit
rs
5-bit
rt
5-bit
rd
5-bit
shamt
5-bit
funct
6-bit
opcode
6-bit
immediate
26-bit
J-type

Funct in MIPS R-Type Instructions (I)
55
Harris and Harris, Appendix B: MIPS Instructions
Opcode is 0
in MIPS R-
Type
instructions.
Funct
defines the
operation

Funct in MIPS R-Type Instructions (II)
56
Harris and Harris, Appendix B: MIPS Instructions
 More complete list of instructions are in H&H Appendix
B

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