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1
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Mesh-Current Method (Loop Analysis)
• Nodal analysis was developed by applying KCL at each non-reference
node.
• Mesh-Current method is developed by applying KVL around
meshes in the circuit.
• A mesh is a loop which doesn't contain any other loops within it.
• Loop (mesh) analysis results in a system of linear equations which
must be solved for unknown currents.
• Reduces the number of required equations to the number of meshes
• Can be done systematically with little thinking
• As usual, be careful writing mesh equations – follow sign convention.
2
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
•Powerful analysis method which applies KVL to find unknown currents.
•It is applicable to a circuit with no branches crossing each other.
no branches
Crossing
3
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Definitions
+
-
ig
A
B C i3
i1
i2
i4
i5
A mesh is a loop which does not contain any other loops within it.
4
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Steps of Mesh Analysis
Step1
Identify the number of
basic meshes.
Step 2
Assign a current to each mesh.
5
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Step 4
Solve the resulting system of linear equations.
As an example
V1 + I1 R1 + (I1 - I2) R3 = 0
I2 R2 + V2 + (I2-I1) R3 = 0
Step 3
Apply KVL around each loop to get
an equation in terms of the loop currents.
6
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Example
Use mesh analysis to find the current io
Solution
We apply KVL to the three meshes
For mesh 1
For mesh 2
Divide by 2
Divide by 2
7
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
For mesh 3
at node A
Divide by 2
By Substitution
8
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
For Loop 1
-10 + 4i1 + 6(i1-i2) = 0
For Loop 2
(No need to write a loop equation)
Cases to be considered for Mesh Analysis
Case I
A current source exists only in one mesh
set i2 = −5A and write a mesh equation for the other
mesh
i2 = - 5A
9
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Case II
A current source exists between two meshes
Exclude this part
10
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
a supermesh was created by
excluding the current source and any
elements connected in series with it,
A supermesh results when two meshes have a (dependent
or independent) current source in common.
Because mesh analysis applies KVL—we do not know the
voltage across a current source in advance.
Why???
11
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Applying KVL to the supermesh
i1 i2
Apply KCL to a node in the branch where the two meshes intersect.
12
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
-75 + 5i1 + 20(i1-i2) = 0
10ix + 20(i2-i1) + 4i2 = 0
-75 + 5i1 + 20(i1-i2) = 0 …………………(1)
10(i1-i2) + 20(i2-i1) + 4i2 = 0 …………….(2)
i2 = 5A
i1 = 7A
Case III
Mesh with Dependent Sources
Solve for Ix
ix = i1 - i2
Solve the two equations
then
13
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Example:
Use the mesh-current method to find io
14
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Solution
meshes 1 and 2 form a supermesh
meshes 2 and 3 form a supermesh
15
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Applying KVL to the larger supermesh,
16
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
For the independent current source, we apply KCL to node P
17
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
For the dependent current source, we apply KCL to node Q:
18
Dr.-Eng. Hisham El-Sherif
Electronics and Electrical Engineering Department
ELCT608, Electrical Engineering
Applying KVL in mesh 4,

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Lecture 6

  • 1. 1 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Mesh-Current Method (Loop Analysis) • Nodal analysis was developed by applying KCL at each non-reference node. • Mesh-Current method is developed by applying KVL around meshes in the circuit. • A mesh is a loop which doesn't contain any other loops within it. • Loop (mesh) analysis results in a system of linear equations which must be solved for unknown currents. • Reduces the number of required equations to the number of meshes • Can be done systematically with little thinking • As usual, be careful writing mesh equations – follow sign convention.
  • 2. 2 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering •Powerful analysis method which applies KVL to find unknown currents. •It is applicable to a circuit with no branches crossing each other. no branches Crossing
  • 3. 3 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Definitions + - ig A B C i3 i1 i2 i4 i5 A mesh is a loop which does not contain any other loops within it.
  • 4. 4 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Steps of Mesh Analysis Step1 Identify the number of basic meshes. Step 2 Assign a current to each mesh.
  • 5. 5 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Step 4 Solve the resulting system of linear equations. As an example V1 + I1 R1 + (I1 - I2) R3 = 0 I2 R2 + V2 + (I2-I1) R3 = 0 Step 3 Apply KVL around each loop to get an equation in terms of the loop currents.
  • 6. 6 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Example Use mesh analysis to find the current io Solution We apply KVL to the three meshes For mesh 1 For mesh 2 Divide by 2 Divide by 2
  • 7. 7 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering For mesh 3 at node A Divide by 2 By Substitution
  • 8. 8 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering For Loop 1 -10 + 4i1 + 6(i1-i2) = 0 For Loop 2 (No need to write a loop equation) Cases to be considered for Mesh Analysis Case I A current source exists only in one mesh set i2 = −5A and write a mesh equation for the other mesh i2 = - 5A
  • 9. 9 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Case II A current source exists between two meshes Exclude this part
  • 10. 10 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering a supermesh was created by excluding the current source and any elements connected in series with it, A supermesh results when two meshes have a (dependent or independent) current source in common. Because mesh analysis applies KVL—we do not know the voltage across a current source in advance. Why???
  • 11. 11 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Applying KVL to the supermesh i1 i2 Apply KCL to a node in the branch where the two meshes intersect.
  • 12. 12 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering -75 + 5i1 + 20(i1-i2) = 0 10ix + 20(i2-i1) + 4i2 = 0 -75 + 5i1 + 20(i1-i2) = 0 …………………(1) 10(i1-i2) + 20(i2-i1) + 4i2 = 0 …………….(2) i2 = 5A i1 = 7A Case III Mesh with Dependent Sources Solve for Ix ix = i1 - i2 Solve the two equations then
  • 13. 13 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Example: Use the mesh-current method to find io
  • 14. 14 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Solution meshes 1 and 2 form a supermesh meshes 2 and 3 form a supermesh
  • 15. 15 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Applying KVL to the larger supermesh,
  • 16. 16 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering For the independent current source, we apply KCL to node P
  • 17. 17 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering For the dependent current source, we apply KCL to node Q:
  • 18. 18 Dr.-Eng. Hisham El-Sherif Electronics and Electrical Engineering Department ELCT608, Electrical Engineering Applying KVL in mesh 4,