LESSON 4 SOLUTIONS - SCIENCE GRADE 7 - Q1
- 2. LEARNING OBJECTIVES: • DEFINE SOLUTE, SOLVENT, SOLUTION, SATURATED AND UNSATURATED SOLUTION AND GIVE EXAMPLES EACH.
- 5. 1. 2. 3. 4. 5. IDENTIFY THE PICTURES WHETHER THEY ARE CLASSIFIED AS SOLUTE O SOLVENT.
- 7. SOLUBILITY • IT DESCRIBES WHETHER A CERTAIN SOLUTE CAN BE DISSOLVED IN A SPECIFIC SOLVENT • A MEASURE OF THE MAXIMUM AMOUNT OF SOLUTE THAT WILL DISSOLVE IN A GIVEN AMOUNT OF SOLVENT AT A CERTAIN TEMPERATURE WHY SUGAR DISSOLVES IN WATER?
- 8. ACCORDING TO THE AMOUNT OF SOLUTE THAT CAN BE DISSOLVED IN A SOLVENT… SATURATED UNSATURATED
- 11. SCIENCE TERM EXPLANATION Solute (Give two examples) Solvent (Give two examples) Solution Mixture Saturated solution Unsaturated solution
- 13. OBJECTIVE FOR THE DAY: • Explain the difference between percentage concentration by volume and mass.
- 14. CONCENTRATION OF SOLUTION The measure how much solute is dissolved in a specific amount of solvent or solution.
- 15. CONCENTRATION OF SOLUTION can be expressed in PERCENT BY MASS PERCENT BY VOLUME The amount of solute in a given mass solution. The amount of solute in a given volume of solution Ratio of Amount of solute x 100 % Amount of solution
- 16. CONCENTRATION OF SOLUTION can be expressed in PERCENT BY MASS PERCENT BY VOLUME The amount of solute in a given mass solution. The amount of solute in a given volume of solution % m/m = Mass of solute X 100% Mass of solution % v/v = Volume of solute X 100% Volume of solution
- 17. PERCENT BY MASS – concentration expressed in terms of percent by mass is a ratio of a measured amount of solute to a measured amount of solution. Formula: Percent by Mass = Mass of solute X 100% Mass of solution
- 18. Read and analyze the problem Write the given and the required (the one to be solved) Write the formula SOLVE! 1 2 3 4 STEPS TO FOLLOW:
- 19. SAMPLE PROBLEM #1: What is the percent by mass of a salt solution by dissolving 11 g of salt in 80 g of solutions? Given: 11 g mass solute 80 g mass solution Required: percent by mass Formula: % m/m = Mass of solute X 100% Mass of solution Solution: % m/m = 11 g X 100 % = 13.75 % 80 g
- 20. EXERCISE PROBLEM #1: Luna prepared milk for her cat. She then pour 10 g of sugar in 170 g of milk solution. Calculate the percent by mass. Given: Required: Formula: Solution:
- 21. EXERCISE PROBLEM #1: Luna prepared milk for her cat. She then pour 10 g of sugar in 170 g of milk solution. Calculate the percent by mass. Given: 10 g - mass solute 170 g - mass of solution Required: percent by mass Formula: Percent by Mass = Mass of solute X 100% Mass of solution Solution: % m/m = 10 g x 100 % = 5.88 % 170 g
- 22. PERCENT BY VOLUME – usually describes solutions in which both solute and solvent are liquid. Formula: Percent by Volume = Volume of solute X 100% Volume of solution
- 23. SAMPLE PROBLEM #1: A solution contains 50 mL ethanol in 300 mL of alcohol solution. What is the percent by volume concentration of the solution? Given: 50 mL - volume solute 300 mL - volume solution Required: percent by volume Formula: % v/v = Volume of solute X 100% Volume of solution Solution: % v/v = 50 mL X 100 % = 16.67 % 300 mL
- 24. EXAMPLE PROBLEM #2: What is the volume percent of a solution containing 30 mL of soda in 120 mL of water? Given: Required: Formula: Solution:
- 25. EXAMPLE PROBLEM #2: What is the volume percent of a solution containing 30 mL of soda in 120 mL of water? Given: 30 mL - volume solute 120 mL - volume solution Required: percent by volume Formula: % v/v = Volume of solute X 100% Volume of solution Solution: % v/v = 30 mL X 100 % = 25 % 120 mL
- 26. ACTIVITY TIME! 1. What is the volume percent of a solution containing 50 mL of water in 170 mL of acetic acid? Given: Required: Formula: Solution: 2. What is the mass percent of a salt solution by dissolving 20 g of sugar in 60 g of solutions? Given: Required: Formula: Solution:
- 27. ANSWER: 1. What is the volume percent of a solution containing 50 mL of water in 170 mL of acetic acid? Given: 50 mL - volume solute 170 mL - volume solution Required: percent by volume Formula: % v/v = Volume of solute X 100% Volume of solution Solution: % v/v = 50 mL X 100 % = 29.41 % 170 mL
- 28. ANSWER: 2. What is the mass percent of a salt solution by dissolving 20 g of sugar in 60 g of solutions? Given: 20 g mass of solute 60 g mass of solution Required: percent by mass Formula: % m/m = Mass of solute X 100% Mass of solution Solution: % m/m = 20 g X 100 % = 33.33 % 60 g