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Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin
1 | P a g e
Form 3 - Chapter 9 – Scale Drawing [Notes Completely]
1. Ratio Scale of Scale Drawing = size of drawing(image) : size of actual object
2. Scale Drawing= Length of a side of the drawing .
Length of the corresponding side of the object
3. **1 : __. eg. 1 : 2, 1 : 2
1
.
4. Use in map.
5. Unit conversation:
1km=1000m,1m=100cm,. 1cm=10mm.
6. Unit conversation (in area): 1km2
=1 000 000 m2
,
1m2
=1 00 00 cm2
, 1cm2
=1 0 0 mm2
.
7. Solving problems (formula): FINDING
DISTACE: O
I
O
I
 , FINDING SCALE: I:O.
8. Redraw on the grid dependon scale.
Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin
2 | P a g e
Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin
3 | P a g e
Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin
4 | P a g e
4.
Solve the following problems.
The length of a roomis 3.5 cm on a map
drawn to a scale of 1:200. Find the
length, in m, of the room.
A road with a length 70 km is represented
by 3.5 cm on a map. Find the scale of the
map.
Square B with 256 cm2
is the scale
drawing same as square A with 64
cm2
. Find the scale used.
The diagram shows a solid in the
shape of a cone with a
hemisphere at the top,drawn to a
scale of 1:5. Find the actual
volume of the solid.
(Use= )
Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin
5 | P a g e
Form 3 - Chapter 10 – Transformation II [Notes Completely]
1. Topic same as Form3 - Chapter9 (scale)
2. Similarity of Shapes (Yes and No)
3. Enlargement Scale = Length of (the side) the drawing .
Length of (the corresponding side) the object
4. Finding value: FIND : ORIGIN x = 5
. 8 10 (打岔乘)
10x=40
x = 10÷10
x = 4cm
5. Area of image = (scale factor)2
× area of object *k=scale factor
6. TriangularFormula:
I
k2 O
7. Complete the following table:
Scale factor Area of object (cm2
) Area of image (cm2
)
4 12
1.5 12
36 81
136 8.5
Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin
6 | P a g e
Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin
7 | P a g e
Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin
8 | P a g e
Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin
9 | P a g e
6 (b)(i) (ii)
Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin
10 | P a g e
9

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Mathematics form 3-chapter 9 & 10 Scale Drawing + Transformation II © By Kelvin

  • 1. Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin 1 | P a g e Form 3 - Chapter 9 – Scale Drawing [Notes Completely] 1. Ratio Scale of Scale Drawing = size of drawing(image) : size of actual object 2. Scale Drawing= Length of a side of the drawing . Length of the corresponding side of the object 3. **1 : __. eg. 1 : 2, 1 : 2 1 . 4. Use in map. 5. Unit conversation: 1km=1000m,1m=100cm,. 1cm=10mm. 6. Unit conversation (in area): 1km2 =1 000 000 m2 , 1m2 =1 00 00 cm2 , 1cm2 =1 0 0 mm2 . 7. Solving problems (formula): FINDING DISTACE: O I O I  , FINDING SCALE: I:O. 8. Redraw on the grid dependon scale.
  • 2. Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin 2 | P a g e
  • 3. Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin 3 | P a g e
  • 4. Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin 4 | P a g e 4. Solve the following problems. The length of a roomis 3.5 cm on a map drawn to a scale of 1:200. Find the length, in m, of the room. A road with a length 70 km is represented by 3.5 cm on a map. Find the scale of the map. Square B with 256 cm2 is the scale drawing same as square A with 64 cm2 . Find the scale used. The diagram shows a solid in the shape of a cone with a hemisphere at the top,drawn to a scale of 1:5. Find the actual volume of the solid. (Use= )
  • 5. Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin 5 | P a g e Form 3 - Chapter 10 – Transformation II [Notes Completely] 1. Topic same as Form3 - Chapter9 (scale) 2. Similarity of Shapes (Yes and No) 3. Enlargement Scale = Length of (the side) the drawing . Length of (the corresponding side) the object 4. Finding value: FIND : ORIGIN x = 5 . 8 10 (打岔乘) 10x=40 x = 10÷10 x = 4cm 5. Area of image = (scale factor)2 × area of object *k=scale factor 6. TriangularFormula: I k2 O 7. Complete the following table: Scale factor Area of object (cm2 ) Area of image (cm2 ) 4 12 1.5 12 36 81 136 8.5
  • 6. Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin 6 | P a g e
  • 7. Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin 7 | P a g e
  • 8. Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin 8 | P a g e
  • 9. Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin 9 | P a g e 6 (b)(i) (ii)
  • 10. Mathematics Form 3 – Chapter 9 & 10 © Notes Prepared by Kelvin 10 | P a g e 9