Mca4020 probability and statistics
Download as DOCX, PDF0 likes135 views
This document provides information about getting fully solved assignments for the summer 2015 semester for MCA students. It includes contact information to email or call for assistance with assignments in subjects like Probability and Statistics. Sample assignments are provided covering topics like probability, distributions, trend lines, and standard deviation. Students should contact the given email or phone number to get help with their MCA semester 4 assignments.
Mca4020 probability and statistics
- 1. Dear students get fully solved assignments Send your semester & Specialization name to our mail id : help.mbaassignments@gmail.com or call us at : 08263069601 SUMMER 2015 ASSIGNMENT DRIVE SUMMER 2015 PROGRAM MCA SEMESTER FOURTH SUBJECT CODE & NAME MCA4020- PROBABILITY AND STATISTICS BK ID B1779 CREDIT & MARKS 4 CREDITS & 60 MARKS 1 Three machines A, B and C produce respectively 60%, 30% and 10% of the total number of items of a factory. The percentage of defective output of these machines are respectively 2%, 3% and 4%. An item is selected at random and is found to be defective. Find the probability that the item was producedby machine C. Answer: Multiply the respective percentage of production by the percentage of defects for each machine A = 60% * 2% = 1.2% of the factory'stotal outputare defectsproducedbyMachine A B = 30% * 3% = 0.9% of the factory's total outputare defectsproducedbyMachine B C = 10% * 4% = 0.4% of the factory's total outputare defectsproducedbyMachine C Therefore the total defects=1.2% + 0.9% + 0.4% = 2.5%
- 2. 2 Findthe constant k so that F(x,y) = {k(x+1)e-y , 0<x<1,y>0 0 elsewhere Is a jointprobabilitydensityfunction.Are X and Y independent? Answer: Probability density function:- In probability theory and statistics, given two jointly distributed random variables X and Y, the conditional probability distribution of Y given X is the probability distribution of Y when X is known to be a particular value; in some cases the conditional probabilities may be expressed as functions containing the unspecified value x of X as a parameter. In case that both "X" and "Y" are categorical variables, a conditional probability table is typically used to represent the conditional probability.The conditional distribution 3 The data shows the distributionofweight ofstudents of1st standard of a school. Findthe quartiles. Class Interval 13-18 18-20 20-21 21-22 22-23 23-25 25-30 Frequency 22 27 51 42 32 16 10 Answer:If a data setof scoresisarranged inascendingorderof magnitude,then: The medianisthe middle value of the dataset. The lowerquartile (Q1) isthe medianof the lowerhalf of the data set. The upperquartile (Q3) isthe medianof the upper 4 Fita trend line to the following data by the freehandmethod: Year Production of wheat(in tonnes) Year Production of wheat(in tonnes)
- 3. 1995 20 2000 25 1996 22 2001 23 1997 24 2002 26 1998 21 2003 25 1999 23 2004 24 Answer: Methods of Freehands: It is familiar concept, briefly described for drawing frequency curves. In case of a time series a scatter diagram of the given observations is plotted against time on the horizontal axis and a freehand smooth curve is drawn through the plotted points. The curve is so drawn that most of the points concentrate around the curve, however, smoothness should not be scarified in trying to let the points exactly fall on the curve. It would be better to draw a straight line through the plotted points insteadof a curve,if possible.The curve fittedby 5 Let X be a random variable and its probabilitymass functionis P(x=r) = qr-1 p,r=1,2,3… Findthe m.g.f. of X and hence it’s mean and variance. Answer:StandardDeviation:-TheStandardDeviationisameasure of how spreadoutnumbersare. Its symbol isσ(the greeklettersigma) The formulaiseasy:it isthe square rootof the Variance.Sonow you ask,"What isthe Variance?" Variance 6 The diastolic blood pressures of men are distributed as shown in table. Find the standard deviation and variance. Pressure 78-80 80-82 82-84 84-86 86-88 88-90 No. of Men 3 15 26 23 9 4 Answer:Givenvaluesare: Pressure 78-80 80-82 82-84 84-86 86-88 88-90 No. of Men 3 15 26 23 9 4 Difference =2
- 4. Dear students get fully solved assignments Send your semester & Specialization name to our mail id : help.mbaassignments@gmail.com or call us at : 08263069601