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Course: Electromagnetic Theory
paper code: EC 501
Course Coordinator: Arpan Deyasi
Department of Electronics and Communication Engineering
RCC Institute of Information Technology
Kolkata, India
Topic: Poynting’s Theorem
20-08-2025 Arpan Deyasi, EC501 1
Arpan Deyasi
Electromagnetic
Theory
Poynting’s Theorem
It states that time rate at which e.m energy in a finite volume decreases, is
equal to the rate of dissipation of energy in the form of Joule heat by the
e.m field, plus the rate at which energy is flowed out through the surface
Arpan Deyasi
Electromagnetic
Theory
Proof
Work done dW F.dl
=
( )
dq E u B .dl
= + 
( )
dq E u B .udt
= + 
( )
dqE.udt dq u B .udt
= + 
( )
dqE.udt dq u B .udt
= + 
( )
dv E.udt
= 
Arpan Deyasi
Electromagnetic
Theory
dW E.Jdvdt
=
Proof
V
dW
P E.Jdv
dt
= = 
Power delivered
From Maxwell’s equation at free space
0 0 0
E
B J
t
  

 = +

( ) 0
0
1 E
J B
t



=  −

Arpan Deyasi
Electromagnetic
Theory
Proof
( ) 0
0
1
. . .
E
E J E B E
t



=  −

( ) ( ) 0
0
1
. . .
E
B E E B E
t



 
=  −  −
  
( ) 0
0
1
. . .
B E
B E B E
t t


 
 
= − −  −
 
 
 
Arpan Deyasi
Electromagnetic
Theory
Proof
( ) ( ) ( )
0
0 0
1
. . . .
2 2
E J B H E B D E
t t


  
 
= − −   −
 
( )
( ) ( )
0
V
0
0
V V
dW
B.H dv
dt 2 t
1
. E B dv D.E dv
2 t
 
 = −
 
 
−   −
  

 
Arpan Deyasi
Electromagnetic
Theory
Proof
( )
( ) ( )
0
V
0
0
S V
dW
B.H dv
dt 2 t
1
E B .ds D.E dv
2 t
 
= −
 
 
−  −
  

 
( ) ( )
( )
0
0
V V
0
S V
B.H dv D.E dv
2 t 2 t
1
E B .ds E.Jdv

  
− −
   
=  +

 
 
Arpan Deyasi
Electromagnetic
Theory
Proof
Electrostatic energy
2
0 0
E
V V
W E dv E.Ddv
2 2
 
= =

 
Total energy stored
2
B
0 0
V V
1
W B dv B.Hdv
2 2

= =
 
 
Magnetostatic energy
0
EB E B
0
V V
W W W E.Ddv B.Hdv
2 2
 
= + = +
 
 
Arpan Deyasi
Electromagnetic
Theory
( )
EB
0
S
dW dW 1
E B .ds
dt dt
 − = + 


Proof
Integral form of Poynting’s theorem
LHS describes time rate of decrease of total energy in e.m field
1st term in RHS denotes power delivered through the motion of free charges
2nd term in RHS signifies rate at which energy is carried out of volume
Arpan Deyasi
Electromagnetic
Theory
Proof
Poynting’s vector is defined as
( )
0
1
S E B
= 

Energy per unit time per unit area transported by the field
Arpan Deyasi
Electromagnetic
Theory
Proof
EB
EB
V
dW d
U dv
dt dt
= 
M
V
dW d
U dv
dt dt
= 
Electromagnetic energy density
Mechanical energy density
Arpan Deyasi
Electromagnetic
Theory
Proof
( )
EB M
0
V V S
d d 1
U dv U dv E B .ds
dt dt
− − = 

  
EB M
V V S
d d
U dv U dv S.ds
dt dt
− − =
  
EB M
V V V
d d
U dv U dv .Sdv
dt dt
− − = 
  
Arpan Deyasi
Electromagnetic
Theory
Proof
( )
EB M
V V
d
U U dv .Sdv
dt
− + = 
 
( )
EB M
.S U U
t

 = − +

Differential form of Poynting’s theorem
Arpan Deyasi
Electromagnetic
Theory

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Poynting's theorem: differential and integral forms

  • 1. Course: Electromagnetic Theory paper code: EC 501 Course Coordinator: Arpan Deyasi Department of Electronics and Communication Engineering RCC Institute of Information Technology Kolkata, India Topic: Poynting’s Theorem 20-08-2025 Arpan Deyasi, EC501 1 Arpan Deyasi Electromagnetic Theory
  • 2. Poynting’s Theorem It states that time rate at which e.m energy in a finite volume decreases, is equal to the rate of dissipation of energy in the form of Joule heat by the e.m field, plus the rate at which energy is flowed out through the surface Arpan Deyasi Electromagnetic Theory
  • 3. Proof Work done dW F.dl = ( ) dq E u B .dl = +  ( ) dq E u B .udt = +  ( ) dqE.udt dq u B .udt = +  ( ) dqE.udt dq u B .udt = +  ( ) dv E.udt =  Arpan Deyasi Electromagnetic Theory
  • 4. dW E.Jdvdt = Proof V dW P E.Jdv dt = =  Power delivered From Maxwell’s equation at free space 0 0 0 E B J t      = +  ( ) 0 0 1 E J B t    =  −  Arpan Deyasi Electromagnetic Theory
  • 5. Proof ( ) 0 0 1 . . . E E J E B E t    =  −  ( ) ( ) 0 0 1 . . . E B E E B E t      =  −  −    ( ) 0 0 1 . . . B E B E B E t t       = − −  −       Arpan Deyasi Electromagnetic Theory
  • 6. Proof ( ) ( ) ( ) 0 0 0 1 . . . . 2 2 E J B H E B D E t t        = − −   −   ( ) ( ) ( ) 0 V 0 0 V V dW B.H dv dt 2 t 1 . E B dv D.E dv 2 t    = −     −   −       Arpan Deyasi Electromagnetic Theory
  • 7. Proof ( ) ( ) ( ) 0 V 0 0 S V dW B.H dv dt 2 t 1 E B .ds D.E dv 2 t   = −     −  −       ( ) ( ) ( ) 0 0 V V 0 S V B.H dv D.E dv 2 t 2 t 1 E B .ds E.Jdv     − −     =  +      Arpan Deyasi Electromagnetic Theory
  • 8. Proof Electrostatic energy 2 0 0 E V V W E dv E.Ddv 2 2   = =    Total energy stored 2 B 0 0 V V 1 W B dv B.Hdv 2 2  = =     Magnetostatic energy 0 EB E B 0 V V W W W E.Ddv B.Hdv 2 2   = + = +     Arpan Deyasi Electromagnetic Theory
  • 9. ( ) EB 0 S dW dW 1 E B .ds dt dt  − = +    Proof Integral form of Poynting’s theorem LHS describes time rate of decrease of total energy in e.m field 1st term in RHS denotes power delivered through the motion of free charges 2nd term in RHS signifies rate at which energy is carried out of volume Arpan Deyasi Electromagnetic Theory
  • 10. Proof Poynting’s vector is defined as ( ) 0 1 S E B =   Energy per unit time per unit area transported by the field Arpan Deyasi Electromagnetic Theory
  • 11. Proof EB EB V dW d U dv dt dt =  M V dW d U dv dt dt =  Electromagnetic energy density Mechanical energy density Arpan Deyasi Electromagnetic Theory
  • 12. Proof ( ) EB M 0 V V S d d 1 U dv U dv E B .ds dt dt − − =      EB M V V S d d U dv U dv S.ds dt dt − − =    EB M V V V d d U dv U dv .Sdv dt dt − − =     Arpan Deyasi Electromagnetic Theory
  • 13. Proof ( ) EB M V V d U U dv .Sdv dt − + =    ( ) EB M .S U U t   = − +  Differential form of Poynting’s theorem Arpan Deyasi Electromagnetic Theory