![The distinction between the prefix and postfix forms of ++ and -- will probably seem
strained at first, but it will make more sense once we begin using these operators in more
realistic situations.
For example,
a[i] = c;
i = i + 1;
using the ++ operator, we could simply write this as
a[i++] = c;
We wanted to increment i after deciding which element of the array to store into, so the
postfix form i++ is appropriate.
Notice that it only makes sense to apply the ++ and -- operators to variables (or to other
“containers,” such as a[i]). It would be meaningless to say something like
1++
or
(2+3)++
The ++ operator doesn’t just mean “add one”; it means “add one to a variable” or “make
a variable’s value one more than it was before.” But (1+2) is not a variable, it’s an
expression; so there’s no place for ++ to store the incremented result.
Another unfortunate example is
i = i++;
which some confused programmers sometimes write, presumably because they want to
be extra sure that i is incremented by 1. But i++ all by itself is sufficient to increment i
by 1; the extra (explicit) assignment to i is unnecessary and in fact counterproductive,
meaningless, and incorrect. If you want to increment i (that is, add one to it, and store the
result back in i), either use
i = i + 1;
or
i += 1;](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-29-320.jpg)
![Table 5.1
scanf() reads the input, matching the characters from format. When a control character is
read, it puts the value in the next variable. Whitespaces (tabs, spaces, etc) are skipped.
Non-whitespace characters are matched to the input, then discarded. If a number comes
between the % sign and the control character, then only that many characters will be
entered into the variable. If scanf() encounters a set of characters, denoted by the %[]
control character, then any characters found within the brackets are read into the variable.
The return value of scanf() is the number of variables that were successfully assigned
values, or EOF if there is an error.
Program 5.2: Program to use scanf() to read integers, floats, characters and strings
from the user.
#include<stdio.h>
main()
{
int i;
float f;
char c;
char str[10];
scanf(“%d %f %c %s”, &i, &f, &c, str);
printf(“%d %f %c %s”, i, f, c, str);
}
Execute this program and observe the result.
Note that for a scanf() function, the addresses of the variable are used as the arguments
for an int, float and a char type variable. But this is not true for a string variable because
a string name itself refers to the address of a string variable.
A s-control character is used to enter strings to string variables. A string that includes
whitespace characters can not be entered. There are ways to work with strings that
include whitespace characters. One way is to use the getchar() function within a loop.
Another way is to use gets() function which will be discussed later.](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-54-320.jpg)
![It is also possible to use the scanf() function to enter such strings. To do so, the s-control
character must be replaced by a sequence of characters enclosed in square brackets,
designated as […]. Whitespace characters may be included within the brackets, thus
accommodating strings that contain such characters.
Example:
#include<stdio.h>
main()
{
char str[80];
…
scanf(“%[ ABCDEFGHIJKLMNOPQRST]”, str);
…
}
This example illustrates the use of the scanf() function to enter a string consisting of
uppercase letters and blank spaces. Please note that if you want to allow lowercase letters
to be entered, all the lowercase letters( i.e from a-z) must be included in the list of control
string.
Self Assessment Questions
i) What are the different characters included in a control string?
ii) The control string used to read a hexadecimal character is –
iii) State true or false.
scanf() functions needs address of the data item to be read as the
argument.
Formatted Output
Output data can be written from the computer onto a standard output device using the
library function printf(). This function can be used to output any combination of
numerical values, single characters and strings. It is similar to the input function scanf(),
except that its purpose is to display data rather than enter into the computer.](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-55-320.jpg)
![char line[80];
gets(line);
puts(line);
}
This program uses gets() and puts() functions rather than scanf() and printf(), to transfer
the line of text into and out of the computer.
Self Assessment Questions
i) State true or false:
gets() is a formatted input statement.
ii) The argument for a gets() and puts() functions are – variables
iii) State true or false.
Using gets() function, you can not include whitespace characters in
the input string.
Interactive Programming
Creating interactive dialog between the computer and the user is a modern style of
programming. These dialogs usually involve some form of question-answer interaction,
where the computer asks the questions and the user provides the answer, or vice versa.
In C, such dialogs can be created by alternate use of the scanf() and printf() functions.
Program 5.3: Program to calculate the simple interest
#include<stdio.h>
main()
{
/* Sample interactive program*/
float principle, rate, time, interest;
printf(“ Please enter the principle amount: “);](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-59-320.jpg)
![3. By using control string %[ ].
4. gets() is not the formatted input function but the scanf() function is a formatted input
function.
5. a) scanf(“%d %d %d”, &i, &j, &k);
b) scanf(“%d %o %x”, &i, &j, &k);
c) scanf(“%x %x %o”, &i, &j, &k);
Exercises
1. Write a program to print the factors of a given number.
2. Given the length of a side, write a C program to compute surface area and volume of a
cube.
3. Write a program to reverse a number and find sum of the digits.
4. Write a program to print the multiplication table for any given number.
5. Write a program to check whether a given number is palindrome.
Unit 6 Making Decisions in C
• The Relational operators, The Logical operators, Bitwise operators, The
increment and decrement operators, Precedence of operators, The GOTO
statements, The IF statement, The IF ELSE statement, Nesting of IF statements,
The conditional expression, The break statement, The switch statement.
Introduction
Statements are the “steps” of a program. Most statements compute and assign values or
call functions, but we will eventually meet several other kinds of statements as well. By
default, statements are executed in sequence, one after another. We can, however, modify
that sequence by using control flow constructs such that a statement or group of
statements is executed only if some condition is true or false. This involves a kind of
decision making to see whether a particular condition has occurred or not and then direct
the computer to execute certain statements accordingly.](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-62-320.jpg)
![else big = c ; // assign C to big
printf (“Largest of %d,%d&%d = %d”, a,b,c,big);
}
Self Assessment Questions
(i) In the cascaded if/else/if/else/… chain, each else clause is another
_______statement.
The conditional expression
The conditional operator (?:) takes three operands. It tests the result of the first operand
and then evaluates one of the other two operands based on the result of the first. Consider
the following example:
E1 ? E2 : E3
If expression E1 is nonzero (true), then E2 is evaluated, and that is the value of the
conditional expression. If E1 is 0 (false), E3 is evaluated, and that is the value of the
conditional expression. Conditional expressions associate from right to left. In the
following example, the conditional operator is used to get the minimum of x and y:
a = (x < y) ? x : y; /* a= min(x, y) */
There is a sequence point after the first expression (E1). The following example’s result
is predictable, and is not subject to unplanned side effects:
i++ > j ? y[i] : x[i];
The conditional operator does not produce a lvalue. Therefore, a statement such as
a ? x : y = 10 is not valid.
Self Assessment Questions
(i) State true or false
The conditional operator does not produce a lvalue.
The switch statement
The switch case statements are a substitute for long if statements that compare a variable
to several “integral” values (”integral” values are simply values that can be expressed as
an integer, such as the value of a char). The basic format for using switch case is
outlined below. The value of the variable given into switch is compared to the value](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-70-320.jpg)
![void linecount(void)
{
/* read a line of text and count the number of characters */
char line[80];
int count=0;
while((line[count]=getchar())!=’n’)
++count;
return count;
}
float cal_avg(void)
{
/* compute average and return*/
return (float)sum/lines;
}
In the above program the variables sum and lines are globally declared and hence they
could be used in both the functions main() and cal_avg()
Self Assessment Questions
i) State true or false.
The variables declared in the main() function are the global variables.
ii) State true or false.
The global variables are more secured than the automatic variables
in a program.
Static Variables](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-120-320.jpg)
![int a[10];
declares an array, named a, consisting of ten elements, each of type int. Simply
speaking, an array is a variable that can hold more than one value. You specify which of
the several values you’re referring to at any given time by using a numeric subscript.
(Arrays in programming are similar to vectors or matrices in mathematics.) We can
represent the array a above with a picture like this:
In C, arrays are zero-based: the ten elements of a 10-element array are numbered from 0
to 9. The subscript which specifies a single element of an array is simply an integer
expression in square brackets. The first element of the array is a[0], the second element
is a[1], etc. You can use these “array subscript expressions” anywhere you can use the
name of a simple variable, for example:
a[0] = 10;
a[1] = 20;
a[2] = a[0] + a[1];
Notice that the subscripted array references (i.e. expressions such as a[0] and a[1]) can
appear on either side of the assignment operator.
The subscript does not have to be a constant like 0 or 1; it can be any integral expression.
For example, it’s common to loop over all elements of an array:
int i;
for(i = 0; i < 10; i = i + 1)
a[i] = 0;
This loop sets all ten elements of the array a to 0.
Arrays are a real convenience for many problems, but there is not a lot that C will do with
them for you automatically. In particular, you can neither set all elements of an array at
once nor assign one array to another; both of the assignments
a = 0; /* WRONG */
and
int b[10];
b = a; /* WRONG */
are illegal.](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-131-320.jpg)
![To set all of the elements of an array to some value, you must do so one by one, as in the
loop example above. To copy the contents of one array to another, you must again do so
one by one:
int b[10];
for(i = 0; i < 10; i = i + 1)
b[i] = a[i];
Remember that for an array declared
int a[10];
there is no element a[10]; the topmost element is a[9]. This is one reason that zero-
based loops are also common in C. Note that the for loop
for(i = 0; i < 10; i = i + 1)
...
does just what you want in this case: it starts at 0, the number 10 suggests (correctly) that
it goes through 10 iterations, but the less-than comparison means that the last trip through
the loop has i set to 9. (The comparison i <= 9 would also work, but it would be less
clear and therefore poorer style.)
In the little examples so far, we’ve always looped over all 10 elements of the sample
array a. It’s common, however, to use an array that’s bigger than necessarily needed, and
to use a second variable to keep track of how many elements of the array are currently in
use. For example, we might have an integer variable
int na; /* number of elements of a[]
in use */
Then, when we wanted to do something with a (such as print it out), the loop would run
from 0 to na, not 10 (or whatever a’s size was):
for(i = 0; i < na; i = i + 1)
printf("%dn", a[i]);
Naturally, we would have to ensure that na’s value was always less than or equal to the
number of elements actually declared in a.
Arrays are not limited to type int; you can have arrays of char or double or any other
type.
Here is a slightly larger example of the use of arrays. Suppose we want to investigate the
behavior of rolling a pair of dice. The total roll can be anywhere from 2 to 12, and we
want to count how often each roll comes up. We will use an array to keep track of the
counts: a[2] will count how many times we’ve rolled 2, etc.](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-132-320.jpg)
![We’ll simulate the roll of a die by calling C’s random number generation function,
rand(). Each time you call rand(), it returns a different, pseudo-random integer. The
values that rand() returns typically span a large range, so we’ll use C’s modulus (or
“remainder”) operator % to produce random numbers in the range we want. The
expression rand() % 6 produces random numbers in the range 0 to 5, and rand() % 6
+ 1 produces random numbers in the range 1 to 6.
Program 10.1: Program to simulate the roll of a die
#include <stdio.h>
#include <stdlib.h>
main()
{
int i;
int d1, d2;
int a[13]; /* uses [2..12] */
for(i = 2; i <= 12; i = i + 1)
a[i] = 0;
for(i = 0; i < 100; i = i + 1)
{
d1 = rand() % 6 + 1;
d2 = rand() % 6 + 1;
a[d1 + d2] = a[d1 + d2] + 1;
}
for(i = 2; i <= 12; i = i + 1)
printf("%d: %dn", i, a[i]);
return 0;
}
We include the header <stdlib.h> because it contains the necessary declarations for the
rand() function. We declare the array of size 13 so that its highest element will be
a[12]. (We’re wasting a[0] and a[1]; this is no great loss.) The variables d1 and d2
contain the rolls of the two individual dice; we add them together to decide which cell of
the array to increment, in the line
a[d1 + d2] = a[d1 + d2] + 1;
After 100 rolls, we print the array out. Typically, we’ll see mostly 7’s, and relatively few
2’s and 12’s.
10.1.1 Passing Arrays to Functions
An array name can be used as an argument to a function, thus permitting the entire array
to be passed to the function. To pass an array to a function, the array name must appear
by itself, without brackets or subscripts, as an actual argument within the function call.
The corresponding formal argument is written in the same manner, though it must be
declared as an array within the formal argument declarations. When declaring a one-
dimensional array as a formal argument, the array name is written with a pair of empty
square brackets. The size of the array is not specified within the formal argument
declaration.](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-133-320.jpg)
![Program 10.2: The following program illustrates the passing of an array from the
main to a function. This program is used to find the average of n floating point
numbers.
#include<stdio.h>
main()
{
int n, i;
float avg;
float list[100];
float average(int, float[]); /* function prototype */
printf(“How many numbers:”);
scanf(“%d”,&n);
printf(“ Enter the numbers:”);
for(i=1;i<=n;i++)
scanf(“%f”, &list[i]);
avg=average(n, list); /* Here list and n are actual arguments */
printf(“Average=%fn”, avg);
}
float average(int a, float x[ ])
{
float avg;
float sum=0;
int i;
for(i=0;i<a;i++)](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-134-320.jpg)
![sum=sum+x[i]; /* find sum of all the numbers */
avg=sum/a; /* find average */
return avg;
}
Self Assessment Questions
i) In C, an array subscript starts from __________
ii) State true or false.
An array name is a pointer
iii) What is the result of the following program segment
int a[5] = {1, 2, 3, 4, 5};
int b[5] = {5, 4, 3, 2, 1};
int c[5][5];
…
c=a+b;
…
Multidimensional Arrays
The C language allows arrays of any dimension to be defined. In this section, we will
take a look at two-dimensional arrays. One of the most natural applications for a two-
dimensional array arises in the case of a matrix. In C, the two-dimensional matrix can be
declared as follows:
int array[3][6];
Following is the way of declaring as well as initializing two-dimensional arrays.
int array[3][6] = {
{4,5,6,7,8,9},
{1,5,6,8,2,4},](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-135-320.jpg)
![{0,4,4,3,1,1}
};
Such arrays are accessed like so:
array[1][4]= -2;
if (array[2][1] > 0) {
printf (”Element [2][1] is %d”, array[2][1]);
}
Remember that, like ordinary arrays, two-dimensional arrays are numbered from 0.
Therefore, the array above has elements from array[0][0] to array[2][5].
Program 10.3: Program to add two matrices.
#include <stdio.h>
main()
{
int a[5][5], b[5][5], c[5][5];
int i, j, m, n;
printf(“Enter the order of the matrices:”);
scanf(“%d%d”, &m, &n);
printf(“ Enter the elements of A matrix:n”);
for(i=0;i<m;i++)
for(j=0;j<n;j++)
scanf(“%d”, &a[i][j]);
printf(“Enter the elements of B matrix:n”);
for(i=0;i<m;i++)
for(j=0;j<n;j++)](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-136-320.jpg)
![scanf(“%d”, &b[i][j]);
/* Add the matrices */
for(i=0;i<m;i++)
for(j=0;j<n;j++)
c[i][j] = a[i][j]+b[i][j];
/* Print the sum */
printf(“The sum of matrices:n”);
for(i=0;i<m;i++)
{
for(j=0;j<n;j++)
printf(“%dt”, c[i][j]);
printf(“n”);
}
}
Multidimensional arrays are processed in the same manner as one-dimensional arrays, on
an element-by-element basis. However, some care is required when passing
multidimensional arrays to a function. In particular, the formal argument declarations
within the function definition must include explicit size specifications in all of the
subscript positions except the first. These size specifications must be consistent with the
corresponding size specifications in the calling program. The first subscript position may
be written as an empty pair of square brackets, as with a one-dimensional array. The
corresponding function prototypes must be written in the same manner. But while calling
the function the array name may be passed as the actual argument as in the case of one-
dimensional arrays. E.g:
void process_array (int [][6]); /* function prototype */
void process_array (int array[][6])/*function definition */
{
…](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-137-320.jpg)
![}
Self Assessment Questions
i) In a two-dimensional matrix, the first subscript in the declaration specifies number of
_____
ii) State true or false.
A two-dimensional array is considered as an array of one-dimensional
arrays.
Strings
Strings in C are represented by arrays of characters. The end of the string is marked with
a special character, the null character, which is simply the character with the value 0.
(The null character has no relation except in name to the null pointer. In the ASCII
character set, the null character is named NULL.) The null or string-terminating character
is represented by another character escape sequence, 0.
Because C has no built-in facilities for manipulating entire arrays (copying them,
comparing them, etc.), it also has very few built-in facilities for manipulating strings.
In fact, C’s only truly built-in string-handling is that it allows us to use string constants
(also called string literals) in our code. Whenever we write a string, enclosed in double
quotes, C automatically creates an array of characters for us, containing that string,
terminated by the 0 character. For example, we can declare and define an array of
characters, and initialize it with a string constant:
char string[ ] = "Hello, world!";
In this case, we can leave out the dimension of the array, since the compiler can compute
it for us based on the size of the initializer (14, including the terminating 0). This is the
only case where the compiler sizes a string array for us, however; in other cases, it will be
necessary that we decide how big the arrays and other data structures we use to hold
strings are.
To do anything else with strings, we must typically call functions. The C library contains
a few basic string manipulation functions, and to learn more about strings, we’ll be
looking at how these functions might be implemented.
Since C never lets us assign entire arrays, we use the strcpy function to copy one string
to another:
#include <string.h>
char string1[ ] = "Hello, world!";](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-138-320.jpg)
![char string2[20];
strcpy(string2, string1);
The destination string is strcpy’s first argument, so that a call to strcpy mimics an
assignment expression (with the destination on the left-hand side). Notice that we had to
allocate string2 big enough to hold the string that would be copied to it. Also, at the top
of any source file where we’re using the standard library’s string-handling functions
(such as strcpy) we must include the line
#include <string.h>
which contains external declarations for these functions.
Since C won’t let us compare entire arrays, either, we must call a function to do that, too.
The standard library’s strcmp function compares two strings, and returns 0 if they are
identical, or a negative number if the first string is alphabetically “less than” the second
string, or a positive number if the first string is “greater.” (Roughly speaking, what it
means for one string to be “less than” another is that it would come first in a dictionary or
telephone book, although there are a few anomalies.) Here is an example:
char string3[] = "this is";
char string4[] = "a test";
if(strcmp(string3, string4) == 0)
printf("strings are equaln");
else printf("strings are differentn");
This code fragment will print “strings are different”. Notice that strcmp does not return a
Boolean, true/false, zero/nonzero answer, so it’s not a good idea to write something like
if(strcmp(string3, string4))
...
because it will behave backwards from what you might reasonably expect. (Nevertheless,
if you start reading other people’s code, you’re likely to come across conditionals like
if(strcmp(a, b)) or even if(!strcmp(a, b)). The first does something if the strings
are unequal; the second does something if they’re equal. You can read these more easily
if you pretend for a moment that strcmp’s name were strdiff, instead.)
Another standard library function is strcat, which concatenates strings. It does not
concatenate two strings together and give you a third, new string; what it really does is
append one string onto the end of another. (If it gave you a new string, it would have to
allocate memory for it somewhere, and the standard library string functions generally
never do that for you automatically.) Here’s an example:
char string5[20] = "Hello, ";
char string6[] = "world!";
printf("%sn", string5);
strcat(string5, string6);
printf("%sn", string5);](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-139-320.jpg)
![The first call to printf prints “Hello, ”, and the second one prints “Hello, world!”,
indicating that the contents of string6 have been tacked on to the end of string5.
Notice that we declared string5 with extra space, to make room for the appended
characters.
If you have a string and you want to know its length (perhaps so that you can check
whether it will fit in some other array you’ve allocated for it), you can call strlen, which
returns the length of the string (i.e. the number of characters in it), not including the 0:
char string7[ ] = "abc";
int len = strlen(string7);
printf("%dn", len);
Finally, you can print strings out with printf using the %s format specifier, as we’ve
been doing in these examples already (e.g. printf("%sn", string5);).
Since a string is just an array of characters, all of the string-handling functions we’ve just
seen can be written quite simply, using no techniques more complicated than the ones we
already know. In fact, it’s quite instructive to look at how these functions might be
implemented. Here is a version of strcpy:
mystrcpy(char dest[ ], char src[ ])
{
int i = 0;
while(src[i] != '0')
{
dest[i] = src[i];
i++;
}
dest[i] = '0';
}
We’ve called it mystrcpy instead of strcpy so that it won’t clash with the version that’s
already in the standard library. Its operation is simple: it looks at characters in the src
string one at a time, and as long as they’re not 0, assigns them, one by one, to the
corresponding positions in the dest string. When it’s done, it terminates the dest string
by appending a 0. (After exiting the while loop, i is guaranteed to have a value one
greater than the subscript of the last character in src.) For comparison, here’s a way of
writing the same code, using a for loop:
for(i = 0; src[i] != '0'; i++)
dest[i] = src[i];
dest[i] = '0';
Yet a third possibility is to move the test for the terminating 0 character out of the for
loop header and into the body of the loop, using an explicit if and break statement, so
that we can perform the test after the assignment and therefore use the assignment inside
the loop to copy the 0 to dest, too:](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-140-320.jpg)
![for(i = 0; ; i++)
{
dest[i] = src[i];
if(src[i] == '0')
break;
}
(There are in fact many, many ways to write strcpy. Many programmers like to combine
the assignment and test, using an expression like (dest[i] = src[i]) != '0')
Here is a version of strcmp:
mystrcmp(char str1[ ], char str2[ ])
{
int i = 0;
while(1)
{
if(str1[i] != str2[i])
return str1[i] - str2[i];
if(str1[i] == '0' || str2[i] == '0')
return 0;
i++;
}
}
Characters are compared one at a time. If two characters in one position differ, the strings
are different, and we are supposed to return a value less than zero if the first string (str1)
is alphabetically less than the second string. Since characters in C are represented by their
numeric character set values, and since most reasonable character sets assign values to
characters in alphabetical order, we can simply subtract the two differing characters from
each other: the expression str1[i] - str2[i] will yield a negative result if the i‘th
character of str1 is less than the corresponding character in str2. (As it turns out, this
will behave a bit strangely when comparing upper and lower-case letters, but it’s the
traditional approach, which the standard versions of strcmp tend to use.) If the characters
are the same, we continue around the loop, unless the characters we just compared were
(both) 0, in which case we’ve reached the end of both strings, and they were both equal.
Notice that we used what may at first appear to be an infinite loop–the controlling
expression is the constant 1, which is always true. What actually happens is that the loop
runs until one of the two return statements breaks out of it (and the entire function).
Note also that when one string is longer than the other, the first test will notice this
(because one string will contain a real character at the [i] location, while the other will
contain 0, and these are not equal) and the return value will be computed by subtracting
the real character’s value from 0, or vice versa. (Thus the shorter string will be treated as
“less than” the longer.)
Finally, here is a version of strlen:
int mystrlen(char str[ ])
{
int i;](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-141-320.jpg)
![for(i = 0; str[i] != '0'; i++)
{ }
return i;
}
In this case, all we have to do is find the 0 that terminates the string, and it turns out that
the three control expressions of the for loop do all the work; there’s nothing left to do in
the body. Therefore, we use an empty pair of braces { } as the loop body. Equivalently,
we could use a null statement, which is simply a semicolon:
for(i = 0; str[i] != '0'; i++)
;
Everything we’ve looked at so far has come out of C’s standard libraries. As one last
example, let’s write a substr function, for extracting a substring out of a larger string.
We might call it like this:
char string8[ ] = "this is a test";
char string9[10];
substr(string9, string8, 5, 4);
printf("%sn", string9);
The idea is that we’ll extract a substring of length 4, starting at character 5 (0-based) of
string8, and copy the substring to string9. Just as with strcpy, it’s our responsibility
to declare the destination string (string9) big enough. Here is an implementation of
substr. Not surprisingly, it’s quite similar to strcpy:
substr(char dest[ ], char src[ ], int offset, int len)
{
int i;
for(i = 0; i < len && src[offset + i] != '0'; i++)
dest[i] = src[i + offset];
dest[i] = '0';
}
If you compare this code to the code for mystrcpy, you’ll see that the only differences
are that characters are fetched from src[offset + i] instead of src[i], and that the
loop stops when len characters have been copied (or when the src string runs out of
characters, whichever comes first).
When working with strings, it’s important to keep firmly in mind the differences between
characters and strings. We must also occasionally remember the way characters are
represented, and about the relation between character values and integers.
As we have had several occasions to mention, a character is represented internally as a
small integer, with a value depending on the character set in use. For example, we might
find that 'A' had the value 65, that 'a' had the value 97, and that '+' had the value 43.
(These are, in fact, the values in the ASCII character set, which most computers use.
However, you don’t need to learn these values, because the vast majority of the time, you](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-142-320.jpg)
![use character constants to refer to characters, and the compiler worries about the values
for you. Using character constants in preference to raw numeric values also makes your
programs more portable.)
As we may also have mentioned, there is a big difference between a character and a
string, even a string which contains only one character (other than the 0). For example,
'A' is not the same as "A". To drive home this point, let’s illustrate it with a few
examples.
If you have a string:
char string[ ] = "hello, world!";
you can modify its first character by saying
string[0] = 'H';
(Of course, there’s nothing magic about the first character; you can modify any character
in the string in this way. Be aware, though, that it is not always safe to modify strings in-
place like this) Since you’re replacing a character, you want a character constant, 'H'. It
would not be right to write
string[0] = "H"; /*
WRONG */
because "H" is a string (an array of characters), not a single character. (The destination of
the assignment, string[0], is a char, but the right-hand side is a string; these types
don’t match.)
On the other hand, when you need a string, you must use a string. To print a single
newline, you could call
printf("n");
It would not be correct to call
printf('n');
/* WRONG */
printf always wants a string as its first argument. (As one final example, putchar wants
a single character, so putchar('n') would be correct, and putchar("n") would be
incorrect.)
We must also remember the difference between strings and integers. If we treat the
character '1' as an integer, perhaps by saying
int i = '1';](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-143-320.jpg)
![we will probably not get the value 1 in i; we’ll get the value of the character '1' in the
machine’s character set. (In ASCII, it’s 49.) When we do need to find the numeric value
of a digit character (or to go the other way, to get the digit character with a particular
value) we can make use of the fact that, in any character set used by C, the values for the
digit characters, whatever they are, are contiguous. In other words, no matter what values
'0' and '1' have, '1' - '0' will be 1 (and, obviously, '0' - '0' will be 0). So, for a
variable c holding some digit character, the expression
c - '0'
gives us its value. (Similarly, for an integer value i, i + '0' gives us the corresponding
digit character, as long as 0 <= i <= 9.)
Just as the character '1' is not the integer 1, the string "123" is not the integer 123.
When we have a string of digits, we can convert it to the corresponding integer by calling
the standard function atoi:
char string[] = "123";
int i = atoi(string);
int j = atoi("456");
Self Assessment Questions
i) What is the output of the following program segment?
char str1[10];
str1=”Hello, world”;
printf(“%s”, str1);
ii) What is the library function used to copy one string to another?
iii) State true or false
The library function atoi can be used for any string
Conclusion
An array is a variable that can hold more than one value. In C, arrays are zero-based. An
array name can be used as an argument to a function, thus permitting the entire array to
be passed to the function. The C language allows arrays of any dimension to be defined.
One of the most natural applications for a two-dimensional array arises in the case of a
matrix. Strings in C are represented by arrays of characters. C has built in library
functions to perform some operations on strings.
Terminal Questions](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-144-320.jpg)
![1. Write a program for 10 times summation of square of a number
2. How many elements can the array in the following declaration accommodate?
int a[3][4][5];
3. Is the following array declaration and initialization correct?
int a[2][2]={1,2,3,4};
4. State true or false.
Strings must be represented as an array of characters in C.
5. State true or false.
When you pass an array as a parameter to a function, the entire array is copied and is
available to function.
6. Write a Program that uses loops for array processing.
Answers for Self Assessment Questions
10.1 i) 0
ii) true
iii) Compilation error
10.2 I) rows
ii) true
10.3 I) Compilation error
ii) strcpy
iii) false
Answers for Terminal Questions
1. #include<stdio.h>](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-145-320.jpg)
![int index, score[SIZE];
int sum = 0;
float average;
printf(”Enter %d golf scores:n”, SIZE);
for (index = 0; index < SIZE; index++)
scanf(”%d”, &score[index]); */read in the ten scores
printf(”The scores read in are as follows:n”);
for (index = 0; index < SIZE; index++)
printf(”%5d”, score[index]); */verify input
printf(”n”);
for (index = 0; index < SIZE; index++)
sum += score[index]; */add them up
average = (float) sum / SIZE; */ time-honored method
printf(”Sum of scores = %d, average = %.2fn”, sum, average);
printf(”That’s a handicap of %.0f.n”, average – PAR);
return 0;
}
Exercises
1. Write a program to count the number of vowels and consonants in a given string.
2. Write a program to arrange a list of numbers in ascending order
3. Write a program to multiply two matrices
4. Write a program to rewrite a given string in the alphabetical order
5. Write a program to transpose a given matrix.](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-147-320.jpg)
![printf(”%dn”, *ip);
which would print 5, since ip points to i, and i is (at the moment) 5.
(You may wonder how the asterisk * can be the pointer contents-of operator when it is
also the multiplication operator. There is no ambiguity here: it is the multiplication
operator when it sits between two variables, and it is the contents-of operator when it sits
in front of a single variable. The situation is analogous to the minus sign: between two
variables or expressions it’s the subtraction operator, but in front of a single operator or
expression it’s the negation operator. Technical terms you may hear for these distinct
roles are unary and binary: a binary operator applies to two operands, usually on either
side of it, while a unary operator applies to a single operand.)
The contents-of operator * does not merely fetch values through pointers; it can also set
values through pointers. We can write something like
*ip = 7;
which means “set whatever ip points to 7.” Again, the * tells us to go to the location
pointed to by ip, but this time, the location isn’t the one to fetch from–we’re on the left-
hand sign of an assignment operator, so *ip tells us the location to store to. (The situation
is no different from array subscripting expressions such as a[3] which we’ve already
seen appearing on both sides of assignments.)
The result of the assignment *ip = 7 is that i’s value is changed to 7, and the picture
changes to:
If we called printf("%dn", *ip) again, it would now print 7.
At this point, you may be wonder, if we wanted to set i to 7, why didn’t we do it
directly? We’ll begin to explore that next, but first let’s notice the difference between
changing a pointer (that is, changing what variable it points to) and changing the value at
the location it points to. When we wrote *ip = 7, we changed the value pointed to by ip,
but if we declare another variable j:
int j = 3;
and write
ip = &j;
we’ve changed ip itself. The picture now looks like this:](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-150-320.jpg)
![iii. State whether the following statements are correct:
int a, b;
b=&a;
Basics of Structures
C supports a constructed data type known as structure, which is a method for packing
data of different types. A structure is a convenient tool for handling a group of logically
related data items. Structures help to organize complex data in a more meaningful way. It
is a powerful concept that we may often need to use in our program design.
Structure Definition : A Structure definition creates a format that may be used to
declare structure variables. For e.g., Consider a book database consisting of book name,
author, number of pages and price.
struct book_bank
{
char title[20];
char author[15];
int pages;
float price;
};
The keyword struct declares a structure to hold the details of four fields, namely title,
author, pages and price. These fields are called structure elements or members. Each
member may belong to a different type of data. book_bank is the name of the structure
and is called the structure tag. The tag name may be used subsequently to declare
variables that have the tag’s structure. Note that the above declaration has not declared
any variables. It simply describes a format called template to represent information as
shown below:
struct book_bank](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-155-320.jpg)
![We can declare structure variables using the tag name anywhere in the program. e.g, the
statement:
struct book_bank book1, book2, book3;
declares book1, book2 and book3 as variables of type book_bank.
Each one of these variables has four members as specified by the template. The complete
declaration might look like this :
struct book_bank
{
char title[20];
char author[15];
int pages;
float price;
};
struct book_bank book1, book2, book3;
It is also allowed to combine both the template declaration and variables declaration in
one statement.
struct book_bank
{
char title[20];](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-156-320.jpg)
![char author[15];
int pages;
float price;
} book1, book2, book3;
General format of a Structure Definition :
The general format of a structure definition is as follows:
struct tag_name
{
data_type member1;
data_type member2;
——-
};
In defining a structure you may note the following syntax:
1. The template is terminated with a semicolon.
2. While the entire declaration is considered as a statement, each member is declared
independently for its name and type in a separate statement inside the template.
3. The tag name such as tag_name can be used to declare structure variables of its type,
later in the program.
Giving values to Members :
Structure members need to be linked to the structure variables in order to make them
meaningful members. The link between a member and a variable is established using the
member operator ‘.’ which is also known as ‘dot operator’ or ‘period operator’.
Here is how we would assign values to the members of book1.
strcpy(book1.title,”BASIC”);
strcpy(book1.author,”Balagurusamy”);](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-157-320.jpg)
![book1.pages = 250;
book1.price = 28.50;
We can also give the values through the keyboard.
gets(book1.title);
gets(book1.author);
printf(“%d”,book1.pages);
printf(“%f”,book1.price);
Structure Initialization :
void main( )
{
struct st_record
{
char name[20];
int weight;
float height;
};
static struct st_record student1 = {“Suresh”, 60, 180.75};
static struct st_record student2 = {“Umesh”, 53, 170.60};
}
Structures and Functions
We can write programs with structures by using modular programming. We can write a
function that returns the structure. While writing the function, you should indicate the
type of structure that is returned by the function. The return statement should return the
structure using a variable. It is possible to pass a structure as an argument. We can
modify a member of the structure by passing the structure as an argument. The changes in
the member made by the function are retained in the called module. This is not against](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-158-320.jpg)
![the principle of call by value because we are not modifying the structure variable, but are
instead modifying the members of the structure.
Program 11.4 To Illustrate the concept of structures and functions
struct student
{
name char[30];
marks float;
};
main ( )
{
struct student student1;
student1 = read_student ( );
print_student( student1);
read_student_p(student1);
print_student (student1);
}
struct student read_student( )
{
struct student student2;
gets(student2.name);
scanf("%d",&student2.marks);
return (student2);
}
void print_student (struct student student2)
{
printf( "name is %sn", student2.name);
printf( "marks are%dn", student2.marks);
}
void read_student_p(struct student student2)
{
gets(student2.name);
scanf("%d",&student2.marks);
}
Explanation
1. The function read_student reads values in structures and returns the structure.
2. The function print_student takes the structure variable as input and prints the
content in the structure.
3. The function read_student_p reads the data in the structure similarly to
read_student. It takes the structure student as an argument and puts the data in the
structure. Since the data of a member of the structure is modified, you need not pass the
structure as a pointer even though structure members are modified. Here you are not
modifying the structure, but you are modifying the structure members through the
structure.
Self Assessment Questions](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-159-320.jpg)
![i) State true or false:
We cannot write a function that returns the structure.
ii) State true or false:
We can modify a member of the structure by passing the structure as an argument.
Arrays of Structures
We can use structures to describe the format of a number of related variables. For
example, in analyzing the marks obtained by a class of students, we may use a template
to describe student name and marks obtained in various subjects and then declare all the
students as structure variables. In such cases, we may declare an array of structures, each
element of the array representing a structure variable. e.g, struct stclass student[100];
defines an array called student, that consists of 100 elements. Each element is defined to
be of the type struct stclass. Consider the following declaration :
struct marks
{
int subject1;
int subject2;
int subject3;
};
main( )
{
static struct marks student[3]={{45,68,81},{75,53,69},{57,36,71}};
}
This declares the student as an array of three elements student[0], student[1] and
student[2] and initializes their members as follows:
student[0].subject1 = 45;
student[0].subject2 = 68;
……..](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-160-320.jpg)
![student[2].subject3 = 71;
Program 11.5 To process employee details using structures
#include<conio.h>
#include<stdio.h>
struct employee
{
int empno;
char name[30];
int basic;
int hra;
};
void main()
{
int i,j,n,net[50];
float avg;
employee e[50];
printf(”nEnter the number of employees:”);
scanf(“%d”, &n);
printf(“nEnter Empno.tNametBasictHra of each employee:n”);
for(i=0;i<n;i++)
{
scanf(“%d”,&e[i].empno);
gets(e[i].name);](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-161-320.jpg)
![scanf(“%d”,&e[i].basic);
scanf(%d”,&e[i].hra);
net[i]= e[i].basic+e[i].hra;
avg=avg+net[i];
}
avg=avg/n;
printf(”nEmpno.tNametNetpayn”);
for(i=0;i<n;i++)
{
if(net[i]>avg)
{
printf(e[i].empnot)”;
printf(e[i].namet)”;
printf(net[i]n”);
}
}
getch();
}
Program 11.6 To process student details using structures
#include<conio.h>
#include<stdio.h>
struct student
{](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-162-320.jpg)
![int rollno;
char name[30];
int marks1;
int marks2;
int marks3;
};
void main()
{
int i,j,n,tot[50],t;
student s[50],temp;
printf(”nEnter the number of students:”);
scanf(“%d”,&n);
printf(”nEnter Rollno.tNametMarks1tMarks2tMarks3 of each student:n”);
for(i=0;i<n;i++)
{
scanf(“%d”,&s[i].rollno);
gets(s[i].name);
scanf(“%d”,&s[i].marks1);
scanf(“%d”,&s[i].marks2);
scanf(“%d”,&s[i].marks3);
tot[i]= s[i].marks1+s[i].marks2+s[i].marks3;
}
for(i=0;i<n-1;i++)](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-163-320.jpg)
![{
for(j=i+1;j<n;j++)
{
if(tot[i]<tot[j])
{
temp=s[i];
s[i]=s[j];
s[j]=temp;
t=tot[i];
tot[i]=tot[j];
tot[j]=t;
}
}
}
printf(”nRollno.tNametTotal marks in decreasing order of total marks is:n”);
for(i=0;i<n;i++)
{
printf(“%dt”,s[i].rollno);
printf(“%st”,s[i].name);
printf(“%dt”,s[i].tot);
}
getch();
}](https://image.slidesharecdn.com/programminginc-120111001401-phpapp02/85/Programming-in-c-164-320.jpg)
Programming in c
- 1. E-528-529, sector-7, Dwarka, New delhi-110075 (Nr. Ramphal chowk and Sector 9 metro station) Ph. 011-47350606, (M) 7838010301-04 www.eduproz.in Educate Anytime...Anywhere... "Greetings For The Day" About Eduproz We, at EduProz, started our voyage with a dream of making higher education available for everyone. Since its inception, EduProz has been working as a stepping-stone for the students coming from varied backgrounds. The best part is – the classroom for distance learning or correspondence courses for both management (MBA and BBA) and Information Technology (MCA and BCA) streams are free of cost. Experienced faculty-members, a state-of-the-art infrastructure and a congenial environment for learning - are the few things that we offer to our students. Our panel of industrial experts, coming from various industrial domains, lead students not only to secure good marks in examination, but also to get an edge over others in their professional lives. Our study materials are sufficient to keep students abreast of the present nuances of the industry. In addition, we give importance to regular tests and sessions to evaluate our students’ progress. Students can attend regular classes of distance learning MBA, BBA, MCA and BCA courses at EduProz without paying anything extra. Our centrally air-conditioned classrooms, well-maintained library and well- equipped laboratory facilities provide a comfortable environment for learning. Honing specific skills is inevitable to get success in an interview. Keeping this in mind, EduProz has a career counselling and career development cell where we help student to prepare for interviews. Our dedicated placement cell has been helping students to land in their dream jobs on completion of the course. EduProz is strategically located in Dwarka, West Delhi (walking distance from Dwarka Sector 9 Metro Station and 4-minutes drive from the national highway); students can easily come to our centre from anywhere Delhi and neighbouring Gurgaon, Haryana and avail of a quality-oriented education facility at apparently no extra cost. Why Choose Edu Proz for distance learning? • Edu Proz provides class room facilities free of cost. • In EduProz Class room teaching is conducted through experienced faculty. • Class rooms are spacious fully air-conditioned ensuring comfortable ambience. • Course free is not wearily expensive. • Placement assistance and student counseling facilities. • Edu Proz unlike several other distance learning courses strives to help and motivate pupils to get
- 2. high grades thus ensuring that they are well placed in life. • Students are groomed and prepared to face interview boards. • Mock tests, unit tests and examinations are held to evaluate progress. • Special care is taken in the personality development department. "HAVE A GOOD DAY"
- 3. Karnataka State Open University (KSOU) was established on 1st June 1996 with the assent of H.E. Governor of Karnataka as a full fledged University in the academic year 1996 vide Government notification No/EDI/UOV/dated 12th February 1996 (Karnataka State Open University Act – 1992). The act was promulgated with the object to incorporate an Open University at the State level for the introduction and promotion of Open University and Distance Education systems in the education pattern of the State and the country for the Co-ordination and determination of standard of such systems. Keeping in view the educational needs of our country, in general, and state in particular the policies and programmes have been geared to cater to the needy. Karnataka State Open University is a UGC recognised University of Distance Education Council (DEC), New Delhi, regular member of the Association of Indian Universities (AIU), Delhi, permanent member of Association of Commonwealth Universities (ACU), London, UK, Asian Association of Open Universities (AAOU), Beijing, China, and also has association with Commonwealth of Learning (COL). Karnataka State Open University is situated at the North–Western end of the Manasagangotri campus, Mysore. The campus, which is about 5 kms, from the city centre, has a serene atmosphere ideally suited for academic pursuits. The University houses at present the Administrative Office, Academic Block, Lecture Halls, a well-equipped Library, Guest House Cottages, a Moderate Canteen, Girls Hostel and a few cottages providing limited accommodation to students coming to Mysore for attending the Contact Programmes or Term-end examinations.
- 4. Unit 1 Introduction to C Programming • Introduction, Features of C, A Typical C Program, The structure of a Simple C Program, The new line Character, The use of Semicolon, Braces and comments in a Program. Introduction C is a general-purpose, structured programming language. Its instructions consist of terms that resemble algebraic expressions, augmented by certain English keywords such as if, else, for, do and while. C was the offspring of the ‘Basic Combined Programming Language’ (BPCL) called B, developed in the 1960’s at Cambridge University. B language was modified by Dennis Ritchie and was implemented at Bell laboratories in 1972. The new language was named C. Since it was developed along with the UNIX operating system, it is strongly associated with UNIX. This operating system, which was also developed at Bell laboratories, was coded almost entirely in C. Objectives At the end of this unit, you will be able to: · Understand the features of C programming language · Understand the basic structure of a C program · Write simple C programs Features of C C is characterized by the ability to write very concise source programs, due in part to the large number of operators included within the language. It has a relatively small instruction set, though actual implementations include extensive library functions which enhance the basic instructions. The language encourages users to write additional library functions of their own. Thus, the features and capabilities of the language can easily be extended by the user. C compilers are commonly available for computers of all sizes. The compilers are usually compact, and they generate object programs that are small and highly efficient when compared with programs compiled from other high-level languages.
- 5. Another important characteristic of C is that its programs are highly portable, even more so than with other high-level languages. The reason for this is that C relegates most computer dependent features to its library functions. Thus, every version of C is accompanied by its own set of library functions, which are written for the particular characteristics of the host computer. Self Assessment Questions i) State true or false Using C language programmers can write their own library functions ii) C is a ________ level programming language Basic structure of C Programs A C program can be viewed as a group of building blocks called functions. A function is a subroutine that may include one or more statements designed to perform a specific task. To write a C program we first create functions and then put them together. A C program may contain one or more sections shown in Fig. 1.1. Fig. 1.1 The documentation section consists of a set of comment(remarks) lines giving the name of the program, the author and other details which the programmer would like to use later. Comments may appear anywhere within a program, as long as they are placed within the delimiters /* and */ (e.g., /*this is a comment*/). Such comments are helpful in identifying the program’s principal features or in explaining the underlying logic of various program features. The link section provides instructions to the compiler to link functions from the system library. The definition section defines all symbolic constants.
- 6. There are some variables that are used in more than one function. Such variables are called global variables and are declared in the global declaration section that is outside of all the functions. Every C program must have one main function section. This section contains two parts, declaration part and executable part. The declaration part declares all the variables used in the executable part. There is at least one statement in the executable part. These two parts must appear between opening and closing braces({ and }). The program execution begins at the opening brace and ends at the closing brace. The closing brace of the main function section is the logical end of the program. All statements in the declaration and executable parts end with a semicolon(;). The subprogram section contains all the user-defined functions that are called in the main function. User-defined functions are generally placed immediately after the main function, although they may appear in any order. All sections, except the main function section may be absent when they are not required. Self Assessment Questions i) The documentation section contains a set of __________ lines. ii) State true or false Every C program must have one main() function. iii) What are global variables? A simple C Program #include <stdio.h> main() { printf(”Hello, world!n”); return 0; } If you have a C compiler, the first thing to do is figure out how to type this program in and compile it and run it and see where its output went.
- 7. The first line is practically boilerplate; it will appear in almost all programs we write. It asks that some definitions having to do with the “Standard I/O Library” be included in our program; these definitions are needed if we are to call the library function printf correctly. The second line says that we are defining a function named main. Most of the time, we can name our functions anything we want, but the function name main is special: it is the function that will be “called” first when our program starts running. The empty pair of parentheses indicates that our main function accepts no arguments, that is, there isn’t any information which needs to be passed in when the function is called. The braces { and } surround a list of statements in C. Here, they surround the list of statements making up the function main. The line printf(”Hello, world!n”); is the first statement in the program. It asks that the function printf be called; printf is a library function which prints formatted output. The parentheses surround printf ’s argument list: the information which is handed to it which it should act on. The semicolon at the end of the line terminates the statement. printf ’s first (and, in this case, only) argument is the string which it should print. The string, enclosed in double quotes (""), consists of the words “Hello, world!” followed by a special sequence: n. In strings, any two-character sequence beginning with the backslash represents a single special character. The sequence n represents the “`new line” character, which prints a carriage return or line feed or whatever it takes to end one line of output and move down to the next. (This program only prints one line of output, but it’s still important to terminate it.) The second line in the main function is return 0; In general, a function may return a value to its caller, and main is no exception. When main returns (that is, reaches its end and stops functioning), the program is at its end, and the return value from main tells the operating system (or whatever invoked the program that main is the main function of) whether it succeeded or not. By convention, a return value of 0 indicates success. Self Assessment Questions i) The information that needs to be passed in when a function is called is ______ ii) State true or false
- 8. The main() function doesn’t return any value. More simple C programs Program 1.1 Area of a circle Here is an elementary C program that reads in the radius of a circle, calculates the area and then writes the calculated result. #include <stdio.h> /* Library file access */ /* program to calculate the area of a circle */ /* Title (Comment) */ main() /* Function heading */ { float radius, area; /*Variable declarations */ printf(“Radius=?”); /* Output statement(prompt) */ scanf(“%f”, &radius); /* Input statement */ area=3.14159*radius*radius; /* Assignment statement */ printf(“Area=%f”,area); /* Output statement */ } Program 1.2 Print a few numbers Here is a program to illustrate a simple loop #include <stdio.h> /* print a few numbers, to illustrate a simple loop */ main() { int i; for(i = 0; i < 10; i = i + 1) /* Looping statement */ printf(”i is %dn”, i); return 0; }
- 9. Program 1.3: Program to add two numbers #include <stdio.h> main() { int i,j,k; // Defining variables i = 6; // Assign values j = 8; k = i + j; printf(”sum of two numbers is %d n”,k); // Printing results } Summary C is a general-purpose, structured programming language. Its instructions consist of terms that resemble algebraic expressions, augmented by certain English keywords such as if, else, for, do and while. C is characterized by the ability to write very concise source programs, due in part to the large number of operators included within the language. Every C program consists of one or more functions, one of which must be called main. The program will always begin by executing the main function. Additional function definitions may precede or follow main. Terminal Questions 1. _____ enhance the basic instructions of C language 2. C was originally developed by _____ 3. What are the major components of a C program? 4. What significance is attached to the function main? 5. What are arguments? Where do arguments appear within a C program? Answers to Self Assessment Questions 1.1 i) True
- 10. ii) High 1.2 i) Comment ii) True iii) The variables that can be used in more than one functions 1.3 i) Arguments ii) False Answers to Terminal Questions 1. Library functions 2. Dennis Ritchie 3. Documentation section, Link section, Definition section, Global declaration section, main() function section, Subprogram section 4. main is the function that will be “called” first when our program starts running. 5. The arguments are symbols that represent information being passed between the function and other parts of the program. They appear in the function heading. Exercises 1. Explain the history of C language. 2. What are the advantages of C language? 3. Explain the basic structure of a C program with an example. 4. What are the different steps in executing a C program ? 5. Write a C program to convert Celsius to Fahrenheit and vice versa. Unit 2 Constants, Variables and Declarations • Concept of an Integer and Variable, Declaring an Integer Variable, The rules for naming Variables, The Assignment Variable Arithmetic Operators
- 11. Introduction The type of a variable determines what kinds of values it may take on. The type of an object determines the set of values it can have and what operations can be performed on it. This is a fairly formal, mathematical definition of what a type is, but it is traditional (and meaningful). There are several implications to remember: 1. The “set of values” is finite. C’s int type can not represent all of the integers; its float type can not represent all floating-point numbers. 2. When you’re using an object (that is, a variable) of some type, you may have to remember what values it can take on and what operations you can perform on it. For example, there are several operators which play with the binary (bit-level) representation of integers, but these operators are not meaningful for and may not be applied to floating- point operands. 3. When declaring a new variable and picking a type for it, you have to keep in mind the values and operations you’ll be needing. Objectives At the end of this unit, you will be able to: · Understand the concept of Constants · Understand the concept of Integers · Understand the variable and its declaration in C 2.1 Constants Constants in C refer to fixed values that do not change during the execution of a program. C supports several types of constants as illustrated in Fig 2.1 Fig 2.1
- 12. Integer constants An integer constant refers to a sequence of digits. There are three types of integers, namely decimal, octal and hexadecimal. Decimal integers consist of a set of digits, 0 through 9, preceded by an optional – or +. Examples: 12, -546, 0, 354647, +56 An octal integer constant consists of any combination of digits from the set 0 through 7, with a leading 0. Examples: 045, 0, 0567 A sequence of digits preceded by 0x or 0X is considered as hexadecimal integer. They may also include alphabets A through F or a through f. The letters A through F represent numbers 10 through 15. Examples: 0X6, 0×5B, 0Xbcd, 0X The largest integer value that can be stored is machine-dependent. It is 32767 on 16-bit machines and 2,147,483,647 on 32-bit machines. It is also possible to store larger integer constants on these machines by appending qualifiers such as U, L and UL to the constants. Examples: 54637U or 54637u (unsigned integer) 65757564345UL or 65757564345ul (unsigned long integer) 7685784L or 7685784l (long integer) Program 2.1: Program to represent integer constants on a 16-bit computer /* Integer numbers on 16-bit machine */ main() { printf(“Integer valuesnn”); printf(“%d %d %dn”, 32767,32767+1,32767+10); printf(“n”); printf(“Long integer valuesnn”);
- 13. printf(“%ld %ld %ldn”, 32767L, 32767L+1L, 32767L+10L); } Type and execute the above program and observe the output Real constants The numbers containing fractional parts like 67.45 are called real(or floating point) constants. Examples: 0.0045, -8.5, +345.678 A real number may also be expressed in exponential(scientific) notation. The general form is: mantissa e exponent The mantissa is either a real number expressed in decimal notation or an integer. The exponent is an integer number with an optional plus or minus sign. The letter e separating the mantissa and the exponent can be written in either lowercase or uppercase. Examples: 04e4, 12e-2, -1.3E-2 7500000000 may be written as 7.5E9 or 75E8. Floating point constants are normally represented as double-precision quantities. However, the suffixes f or F may be used to force single precision and l or L to extend double-precision further. Character constants A single character constant( or simple character constant) contains a single character enclosed within a pair of single quote marks. Examples: ‘6’, ‘X’, ‘;’ Character constants have integer values known as ASCII values. For example, the statement printf(“%d”, ‘a’); would print the number 97, the ASCII value of the letter a. Similarly, the statement printf(“%c”, 97);
- 14. would print the letter a. String constants A string constant is a sequence of characters enclosed within double quotes. The characters may be letters, numbers, special characters and blank space. Examples: “Hello!”, “1947”, “5+3” Backslash character constants C supports some special backslash character constants that are used in output functions. A list of such backslash character constants is given in Table 2.1. Note that each one of them represents one character, although they consist of two characters. These character combinations are called escape sequences. Table 2.1 Self Assessment Questions i) List different types of constants. ii) What are the different types of integer constants? iii) What are escape sequences? Concept of an Integer and Variable Integers are whole numbers with a range of values supported by a particular machine. Generally, integers occupy one word of storage, and since the word sizes of machines vary (typically, 16 or 32 bits) the size of an integer that can be stored depends on the computer. If we use 16 bit word length, the size of the integer value is limited to the range -32768 to +32767 (that is, -215 to +2 15 -1 ). A signed integer uses one bit for sign
- 15. and 15 bits for the magnitude of the number. Similarly, a 32 bit word length can store an integer ranging from -2,147,483,648 to 2,147,483,647. In order to provide some control over the range of numbers and storage space, C has three classes of integer storage, namely short int, int , and long int, in both signed and unsigned forms. For example, short int represents fairly small integer values and requires half the amount of storage as a regular int number uses. A signed integer uses one bit for sign and 15 bits for the magnitude of the number, therefore, for a 16 bit machine, the range of unsigned integer numbers will be from 0 to 65,535. We declare long and unsigned integers to increase the range of values. The use of qualifier signed on integers is optional because the default declaration assumes a signed number. The Table 2.2 shows all the allowed combinations of basic types and qualifiers and their size and range on a 16-bit machine. Table 2.2 Informally, a variable (also called an object) is a place where you can store a value so that you can refer to it unambiguously. A variable needs a name. You can think of the variables in your program as a set of boxes, each with a label giving its name; you might imagine that storing a value “in” a variable consists of writing the value on a slip of paper and placing it in the box. Self Assessment Questions State true or false i) The size of the Integers in C language is same in all the machines. ii) A ________is a place where we can store values. iii) Size of int is _________ bits Declaring an Integer Variable A declaration tells the compiler the name and type of a variable you’ll be using in your program. In its simplest form, a declaration consists of the type, the name of the variable, and a terminating semicolon: int i; The above statement declares an integer variable i.
- 16. long int i1, i2; We can also declare several variables of the same type in one declaration, separating them with commas as shown above. The placement of declarations is significant. You can’t place them just anywhere (i.e. they cannot be interspersed with the other statements in your program). They must either be placed at the beginning of a function, or at the beginning of a brace-enclosed block of statements, or outside of any function. Furthermore, the placement of a declaration, as well as its storage class, controls several things about its visibility and lifetime, as we’ll see later. You may wonder why variables must be declared before use. There are two reasons: 1. It makes things somewhat easier on the compiler; it knows right away what kind of storage to allocate and what code to emit to store and manipulate each variable; it doesn’t have to try to intuit the programmer’s intentions. 2. It forces a bit of useful discipline on the programmer: you cannot introduce variables wherever you wish ; you must think about them enough to pick appropriate types for them. (The compiler’s error messages to you, telling you that you apparently forgot to declare a variable, are as often helpful as they are a nuisance: they’re helpful when they tell you that you misspelled a variable, or forgot to think about exactly how you were going to use it.) Most of the time, it is recommended to write one declaration per line. For the most part, the compiler doesn’t care what order declarations are in. You can order the declarations alphabetically, or in the order that they’re used, or to put related declarations next to each other. Collecting all variables of the same type together on one line essentially orders declarations by type, which isn’t a very useful order (it’s only slightly more useful than random order). A declaration for a variable can also contain an initial value. This initializer consists of an equal sign and an expression, which is usually a single constant: int i = 1; int i1 = 10, i2 = 20; Self Assessment Questions i) What is meant by declaration? ii) What is an initializer? iii) State true or false A single declaration statement can contain variables of different types The rules for naming Variables
- 17. Within limits, you can give your variables and functions any names you want. These names (the formal term is “identifiers”) consist of letters, numbers, and underscores. For our purposes, names must begin with a letter. Theoretically, names can be as long as you want, but extremely long ones get tedious to type after a while, and the compiler is not required to keep track of extremely long ones perfectly. (What this means is that if you were to name a variable, say, supercalafragalisticespialidocious, the compiler might get lazy and pretend that you’d named it super- calafragalisticespialidocio, such that if you later misspelled it super-calafragalisticespialidociouz, the compiler wouldn’t catch your mistake. Nor would the compiler necessarily be able to tell the difference if for some perverse reason you deliberately declared a second variable named supercalafragalisticespialidociouz.) The capitalization of names in C is significant: the variable names variable, Variable, and VARIABLE (as well as silly combinations like variAble) are all distinct. A final restriction on names is that you may not use keywords (the words such as int and for which are part of the syntax of the language) as the names of variables or functions (or as identifiers of any kind). Self Assessment Questions i) State true or false. In C, variable names are case sensitive. ii) A variable name in C consists of letters, numbers and _________ Assigning values to variables The assignment operator = assigns a value to a variable. For example, x = 1; sets x to 1, and a = b; sets a to whatever b’s value is. The expression i = i + 1; is, as we’ve mentioned elsewhere, the standard programming idiom for increasing a variable’s value by 1: this expression takes i’s old value, adds 1 to it, and stores it back into i. (C provides several “shortcut” operators for modifying variables in this and similar ways, which we’ll meet later.)
- 18. We’ve called the = sign the “assignment operator” and referred to “assignment expressions” because, in fact, = is an operator just like + or -. C does not have “assignment statements”; instead, an assignment like a = b is an expression and can be used wherever any expression can appear. Since it’s an expression, the assignment a = b has a value, namely, the same value that’s assigned to a. This value can then be used in a larger expression; for example, we might write c = a = b; Which is equivalent to? c = (a = b); and assigns b’s value to both a and c. (The assignment operator, therefore, groups from right to left.) Later we’ll see other circumstances in which it can be useful to use the value of an assignment expression. It’s usually a matter of style whether you initialize a variable with an initializer in its declaration or with an assignment expression near where you first use it. That is, there’s no particular difference between int a = 10; and int a; /* later... */ a = 10; Summary Integers are whole numbers with a range of values supported by a particular machine. Generally, integers occupy one word of storage, and since the word sizes of machines vary (typically, 16 or 32 bits) the size of an integer that can be stored depends on the computer. A variable (also called an object) is a place where you can store a value. A declaration tells the compiler the name and type of a variable you’ll be using in your program. The assignment operator = assigns a value to a variable Terminal Questions 1. Distinguish between signed and unsigned integers. 2. What are the components of declaration statement?
- 19. 3. State the rules for naming a variable in C. 4. What is the use of an assignment operator ? 5. The ____________ of a variable determines what kinds of values it may take on. 6. Find errors, if any, in the following declaration statements. 7. Which of the following are invalid variable names and why? Answers to Self Assessment Questions 2.1 i) Integer constants, Real constants, Character constants, String constants. ii) Decimal, Octal and Hexadecimal iii) Backslash character constants are called escape sequences 2.2 i) False ii) Variable iii) 16 2.3 i) A declaration tells the compiler the name and type of a variable you’ll be using in your program. ii) An initializer is used to assign a value to a variable. The initializer consists of an equal sign and an expression, which is usually a single constant. iii) False 2.4 i) True ii) Underscores Answers to Terminal Questions
- 20. 1. A signed integer uses one bit for sign and remaining bits for the magnitude of the number, whereas an unsigned integer uses all the bits to represent magnitude. 2. A declaration consists of the type, the name of the variable, and a terminating semicolon. 3. Variables (the formal term is “identifiers”) consist of letters, numbers, and underscores. The capitalization of names in C is significant. you may not use keywords (the words such as int and for which are part of the syntax of the language) as the names of variables or functions (or as identifiers of any kind). 4. The assignment operator (=) assigns a value to a variable. 5. type 6. (i) In the first line capital I for Int is not allowed (ii) In the third line there must be coma between m and count. (iii) The declaration of integer elements a,b,c is as follows: int a,b,c; 7. The following are invalid variable names: (i) First.name- because the symbol . is not allowed. (ii) 2nd_row – because the variable names should not begin with numbers (iii) int – because int is a keyword (iv) Row total – because space is not allowe Exercises 1. Determine the valid identifiers from below a) record 1 b) file_2 c) a+b d) return 2. Which of the following are invalid constants and why? a) 0.001 b) 5×1.5 c) 999999 d) ‘12’ 3. Determine which of the following are valid string constants a) 9:00 p.m b) “Name: c) “chapter 3 (cont’d)’ d) p,q
- 21. 4. Explain different types of constants. 5. What are the rules used in naming a variable? Give examples. Unit 3 Operators and Expressions • Declaration and Initialization Statement, Integer Division, Priority of the Arithmetic Operators, The use of Parenthesis, The Modulus Operator, The Unary Minus Operator. Introduction C supports a rich set of operators. An operator is a symbol that tells the computer to perform certain mathematical or logical manipulations. Operators are used in programs to manipulate data and variables. They usually form a part of the mathematical or logical expressions. C operator can be classified into a number of categories. They include: 1. Arithmetic operators 2. Unary operator 3. Relational operators 4. Logical operators 5. Conditional operator 6. Bitwise operators 7. Increment and Decrement operators Objectives At the end of this module you will be able to: · Understand different categories of operators · Understand how to use operators and on how many operands they can be used · Precedence and Associativity of operators · Understand library functions and their use
- 22. · Write small programs using different types of operators Arithmetic Operators The basic operators for performing arithmetic are the same in many computer languages: + addition - subtraction * multiplication / division % modulus (remainder) The - operator can be used in two ways: to subtract two numbers (as in a – b), or to negate one number (as in -a + b or a + -b). When applied to integers, the division operator / discards any remainder, so 1 / 2 is 0 and 7 / 4 is 1. But when either operand is a floating-point quantity (a real number), the division operator yields a floating-point result, with a potentially nonzero fractional part. So 1 / 2.0 is 0.5, and 7.0 / 4.0 is 1.75. The modulus operator % gives you the remainder when two integers are divided: 1 % 2 is 1; 7 % 4 is 3. (The modulus operator can only be applied to integers.) An additional arithmetic operation you might be wondering about is exponentiation. Some languages have an exponentiation operator (typically ^ or **), but C doesn’t. (To square or cube a number, just multiply it by itself.) Multiplication, division, and modulus all have higher precedence than addition and subtraction. The term “precedence” refers to how “tightly” operators bind to their operands (that is, to the things they operate on). In mathematics, multiplication has higher precedence than addition, so 1 + 2 * 3 is 7, not 9. In other words, 1 + 2 * 3 is equivalent to 1 + (2 * 3). C is the same way. All of these operators “group” from left to right, which means that when two or more of them have the same precedence and participate next to each other in an expression, the evaluation conceptually proceeds from left to right. For example, 1 – 2 – 3 is equivalent to (1 – 2) – 3 and gives -4, not +2. (“Grouping” is sometimes called associativity, although the term is used somewhat differently in programming than it is in mathematics. Not all C operators group from left to right; a few groups from right to left.) Whenever the default precedence or associativity doesn’t give you the grouping you want, you can always use explicit parentheses. For example, if you want to add 1 to 2 and then multiply the result by 3, you could write (1 + 2) * 3. Program 3.1: Program that shows the use of integer arithmetic to convert a given number of days into months and days.
- 23. /* Program to convert days to months and days */ main() { int months, days; printf(“Enter daysn”); scanf(“%d”,&days); months=days/30; days=days%30; printf(“Months=%d Days=%d”, months,days); } Self Assessment Questions i) What is the value of the following arithmetic expression? 14 % 3 + 7 % 2 ii) __________ operator can be only applied to integers. Unary Operator A unary operator acts upon a single operand to produce a new value. Unary Minus The most well known unary operator is minus, where a minus sign precedes a constant, variable or expression. In C, all numeric constants are positive. Therefore, a negative number is actually a positive constant preceded by a unary minus, for example: The Conditional operator The Conditional operator (ternary operator) pair “?:” is available in C to construct conditional expressions of the form expr1?expr2:expr3 where expr1, expr2 and expr3 are expressions.
- 24. The operator ? : works as follows: expr1 is evaluated first. If it is nonzero(true), then the expression expr2 is evaluated and becomes the value of the expression. If expr1 is false, expr3 is evaluated and its value becomes the value of the expression. For example, consider the following statements: a=100; b=200; c=(a>b)?a:b; In this example, c will be assigned the value of b. This can be achieved using the if..else statements as follows: if(a>b) c=a; else c=b; Library functions The C language is accompanied by a number of library functions or built in functions that carry out various commonly used operations or calculations. There are library functions that carry out standard input/output operations, functions that perform operations on characters, functions that perform operations on strings and functions that carry out various mathematical calculations. Functionally similar library functions are usually grouped together as object programs in separate library files. A library function is accessed simply by writing the function name, followed by a list of arguments that represent information being passed to the function. A function that returns a data item can appear anywhere within an expression in place of a constant or an identifier. A function that carries out operations on data items but does not return anything can be accessed simply by writing the function name. A typical set of library functions will include a large number of functions that are common to most C compilers, such as those shown in table 3.1
- 25. Table 3.1 Program 3.2: Program to convert lowercase to uppercase #include <stdio.h> /* Input/Output functions are available in stdio.h */ #include<ctype.h> /* Character functions are available in the file ctype.h */ main() /* read a lowercase character and print its uppercase equivalent */ { int lower, upper; lower=getchar(); upper=toupper(lower); putchar(upper); } Program 3.3: Program to illustrate the use of library functions #include<stdio.h> #include<ctype.h> #include<math.h> /* Mathematical functions are available in math. h*/ main() { int i=-10, e=2, d=10;
- 26. float rad=1.57; double d1=2.0, d2=3.0; printf(“%dn”, abs(i)); printf(“%fn”, sin(rad)); printf(“%fn”, cos(rad)); printf(“%fn”, exp(e)); printf(“%dn”, log(d)); printf(“%fn”, pow(d1,d2)); } Execute the above program and observe the result Self Assessment Questions i) What are library functions? ii) What is the value of the following: a) floor(5.8) b) floor(-5.8) c) ceil(5.8) d) ceil(-5.8) The Bitwise operators The bitwise operators &, |, ^, and ~ operate on integers thought of as binary numbers or strings of bits. The & operator is bitwise AND, the | operator is bitwise OR, the ^ operator is bitwise exclusive-OR (XOR), and the ~ operator is a bitwise negation or complement. (&, |, and ^ are “binary” in that they take two operands; ~ is unary.) These operators let you work with the individual bits of a variable; one common use is to treat an integer as a set of single-bit flags. You might define the 3rd bit as the “verbose” flag bit by defining #define VERBOSE 4
- 27. Then you can “turn the verbose bit on” in an integer variable flags by executing flags = flags | VERBOSE; and turn it off with flags = flags & ~VERBOSE; and test whether it’s set with if(flags & VERBOSE) The left-shift and right-shift operators << and >> let you shift an integer left or right by some number of bit positions; for example, value << 2 shifts value left by two bits. The comma operator can be used to link the related expressions together. The expressions are executed one after the other. The most common use for comma operators is when you want multiple variables controlling a for loop, for example: for(i = 0, j = 10; i < j; i++, j–) Self Assessment Questions i) What is the use of bitwise operators? ii) if flag1=5, flag2=8, compute the following a) flag1&flag2 b) flag1|flag2 c) ~flag1 d) flag1^flag2 Increment and Decrement Operators When we want to add or subtract constant 1 to a variable, C provides a set of shortcuts: the autoincrement and autodecrement operators. In their simplest forms, they look like this: ++i add 1 to i –j subtract 1 from j These correspond to the forms i = i + 1 and j = j - 1. They are also equivalent to the short hand forms i+=1 and j-=1. C has a set of ‘shorthand’ assignment operators of the form: v op=exp;
- 28. where v is a variable, exp is an expression and op is a C binary arithmetic operator. The assignment statement v op=exp; is equivalent to v= v op(exp); Example: x+=y+1; This is same as the statement x=x+(y+1); The ++ and -- operators apply to one operand (they’re unary operators). The expression ++i adds 1 to i, and stores the incremented result back in i. This means that these operators don’t just compute new values; they also modify the value of some variable. (They share this property–modifying some variable–with the assignment operators; we can say that these operators all have side effects. That is, they have some effect, on the side, other than just computing a new value.) The incremented (or decremented) result is also made available to the rest of the expression, so an expression like k = 2 * ++i means “add one to i, store the result back in i, multiply it by 2, and store that result in k.” (This is a pretty meaningless expression; our actual uses of ++ later will make more sense.) Both the ++ and -- operators have an unusual property: they can be used in two ways, depending on whether they are written to the left or the right of the variable they’re operating on. In either case, they increment or decrement the variable they’re operating on; the difference concerns whether it’s the old or the new value that’s “returned” to the surrounding expression. The prefix form ++i increments i and returns the incremented value. The postfix form i++ increments i, but returns the prior, non-incremented value. Rewriting our previous example slightly, the expression k = 2 * i++ means “take i’s old value and multiply it by 2, increment i, store the result of the multiplication in k.”
- 29. The distinction between the prefix and postfix forms of ++ and -- will probably seem strained at first, but it will make more sense once we begin using these operators in more realistic situations. For example, a[i] = c; i = i + 1; using the ++ operator, we could simply write this as a[i++] = c; We wanted to increment i after deciding which element of the array to store into, so the postfix form i++ is appropriate. Notice that it only makes sense to apply the ++ and -- operators to variables (or to other “containers,” such as a[i]). It would be meaningless to say something like 1++ or (2+3)++ The ++ operator doesn’t just mean “add one”; it means “add one to a variable” or “make a variable’s value one more than it was before.” But (1+2) is not a variable, it’s an expression; so there’s no place for ++ to store the incremented result. Another unfortunate example is i = i++; which some confused programmers sometimes write, presumably because they want to be extra sure that i is incremented by 1. But i++ all by itself is sufficient to increment i by 1; the extra (explicit) assignment to i is unnecessary and in fact counterproductive, meaningless, and incorrect. If you want to increment i (that is, add one to it, and store the result back in i), either use i = i + 1; or i += 1;
- 30. or ++i; or i++; Did it matter whether we used ++i or i++ in this last example? Remember, the difference between the two forms is what value (either the old or the new) is passed on to the surrounding expression. If there is no surrounding expression, if the ++i or i++ appears all by itself, to increment i and do nothing else, you can use either form; it makes no difference. (Two ways that an expression can appear “all by itself,” with “no surrounding expression,” are when it is an expression statement terminated by a semicolon, as above, or when it is one of the controlling expressions of a for loop.) For example, both the loops for(i = 0; i < 10; ++i) printf(”%dn”, i); and for(i = 0; i < 10; i++) printf(”%dn”, i); will behave exactly the same way and produce exactly the same results. (In real code, postfix increment is probably more common, though prefix definitely has its uses, too.) Self Assessment Questions i) State true or false: Increment and Decrement operators are binary operators ii) What is the difference between the statements ++i and i++? The size of operator The size of is a compile time operator and, when used with an operand, it returns the number of bytes the operand occupies. The operand may be a variable, a constant or a data type qualifier. Examples:
- 31. m=sizeof(sum); n=sizeof(long int); k=sizeof(235L); The size of operator is normally used to determine the lengths of arrays and structures when their sizes are not known to the programmer. It is also used to allocate memory space dynamically to variables during execution of a program. Program 3.4: Program to illustrate the use of sizeof operator #include<stdio.h> main() { int i=10; printf(“integer: %dn”, sizeof(i); } The above program might generate the following output: integer: 2 Thus we see that this version of C allocates 2 bytes to each integer quantity. Program 3.5: Program to illustrate arithmetic operators #include<stdio.h> main() { int a, b, c, d; a=10; b=15; c=++a-b;
- 32. printf(“a=%d b=%d c=%dn”, a, b, c); d=b++ +a; printf(“a=%d b=%d d=%dn”, a, b, d); printf(“a/b=%dn”, a/b); printf(“a%%b=%dn”, a%b); printf(“a*=b=%dn”, a*=b); printf(“%dn”, (c>d)?1:0); printf(“%dn”, (c<d)?1:0); } Execute the above program and observe the result. Precedence of Operators The precedence of C operators dictates the order of evaluation within an expression. The precedence of the operators introduced here is summarised in the Table 3.2. The highest precedence operators are given first. Table 3.2 Where the same operator appears twice (for example *) the first one is the unary version. Program 3.6: A program to illustrate evaluation of expressions #include<stdio.h> main()
- 33. /* Evaluation of expressions */ { float a, b, c, x, y, z; a=20; b=2; c=-23; x = a + b / ( 3 + c * 4 – 1); y = a – b / (3 + c) * ( 4 – 1); z= a – ( b / ( 3 + c ) * 2 ) – 1; printf( “x=%fn”, x); printf(“y=%fn”, y); printf(“z=%fn”, z); } Execute the above program and observe the result. Program 3.7: Program to convert seconds to minutes and seconds #include <stdio.h> #define SEC_PER_MIN 60 // seconds in a minute int main(void) { int sec, min, left; printf(”Convert seconds to minutes and seconds!n”); printf(”Enter the number of seconds you wish to convert.n”); scanf(”%d”, &sec); *number of seconds is read in
- 34. min = sec / SEC_PER_MIN; *truncated number of minutes left = sec % SEC_PER_MIN; *number of seconds left over printf(”%d seconds is %d minutes, %d seconds.n”, sec, min, left); return 0; } Summary C supports a rich set of operators. An operator is a symbol that tells the computer to perform certain mathematical or logical manipulations. Operators are used in programs to manipulate data and variables. A binary operator acts on two operands. A unary operator acts upon a single operand to produce a new value. Multiplication, division, and modulus all have higher precedence than addition and subtraction. Relational and Boolean expressions are usually used in contexts such as an if statement, where something is to be done or not done depending on some condition. The C language is accompanied by a number of library functions or built in functions that carry out various commonly used operations or calculations. The sizeof operator is normally used to determine the lengths of arrays and structures when their sizes are not known to the programmer. It is also used to allocate memory space dynamically to variables during execution of a program. Associativity is the order in which consecutive operations within the same precedence group are carried out. Terminal questions 1. If i=10 and j=12, what are the values of c and d after executing the following program segment: i++; c=j++ + i; d=++i + j++; 2. Suppose that x, y and z are integer variables which have been assigned the values 2, 3 and 4, respectively. Evaluate the following expression and determine the value of x. x *= -2 * (y + z) / 3 3. Suppose that i is an integer variable whose value is 7 and c is a character variable that represents the character ‘w’, evaluate the following logical expression:
- 35. (i>=6) && (c==’w’) 4. Suppose that i is an integer variable whose value is 7 and f is a floating –point variable whose value is 8.5. Evaluate the following expression: (i + f) %4 5. What is meant by associativity? Answers to Self Assessment Questions 3.1 i) 3 ii) %(modulus) 3.3 i) The logical operators && and || are used when we want to test more than one condition and make decisions. ii) Not correct 3.5 i) Library functions are built-in functions that carry out various commonly used operations or calculations ii) a) 5 b) -6 c) 6 d) -5 3.6 i) Bitwise operators let you work with the individual bits of a variable; one common use is to treat an integer as a set of single-bit flags. ii) a) 0 b) 13 c) 10 d) 13 3.7 i) False ii) Both are same when they are written as independent statements Answers to terminal questions 1. c=23 and d=25 2. -8 3. true 4. Given expression is invalid because a floating point variable can not be used in a modulus operation.
- 36. 5. Associativity is the order in which consecutive operations within the same precedence group are carried out. 3.14 Exercises 1. Suppose a=3, b=5, c=8 and d=4, give the output of the following: a) x=a*b-c/d+4 b) z=a-b/d*c+10 2. Suppose i=5, j=8, k=10, then , what is the output of the following: a) x=a++ -j b) y=k++ *j— 3. What is the precedence of operators? How expressions are evaluated using the precedences? 4. Suppose a=7, b=11, find the output of the following: a) x=(a>b)?b:a b) x=(a<b)?a:b 5. Explain the use of bitwise operators with suitable examples. Unit 4 Some More Data Types • Floating-point Numbers, The type double, Converting Integers to Floating-point and vice-versa, Mixed-mode Expressions, The type cast Operator, The type char, Keywords. Introduction Integer is one of the fundamental data types. All C compilers support four fundamental data types, namely integer (int), character (char), floating point (float), and double- precision floating point (double). Like integer data type, other data types also offer extended data types such as long double and signed char. C supports a rich set of operators. We have already used several of them, such as =, +, -, *, / and %. An operator is a symbol that tells the computer to perform certain mathematical or logical manipulations. Operators are used in programs to manipulate data and variables. They usually form a part of the mathematical or logical expressions. It is possible to combine operands of different data types in arithmetic expressions. Such expressions are called mixed-mode arithmetic expressions.
- 37. Objectives At the end of this unit, you will be able to: · Understand the concept of Real Numbers in C · Understand the concept of Characters in C · Combine different data types and form more complicated arithmetic expressions Floating-point Numbers Floating point (or real) numbers are stored in 32 bit (on all 16 bit and 32 bit machines), with 6 digits of precision. Floating point numbers are defined in C by the keyword float. When the accuracy provided by a float number is not sufficient, the type double can be used to define the number. A double data type number uses 64 bits giving a precision of 14 digits. These are known as double precision numbers. To extend the precision further, we may use long double which uses 80 bits. The following table shows all the allowed combinations of floating point numbers and qualifiers and their size and range on a 16-bit machine. Table 4.1 Program 4.1: The following program illustrates typical declarations, assignments and values stored in various types of variables. main() { /* …….DECLARATIONS……………………..*/ float x, p; double y, q; unsigned k; /* ……………….DECLARATIONS AND ASSIGNMENTS………..*/ int m=54321;
- 38. long int n=1234567890; /*…………..ASSIGNMENTS……………………*/ x = 1.234567890000; y = 9.87654321; k = 54321; p=q=1.0; /*…………….PRINTING………………….*/ printf(“m=%dn”,m); printf(“n=%ldn”,n); printf(“x=%.12lfn”,x); printf(“x=%fn”,x); printf(“y=%.12lfn”,y); printf(“y=%lfn”,y); printf(“k=%u p= %f q=%.12lfn”,k,p,q); } Output m = -11215 n = 1234567890 x = 1.234567880630 x = 1.234568 y = 9.876543210000 y = 9.876543 k = 54321 p = 1.000000 q= 1.000000000000
- 39. Program 4.2: Program to calculate the average of N numbers #define N 10 /* SYMBOLIC CONSTANT */ main() { int count; /* DECLARATION OF float sum, average, number; VARIABLES */ sum = 0; / * INITIALIZATION OF count = 0; VARIABLES*/ while (count<N) { scanf(“%f”, &number); sum = sum + number; count = count + 1; } average = sum / N; printf(“N = % d Sum = %f “, N, sum); printf(“Average = %f”, average); Output 1 2.3 4.67 1.42 7
- 40. 3.67 4.08 2.2 4.25 8.21 N= 10 Sum= 38.799999 Average= 3.880000 Program 4.3: Program to compute the roots of a quadratic equation #include <math.h> main() { float a,b,c,discriminant, root1, root2; printf(“input the values of a,b and cn”); scanf (“%f %f %f”, &a, &b, &c); discriminant = b * b – 4 * a *c; if (discriminant<0) printf(“roots are imaginaryn”); else { root1 = (-b + sqrt(discriminant)) / (2 * a); root2 = (-b – sqrt(discriminant)) / (2 * a); printf (“Root1 = %5.2f n Root2 = %5.2f n”, root1, root2); } }
- 41. Output input the values of a,b and c 2 4 -16 Root1 = 2.00 Root2 = -4.00 input the values of a,b and c 123 roots are imaginary Self Assessment Questions i) State true or false. When the accuracy provided by a float number is not sufficient, the type long float can be used to define the number. ii) A double data type uses __________ bits. Converting Integers to Floating-point and vice-versa C permits mixing of constants and variables of different types in an expression, but during evaluation it adheres to very strict rules of type conversion. We know that the computer considers one operator at a time, involving two operands. If the operands are of different types, the ‘lower’ type is automatically converted to the ‘higher’ type before the operation proceeds. The result is of higher type. Given below is the sequence of rules that are applied while evaluating expressions. All short type are automatically converted to int ; then 1. If one of the operands is long double, the other will be converted to long double and the result will be long double; 2. else, if one of the operands is double, the other will be converted to double and the result will be double; 3. else, if one of the operands is float, the other will be converted to float and the result will be float;
- 42. 4. else, if one of the operands is unsigned long int, the other will be converted to unsigned long int and the result will be unsigned long int; 5. else if one of the operands is long int and the other is unsigned int, then: · if unsigned int can be converted to long int, the unsigned int operand will be converted as such and the result will be long int; · else, both operands will be converted to unsigned long int and the result will be unsigned long int; 6. else, if one of the operands is long int , the other will be converted to long int and the result will be long int; 7. else, if one of the operands is unsigned int , the other will be converted to unsigned int and the result will be unsigned int; The final result of an expression is converted to type of the variable on the left of the assignment sign before assigning the value to it. However, the following changes are introduced during the final assignment: 1. float to int causes truncation of the fractional part. 2. double to float causes rounding of digits. 3. long int to int causes dropping of the excess higher order bits Self Assessment Questions i) State true or false. If the operands are of different data types, the ‘lower’ type is automatically converted to the ‘higher’ type before the operation proceeds. ii) During the final assignment ________ to int causes dropping of the excess higher order bits. Mixed-mode Expressions When one of the operands is real and the other is integer, the expression is called a mixed-mode arithmetic expression. If either operand is of the real type, then only the real operation is performed and the result is always real number. Thus 25 / 10.0 = 2.5 Where as 25 / 10 =2
- 43. Self Assessment Questions i) The value of the expression 22.0/10 is ________ The type cast Operator C performs type conversions automatically. However, there are instances when we want to force a type conversion in a way that is different from the automatic conversion. Consider, for example, the calculation of ratio of doctors to engineers in a town. Ratio = doctor_number / engineer _number Since doctor _number and engineer_number are declared as integers in the program, the decimal part of the result of the division would be lost and Ratio would represent a wrong figure. This problem can be solved by converting locally one of the variables to the floating point as shown below: Ratio = (float) doctor_number / engineer _number The operator (float) converts the doctor_number to floating point for the purpose of evaluation of the expression. Then using the rule of automatic conversion, the division is performed in floating point mode, thus retaining the fractional part of the result. Note that in no way does the operator (float) affect the value of the variable doctor_number. And also, the type of doctor_number remains as int in the other parts of the program. The process of such local conversion is known as casting a value. The general form of cast is: (type-name) expression where type-name is one of the standard C data types. The expression may be a constant, variable or an expression. The Table 4.2 shows some examples of casts and their actions: Example Action X=(int) 8.5 8.5 is converted to integer by truncation. A=(int) 21.3 / (int) 4.5 Evaluated as 21/4 and the result would be 5. B=(double) sum/n Division is done in floating point mode. Y= (int) (a+b) The result of a+b is converted to integer. Z= (int) a+b a is converted to integer and then added to b. P=cos(( double)x) Converts x to double before using it. Table 4.2: Use of Casts Program 4.4: The following program shows the use of casts
- 44. main() { /* Program to find average of two integers */ float avg; int n=2,n1,n2; printf(”enter any 2 numbersn”); scanf(”%d %d”,&n1,&n2); avg=(n1+n2)/(float)n; printf(” their average isn”,avg); } Casting can be used to round-off a given value. Consider the following statement: X= (int) (y+0.5); If y is 37.7, y+0.5 is 38.2 and on casting, the result becomes 38, the value that is assigned to X. Of course, the expression , being cast is not changed. When combining two different types of variables in an expression, never assume the rules of automatic conversion. It is always a good practice to explicitly force the conversion. It is more safer and more portable. For example, when y and p are double and m is int , the following two statements are equivalent. y = p + m; y = p + (double)m; However, the second statement is preferable. It will work the same way on all machines and is more readable. Self Assessment Questions i) State true or false Casting can be used to round-off a given value.
- 45. ii) The value of A in the expression A=(int) 11.35 / (int) 14.5 is ___________. iii) If the value of X is 35.2, what is the value of A in the following expression? A = (int)(X+0.5); The type char A single character can be defined as a character(char) type data. Characters are usually stored in 8 bits (one byte) of internal storage. The qualifier signed or unsigned may be explicitly applied to char. While unsigned chars have values between 0 and 255, signed chars have values from -128 to 127. A character constant is formed by enclosing the character within a pair of single quote marks. So ‘b’, ‘.’ and ‘5’ are all valid examples of character constants. Note that a character constant, which is a single character enclosed in single quotes is different from a character string, which is any number of characters enclosed in double quotes. The format characters %c can be used in a printf statement to display the value of a char variable at the terminal. Program 4.5: The following program illustrates how to use char data type. #include<stdio.h> main() { char c=’A’; int a=65; printf(“%cn”, c); printf(“%dn”, c); printf(“%cn”,a); } Output A 65
- 46. A Note that with the format characters %d, the ASCII number of the character is displayed. With the format character %c, the character corresponding to the given ASCII number is displayed. Self Assessment Questions i) What is the format character to display the value of a char variable? ii) What is the output of the following C statement? printf(“%c”, 70) Keywords Keywords are the reserved words of a programming language. All the keywords have fixed meanings and these meanings cannot be changed. Keywords serve as basic building blocks for program statements. The list of all keywords in ANSI C are listed in the Table 4.3 All keywords must be written in lowercase. Some compilers may use additional keywords that must be identified from the C manual. Self Assessment Questions i) All keywords must be written in ____________. ii) State true or false: default is not a valid keyword in C. Summary Floating point(or real) numbers are stored in 32 bit (on all 16 bit and 32 bit machines), with 6 digits of precision. Floating point numbers are defined in C by the keyword float. When the accuracy provided by a float number is not sufficient, the type double can be
- 47. used to define the number. Characters are usually stored in 8 bits (one byte) of internal storage. Like integer data type other data types also offer extended data types such as long double and signed char. C permits mixing of constants and variables of different types in an expression, but during evaluation it adheres to very strict rules of type conversion. When one of the operands is real and the other is integer, the expression is called a mixed-mode arithmetic expression. There are instances when we want to force a type conversion in a way that is different from the automatic conversion. That is, by using type cast operator. All keywords have fixed meanings and these meanings cannot be changed. Terminal Questions 1. Which of the following arithmetic expressions are valid? If valid , give the value of the expression; otherwise give reason. a) 7.5 % 3 b) 14 % 3 + 7 %2 c) 21 % (int) 4.5 d) 15.25 + – 5.0 2. Find errors, if any, in the following declaration statements: Int x; float letter, DIGIT; double = p, q exponent alpha, beta; m,n,z:INTEGER short char c; long int m; count; long float temp; 3. What would be the value of x after execution of the following statements? int x, y = 10; char z = ‘a’; x = y + z; 4. The _______ chars have values from -128 to 127.
- 48. Answers to Self Assessment Questions 4.1 i) False ii) 64 4.2 i) True ii) long int 4.3 i) 2.2 4.4 i) true ii) 0 iii) 35 4.5 i) %c ii) F 4.6 i) lowercase ii) false Answers to Terminal Questions 1. a) invalid, because % can be used only with integers. b) valid, answer is 3 c) valid, answer is 1 d) valid, answer is 10.25 2. Errors in the following statements i) Int x; Can be written as int x; ii) double = p, q
- 49. Can be written as double p,q; iii) exponent alpha, beta; There is no data type exponent in C. iv) m,n,z:INTEGER Can be written as int m,n,z; v) short char c; There is no data type short char in C. vi) long int m; count; Can be written as long int m,count; vii) long float temp; There is no data type long float in C 3. 107 4. signed Exercises 1. Represent the following numbers using scientific notation: a) 0.001 b)-1.5 2. Represent the following scientific numbers into decimal notation: a) 1.0E+2 b) 0.001E-2 3. What is unsigned char? Explain. 4. What is short char? Explain. 5. Distinguish between float and double data types.
- 50. Unit 5 Input and Output operators • Reading a Character, Writing a Character, Formatted Input, Formatted Output. Introduction We have already seen that the C language is accompanied by some library functions to handle input/output(I/O) operations. In this unit we will make use of six I/O functions : getchar(), putchar(), scanf(), printf(), gets() and puts(). These functions are used to transfer the information between the computer and the standard input/output devices. Throughout this course we assume that keyboard is the standard input device and the user screen is the standard output device. The first two functions, getchar() and putchar(), allow single character to be transferred into and out of the computer; the functions scanf() and printf() permit the transfer of single character, numerical values and strings; the functions gets() and puts() facilitate the input and output of strings. These functions can be accessed within a program by including the header file stdio.h. Objectives At the end of this unit you will be able to understand: · How to transfer a character between the computer and I/O devices · How to transfer a numerical value and a string between the computer and I/O devices · How to write programs using I/O functions to handle single character, numerical values and strings Character Input and Output The most basic way of reading input is by calling the function getchar(). getchar() reads one character from the “standard input,” which is usually the user’s keyboard. getchar() returns (rather obviously) the character it reads, or, if there are no more characters available, the special value EOF (“end of file”). This value will be assigned within the stdio.h file. Typically, EOF will be assigned the value -1, but this may vary from one compiler to another. The syntax of the getchar() function is written as character variable= getchar() where character variable refers to some previously declared character variable.
- 51. Example: char c; … c=getchar(); The first statement declares that c is a character-type variable. The second statement causes a single character to be entered from the keyboard and then assign to c. A companion function is putchar(), which writes one character to the “standard output.” (The standard output is usually the user’s screen). The syntax of the putchar() function is written as putchar(character variable) where character variable refers to some previously declared character variable. Example: char c; … putchar(c); The first statement declares that c is a character-type variable. The second statement causes the current value of c to be transmitted to the user monitor where it will be displayed. Using these two functions, we can write a very basic program to copy the input, a character at a time, to the output: Program 5.1: Program to copy the input, a character at a time, to the output #include <stdio.h> /* copy input to output */ main() { int c;
- 52. c = getchar(); while(c != EOF) { putchar(c); c = getchar(); } return 0; } Execute the above program and observe the result. It reads one character, and if it is not the EOF code, enters a while loop, printing one character and reading another, as long as the character read is not EOF. A char variable could hold integers corresponding to character set values, and that an int could hold integers of more arbitrary values(from -32768 to + 32767). Since most character sets contain a few hundred characters (nowhere near 32767), an int variable can in general comfortably hold all char values, and then some. Therefore, there’s nothing wrong with declaring c as an int. But in fact, it’s important to do so, because getchar() can return every character value, plus that special, non-character value EOF, indicating that there are no more characters. Type char is only guaranteed to be able to hold all the character values; it is not guaranteed to be able to hold EOF value without possibly mixing it up with some actual character value. Therefore, you should always remember to use an int for anything you assign getchar()’s return value to. When you run the character copying program, and it begins copying its input (you’re typing) to its output (your screen), you may find yourself wondering how to stop it. It stops when it receives end-of-file (EOF), but how do you send EOF? The answer depends on what kind of computer you’re using. On Unix and Unix-related systems, it’s almost always control-D. On MS-DOS machines, it’s control-Z followed by the RETURN key. (Note, too, that the character you type to generate an end-of-file condition from the keyboard is not the same as the special EOF value returned by getchar(). The EOF value returned by getchar() is a code indicating that the input system has detected an end-of- file condition, whether it’s reading the keyboard or a file or a magnetic tape or a network connection or anything else. In a disk file, at least, there is not likely to be any character in the file corresponding to EOF; as far as your program is concerned, EOF indicates the absence of any more characters to read.)
- 53. Another excellent thing to know when doing any kind of programming is how to terminate a runaway program. If a program is running forever waiting for input, you can usually stop it by sending it an end-of-file, as above, but if it’s running forever not waiting for something, you’ll have to take more drastic measures. Under Unix, control-C (or, occasionally, the DELETE key) will terminate the current program, almost no matter what. Under MS-DOS, control-C or control-BREAK will sometimes terminate the current program. Self Assessment Questions i) State true or false: getchar() function is an output function. ii) In order to stop reading the input character, you can use a value called __________________. Formatted Input Input data can be entered into the computer from a standard input device by means of the standard C library function scanf(). This function can be used to enter any combination of numerical values, single character and strings. The function returns the number of data items that have been entered successfully. The syntax of scanf function is as follows: scanf(control string, arg1, arg2, …argn) where control string refers to a string containing certain required formatting information, and arg1, arg2,…, argn are arguments that represent the individual input data items. The arguments represent pointers that indicate addresses of the data items within the computer’s memory. The control string consists of control characters, whitespace characters, and non- whitespace characters. The control characters are preceded by a % sign, and are listed in Table 5.1
- 54. Table 5.1 scanf() reads the input, matching the characters from format. When a control character is read, it puts the value in the next variable. Whitespaces (tabs, spaces, etc) are skipped. Non-whitespace characters are matched to the input, then discarded. If a number comes between the % sign and the control character, then only that many characters will be entered into the variable. If scanf() encounters a set of characters, denoted by the %[] control character, then any characters found within the brackets are read into the variable. The return value of scanf() is the number of variables that were successfully assigned values, or EOF if there is an error. Program 5.2: Program to use scanf() to read integers, floats, characters and strings from the user. #include<stdio.h> main() { int i; float f; char c; char str[10]; scanf(“%d %f %c %s”, &i, &f, &c, str); printf(“%d %f %c %s”, i, f, c, str); } Execute this program and observe the result. Note that for a scanf() function, the addresses of the variable are used as the arguments for an int, float and a char type variable. But this is not true for a string variable because a string name itself refers to the address of a string variable. A s-control character is used to enter strings to string variables. A string that includes whitespace characters can not be entered. There are ways to work with strings that include whitespace characters. One way is to use the getchar() function within a loop. Another way is to use gets() function which will be discussed later.
- 55. It is also possible to use the scanf() function to enter such strings. To do so, the s-control character must be replaced by a sequence of characters enclosed in square brackets, designated as […]. Whitespace characters may be included within the brackets, thus accommodating strings that contain such characters. Example: #include<stdio.h> main() { char str[80]; … scanf(“%[ ABCDEFGHIJKLMNOPQRST]”, str); … } This example illustrates the use of the scanf() function to enter a string consisting of uppercase letters and blank spaces. Please note that if you want to allow lowercase letters to be entered, all the lowercase letters( i.e from a-z) must be included in the list of control string. Self Assessment Questions i) What are the different characters included in a control string? ii) The control string used to read a hexadecimal character is – iii) State true or false. scanf() functions needs address of the data item to be read as the argument. Formatted Output Output data can be written from the computer onto a standard output device using the library function printf(). This function can be used to output any combination of numerical values, single characters and strings. It is similar to the input function scanf(), except that its purpose is to display data rather than enter into the computer.
- 56. The syntax of the printf function can be written as follows: printf(control string, arg1, arg2, …, argn) where control string refers to a string that contains formatting information, and arg1, arg2, …, argn are arguments that represent the individual output data items. The arguments can be written as constants, single variable or array names, or more complex expressions. Examples: printf(”Hello, world!n”); printf(”i is %dn”, i); printf(”%d”, 10); printf(”%d”, i+j); The first statement simply displays the string given as argument to the printf() function. In the second statement, printf() function replaces the two characters %d with the value of the variable i. In the third statement the argument to be printed is a constant and in the fourth, the argument is an expression. There are quite a number of format specifiers for printf(). Some of them are listed in Table 5.2. %d Print an int argument in decimal %ld print a long int argument in decimal %c print a character %s print a string %f print a float or double argument %e same as %f, but use exponential notation %g use %e or %f, whichever is better %o print an int argument in octal (base %x print an int argument in hexadecimal (base 16) %% print a single % Table 5.2 It is also possible to specify the width and precision of numbers and strings as they are inserted ; For example, a notation like %3d means to print an int in a field at least 3 spaces wide; a notation like %5.2f means to print a float or double in a field at least 5 spaces wide, with two places to the right of the decimal.)
- 57. To illustrate with a few more examples: the call printf(”%c %d %f %e %s %d%%n”, ‘3′, 4, 3.24, 66000000, “nine”, 8); would print 3 4 3.240000 6.600000e+07 nine 8% The call printf(”%d %o %xn”, 100, 100, 100); would print 100 144 64 Successive calls to printf() just build up the output a piece at a time, so the calls printf(”Hello, “); printf(”world!n”); would also print Hello, world! (on one line of output). Earlier we learned that C represents characters internally as small integers corresponding to the characters’ values in the machine’s character set (typically ASCII). This means that there isn’t really much difference between a character and an integer in C; most of the difference is in whether we choose to interpret an integer as an integer or a character. printf is one place where we get to make that choice: %d prints an integer value as a string of digits representing its decimal value, while %c prints the character corresponding to a character set value. So the lines char c = ‘A’; int i = 97; printf(”c = %c, i = %dn”, c, i); would print c as the character A and i as the number 97. But if, on the other hand, we called printf(”c = %d, i = %cn”, c, i); we’d see the decimal value (printed by %d) of the character ‘A’, followed by the character (whatever it is) which happens to have the decimal value 97.
- 58. You have to be careful when calling printf(). It has no way of knowing how many arguments you’ve passed it or what their types are other than by looking for the format specifiers in the format string. If there are more format specifiers (that is, more % signs) than the arguments, or if the arguments have the wrong types for the format specifiers, printf() can misbehave badly, often printing nonsense numbers or (even worse) numbers which mislead you into thinking that some other part of your program is broken. Because of some automatic conversion rules which we haven’t covered yet, you have a small amount of latitude in the types of the expressions you pass as arguments to printf(). The argument for %c may be of type char or int, and the argument for %d may be of type char or int. The string argument for %s may be a string constant, an array of characters, or a pointer to some characters. Finally, the arguments corresponding to %e, %f, and %g may be of types float or double. But other combinations do not work reliably: %d will not print a long int or a float or a double; %ld will not print an int; %e, %f, and %g will not print an int. Self Assessment Questions i) What is the output of the following statement: printf(”%d %o %xn”, 64, 10, 75); ii) To print an int argument in octal, you can use ___ format string iii) What is the output of the following program segment? int a=97; printf(”%c”, a); The gets() and puts() functions gets() and puts() functions facilitate the transfer of strings between the computer and the standard input/output devices. Each of these functions accepts a single argument. The argument must be a data item that represents a string( an array of characters). The string may include whitespace characters. In the case of gets(), the string will be entered from the keyboard, and will terminate with a newline character(i.e. a string will end when the user presses the RETURN key). Example: Reading and writing a line of text. #include<stdio.h> main() {
- 59. char line[80]; gets(line); puts(line); } This program uses gets() and puts() functions rather than scanf() and printf(), to transfer the line of text into and out of the computer. Self Assessment Questions i) State true or false: gets() is a formatted input statement. ii) The argument for a gets() and puts() functions are – variables iii) State true or false. Using gets() function, you can not include whitespace characters in the input string. Interactive Programming Creating interactive dialog between the computer and the user is a modern style of programming. These dialogs usually involve some form of question-answer interaction, where the computer asks the questions and the user provides the answer, or vice versa. In C, such dialogs can be created by alternate use of the scanf() and printf() functions. Program 5.3: Program to calculate the simple interest #include<stdio.h> main() { /* Sample interactive program*/ float principle, rate, time, interest; printf(“ Please enter the principle amount: “);
- 60. scanf(“%f”, &principle); printf(“ Please enter the rate of interest: “); scanf(“%f”, &rate); printf(“ Please enter the period of deposit: “); scanf(“%f”, &time); interest=principle*rate*time/100.0; printf(“Principle=%7.2fn”, principle); printf(“Rate of interest=%5.2fn”,rate); printf(“Period of deposit=%5.2fn”, time); printf(“Interest=%7.2fn”, interest); } Execute the above program and observe the result. Conclusion getchar(), putchar(), scanf(), printf(), gets() and puts() are the commonly used input/output functions in C. These functions are used to transfer of information between the computer and the standard input/output devices. getchar() and putchar() are the two functions to read and write single character. scanf() and printf() are the two formatted input/output functions. These functions can handle characters, numerical values and strings as well. gets() and puts() functions are used to handle strings. scanf(), printf(), gets() and puts() functions are used in interactive programming. Terminal Questions 1. What are the commonly used input/output functions in C? How are they accessed? 2. Distinguish between getchar() and putchar() functions? 3. When entering a string using scanf() function, how can a single string which includes whitespace characters be entered? 4. Distinguish between gets() and scanf() functions. 5. A C program contains the following statements:
- 61. #include<stdio.h> int i, j, k; Write an appropriate scanf() function to enter numerical values for i, j and k assuming a) The values for i, j and k will be decimal integers b) The value for i will be a decimal integer, j an octal integer and k a hexadecimal integer. c) The values for i and j will be hexadecimal integers and k will be an octal integer. Answers to Self Assessment Questions 5.1 i) False ii) EOF 5.2 i) The control string consists of control characters, whitespace characters, and non- whitespace characters. ii) %x iii) true 5.3 i) 64, 12, 4B ii) %o iii) a 5.4 i) False ii) String iii) False Answers for Terminal Questions 1. The commonly used input/output functions in C are : getchar(), putchar(), scanf(), printf(), gets() and puts(). These functions can be accessed within a program by including the header file stdio.h. 2. getchar() function is used to accept a single character from the keyboard and putchar() function is used to display single character on the user’s screen.
- 62. 3. By using control string %[ ]. 4. gets() is not the formatted input function but the scanf() function is a formatted input function. 5. a) scanf(“%d %d %d”, &i, &j, &k); b) scanf(“%d %o %x”, &i, &j, &k); c) scanf(“%x %x %o”, &i, &j, &k); Exercises 1. Write a program to print the factors of a given number. 2. Given the length of a side, write a C program to compute surface area and volume of a cube. 3. Write a program to reverse a number and find sum of the digits. 4. Write a program to print the multiplication table for any given number. 5. Write a program to check whether a given number is palindrome. Unit 6 Making Decisions in C • The Relational operators, The Logical operators, Bitwise operators, The increment and decrement operators, Precedence of operators, The GOTO statements, The IF statement, The IF ELSE statement, Nesting of IF statements, The conditional expression, The break statement, The switch statement. Introduction Statements are the “steps” of a program. Most statements compute and assign values or call functions, but we will eventually meet several other kinds of statements as well. By default, statements are executed in sequence, one after another. We can, however, modify that sequence by using control flow constructs such that a statement or group of statements is executed only if some condition is true or false. This involves a kind of decision making to see whether a particular condition has occurred or not and then direct the computer to execute certain statements accordingly.
- 63. C language possesses such decision making capabilities and supports the following statements known as the control or decision making statements. · if statement · switch statement · goto statement · conditional operator statement Objectives At the end of this unit, you will be able to: · Control the flow of execution of statements using two-way decision. · Control the flow of execution of statements using multipath decision. · Branch unconditionally from one point to another in the program. · Evaluate the conditional expressions. The goto statement C supports the goto statement to branch unconditionally from one point to another in the program. Although it may not be essential to use the goto statement in a highly structured language like C, there may be occasions when the use of goto might be desirable. The goto requires a label in order to identify the place where the branch is to be made. A label is any valid variable name, and must be followed by a colon. The label is placed immediately before the statement where the control is to be transferred. The general forms of goto and label statements are shown below: The label can be anywhere in the program either before the goto or after the goto label; statement. During execution of the program when a statement like goto first;
- 64. is met, the flow of control will jump to the statement immediately following the label first. This happens unconditionally. Note that a goto breaks the normal sequential execution of the program. If the label is before the statement goto label; a loop will be formed and some statements will be executed repeatedly. Such a jump is known as a backward jump. On the other hand , if the label is placed after the goto label; some statements will be skipped and the jump is known as the forward jump. A goto is often used at the end of a program to direct the control to go to the input statement, to read further data. Consider the following example: Program 6.1: Program showing unconditional branching main() { double a, b; read: printf(“enter the value of an”); scanf(“%f”, &a); if (a<0) goto read; b=sqrt(a); printf(“%f %f n”,a, b); goto read; } This program is written to evaluate the square root of a series of numbers read from the terminal. The program uses two goto statements, one at the end, after printing the results to transfer the control back to the input statements and the other to skip any further computation when the number is negative. Due to the unconditional goto statement at the end, the control is always transferred back to the input statement. In fact, this program puts the computer in a permanent loop known as an infinite loop. Self Assessment Questions
- 65. (i) The goto requires a _________ in order to identify the place where the branch is to be made. (ii) State true or false goto is an unconditional branching statement. The if statement The simplest way to modify the control flow of a program is with an if statement, which in its simplest form looks like this: if(x > max) max = x; Even if you didn’t know any C, it would probably be pretty obvious that what happens here is that if x is greater than max, x gets assigned to max. (We’d use code like this to keep track of the maximum value of x we’d seen–for each new x, we’d compare it to the old maximum value max, and if the new value was greater, we’d update max.) More generally, we can say that the syntax of an if statement is: if( expression ) statement where expression is any expression and statement is any statement. What if you have a series of statements, all of which should be executed together or not at all depending on whether some condition is true? The answer is that you enclose them in braces: if( expression ) { statemen 1; statement 2; statement n; }
- 66. As a general rule, anywhere the syntax of C calls for a statement, you may write a series of statements enclosed by braces. (You do not need to, and should not, put a semicolon after the closing brace, because the series of statements enclosed by braces is not itself a simple expression statement.) Program 6.2: Program to calculate the absolute value of an integer # include < stdio.h > void main ( ) { int number; printf (“Type a number:”); scanf (“%d”, & number); if (number < 0) /* check whether the number is a negative number */ number = – number; /* If it is negative then convert it into positive. */ printf (“The absolute value is % d n”, number); } Self Assessment Questions (i) State true or false The series of statements enclosed by braces after the expression in simple if statement is itself a simple expression statement. The if-else statement An if statement may also optionally contain a second statement, the “else clause,” which is to be executed if the condition is not met. Here is an example: if(n > 0) average = sum / n; else { printf(”can’t compute averagen”); average = 0; } The first statement or block of statements is executed if the condition is true, and the second statement or block of statements (following the keyword else) is executed if the condition is not true. In this example, we can compute a meaningful average only if n is
- 67. greater than 0; otherwise, we print a message saying that we cannot compute the average. The general syntax of an if statement is therefore if( expression ) statement(s) else statement(s) (if there are more than one statements, they should be enclosed within braces). Program 6.3: To find whether a number is negative or positive #include < stdio.h > void main ( ) { int num; printf (“Enter the number”); scanf (“%d”, &num); if (num < 0) printf (“The number is negative”) else printf (“The number is positive”); } Nesting of if statements It’s also possible to nest one if statement inside another. (For that matter, it’s in general possible to nest any kind of statement or control flow construct within another.) For example, here is a little piece of code which decides roughly which quadrant of the compass you’re walking into, based on an x value which is positive if you’re walking east, and a y value which is positive if you’re walking north: if(x > 0) { if(y > 0) printf("Northeast.n"); else printf("Southeast.n"); } else {
- 68. if(y > 0) printf("Northwest.n"); else printf("Southwest.n"); } When you have one if statement (or loop) nested inside another, it’s a very good idea to use explicit braces {}, as shown, to make it clear (both to you and to the compiler) how they’re nested and which else goes with which if. It’s also a good idea to indent the various levels, also as shown, to make the code more readable to humans. Why do both? You use indentation to make the code visually more readable to yourself and other humans, but the compiler doesn’t pay attention to the indentation (since all whitespace is essentially equivalent and is essentially ignored). Therefore, you also have to make sure that the punctuation is right. Here is an example of another common arrangement of if and else. Suppose we have a variable grade containing a student’s numeric grade, and we want to print out the corresponding letter grade. Here is the code that would do the job: if(grade >= 90) printf("A"); else if(grade >= 80) printf("B"); else if(grade >= 70) printf("C"); else if(grade >= 60) printf("D"); else printf("F"); What happens here is that exactly one of the five printf calls is executed, depending on which of the conditions is true. Each condition is tested in turn, and if one is true, the corresponding statement is executed, and the rest are skipped. If none of the conditions is true, we fall through to the last one, printing “F”. In the cascaded if/else/if/else/… chain, each else clause is another if statement. This may be more obvious at first if we reformat the example, including every set of braces and indenting each if statement relative to the previous one: if(grade >= 90) { printf("A"); } else { if(grade >= 80) { printf("B"); } else {
- 69. if(grade >= 70) { printf("C"); } else { if(grade >= 60) { printf("D"); } else { printf("F"); } } } } By examining the code this way, it should be obvious that exactly one of the printf calls is executed, and that whenever one of the conditions is found true, the remaining conditions do not need to be checked and none of the later statements within the chain will be executed. But once you’ve convinced yourself of this and learned to recognize the idiom, it’s generally preferable to arrange the statements as in the first example, without trying to indent each successive if statement one tabstop further out. 6.4 Program to print the largest of three numbers #include<stdio.h> main() { int a,b,c,big; printf (“Enter three numbers”); scanf (“%d %d %d”, &a, &b, &c); if (a>b) // check whether a is greater than b if true then if(a>c) // check whether a is greater than c big = a ; // assign a to big else big = c ; // assign c to big else if (b>c) // if the condition (a>b) fails check whether b is greater than c big = b ; // assign b to big
- 70. else big = c ; // assign C to big printf (“Largest of %d,%d&%d = %d”, a,b,c,big); } Self Assessment Questions (i) In the cascaded if/else/if/else/… chain, each else clause is another _______statement. The conditional expression The conditional operator (?:) takes three operands. It tests the result of the first operand and then evaluates one of the other two operands based on the result of the first. Consider the following example: E1 ? E2 : E3 If expression E1 is nonzero (true), then E2 is evaluated, and that is the value of the conditional expression. If E1 is 0 (false), E3 is evaluated, and that is the value of the conditional expression. Conditional expressions associate from right to left. In the following example, the conditional operator is used to get the minimum of x and y: a = (x < y) ? x : y; /* a= min(x, y) */ There is a sequence point after the first expression (E1). The following example’s result is predictable, and is not subject to unplanned side effects: i++ > j ? y[i] : x[i]; The conditional operator does not produce a lvalue. Therefore, a statement such as a ? x : y = 10 is not valid. Self Assessment Questions (i) State true or false The conditional operator does not produce a lvalue. The switch statement The switch case statements are a substitute for long if statements that compare a variable to several “integral” values (”integral” values are simply values that can be expressed as an integer, such as the value of a char). The basic format for using switch case is outlined below. The value of the variable given into switch is compared to the value
- 71. following each of the cases, and when one value matches the value of the variable, the computer continues executing the program from that point. switch ( <variable> ) { case this-value: Code to execute if <variable> == this-value break; case that-value: Code to execute if <variable> == that-value break; … default: Code to execute if <variable> does not equal the value following any of the cases break; } The condition of a switch statement is a value. The case says that if it has the value of whatever is after that case then do whatever follows the colon. The break is used to break out of the case statements. break is a keyword that breaks out of the code block, usually surrounded by braces, which it is in. In this case, break prevents the program from falling through and executing the code in all the other case statements. An important thing to note about the switch statement is that the case values may only be constant integral expressions. It isn’t legal to use case like this: int a = 10; int b = 10; int c = 20; switch ( a ) { case b: /* Code */
- 72. break; case c: /* Code */ break; default: /* Code */ break; } The default case is optional, but it is wise to include it as it handles any unexpected cases. It can be useful to put some kind of output to alert you to the code entering the default case if you don’t expect it to. Switch statements serve as a simple way to write long if statements when the requirements are met. Often it can be used to process input from a user. Example: Below is a sample program, in which not all of the proper functions are actually declared, but which shows how one would use switch in a program. #include <stdio.h> void playgame(); void loadgame(); void playmultiplayer(); int main() { int input; printf( “1. Play gamen” ); printf( “2. Load gamen” ); printf( “3. Play multiplayern” ); printf( “4. Exitn” );
- 73. printf( “Selection: ” ); scanf( “%d”, &input ); switch ( input ) { case 1: /* Note the colon, not a semicolon */ playgame(); break; case 2: loadgame(); break; case 3: playmultiplayer(); break; case 4: printf( “Thanks for playing!n” ); break; default: printf( “Bad input, quitting!n” ); break; } getchar(); } This program will compile, but cannot be run until the undefined functions are given bodies, but it serves as a model (albeit simple) for processing input. If you do not understand this then try mentally putting in if statements for the case statements. default simply skips out of the switch case construction and allows the program to terminate
- 74. naturally. If you do not like that, then you can make a loop around the whole thing to have it wait for valid input. You could easily make a few small functions if you wish to test the code. Self Assessment Questions i) The condition of a switch statement is a _______. ii) State true or false switch statement is an unconditional branching statement. Summary In C by default, statements are executed in sequence, one after another. We can, however, modify that sequence by using control flow constructs. C language possesses decision making capabilities and supports the following statements known as the control or decision making statements: goto, if, switch. The goto statement is used to branch unconditionally from one point to another in the program. The simplest way to modify the control flow of a program is with an if statement. switch statements serve as a simple way to write long if statements when the requirements are met. Terminal Questions 1. State whether true or false A switch expression can be of any type. 2. Consider the following program segment: x=1; y=1; if (n>0) x=x+1; y=y-1; printf(“%d %d”,x,y); What will be the values of x and y if n assumes a value of (a) 1 and (b) 0. 3. State whether true or false
- 75. A program stops its execution when a break statement is encountered. 4. Rewrite the following without using compound relation: if (grade<=59 && grade>=50) second = second +1; 5. Write a program to check whether an input number is odd or even. Answers to Self Assessment Questions 6.1 i) label ii) true 6.2 i) false 6.4 i) if 6.5 i) true 6.6 i) value ii) false Answers to Terminal Questions 1. false 2. (a) x=2, y=0 (b) x=1, y=0 3. false 4. if (grade<=59) if (grade>=50) second = second+1; 5. void main() {
- 76. int no; printf(“enter a numbern”); scanf(“%d”,&no); if (no%2==0) printf(“even numbern”); else printf(“odd numbern”); } Exercises 1. Explain different types of if statements with examples. 2. Explain the syntax of switch statement with an example. 3. Write a program to check whether a given number is odd or even using switch statement. 4. Write a program to find the smallest of 3 numbers using if-else statement. 5. Write a program to find the roots of a quadratic equation. Unit 7 Control Statements • The WHILE loop, The DO-WHILE loop, The break and continue statements, The for loop, Structure of a for loop, Nesting of for loops, Jumps in loops, Validating input. Introduction Loops generally consist of two parts: one or more control expressions which control the execution of the loop, and the body, which is the statement or set of statements which is executed over and over. The most basic loop in C is the while loop. A while loop has one conditional expression, and executes as long as that condition is true. As far as C is concerned, a true/false condition can be represented as an integer. (An integer can represent many values; here we care about only two values: “true” and
- 77. “false.” The study of mathematics involving only two values is called Boolean algebra, after George Boole, a mathematician who refined this study.) In C, “false” is represented by a value of 0 (zero), and “true” is represented by any value that is nonzero. Since there are many nonzero values (at least 65,534, for values of type int), when we have to pick a specific value for “true,” we’ll pick 1. Do…while loop is used in a situation where we need to execute the body of the loop before the test is performed. The for loop is used to execute the body of the loop for a specified number of times. The break statement is used to exit any loop. However, unlike break, the continue causes the control to go directly to the test-condition and then to continue the iteration process. Objectives At the end of this unit, you will be able to: · Repeat the execution of statements by checking the condition before the loop body is executed. · Repeat the execution of statements by checking the condition at the end of the loop. · Exit from the loop depending on some condition. · Break the current iteration and continue with next iteration of loop. The while loop Loops generally consist of two parts: one or more control expressions which control the execution of the loop, and the body, which is the statement or set of statements which is executed over and over. The most basic loop in C is the while loop. A while loop has one control expression, and executes as long as that expression is true. Here before executing the body of the loop, the condition is tested. Therefore it is called an entry-controlled loop. The following example repeatedly doubles the number 2 (2, 4, 8, 16, …) and prints the resulting numbers as long as they are less than 1000: int x = 2; while(x < 1000) { printf("%dn", x); x = x * 2; } (Once again, we’ve used braces {} to enclose the group of statements which are to be executed together as the body of the loop.)
- 78. The general syntax of a while loop is while( expression ) statement(s) A while loop starts out like an if statement: if the condition expressed by the expression is true, the statement is executed. However, after executing the statement, the condition is tested again, and if it’s still true, the statement is executed again. (Presumably, the condition depends on some value which is changed in the body of the loop.) As long as the condition remains true, the body of the loop is executed over and over again. (If the condition is false right at the start, the body of the loop is not executed at all.) As another example, if you wanted to print a number of blank lines, with the variable n holding the number of blank lines to be printed, you might use code like this: while(n > 0) { printf("n"); n = n - 1; } After the loop finishes (when control “falls out” of it, due to the condition being false), n will have the value 0. You use a while loop when you have a statement or group of statements which may have to be executed a number of times to complete their task. The controlling expression represents the condition “the loop is not done” or “there’s more work to do.” As long as the expression is true, the body of the loop is executed; presumably, it makes at least some progress at its task. When the expression becomes false, the task is done, and the rest of the program (beyond the loop) can proceed. When we think about a loop in this way, we can see an additional important property: if the expression evaluates to “false” before the very first trip through the loop, we make zero trips through the loop. In other words, if the task is already done (if there’s no work to do) the body of the loop is not executed at all. (It’s always a good idea to think about the “boundary conditions” in a piece of code, and to make sure that the code will work correctly when there is no work to do, or when there is a trivial task to do, such as sorting an array of one number. Experience has shown that bugs at boundary conditions are quite common.) Program 7.1 Program to find largest of n numbers main() { int num, large, n, i; clrscr();
- 79. printf(”enter number of numbers n”); scanf(“%d”,&n); large=0; i=0; while(i<n) { printf(”n enter number “); scanf(“%d”, &num); if(large<num) large=num; i++; } printf(”n large = %d”, large); } Program 7.2 Program to evaluate sine series sin(x)=x-x^3/3!+x^5/5!-x^7/7!+—– depending on accuracy # include<stdio.h> # include <math.h> void main() { int n, i=1,count; float acc, x, term, sum; printf(”enter the anglen”); scanf(“%d”, &x);
- 80. x=x*3.1416/180.0; printf(“nenter the accuracy)”; scanf(“%f”, &acc); sum=x; term=x; while ((fabs(term))>acc) { term=-term*x*x/((2*i)*(2*i+1)); sum+=term; i++; } printf”nsum of sine series is %f”, sum); } Self Assessment Questions i) A _______ loop starts out like an if statement . ii) State true or false while is an entry-controlled loop. do…while loop The do…while loop is used in a situation where we need to execute the body of the loop before the test is performed. Therefore, the body of the loop may not be executed at all if the condition is not satisfied at the very first attempt. Where as while loop makes a test of condition before the body of the loop is executed. For above reasons while loop is called an entry-controlled loop and do..while loop is called an exit-controlled loop. do while loop takes the following form:
- 81. do { Body of the loop } while ( expression); On reaching the do statement , the program proceeds to evaluate the body of the loop first. At the end of the loop, the conditional expression in the while statement is evaluated. If the expression is true, the program continues to evaluate the body of the loop once again. This process continues as long as the expression is true. When the expression becomes false, the loop will be terminated and the control goes to the statement that appears immediately after the while statement. On using the do loop, the body of the loop is always executed at least once irrespective of the expression. Program 7.3: A program to print the multiplication table from 1 x 1 to 10 x 10 as shown below using do-while loop. // Program to print multiplication table main() { int rowmax=10,colmax=10,row,col,x; printf(” Multiplication tablen”); printf(”………………………………..n”); row=1; do {
- 82. col=1; do { x=row*col; printf(“%4d”, x); col=col+1; } while (col<=colmax); printf(“n”);; row=row+1; } while(row<=rowmax); Printf(”…………………………………………………………………………………… …………n”); } Self Assessment Questions i) On using the ________, the body of the loop is always executed at least once irrespective of the expression. ii) State true or false do…while is an entry-controlled loop. The for loop The for loop is used to repeat the execution of set of statements for a fixed number of times. The for loop is also an entry-controlled loop. Generally, the syntax of a for loop is for(expr1; expr2; expr3) statement(s)
- 83. (Here we see that the for loop has three control expressions. As always, the statement can be a brace-enclosed block.) Many loops are set up to cause some variable to step through a range of values, or, more generally, to set up an initial condition and then modify some value to perform each succeeding loop as long as some condition is true. The three expressions in a for loop encapsulate these conditions: expr1 sets up the initial condition, expr 2 tests whether another trip through the loop should be taken, and expr3 increments or updates things after each trip through the loop and prior to the next one. Consider the following : for (i = 0; i < 10; i = i + 1) printf(”i is %dn”, i); In the above example, we had i = 0 as expr1, i < 10 as expr2 , i = i + 1 as expr3, and the call to printf as statement, the body of the loop. So the loop began by setting i to 0, proceeded as long as i was less than 10, printed out i’s value during each trip through the loop, and added 1 to i between each trip through the loop. When the compiler sees a for loop, first, expr1 is evaluated. Then, expr2 is evaluated, and if it is true, the body of the loop (statement) is executed. Then, expr3 is evaluated to go to the next step, and expr2 is evaluated again, to see if there is a next step. During the execution of a for loop, the sequence is: expr1 expr2 statement expr3 expr2 statement expr3 … expr2 statement expr3
- 84. expr2 The first thing executed is expr1. expr3 is evaluated after every trip through the loop. The last thing executed is always expr2, because when expr2 evaluates false, the loop exits. All three expressions of a for loop are optional. If you leave out expr1, there simply is no initialization step, and the variable(s) used with the loop had better have been initialized already. If you leave out expr2, there is no test, and the default for the for loop is that another trip through the loop should be taken (such that unless you break out of it some other way, the loop runs forever). If you leave out expr3, there is no increment step. The semicolons separate the three controlling expressions of a for loop. (These semicolons, by the way, have nothing to do with statement terminators.) If you leave out one or more of the expressions, the semicolons remain. Therefore, one way of writing a deliberately infinite loop in C is for(;;) … It’s also worth noting that a for loop can be used in more general ways than the simple, iterative examples we’ve seen so far. The “control variable” of a for loop does not have to be an integer, and it does not have to be incremented by an additive increment. It could be “incremented” by a multiplicative factor (1, 2, 4, 8, …) if that was what you needed, or it could be a floating-point variable, or it could be another type of variable which we haven’t met yet which would step, not over numeric values, but over the elements of an array or other data structure. Strictly speaking, a for loop doesn’t have to have a “control variable” at all; the three expressions can be anything, although the loop will make the most sense if they are related and together form the expected initialize, test, increment sequence. The powers-of-two example using for is: int x; for(x = 2; x < 1000; x = x * 2) printf(”%dn”, x); There is no earth-shaking or fundamental difference between the while and for loops. In fact, given the general for loop for(expr1; expr2; expr3) statement
- 85. you could usually rewrite it as a while loop, moving the initialize and increment expressions to statements before and within the loop: expr1; while(expr2) { statement expr3; } Similarly, given the general while loop while(expr) statement you could rewrite it as a for loop: for(; expr; ) statement Another contrast between the for and while loops is that although the test expression (expr2) is optional in a for loop, it is required in a while loop. If you leave out the controlling expression of a while loop, the compiler will complain about a syntax error. (To write a deliberately infinite while loop, you have to supply an expression which is always nonzero. The most obvious one would simply be while(1) .) If it’s possible to rewrite a for loop as a while loop and vice versa, why do they both exist? Which one should you choose? In general, when you choose a for loop, its three expressions should all manipulate the same variable or data structure, using the initialize, test, increment pattern. If they don’t manipulate the same variable or don’t follow that pattern, wedging them into a for loop buys nothing and a while loop would probably be clearer. (The reason that one loop or the other can be clearer is simply that, when you see a for loop, you expect to see an idiomatic initialize/test/increment of a single variable, and if the for loop you’re looking at doesn’t end up matching that pattern, you’ve been momentarily misled.) Program 7.4: A Program to find the factorial of a number void main()
- 86. { int M,N; long int F=1; clrscr(); printf(“enter the numbern”)”; scanf(“%d”,&N); if(N<=0) F=1; else { for(M=1;M<=N;M++) F*=M; } printf(“the factorial of the number is %ld”,F); getch(); } Self Assessment Questions i) State true or false for loop is an exit-controlled loop. ii) State true or false The “control variable” of a for loop does not have to be an integer. Nesting of for loops Nesting of for loops, that is, one for statement within another for statement, is allowed in C. For example, two loops can be nested as follows:
- 87. ……… ……… for(i=1;i<10;i++) { ……. ……. for(j=1;j<5;j++) { …… …… } ……. ……. } ……… ……… .5 The break statement The purpose of break statement is to break out of a loop(while, do while, or for loop) or a switch statement. When a break statement is encountered inside a loop, the loop is immediately exited and the program continues with the statement immediately following the loop. When the loops are nested , the break would only exit from the loop containing it. That is, the break would exit only a single loop. Syntax : break; Program 7.5: Program to illustrate the use of break statement. void main ( )
- 88. { int x; for (x=1; x<=10; x++) { if (x==5) break; /*break loop only if x==5 */ printf(“%d”, x); } printf (“nBroke out of loop”) printf( “at x =%d“); } The above program displays the numbers from 1to 4 and prints the message “Broke out of loop when 5 is encountered. The continue statement The continue statement is used to continue the next iteration of the loop by skipping a part of the body of the loop (for , do/while or while loops). The continue statement does not apply to a switch, like a break statement. Unlike the break which causes the loop to be terminated, the continue , causes the loop to be continued with the next iteration after skipping any statements in between. Syntax: continue; Program 7.6: Program to illustrate the use of continue statement. void main ( ) { int x; for (x=1; x<=10; x++) { if (x==5)
- 89. continue; /* skip remaining code in loop only if x == 5 */ printf (“%dn”, x); } printf(“nUsed continue to skip”); } The above program displays the numbers from 1to 10, except the number 5.. Program 7.7: Program to sum integers entered interactively #include <stdio.h> int main(void) { long num; long sum = 0L; /* initialize sum to zero */ int status; printf(”Please enter an integer to be summed. “); printf(”Enter q to quit.n”); status = scanf(”%ld”, &num); while (status == 1) { sum = sum + num; printf(”Please enter next integer to be summed. “); printf(”Enter q to quit.n”); status = scanf(”%ld”, &num);
- 90. } printf(”Those integers sum to %ld.n”, sum); return 0; } Summary The most basic loop in C is the while loop. A while loop has one control expression, and executes as long as that expression is true. do..while loop is used in a situation where we need to execute the body of the loop before the test is performed. The for loop is used to execute the set of statements repeatedly for a fixed number of times. It is an entry controlled loop. break statement is used to exit any loop. Unlike the break which causes the loop to be terminated, the continue , causes the loop to be continued with the next iteration after skipping any statements in between. Terminal Questions 1. State whether true or false A continue statement can be used with switch . 2. _______causes the loop to be continued with the next iteration after skipping any statements in between. 3. Write the output that will be generated by the following C program: void main() { int i=0, x=0; while (i<20) { if (i%5 == 0) { x+=i;
- 91. printf(“%dt”, i); } i++; } printf(“nx=%d”; x); } 4. Write the output that will be generated by the following C program: void main() { int i=0, x=0; do { if (i%5 == 0) { x++; printf(“%dt”, x); } ++i; } while (i<20); printf(“nx=%d”, x); } 5. State whether true or false A program stops its execution when a break statement is encountered.
- 92. Answers to Self Assessment Questions 7.1 i) while ii) true 7.2 i) do…while ii) false 7.3 i) false ii) true Answers to Terminal Questions 1. false 2. continue 3. 0 5 10 15 x = 30 4. 1 2 3 4 x=4 5. false Exercises 1. compare the following statements a) while and do…while b) break and continue 2. Write a program to compute the sum of digits of a given number using while loop. 3. Write a program that will read a positive integer and determine and print its binary equivalent using do…while loop. 4. The numbers in the sequence 1 1 2 3 5 8 13 ………..
- 93. are called Fibonacci numbers. Write a program using do…while loop to calculate and print the first n Fibonacci numbers. 5. Find errors, if any, in each of the following segments. Assume that all the variables have been declared and assigned values. (a) while (count !=10); { count = 1; sum = sum + x; count = count + 1; } (b) do; total = total + value; scanf(“%f”, &value); while (value ! =999); 6. Write programs to print the following outputs using for loops. 7. Write a program to read the age of 100 persons and count the number of persons in the age group 50 to 60. Use for and continue statements 8. Write a program to print the multiplication table using nested for loops. Unit 8 Functions
- 94. • Introduction, Function Basics, The form of C functions, Returning value from a function, Function prototypes, Parameters, Declaring the type of a function, Recursion, The Function philosophy. Introduction A function is a “black box” that we’ve locked part of our program into. The idea behind a function is that it compartmentalizes part of the program, and in particular, that the code within the function has some useful properties: It performs some well-defined task, which will be useful to other parts of the program. It might be useful to other programs as well; that is, we might be able to reuse it (and without having to rewrite it). The rest of the program doesn’t have to know the details of how the function is implemented. This can make the rest of the program easier to think about. The function performs its task well. It may be written to do a little more than is required by the first program that calls it, with the anticipation that the calling program (or some other program) may later need the extra functionality or improved performance. (It’s important that a finished function do its job well, otherwise there might be a reluctance to call it, and it therefore might not achieve the goal of reusability.) By placing the code to perform the useful task into a function, and simply calling the function in the other parts of the program where the task must be performed, the rest of the program becomes clearer: rather than having some large, complicated, difficult-to- understand piece of code repeated wherever the task is being performed, we have a single simple function call, and the name of the function reminds us which task is being performed. Since the rest of the program doesn’t have to know the details of how the function is implemented, the rest of the program doesn’t care if the function is reimplemented later, in some different way (as long as it continues to perform its same task, of course!). This means that one part of the program can be rewritten, to improve performance or add a new feature (or simply to fix a bug), without having to rewrite the rest of the program. Functions are probably the most important weapon in our battle against software complexity. You’ll want to learn when it’s appropriate to break processing out into functions (and also when it’s not), and how to set up function interfaces to best achieve the qualities mentioned above: reusability, information hiding, clarity, and maintainability. Objectives
- 95. At the end of this unit you will be able to understand: · The importance of functions · Concepts of formal arguments and actual arguments · Function declaration(function prototypes) and function definition · The concept of recursion · How the concept of functions reduces software complexity Function Basics A function is a self-contained program segment that carries out some specific, well- defined task. Every C program contains one or more functions. One of these functions must be called main. Program execution will always begin by carrying out the instructions in main. Additional functions will be subordinate to main, and perhaps to one another. So what defines a function? It has a name that you call it by, and a list of zero or more arguments or parameters. Parameters(also called formal parameters) or arguments are the special identifiers through which information can be passed to the function. A function has a body containing the actual instructions (statements) for carrying out the task the function is supposed to perform; and it may give you back a return value, of a particular type. In general terms, the first line can be written as data-type name(data-type parameter 1, data-type parameter 2, …, data-type parameter n) Example 8.1: Here is a very simple function, which accepts one argument, multiplies it by 4, and hands that value back. int multbyfour(int x) { int retval; retval = x * 4; return retval; }
- 96. On the first line we see the return type of the function (int), the name of the function (multbyfour), and a list of the function’s arguments, enclosed in parentheses. Each argument has both a name and a type; multbyfour accepts one argument, of type int, named x. The name x is arbitrary, and is used only within the definition of multbyfour. The caller of this function only needs to know that a single argument of type int is expected; the caller does not need to know what name the function will use internally to refer to that argument. (In particular, the caller does not have to pass the value of a variable named x.) Next we see, surrounded by the familiar braces, the body of the function itself. This function consists of one declaration (of a local variable retval) and two statements. The first statement is a conventional expression statement, which computes and assigns a value to retval, and the second statement is a return statement, which causes the function to return to its caller, and also specifies the value which the function returns to its caller. In general term, a return statement is written as return expression The return statement can return the value of any expression, so we don’t really need the local retval variable; this function can also be written as int multbyfour(int x) { return x * 4; } How do we call a function? We’ve been doing so informally since day one, but now we have a chance to call one that we’ve written, in full detail. The arguments in the function call are referred to as actual arguments or actual parameters, in contrast to the formal arguments that appear in the first line of the function definition. Here is a tiny skeletal program to call multbyfour: #include <stdio.h> extern int multbyfour(int); int main() { int i, j;
- 97. i = 5; j = multbyfour(i); printf(”%dn”, j); return 0; } This looks much like our other test programs, with the exception of the new line extern int multbyfour(int); This is an external function prototype declaration. It is an external declaration, in that it declares something which is defined somewhere else. (We’ve already seen the defining instance of the function multbyfour, but may be the compiler hasn’t seen it yet.) The function prototype declaration contains the three pieces of information about the function that a caller needs to know: the function’s name, return type, and argument type(s). Since we don’t care what name the multbyfour function will use to refer to its first argument, we don’t need to mention it. (On the other hand, if a function takes several arguments, giving them names in the prototype may make it easier to remember which is which, so names may optionally be used in function prototype declarations.) Finally, to remind us that this is an external declaration and not a defining instance, the prototype is preceded by the keyword extern. The presence of the function prototype declaration lets the compiler know that we intend to call this function, multbyfour. The information in the prototype lets the compiler generate the correct code for calling the function, and also enables the compiler to check up on our code (by making sure, for example, that we pass the correct number of arguments to each function we call). Down in the body of main, the action of the function call should be obvious: the line j = multbyfour(i); calls B, passing it the value of i as its argument. When multbyfour returns, the return value is assigned to the variable j. (Notice that the value of main’s local variable i will become the value of multbyfour’s parameter x; this is absolutely not a problem, and is a normal sort of affair.) This example is written out in “longhand,” to make each step equivalent. The variable i isn’t really needed, since we could just as well call j = multbyfour(5);
- 98. And the variable j isn’t really needed, either, since we could just as well call printf(”%dn”, multbyfour(5)); Here, the call to multbyfour is a subexpression which serves as the second argument to printf. The value returned by multbyfour is passed immediately to printf. (Here, as in general, we see the flexibility and generality of expressions in C. An argument passed to a function may be an arbitrarily complex subexpression, and a function call is itself an expression which may be embedded as a subexpression within arbitrarily complicated surrounding expressions.) We should say a little more about the mechanism by which an argument is passed down from a caller into a function. Formally, C is call by value, which means that a function receives copies of the values of its arguments. We can illustrate this with an example. Suppose, in our implementation of multbyfour, we had gotten rid of the unnecessary retval variable like this: int multbyfour(int x) { x = x * 4; return x; } We might wonder, if we wrote it this way, what would happen to the value of the variable i when we called j = multbyfour(i); When our implementation of multbyfour changes the value of x, does that change the value of i up in the caller? The answer is no. x receives a copy of i’s value, so when we change x we don’t change i. However, there is an exception to this rule. When the argument you pass to a function is not a single variable, but is rather an array, the function does not receive a copy of the array, and it therefore can modify the array in the caller. The reason is that it might be too expensive to copy the entire array, and furthermore, it can be useful for the function to write into the caller’s array, as a way of handing back more data than would fit in the function’s single return value. We will discuss more about passing arrays as arguments to a function later. There may be several different calls to the same function from various places within a program. The actual arguments may differ from one function call to another. Within each
- 99. function call, however, the actual arguments must correspond to the formal arguments in the function definition; i.e the actual arguments must match in number and type with the corresponding formal arguments. Program 8.1: A program to find the largest of three integers #include<stdio.h> main() { int x, y, z, w; /* read the integers */ int max(int, int); printf(“nx= “); scanf(“%d”, &x); printf(“ny= “); scanf(“%d”, &y); printf(“nz= “); scanf(“%d”, &z); /* Calculate and display the maximum value */ w= max(x,y); printf(“nnmaximum=%dn”, max(z,w)); } int max(int a, int b) { int c; c=(a>=b)?a:b;
- 100. return c; } Please execute this program and observe the result. Function calls can span several levels within a program; function A can call function B, which can call function C and so on. Program 8.2: Program to check whether a given integer is a perfect square or not. #include<stdio.h> main() { int psquare(int); int num; printf(“ Enter the number:”); scanf(“%d”, &num); if(psquare(num)) /* main() calls the function psquare() */ { printf(“%d is a perfect squaren”); else printf(“%d is not a perfect squaren”); } } int psquare(int x) { int positive(int); float sqr;
- 101. if(positive(x)) /* psquare() in turn calls the function positive() */ { sqr=sqrt(x)); if(sqr-int(sqr))==0) return 1; else return 0; } int positive(int m) { if(m>0) return 1; else return 0; } Execute the above program and observe the result. In the above program the main function calls the function psquare() and it in turn calls the function positive() to check whether the number to be checked for perfect square is a positive or not before checking. The return statement can be absent altogether from a function definition, though this is generally regarded as a poor programming practice. If a function reaches end of the block without encountering a return statement, control simply reverts back to the calling portion of the program without returning any information. Using an empty return statement(without the accompanying expressions) is recommended. Example 8.2: The following function accepts two integers and determines the larger one, which is then written out. The function doesn’t return any information to the calling program. void max(int x, int y)
- 102. { int m; m=(x>=y)?x:y; printf(“ The larger integer is=%dn”, m); return; } Self Assessment Questions i) State true or false The function main() is optional in a C program. ii) What is the significance of the keyword ‘extern’ in a function declaration? iii) What is the difference between formal arguments and actual arguments? iv) What are the different components in the first line of a function definition? v) What is the output of the following program? #include<stdio.h> main() { int m, count; int fun(int count); for(count=1;count<=10;count++) { m=fun(count); printf(“%d”, m); } }
- 103. int fun(int n) { int x; x= n*n; return x; } Function Prototypes In modern C programming, it is considered good practice to use prototype declarations for all functions that you call. As we mentioned, these prototypes help to ensure that the compiler can generate correct code for calling the functions, as well as allowing the compiler to catch certain mistakes you might make. In general terms, a function prototype can be written as data-type name(type1, type2, …, type n) Examples: int sample(int, int) or int sample(int a, int b); float fun(int, float) or float fun( int a, float b); void demo(void); Here void indicates function neither return any value to the caller nor it has any arguments. If you write the function definition after the definition of its caller function, then the prototype is required in the caller, but the prototype is optional if you write the definition of the function before the definition of the caller function. But it is good programming practice to include the function prototype wherever it is defined. If prototypes are a good idea, and if we’re going to get in the habit of writing function prototype declarations for functions we call that we’ve written (such as multbyfour), what happens for library functions such as printf? Where are their prototypes? The answer is in that boilerplate line #include <stdio.h> we’ve been including at the top of all of our programs. stdio.h is conceptually a file full of external declarations and other information pertaining to the “Standard I/O” library
- 104. functions, including printf. The #include directive arranges all of the declarations within stdio.h that are considered by the compiler, rather as if we’d typed them all in ourselves. Somewhere within these declarations is an external function prototype declaration for printf, which satisfies the rule that there should be a prototype for each function we call. (For other standard library functions we call, there will be other “header files” to include.) Finally, one more thing about external function prototype declarations: we’ve said that the distinction between external declarations and defining instances of normal variables hinges on the presence or absence of the keyword extern. The situation is a little bit different for functions. The “defining instance” of a function is the function, including its body (that is, the brace-enclosed list of declarations and statements implementing the function). An external declaration of a function, even without the keyword extern, looks nothing like a function declaration. Therefore, the keyword extern is optional in function prototype declarations. If you wish, you can write int multbyfour(int); and this is just like an external function prototype declaration as extern int multbyfour(int); (In the first form, without the extern, as soon as the compiler sees the semicolon, it knows it’s not going to see a function body, so the declaration can’t be a definition.) You may want to stay in the habit of using extern in all external declarations, including function declarations, since “extern = external declaration” is an easier rule to remember. Program 8.3: Program to illustrate that the function prototype is optional in the caller function. The program is to convert a character from lowercase to uppercase. #include<stdio.h> char lower_to_upper(char ch) /* Function definition precedes main()*/ { char c; c=(ch>=’a’ && ch<=’z’) ? (‘A’+ch-‘a’):ch; return c; } main() {
- 105. char lower, upper; /* char lower_to_upper(char lower); */ /* Function prototype is optional here*/ printf(“Please enter a lowercase character:”); scanf(“%c”, &lower); upper=lower_to_upper(lower); printf(“nThe uppercase equivalent of %c is %cn”, lower, upper); } Self Assessment Questions i) Function prototype is also called ________ ii) State true or false. The function prototypes are optional. iii) Where are the function prototypes of the library functions? iv) Add the function prototype for the function fun() called in main() below. main() { double x, y, z; … z=fun(x, y); … } Recursion Recursion is a process by which a function calls itself repeatedly, until some specified condition has been met. The process is used for repetitive computations in which each action is stated in terms of a previous result. Many repetitive problems can be written in this form.
- 106. In order to solve a problem recursively, two conditions must be satisfied. First, the problem must be written in a recursive form, and the second, the problem statement must include a stopping condition. Example 8.3: Factorial of a number. Suppose we wish to calculate the factorial of a positive integer, n. We would normally express this problem as n!=1 x 2 x 3 x … x n. This can also be written as n!=n x (n-1)!. This is the recursive statement of the problem in which the desired action(the calculation of n!) is expressed in terms of a previous result (the value of (n-1)! which is assumed to be known). Also, we know that 0!=1 by definition. This expression provides stopping condition for the recursion. Thus the recursive definition for finding factorial of positive integer n can be written as: fact(n)={ 1 if n=0 n x fact(n-1) otherwise} Program 8.4: Program to find factorial of a given positive integer #include<stdio.h> main() { int n; long int fact(int); /* Read in the integer quantity*/ scanf(“%d”, &n); /*calaculate and display the factorial*/ printf(“n!=%ldn”, fact(n)); } long int fact(int n) { if(n==0)
- 107. return(1); else return (n*fact(n-1)); } Please execute this program and observe the result. Example 8.4: The Towers of Hanoi. The Towers of Hanoi is a game played with three poles and a number of different sized disks. Each disk has a hole in the center, allowing it to be stacked around any of the poles. Initially, the disks are stacked on the leftmost pole in the order of decreasing size, i.e, the largest on the bottom, and the smallest on the top as illustrated in Figure 8.1. Figure 8.1 The aim of the game is to transfer the disks from the leftmost pole to the rightmost pole, without ever placing a larger disk on top of a smaller disk. Only one disk may be moved at a time, and each disk must always be placed around one of the poles. The general strategy is to consider one of the poles to be the origin, and another to be the destination. The third pole will be used for intermediate storage, thus allowing the disks to be moved without placing a larger disk over a smaller one. Assume there are n disks, numbered from smallest to largest as in Figure 8.1. If the disks are initially stacked on the left pole, the problem of moving all n disks to the right pole can be stated in the following recursive manner: 1. Move the top n-1 disks from the left pole to the center pole. 2. Move the nth disk( the largest disk) to the right pole. 3. Move the n-1 disks on the center pole to the right pole. The problem can be solved for any value of n greater than 0(n=0 represents a stopping condition).
- 108. In order to program this game, we first label the poles, so that the left pole is represented as L, the center pole as C and the right pole as R. Let us refer the individual poles with the char-type variables from, to and temp for the origin, destination and temporary storage respectively. Program 8.5: Recursive Program to solve Towers of Hanoi problem. #include<stdio.h> main() { void Recursive_Hanoi(int, char, char, char); int n; printf(“ Towers of Hanoinn”); printf(“ How many disks?”); scanf(“%d”, &n); printf(“n”); Recusrive_Hanoi(n, ‘L’, ‘R’, ‘C’); } void Recursive_Hanoi(int n, char from, char to, char temp) { /* Transfer n disks from one pole to another */ /* n= number of disks from=origin to=destination temp=temporary storage */ { if(n>0){
- 109. /* move n-1 disks from origin to temporary */ Recursive_Hanoi(n-1, from, temp, to); /* move nth disk from origin to destination */ printf(“ Move disk %d from %c to %cn”, n, from, to); /* move n-1 disks from temporary to destination */ Recursive_Hanoi(n-1, temp, to, from); } return; } Please execute this program and observe the result Self Assessment Questions i) What is meant by recursion? ii) State true or false A stopping condition must be there in a recursive definition. iii) What is the output of the following program? #include<stdio.h> main() { int n=5; int fun(int n); printf(“%dn”, fun(n)); } int fun(int n)
- 110. { if(n==0) return 0; else return (n+fun(n-1)); } Function Philosophy What makes a good function? The most important aspect of a good “building block” is that have a single, well-defined task to perform. When you find that a program is hard to manage, it’s often because it has not been designed and broken up into functions cleanly. Two obvious reasons for moving code down into a function are because: 1. It appeared in the main program several times, such that by making it a function, it can be written just once, and the several places where it used to appear can be replaced with calls to the new function. 2. The main program was getting too big, so it could be made (presumably) smaller and more manageable by lopping part of it off and making it a function. These two reasons are important, and they represent significant benefits of well-chosen functions, but they are not sufficient to automatically identify a good function. As we’ve been suggesting, a good function has at least these two additional attributes: 3. It does just one well-defined task, and does it well. 4. Its interface to the rest of the program is clean and narrow. Attribute 3 is just a restatement of two things we said above. Attribute 4 says that you shouldn’t have to keep track of too many things when calling a function. If you know what a function is supposed to do, and if its task is simple and well-defined, there should be just a few pieces of information you have to give it to act upon, and one or just a few pieces of information which it returns to you when it’s done. If you find yourself having to pass lots and lots of information to a function, or remember details of its internal implementation to make sure that it will work properly this time, it’s often a sign that the function is not sufficiently well-defined. (A poorly-defined function may be an arbitrary chunk of code that was ripped out of a main program that was getting too big, such that it essentially has to have access to all of that main function’s local variables.)
- 111. The whole point of breaking a program up into functions is so that you don’t have to think about the entire program at once; ideally, you can think about just one function at a time. We say that a good function is a “black box,” which is supposed to suggest that the “container” it’s in is opaque – callers can’t see inside it (and the function inside can’t see out). When you call a function, you only have to know what it does, not how it does it. When you’re writing a function, you only have to know what it’s supposed to do, and you don’t have to know why or under what circumstances its caller will be calling it. (When designing a function, we should perhaps think about the callers just enough to ensure that the function we’re designing will be easy to call, and that we aren’t accidentally setting things up so that callers will have to think about any internal details.) Some functions may be hard to write (if they have a hard job to do, or if it’s hard to make them do it truly well), but that difficulty should be compartmentalized along with the function itself. Once you’ve written a “hard” function, you should be able to sit back and relax and watch it do that hard work on call from the rest of your program. It should be pleasant to notice (in the ideal case) how much easier the rest of the program is to write, now that the hard work can be deferred to this workhorse function. (In fact, if a difficult-to-write function’s interface is well-defined, you may be able to get away with writing a quick-and-dirty version of the function first, so that you can begin testing the rest of the program, and then go back later and rewrite the function to do the hard parts. As long as the function’s original interface anticipated the hard parts, you won’t have to rewrite the rest of the program when you fix the function.) The functions are important for far more important reasons than just saving typing. Sometimes, we’ll write a function which we only call once, just because breaking it out into a function makes things clearer and easier. If you find that difficulties pervade a program, that the hard parts can’t be buried inside black-box functions and then forgotten about; if you find that there are hard parts which involve complicated interactions among multiple functions, then the program probably needs redesigning. For the purposes of explanation, we’ve been seeming to talk so far only about “main programs” and the functions they call and the rationale behind moving some piece of code down out of a “main program” into a function. But in reality, there’s obviously no need to restrict ourselves to a two-tier scheme. Any function we find ourselves writing will often be appropriately written in terms of sub-functions, sub-sub-functions, etc. Program 8.6: Program to create a function that types 65 asterisks in a row /* letterhead1.c */ #include <stdio.h> #define NAME “MEGATHINK, INC.”
- 112. #define ADDRESS “10 Megabuck Plaza” #define PLACE “Megapolis, CA 94904″ #define LIMIT 65 void starbar(void); /* prototype the function */ int main(void) { starbar(); printf(”%sn”, NAME); printf(”%sn”, ADDRESS); printf(”%sn”, PLACE); starbar(); /* use the function */ return 0; } void starbar(void) /* define the function */ { int count; for (count = 1; count <= LIMIT; count++) putchar(’*'); putchar(’n’); } Self Assessment Questions i) How the concept of function reduces software complexity? ii) State true or false.
- 113. The main purpose of function is to save typing time. Conclusion A function is a self-contained program segment that carries out some specific, well- defined task. When you find that a program is hard to manage, it’s often because it has not been designed and broken up into functions cleanly. A function is a “black box” that we’ve locked part of our program into. The idea behind a function is that it compartmentalizes part of the program. The function main() is must in every C program. The function prototype is nothing but the function declaration. Recursion is a process by which a function calls itself repeatedly, until some specified condition has been met. Terminal Questions 1. What is the significance of the keyword ‘void’? 2. What is the difference between function declaration and function definition? 3. Write a recursive function to find sum of even numbers from 2 to 10. 4. Write a recursive definition to find gcd of two numbers. 5. Write a recursive definition to find nth fibonacci number. The Fibonacci series forms a sequence of numbers in which each number is equal to the sum of the previous two numbers. In other words, Fi=Fi-1 + Fi-2 where Fi refers to the ith Fibonacci number. The first two Fibonacci numbers are 0 and 1, i.e, F1=0, F2=1; Answers for Self Assessment Questions 8.1 I) False ii) If the function is defined elsewhere(not in the same program where it is called), the function prototype must be preceded by the keyword ‘extern’. iii) The arguments that appear in function definition are called formal arguments whereas the arguments that appear when the function is called are the actual arguments. iv) The return data type, function name and the list of formal parameters enclosed in brackets separated by comma. V) Square of the integers from 1 to 10 are displayed.
- 114. 8.2 i) Function declaration ii) False iii) In the corresponding header files iv) double fun(double, double); 8.3 I) Recursion is a process by which a function calls itself repeatedly, until some specified condition is satisfied. ii) True iii) 15 8.1 i) By modularizing the problem into different sub problems. Each subproblem can be implemented as a function. ii) False Answers for Terminal Questions 1. ‘void’ is the keyword used to specify that the function doesn’t return any value. It can also be used to specify the absence of arguments. 2. Function declaration is a direction to the compiler that what type of data is returned by the function, the function name and about the arguments where as the function definition is actually writing the body of the function along with the function header. 3. #include<stdio.h> main() { int n=10; int fun(int n); printf(“%d”, fun(n)); } int fun(int n) {
- 115. if(n>0) return (n+fun(n-2)); } 4. gcd(m,n)= { m or n if m=n GCD(m, m-n) if m>n GCD(n,m) if m<n } 5. fib(i)= { 0 if i=1 1 if i=2 fib(i-1)+fib(i-2) otherwise} Exercises 1. Suppose function F1 calls function F2 within a C program. Does the order of function definitions make any difference? Explain. 2. When a program containing recursive function calls is executed, how are the local variables within the recursive function interpreted? 3. Express the following algebraic formula in a recursive form: Y = (x1+x2+…+xn) 4. Write a function that will allow a floating point number to be raised to an integer power. 5. Write a function to swap two numbers using pass by value technique. What is the drawback of the function? Unit 9 Storage Classes • Introduction, Automatic variables, Static variables, Global variables, External variables Introduction
- 116. Variables are channels of communication within a program. You set a variable to a value at one point in a program, and at another point (or points) you read the value out again. The two points may be in adjoining statements, or they may be in widely separated parts of the program. How long does a variable last? How widely separated can the setting and fetching parts of the program be, and how long after a variable is set does it persist? Depending on the variable and how you’re using it, you might want different answers to these questions. For example, in some situations it may be desirable to introduce certain “global” variables that are recognized throughout the entire program( or within major portions of the program, e.g two or more functions). Such variables are defined differently than the usual “local” variables, which are recognized only within a single function. We will also consider the issue of static variables which can retain their values, so that the function can be reentered later and the computation resumed. Finally, we may be required to develop a large, multifunction program in terms of several independent files, with few functions defined within each file. In such programs, the individual functions can be defined and accessed locally within a single file, or globally within multiple files. Objectives After completing this Unit, students will be able to · Understand the concept of storage classes and visibility of variables · Understand the difference between automatic variables, global variables, static variables and external variables. · Compile and execute a program made up of more than one source files. Storage Classes and Visibility There are two ways to categorize variables: by data type, and by storage class. Data type refers to the type of information represented by a variable, for example, integer number, floating-point number, character etc. Storage class refers to the persistence of a variable and its scope within the program, that is, the portion of the program over which the variable is recognized. The following types of storage-class specifications in C are discussed in this unit: global, automatic or local, static, and extern. The exact procedure for establishing a storage class for a variable depends upon the particular storage class, and the manner in which the program is organized, (i.e single file vs. multiple file).
- 117. The visibility of a variable determines how much of the rest of the program can access that variable. You can arrange that a variable is visible only within one part of one function, or in one function, or in one source file, or anywhere in the program. Why would you want to limit the visibility of a variable? For maximum flexibility, wouldn’t it be handy if all variables were potentially visible everywhere? As it happens, that arrangement would be too flexible: everywhere in a program, you would have to keep track of the names of all the variables declared anywhere else in the program, so that you didn’t accidentally re-use one. Whenever a variable had the wrong value by mistake, you’d have to search the entire program for the bug, because any statement in the entire program could potentially have modified that variable. You would constantly be stepping all over yourself by using a common variable name like i in two parts of your program, and having one snippet of code accidentally overwrite the values being used by another part of the code. Self Assessment Questions i) What is meant by visibility? ii) What is a storage class? iii) State true or false. Visibility provides security for your data used in a program. Automatic or local variables A variable declared within the braces {} of a function is visible only within that function; variables declared within functions are called local variables. Their scope is confined to that function. You can use the keyword auto to declare automatic variables, but, however it is optional. If another function somewhere else declares a local variable with the same name, it’s a different variable entirely, and the two don’t clash with each other. If an automatic variable is not initialized in some manner, however, its initial value will be unpredictable and contains some garbage value. Program 9.1: Program to find factorial of a number #include<stdio.h> main() { auto int n; /* Here the keyword auto is optional */ long int fact(int);
- 118. printf(“read the integer n:”); scanf(“%d”, &n); printf(“nn!=%ld”, fact(n) ); } long int fact(auto int n) /* n is local to the function fact() and auto is optional*/ { auto int i; /* Here the keyword auto is optional */ auto long int factorial=1; /* Here the keyword auto is optional */ while(n>0) { factorial=factorial*n; n=n-1; } return factorial; } An automatic variable doesn’t retain its value once control is transferred out of its defining function. Therefore, any value assigned to an automatic variable within a function will be lost once the function is exited. Self Assessment Questions i) What is the scope of an automatic variable? ii) Does an automatic variable retain its value once control is transferred out of its defining function? iii) State true or false. The key word auto is must in the declaration of automatic variables. Global Variables
- 119. A variable declared outside of any function is a global variable, and it is potentially visible anywhere within the program. You use global variables when you do want to use the variable in any part of the program. When you declare a global variable, you will usually give it a longer, more descriptive name (not something generic like i) so that whenever you use it you will remember that it’s the same variable everywhere. The values stored in global variables persist, for as long as the program does. (Of course, the values can in general still be overwritten, so they don’t necessarily persist forever.) Program 9.2: Program to find average length of several lines of text #include<stdio.h> /* Declare global variables outside of all the functions*/ int sum=0; /* total number of characters */ int lines=0; /* total number of lines */ main() { int n; /* number of characters in given line */ float avg; /* average number of characters per line */ void linecount(void); /* function declaraction */ float cal_avg(void); printf(“Enter the text below:n”); while((n=linecount())>0) { sum+=n; ++lines; } avg=cal_avg(); printf(“nAverage number of characters per line: %5.2f”, avg); }
- 120. void linecount(void) { /* read a line of text and count the number of characters */ char line[80]; int count=0; while((line[count]=getchar())!=’n’) ++count; return count; } float cal_avg(void) { /* compute average and return*/ return (float)sum/lines; } In the above program the variables sum and lines are globally declared and hence they could be used in both the functions main() and cal_avg() Self Assessment Questions i) State true or false. The variables declared in the main() function are the global variables. ii) State true or false. The global variables are more secured than the automatic variables in a program. Static Variables
- 121. Static variables are defined within individual functions and therefore have the same scope as automatic variables, i.e. they are local to the functions in which they are declared. Unlike automatic variables, however, static variables retain their values throughout the life of the program. As a result, if a function is exited and then reentered later, the static variables defined within that function will retain their previous values. This feature allows functions to retain information permanently throughout the execution of a program. Static variables can be utilized within the function in the same manner as other variables. They cannot be accessed outside of their defining function. In order to declare a static variable the keyword static is used as shown below: static int count; You can define automatic or static variables having the same name as global variables. In such situations the local variables will take precedence over the global variables, though the values of global variables will be unaffected by any manipulation of the local variables. Initial values can be included in static variable declaration. The rules associated with the initialization remain same as the initialization of automatic or global variables. They are: 1. The initial values must be constants, not expressions. 2. The initial values are assigned to their respective variables at the beginning of the program execution. The variables retain these values throughout the life of the program, unless different values are assigned during the course of computation. 3. Zeros will be assigned to all static variables whose declarations do not include explicit initial values. Program 9.3: Program to generate Fibonacci numbers. #include<stdio.h> main() { int count, n; long int fib(int); printf(“n How many Fibonacci numbers?”); scanf(“%dn”, &n);
- 122. for(count=1;count<=n;count++) { printf(“ni=%d F=%ld”, count, fib(count)); } long int fib(int count) { /* calculate a Fibonacci number using the formula if i=1, F=0; if i=2, F=1, and F=F1+F2 for i>=3 */ static long int f1=0, f2=1; /* declaration of static variables */ long int f; if (count==1) f=0; else if (count==2) f=1; else f=f1+f2; f2=f1; f1=f; /* f1 and f2 retain their values between different calls of the function*/ return f; } Self Assessment Questions i) State true or false. The scope of static variables and automatic variables is the same.
- 123. ii) What is the main feature of a static variable? iii) By default, a static variable is initialized to _______ External Variables It is possible to split a function up into several source files, for easier maintenance. When several source files are combined into one program the compiler must have a way of correlating the variables which might be used to communicate between the several source files. Furthermore, if a variable is going to be useful for communication, there must be exactly one of it: you wouldn’t want one function in one source file to store a value in one variable named externvar, and then have another function in another source file read from a different variable named externvar. Therefore, a variable should have exactly one defining instance, in one place in one source file. If the same variable is to be used anywhere else (i.e. in some other source file or files), the variable is declared in those other file(s) with an external declaration, which is not a defining instance. The external declaration says the compiler that the variable will be used in this source file but defined in some other source file. Thus the compiler doesn’t allocate space for that variable with this source file. To make a variable as an external declaration, which is defined somewhere else, you precede it with the keyword extern: extern int j; Program 9.4: Program to illustrate the concept of external variables. Type and save the following program in a source file called externvariables.h int principle=10000; float rate=5.5; int time=2; float interest; Type and save the following program in a separate source file called demoexternvar.c #include<stdio.h> #include “externvariables.h” /* the source file where the external variables are defined should be included here.*/ main()
- 124. { /* external declarations of the variables which are defined in externvariables.h */ extern int principle; extern float rate; extern int time; extern float interest; /*compute interest*/ interest= principle*rate*time/100.0; printf(“Interest=%fn”, interest); } Compile demoexternvar.c and execute the program. The concept of external storage class can be extended to functions also. A source file can access a function defined in any other source file provided the source file is included within the source file where you access that function. Program 9.5: Program to illustrate the concept of external functions. Type and save the following program in a file externfunction.h void output(void) { printf(“ Hi, Manipal!n”); return; } Type and save the following program in a separate source file called demoexternfun.c #include<stdio.h> #include “ externfunction.h” extern void output(void);
- 125. main() { output(); } Compile and execute the above program and observe the result. However, the keyword extern is optional in some C compilers. Self Assessment Questions i) What is the main purpose of using external variables? ii) State true or false. Compiler doesn’t allocate memory for an external variable where it is accessed? iii) State true or false. Global variables and external variables have the same scope. Example 9.1: Here is an example demonstrating almost everything we’ve seen so far: int globalvar = 1; extern int anotherglobalvar; static int privatevar; f() { int localvar; int localvar2 = 2; static int persistentvar; }
- 126. Here we have six variables, three declared outside and three declared inside of the function f(). globalvar is a global variable. The declaration we see is its defining instance (it happens also to include an initial value). globalvar can be used anywhere in this source file, and it could be used in other source files, too (as long as corresponding external declarations are issued in those other source files). anotherglobalvar is a second global variable. It is not defined here; the defining instance for it (and its initialization) is somewhere else. privatevar is a “private” global variable. It can be used anywhere within this source file, but functions in other source files cannot access it, even if they try to issue external declarations for it. (If other source files try to declare a global variable called ‘’privatevar”, they’ll get their own; they won’t be sharing this one.) Since it has static duration and receives no explicit initialization, privatevar will be initialized to 0. localvar is a local variable within the function f(). It can be accessed only within the function f(). (If any other part of the program declares a variable named “localvar”, that variable will be distinct from the one we’re looking at here.) localvar is conceptually “created” each time f() is called, and disappears when f() returns. Any value which was stored in localvar last time f() was running will be lost and will not be available next time f() is called. Furthermore, since it has no explicit initializer, the value of localvar will in general be garbage each time f() is called. localvar2 is also local, and everything that we said about localvar applies to it, except that since its declaration includes an explicit initializer, it will be initialized to 2 each time f() is called. Finally, persistentvar is again local to f(), but it does maintain its value between calls to f(). It has static duration but no explicit initializer, so its initial value will be 0. The term declaration is a general one which encompasses defining instances and external declarations; defining instances and external declarations are two different kinds of declarations. Furthermore, either kind of declaration suffices to inform the compiler of the name and type of a particular variable (or function). If you have the defining instance of a global variable in a source file, the rest of that source file can use that variable without having to issue any external declarations. It’s only in source files where the defining instance hasn’t been seen that you need external declarations. You will sometimes hear a defining instance referred to simply as a “definition,” and you will sometimes hear an external declaration referred to simply as a “declaration.” These usages are mildly ambiguous, in that you can’t tell out of context whether a “declaration” is a generic declaration (that might be a defining instance or an external declaration) or whether it’s an external declaration that specifically is not a defining instance. Similarly,
- 127. there are other constructions that can be called “definitions” in C, namely the definitions of preprocessor macros, structures, and typedefs etc. Program 9.6: Program to illustrate the hiding of variables in blocks /* hiding.c — variables in blocks */ #include <stdio.h> int main() { int x = 30; printf(”x in outer block: %dn”, x); { int x = 77; /* new x, hides first x */ printf(”x in inner block: %dn”, x); } printf(”x in outer block: %dn”, x); while (x++ < 33) { int x = 100; /* new x, hides first x */ x++; printf(”x in while loop: %dn”, x); } return 0; } 9.6 Conclusion
- 128. Variables are channels of communication within a program. Storage class refers to the persistence of a variable and its scope within the program, that is, the portion of the program over which the variable is recognized. The scope of a local or automatic variable is confined to the function where it is defined. A global variable is potentially visible anywhere within the program in which it is defined. Static variables retain their values throughout the life of the program. As a result, if a function is exited and then reentered later, the static variables defined within that function will retain their previous values. The external variable declaration says the compiler that the global variable will be used in this source file but defined in some other source file. Terminal Questions 1. List some of the storage classes available in C. 2. What is the use of header file? Is the use of header file absolutely necessary? 3. What is the difference between declaration and definition of function? 4. What is the significance of external declaration? 5. How can you justify that variables are channels of communication in a program? Answers to Self Assessment Questions 9.1 I) The visibility of a variable determines how much of the rest of the program can access that variable. ii) Storage class refers to the persistence of a variable and its scope within the program, that is, the portion of the program over which the variable is recognized. iii) True 9.2 i) The function in which it is declared. ii) No iii) False 9.3 I) False ii) False 9.4 i) True
- 129. ii) Static variables retain their values throughout the life of the program. As a result, if a function is exited and then reentered later, the static variables defined within that function will retain their previous values. iii) Zero 9.5 I) To access the same variable in different source files. ii) True iii) False Answers for Terminal Questions 1. automatic, global, static, extern 2. Header files are used to define some variables and functions separately in a library. Built-in header files are absolutely necessary if you want to access the variables and functions defined in them. 3. Declaration is nothing but the prototype that contains the type of returned data, name of the function and type of the arguments. But the definition contains the function header and the body of the function. 4. The external declaration says the compiler that the variable will be used in this source file but defined in some other source file. 5. You set a variable to a value at one point in a program, and at another point (or points) you read the value out again. Thus the transfer of information from one point of the program to another is nothing but the communication. Exercises 1. Distinguish between the following i) Global and local variables ii) Automatic and static variables iii) Global and extern variables 2. Write a program to count the number of times a function is called using static variables. 3. Write a function prime that returns 1 if its argument is a prime number and returns zero Otherwise
- 130. 4. Write a function that will round a floating point number to an indicated decimal place. For example, the number 12.456 would yield the value 12. 46 when its is rounded off to two decimal places. 5. Write a program to illustrate the concept of extern variables. Unit 10 Arrays and Strings • Introduction to arrays, One-dimensional arrays, Two-dimensional arrays, Array Initialization, Multi-dimensional arrays, Declaring and Initializing string variables, Reading a string, Writing strings, String handling functions. Introduction Many applications require processing of multiple data items that have common characteristics. In such situations it is always convenient to place the data items into an array, where they will share the same name. An array is a collection of similar type of elements. All elements in the array are referred with the array name. Since arrays hold a group of data, it is very easy to perform looping and arithmetic operations on group of data. This chapter covers the processing of both one-dimensional and two-dimensional arrays. Objectives At the end of this unit you will understand · How to declare, initialize and process one-dimensional arrays · How to declare, initialize and process two-dimensional arrays · What are strings and how to process them · The library functions available in C to process strings One Dimensional Arrays So far, we’ve been declaring simple variables: the declaration int i; declares a single variable, named i, of type int. It is also possible to declare an array of several elements. The declaration
- 131. int a[10]; declares an array, named a, consisting of ten elements, each of type int. Simply speaking, an array is a variable that can hold more than one value. You specify which of the several values you’re referring to at any given time by using a numeric subscript. (Arrays in programming are similar to vectors or matrices in mathematics.) We can represent the array a above with a picture like this: In C, arrays are zero-based: the ten elements of a 10-element array are numbered from 0 to 9. The subscript which specifies a single element of an array is simply an integer expression in square brackets. The first element of the array is a[0], the second element is a[1], etc. You can use these “array subscript expressions” anywhere you can use the name of a simple variable, for example: a[0] = 10; a[1] = 20; a[2] = a[0] + a[1]; Notice that the subscripted array references (i.e. expressions such as a[0] and a[1]) can appear on either side of the assignment operator. The subscript does not have to be a constant like 0 or 1; it can be any integral expression. For example, it’s common to loop over all elements of an array: int i; for(i = 0; i < 10; i = i + 1) a[i] = 0; This loop sets all ten elements of the array a to 0. Arrays are a real convenience for many problems, but there is not a lot that C will do with them for you automatically. In particular, you can neither set all elements of an array at once nor assign one array to another; both of the assignments a = 0; /* WRONG */ and int b[10]; b = a; /* WRONG */ are illegal.
- 132. To set all of the elements of an array to some value, you must do so one by one, as in the loop example above. To copy the contents of one array to another, you must again do so one by one: int b[10]; for(i = 0; i < 10; i = i + 1) b[i] = a[i]; Remember that for an array declared int a[10]; there is no element a[10]; the topmost element is a[9]. This is one reason that zero- based loops are also common in C. Note that the for loop for(i = 0; i < 10; i = i + 1) ... does just what you want in this case: it starts at 0, the number 10 suggests (correctly) that it goes through 10 iterations, but the less-than comparison means that the last trip through the loop has i set to 9. (The comparison i <= 9 would also work, but it would be less clear and therefore poorer style.) In the little examples so far, we’ve always looped over all 10 elements of the sample array a. It’s common, however, to use an array that’s bigger than necessarily needed, and to use a second variable to keep track of how many elements of the array are currently in use. For example, we might have an integer variable int na; /* number of elements of a[] in use */ Then, when we wanted to do something with a (such as print it out), the loop would run from 0 to na, not 10 (or whatever a’s size was): for(i = 0; i < na; i = i + 1) printf("%dn", a[i]); Naturally, we would have to ensure that na’s value was always less than or equal to the number of elements actually declared in a. Arrays are not limited to type int; you can have arrays of char or double or any other type. Here is a slightly larger example of the use of arrays. Suppose we want to investigate the behavior of rolling a pair of dice. The total roll can be anywhere from 2 to 12, and we want to count how often each roll comes up. We will use an array to keep track of the counts: a[2] will count how many times we’ve rolled 2, etc.
- 133. We’ll simulate the roll of a die by calling C’s random number generation function, rand(). Each time you call rand(), it returns a different, pseudo-random integer. The values that rand() returns typically span a large range, so we’ll use C’s modulus (or “remainder”) operator % to produce random numbers in the range we want. The expression rand() % 6 produces random numbers in the range 0 to 5, and rand() % 6 + 1 produces random numbers in the range 1 to 6. Program 10.1: Program to simulate the roll of a die #include <stdio.h> #include <stdlib.h> main() { int i; int d1, d2; int a[13]; /* uses [2..12] */ for(i = 2; i <= 12; i = i + 1) a[i] = 0; for(i = 0; i < 100; i = i + 1) { d1 = rand() % 6 + 1; d2 = rand() % 6 + 1; a[d1 + d2] = a[d1 + d2] + 1; } for(i = 2; i <= 12; i = i + 1) printf("%d: %dn", i, a[i]); return 0; } We include the header <stdlib.h> because it contains the necessary declarations for the rand() function. We declare the array of size 13 so that its highest element will be a[12]. (We’re wasting a[0] and a[1]; this is no great loss.) The variables d1 and d2 contain the rolls of the two individual dice; we add them together to decide which cell of the array to increment, in the line a[d1 + d2] = a[d1 + d2] + 1; After 100 rolls, we print the array out. Typically, we’ll see mostly 7’s, and relatively few 2’s and 12’s. 10.1.1 Passing Arrays to Functions An array name can be used as an argument to a function, thus permitting the entire array to be passed to the function. To pass an array to a function, the array name must appear by itself, without brackets or subscripts, as an actual argument within the function call. The corresponding formal argument is written in the same manner, though it must be declared as an array within the formal argument declarations. When declaring a one- dimensional array as a formal argument, the array name is written with a pair of empty square brackets. The size of the array is not specified within the formal argument declaration.
- 134. Program 10.2: The following program illustrates the passing of an array from the main to a function. This program is used to find the average of n floating point numbers. #include<stdio.h> main() { int n, i; float avg; float list[100]; float average(int, float[]); /* function prototype */ printf(“How many numbers:”); scanf(“%d”,&n); printf(“ Enter the numbers:”); for(i=1;i<=n;i++) scanf(“%f”, &list[i]); avg=average(n, list); /* Here list and n are actual arguments */ printf(“Average=%fn”, avg); } float average(int a, float x[ ]) { float avg; float sum=0; int i; for(i=0;i<a;i++)
- 135. sum=sum+x[i]; /* find sum of all the numbers */ avg=sum/a; /* find average */ return avg; } Self Assessment Questions i) In C, an array subscript starts from __________ ii) State true or false. An array name is a pointer iii) What is the result of the following program segment int a[5] = {1, 2, 3, 4, 5}; int b[5] = {5, 4, 3, 2, 1}; int c[5][5]; … c=a+b; … Multidimensional Arrays The C language allows arrays of any dimension to be defined. In this section, we will take a look at two-dimensional arrays. One of the most natural applications for a two- dimensional array arises in the case of a matrix. In C, the two-dimensional matrix can be declared as follows: int array[3][6]; Following is the way of declaring as well as initializing two-dimensional arrays. int array[3][6] = { {4,5,6,7,8,9}, {1,5,6,8,2,4},
- 136. {0,4,4,3,1,1} }; Such arrays are accessed like so: array[1][4]= -2; if (array[2][1] > 0) { printf (”Element [2][1] is %d”, array[2][1]); } Remember that, like ordinary arrays, two-dimensional arrays are numbered from 0. Therefore, the array above has elements from array[0][0] to array[2][5]. Program 10.3: Program to add two matrices. #include <stdio.h> main() { int a[5][5], b[5][5], c[5][5]; int i, j, m, n; printf(“Enter the order of the matrices:”); scanf(“%d%d”, &m, &n); printf(“ Enter the elements of A matrix:n”); for(i=0;i<m;i++) for(j=0;j<n;j++) scanf(“%d”, &a[i][j]); printf(“Enter the elements of B matrix:n”); for(i=0;i<m;i++) for(j=0;j<n;j++)
- 137. scanf(“%d”, &b[i][j]); /* Add the matrices */ for(i=0;i<m;i++) for(j=0;j<n;j++) c[i][j] = a[i][j]+b[i][j]; /* Print the sum */ printf(“The sum of matrices:n”); for(i=0;i<m;i++) { for(j=0;j<n;j++) printf(“%dt”, c[i][j]); printf(“n”); } } Multidimensional arrays are processed in the same manner as one-dimensional arrays, on an element-by-element basis. However, some care is required when passing multidimensional arrays to a function. In particular, the formal argument declarations within the function definition must include explicit size specifications in all of the subscript positions except the first. These size specifications must be consistent with the corresponding size specifications in the calling program. The first subscript position may be written as an empty pair of square brackets, as with a one-dimensional array. The corresponding function prototypes must be written in the same manner. But while calling the function the array name may be passed as the actual argument as in the case of one- dimensional arrays. E.g: void process_array (int [][6]); /* function prototype */ void process_array (int array[][6])/*function definition */ { …
- 138. } Self Assessment Questions i) In a two-dimensional matrix, the first subscript in the declaration specifies number of _____ ii) State true or false. A two-dimensional array is considered as an array of one-dimensional arrays. Strings Strings in C are represented by arrays of characters. The end of the string is marked with a special character, the null character, which is simply the character with the value 0. (The null character has no relation except in name to the null pointer. In the ASCII character set, the null character is named NULL.) The null or string-terminating character is represented by another character escape sequence, 0. Because C has no built-in facilities for manipulating entire arrays (copying them, comparing them, etc.), it also has very few built-in facilities for manipulating strings. In fact, C’s only truly built-in string-handling is that it allows us to use string constants (also called string literals) in our code. Whenever we write a string, enclosed in double quotes, C automatically creates an array of characters for us, containing that string, terminated by the 0 character. For example, we can declare and define an array of characters, and initialize it with a string constant: char string[ ] = "Hello, world!"; In this case, we can leave out the dimension of the array, since the compiler can compute it for us based on the size of the initializer (14, including the terminating 0). This is the only case where the compiler sizes a string array for us, however; in other cases, it will be necessary that we decide how big the arrays and other data structures we use to hold strings are. To do anything else with strings, we must typically call functions. The C library contains a few basic string manipulation functions, and to learn more about strings, we’ll be looking at how these functions might be implemented. Since C never lets us assign entire arrays, we use the strcpy function to copy one string to another: #include <string.h> char string1[ ] = "Hello, world!";
- 139. char string2[20]; strcpy(string2, string1); The destination string is strcpy’s first argument, so that a call to strcpy mimics an assignment expression (with the destination on the left-hand side). Notice that we had to allocate string2 big enough to hold the string that would be copied to it. Also, at the top of any source file where we’re using the standard library’s string-handling functions (such as strcpy) we must include the line #include <string.h> which contains external declarations for these functions. Since C won’t let us compare entire arrays, either, we must call a function to do that, too. The standard library’s strcmp function compares two strings, and returns 0 if they are identical, or a negative number if the first string is alphabetically “less than” the second string, or a positive number if the first string is “greater.” (Roughly speaking, what it means for one string to be “less than” another is that it would come first in a dictionary or telephone book, although there are a few anomalies.) Here is an example: char string3[] = "this is"; char string4[] = "a test"; if(strcmp(string3, string4) == 0) printf("strings are equaln"); else printf("strings are differentn"); This code fragment will print “strings are different”. Notice that strcmp does not return a Boolean, true/false, zero/nonzero answer, so it’s not a good idea to write something like if(strcmp(string3, string4)) ... because it will behave backwards from what you might reasonably expect. (Nevertheless, if you start reading other people’s code, you’re likely to come across conditionals like if(strcmp(a, b)) or even if(!strcmp(a, b)). The first does something if the strings are unequal; the second does something if they’re equal. You can read these more easily if you pretend for a moment that strcmp’s name were strdiff, instead.) Another standard library function is strcat, which concatenates strings. It does not concatenate two strings together and give you a third, new string; what it really does is append one string onto the end of another. (If it gave you a new string, it would have to allocate memory for it somewhere, and the standard library string functions generally never do that for you automatically.) Here’s an example: char string5[20] = "Hello, "; char string6[] = "world!"; printf("%sn", string5); strcat(string5, string6); printf("%sn", string5);
- 140. The first call to printf prints “Hello, ”, and the second one prints “Hello, world!”, indicating that the contents of string6 have been tacked on to the end of string5. Notice that we declared string5 with extra space, to make room for the appended characters. If you have a string and you want to know its length (perhaps so that you can check whether it will fit in some other array you’ve allocated for it), you can call strlen, which returns the length of the string (i.e. the number of characters in it), not including the 0: char string7[ ] = "abc"; int len = strlen(string7); printf("%dn", len); Finally, you can print strings out with printf using the %s format specifier, as we’ve been doing in these examples already (e.g. printf("%sn", string5);). Since a string is just an array of characters, all of the string-handling functions we’ve just seen can be written quite simply, using no techniques more complicated than the ones we already know. In fact, it’s quite instructive to look at how these functions might be implemented. Here is a version of strcpy: mystrcpy(char dest[ ], char src[ ]) { int i = 0; while(src[i] != '0') { dest[i] = src[i]; i++; } dest[i] = '0'; } We’ve called it mystrcpy instead of strcpy so that it won’t clash with the version that’s already in the standard library. Its operation is simple: it looks at characters in the src string one at a time, and as long as they’re not 0, assigns them, one by one, to the corresponding positions in the dest string. When it’s done, it terminates the dest string by appending a 0. (After exiting the while loop, i is guaranteed to have a value one greater than the subscript of the last character in src.) For comparison, here’s a way of writing the same code, using a for loop: for(i = 0; src[i] != '0'; i++) dest[i] = src[i]; dest[i] = '0'; Yet a third possibility is to move the test for the terminating 0 character out of the for loop header and into the body of the loop, using an explicit if and break statement, so that we can perform the test after the assignment and therefore use the assignment inside the loop to copy the 0 to dest, too:
- 141. for(i = 0; ; i++) { dest[i] = src[i]; if(src[i] == '0') break; } (There are in fact many, many ways to write strcpy. Many programmers like to combine the assignment and test, using an expression like (dest[i] = src[i]) != '0') Here is a version of strcmp: mystrcmp(char str1[ ], char str2[ ]) { int i = 0; while(1) { if(str1[i] != str2[i]) return str1[i] - str2[i]; if(str1[i] == '0' || str2[i] == '0') return 0; i++; } } Characters are compared one at a time. If two characters in one position differ, the strings are different, and we are supposed to return a value less than zero if the first string (str1) is alphabetically less than the second string. Since characters in C are represented by their numeric character set values, and since most reasonable character sets assign values to characters in alphabetical order, we can simply subtract the two differing characters from each other: the expression str1[i] - str2[i] will yield a negative result if the i‘th character of str1 is less than the corresponding character in str2. (As it turns out, this will behave a bit strangely when comparing upper and lower-case letters, but it’s the traditional approach, which the standard versions of strcmp tend to use.) If the characters are the same, we continue around the loop, unless the characters we just compared were (both) 0, in which case we’ve reached the end of both strings, and they were both equal. Notice that we used what may at first appear to be an infinite loop–the controlling expression is the constant 1, which is always true. What actually happens is that the loop runs until one of the two return statements breaks out of it (and the entire function). Note also that when one string is longer than the other, the first test will notice this (because one string will contain a real character at the [i] location, while the other will contain 0, and these are not equal) and the return value will be computed by subtracting the real character’s value from 0, or vice versa. (Thus the shorter string will be treated as “less than” the longer.) Finally, here is a version of strlen: int mystrlen(char str[ ]) { int i;
- 142. for(i = 0; str[i] != '0'; i++) { } return i; } In this case, all we have to do is find the 0 that terminates the string, and it turns out that the three control expressions of the for loop do all the work; there’s nothing left to do in the body. Therefore, we use an empty pair of braces { } as the loop body. Equivalently, we could use a null statement, which is simply a semicolon: for(i = 0; str[i] != '0'; i++) ; Everything we’ve looked at so far has come out of C’s standard libraries. As one last example, let’s write a substr function, for extracting a substring out of a larger string. We might call it like this: char string8[ ] = "this is a test"; char string9[10]; substr(string9, string8, 5, 4); printf("%sn", string9); The idea is that we’ll extract a substring of length 4, starting at character 5 (0-based) of string8, and copy the substring to string9. Just as with strcpy, it’s our responsibility to declare the destination string (string9) big enough. Here is an implementation of substr. Not surprisingly, it’s quite similar to strcpy: substr(char dest[ ], char src[ ], int offset, int len) { int i; for(i = 0; i < len && src[offset + i] != '0'; i++) dest[i] = src[i + offset]; dest[i] = '0'; } If you compare this code to the code for mystrcpy, you’ll see that the only differences are that characters are fetched from src[offset + i] instead of src[i], and that the loop stops when len characters have been copied (or when the src string runs out of characters, whichever comes first). When working with strings, it’s important to keep firmly in mind the differences between characters and strings. We must also occasionally remember the way characters are represented, and about the relation between character values and integers. As we have had several occasions to mention, a character is represented internally as a small integer, with a value depending on the character set in use. For example, we might find that 'A' had the value 65, that 'a' had the value 97, and that '+' had the value 43. (These are, in fact, the values in the ASCII character set, which most computers use. However, you don’t need to learn these values, because the vast majority of the time, you
- 143. use character constants to refer to characters, and the compiler worries about the values for you. Using character constants in preference to raw numeric values also makes your programs more portable.) As we may also have mentioned, there is a big difference between a character and a string, even a string which contains only one character (other than the 0). For example, 'A' is not the same as "A". To drive home this point, let’s illustrate it with a few examples. If you have a string: char string[ ] = "hello, world!"; you can modify its first character by saying string[0] = 'H'; (Of course, there’s nothing magic about the first character; you can modify any character in the string in this way. Be aware, though, that it is not always safe to modify strings in- place like this) Since you’re replacing a character, you want a character constant, 'H'. It would not be right to write string[0] = "H"; /* WRONG */ because "H" is a string (an array of characters), not a single character. (The destination of the assignment, string[0], is a char, but the right-hand side is a string; these types don’t match.) On the other hand, when you need a string, you must use a string. To print a single newline, you could call printf("n"); It would not be correct to call printf('n'); /* WRONG */ printf always wants a string as its first argument. (As one final example, putchar wants a single character, so putchar('n') would be correct, and putchar("n") would be incorrect.) We must also remember the difference between strings and integers. If we treat the character '1' as an integer, perhaps by saying int i = '1';
- 144. we will probably not get the value 1 in i; we’ll get the value of the character '1' in the machine’s character set. (In ASCII, it’s 49.) When we do need to find the numeric value of a digit character (or to go the other way, to get the digit character with a particular value) we can make use of the fact that, in any character set used by C, the values for the digit characters, whatever they are, are contiguous. In other words, no matter what values '0' and '1' have, '1' - '0' will be 1 (and, obviously, '0' - '0' will be 0). So, for a variable c holding some digit character, the expression c - '0' gives us its value. (Similarly, for an integer value i, i + '0' gives us the corresponding digit character, as long as 0 <= i <= 9.) Just as the character '1' is not the integer 1, the string "123" is not the integer 123. When we have a string of digits, we can convert it to the corresponding integer by calling the standard function atoi: char string[] = "123"; int i = atoi(string); int j = atoi("456"); Self Assessment Questions i) What is the output of the following program segment? char str1[10]; str1=”Hello, world”; printf(“%s”, str1); ii) What is the library function used to copy one string to another? iii) State true or false The library function atoi can be used for any string Conclusion An array is a variable that can hold more than one value. In C, arrays are zero-based. An array name can be used as an argument to a function, thus permitting the entire array to be passed to the function. The C language allows arrays of any dimension to be defined. One of the most natural applications for a two-dimensional array arises in the case of a matrix. Strings in C are represented by arrays of characters. C has built in library functions to perform some operations on strings. Terminal Questions
- 145. 1. Write a program for 10 times summation of square of a number 2. How many elements can the array in the following declaration accommodate? int a[3][4][5]; 3. Is the following array declaration and initialization correct? int a[2][2]={1,2,3,4}; 4. State true or false. Strings must be represented as an array of characters in C. 5. State true or false. When you pass an array as a parameter to a function, the entire array is copied and is available to function. 6. Write a Program that uses loops for array processing. Answers for Self Assessment Questions 10.1 i) 0 ii) true iii) Compilation error 10.2 I) rows ii) true 10.3 I) Compilation error ii) strcpy iii) false Answers for Terminal Questions 1. #include<stdio.h>
- 146. main() { int i=0, sum=0, x; printf(‘Enter a number:”); scanf(“%d”, &x); while(i<10) { sum+=x*x; i++; } printf(“Sum=%d”, sum); } 2. 60 3. Yes 4. True 5. False Program that reads in ten golf scores that will be processed later //uses loops for array processing #include <stdio.h> #define SIZE 10 #define PAR 72 int main(void) {
- 147. int index, score[SIZE]; int sum = 0; float average; printf(”Enter %d golf scores:n”, SIZE); for (index = 0; index < SIZE; index++) scanf(”%d”, &score[index]); */read in the ten scores printf(”The scores read in are as follows:n”); for (index = 0; index < SIZE; index++) printf(”%5d”, score[index]); */verify input printf(”n”); for (index = 0; index < SIZE; index++) sum += score[index]; */add them up average = (float) sum / SIZE; */ time-honored method printf(”Sum of scores = %d, average = %.2fn”, sum, average); printf(”That’s a handicap of %.0f.n”, average – PAR); return 0; } Exercises 1. Write a program to count the number of vowels and consonants in a given string. 2. Write a program to arrange a list of numbers in ascending order 3. Write a program to multiply two matrices 4. Write a program to rewrite a given string in the alphabetical order 5. Write a program to transpose a given matrix.
- 148. Unit 11 Pointers, Structures and Unions • Introduction to Pointers, Pointer Declarations, Operations on pointers, Introduction to Structures, Basics of structures, Introduction to Unions. Introduction A pointer is a variable that points at, or refers to, another variable. That is, if we have a pointer variable of type “pointer to int,“ it might point to the int variable i, or to any one of the locations of the int array a. Given a pointer variable, we can ask questions like, “What’s the value of the variable that this pointer points to?”. An array is a data structure whose elements are all of the same data type. We now turn our attention to the structure, which is a data structure whose individual elements can differ in type. Thus, a single structure might contain integer elements, floating-point elements and character elements. Closely associated with the structure is the union, which also contains multiple members. Unlike a structure, however, the members of a union share the same storage area, even though the individual members may differ in type. Objectives At the end of this unit, you will be able to: · Understand the concept of pointers · Handle a group of logically related data items known as structures. · Declare an array of structures, each element of the array representing a structure variable. · Pass Structure as an argument to functions and return structure from functions. · Handle a group of logically related data items in terms of unions. Basics of Pointers The first things to do with pointers are to declare a pointer variable, set it to point somewhere, and finally manipulate the value that it points to. A simple pointer declaration has the following general format: datatype *variablename
- 149. where datatype represents the type of the data to which the pointer variablename points to. In simple terms, the variablename holds the address of the value of type datatype. For example, int *ip; This declaration looks like our earlier declarations, with one obvious difference: that is the asterisk. The asterisk means that ip, the variable we’re declaring, is not of type int, but rather of type pointer-to-int. (Another way of looking at it is that *ip, which as we’ll see is the value pointed to by ip, will be an int.) We may think of setting a pointer variable to point to another variable as a two-step process: first we generate a pointer to that other variable, and then we assign this new pointer to the pointer variable. We can say (but we have to be careful when we’re saying it) that a pointer variable has a value, and that its value is “pointer to that other variable”. This will make more sense when we see how to generate pointer values. Pointers (that is, pointer values) are generated with the “address-of” operator &, which we can also think of as the “pointer-to” operator. We demonstrate this by declaring (and initializing) an int variable i, and then setting ip to point to it: int i = 5; ip = &i; The assignment expression ip = &i; contains both parts of the “two-step process”: &i generates a pointer to i, and the assignment operator assigns the new pointer to (that is, places it “in”) the variable ip. Now ip “points to” i, which we can illustrate with this picture: i is a variable of type int, so the value in its box is a number, 5. ip is a variable of type pointer-to-int, so the “value” in its box is an arrow pointing at another box. Referring once again back to the “two-step process” for setting a pointer variable: the & operator draws us the arrowhead pointing at i’s box, and the assignment operator =, with the pointer variable ip on its left, anchors the other end of the arrow in ip’s box. We discover the value pointed to by a pointer using the “contents-of” operator, *. Placed in front of a pointer, the * operator accesses the value pointed to by that pointer. In other words, if ip is a pointer, then the expression *ip gives us whatever it is that’s in the variable or location pointed to by ip. For example, we could write something like
- 150. printf(”%dn”, *ip); which would print 5, since ip points to i, and i is (at the moment) 5. (You may wonder how the asterisk * can be the pointer contents-of operator when it is also the multiplication operator. There is no ambiguity here: it is the multiplication operator when it sits between two variables, and it is the contents-of operator when it sits in front of a single variable. The situation is analogous to the minus sign: between two variables or expressions it’s the subtraction operator, but in front of a single operator or expression it’s the negation operator. Technical terms you may hear for these distinct roles are unary and binary: a binary operator applies to two operands, usually on either side of it, while a unary operator applies to a single operand.) The contents-of operator * does not merely fetch values through pointers; it can also set values through pointers. We can write something like *ip = 7; which means “set whatever ip points to 7.” Again, the * tells us to go to the location pointed to by ip, but this time, the location isn’t the one to fetch from–we’re on the left- hand sign of an assignment operator, so *ip tells us the location to store to. (The situation is no different from array subscripting expressions such as a[3] which we’ve already seen appearing on both sides of assignments.) The result of the assignment *ip = 7 is that i’s value is changed to 7, and the picture changes to: If we called printf("%dn", *ip) again, it would now print 7. At this point, you may be wonder, if we wanted to set i to 7, why didn’t we do it directly? We’ll begin to explore that next, but first let’s notice the difference between changing a pointer (that is, changing what variable it points to) and changing the value at the location it points to. When we wrote *ip = 7, we changed the value pointed to by ip, but if we declare another variable j: int j = 3; and write ip = &j; we’ve changed ip itself. The picture now looks like this:
- 151. We have to be careful when we say that a pointer assignment changes “what the pointer points to.” Our earlier assignment *ip = 7; changed the value pointed to by ip, but this more recent assignment ip = &j; has changed what variable ip points to. It’s true that “what ip points to” has changed, but this time, it has changed for a different reason. Neither i (which is still 7) nor j (which is still 3) has changed. (What has changed is ip’s value.) If we again call printf(”%dn”, *ip); this time it will print 3. We can also assign pointer values to other pointer variables. If we declare a second pointer variable: int *ip2; then we can say ip2 = ip; Now ip2 points where ip does; we’ve essentially made a “copy” of the arrow: Now, if we set ip to point back to i again: ip = &i; the two arrows point to different places:
- 152. We can now see that the two assignments ip2 = ip; and *ip2 = *ip; do two very different things. The first would make ip2 again point to where ip points (in other words, back to i again). The second would store, at the location pointed to by ip2, a copy of the value pointed to by ip; in other words (if ip and ip2 still point to i and j respectively) it would set j to i’s value, or 7. It’s important to keep very clear in your mind the distinction between a pointer and what it points to. You can’t mix them. You can’t “set ip to 5” by writing something like ip = 5; /* WRONG */ 5 is an integer, but ip is a pointer. You probably wanted to “set the value pointed to by ip to 5,” which you express by writing *ip = 5; Similarly, you can’t “see what ip is” by writing printf(”%dn”, ip); /* WRONG */ Again, ip is a pointer-to-int, but %d expects an int. To print what ip points to, use printf(”%dn”, *ip); Finally, a few more notes about pointer declarations. The * in a pointer declaration is related to, but different from, the contents-of operator *. After we declare a pointer variable int *ip; the expression ip = &i
- 153. sets what ip points to (that is, which location it points to), while the expression *ip = 5 sets the value of the location pointed to by ip. On the other hand, if we declare a pointer variable and include an initializer: int *ip3 = &i; we’re setting the initial value for ip3, which is where ip3 will point, so that initial value is a pointer. (In other words, the * in the declaration int *ip3 = &i; is not the contents- of operator, it’s the indicator that ip3 is a pointer.) If you have a pointer declaration containing an initialization, and you ever have occasion to break it up into a simple declaration and a conventional assignment, do it like this: int *ip3; ip3 = &i; Don’t write int *ip3; *ip3 = &i; or you’ll be trying to mix pointer and the value to which it points Also, when we write int *ip; although the asterisk affects ip’s type, it goes with the identifier name ip, not with the type int on the left. To declare two pointers at once, the declaration looks like int *ip1, *ip2; Some people write pointer declarations like this: int* ip; This works for one pointer, because C essentially ignores whitespace. But if you ever write int* ip1, ip2; /* PROBABLY WRONG */
- 154. it will declare one pointer-to-int ip1 and one plain int ip2, which is probably not what you meant. What is all of this good for? If it was just for changing variables like i from 5 to 7, it would not be good for much. What it’s good for, among other things, is when for various reasons we don’t know exactly which variable we want to change. Program 11.1: A simple program to illustrate the relationship between two integer variables, their corresponding addresses and their associated pointers #include<stdio.h> main() { int x=5; int y; int *px; /* pointer to an integer */ int *py; /* pointer to an integer */ px=&x; /* assign address of x to px */ y=*px; /* assign value of x to y */ py=&y; /* assign address of y to py */ printf(“nx=%d &x=%u px=%u *px=%d”, x, &x, px, *px); printf(“ny=%d &y=%u py=%u *py=%d”, y, &y, py, *py); } Execute this program and observe the result. Self Assessment Questions i. What is an indirection operator? ii. State true or false: Pointer is a variable containing address of another variable
- 155. iii. State whether the following statements are correct: int a, b; b=&a; Basics of Structures C supports a constructed data type known as structure, which is a method for packing data of different types. A structure is a convenient tool for handling a group of logically related data items. Structures help to organize complex data in a more meaningful way. It is a powerful concept that we may often need to use in our program design. Structure Definition : A Structure definition creates a format that may be used to declare structure variables. For e.g., Consider a book database consisting of book name, author, number of pages and price. struct book_bank { char title[20]; char author[15]; int pages; float price; }; The keyword struct declares a structure to hold the details of four fields, namely title, author, pages and price. These fields are called structure elements or members. Each member may belong to a different type of data. book_bank is the name of the structure and is called the structure tag. The tag name may be used subsequently to declare variables that have the tag’s structure. Note that the above declaration has not declared any variables. It simply describes a format called template to represent information as shown below: struct book_bank
- 156. We can declare structure variables using the tag name anywhere in the program. e.g, the statement: struct book_bank book1, book2, book3; declares book1, book2 and book3 as variables of type book_bank. Each one of these variables has four members as specified by the template. The complete declaration might look like this : struct book_bank { char title[20]; char author[15]; int pages; float price; }; struct book_bank book1, book2, book3; It is also allowed to combine both the template declaration and variables declaration in one statement. struct book_bank { char title[20];
- 157. char author[15]; int pages; float price; } book1, book2, book3; General format of a Structure Definition : The general format of a structure definition is as follows: struct tag_name { data_type member1; data_type member2; ——- }; In defining a structure you may note the following syntax: 1. The template is terminated with a semicolon. 2. While the entire declaration is considered as a statement, each member is declared independently for its name and type in a separate statement inside the template. 3. The tag name such as tag_name can be used to declare structure variables of its type, later in the program. Giving values to Members : Structure members need to be linked to the structure variables in order to make them meaningful members. The link between a member and a variable is established using the member operator ‘.’ which is also known as ‘dot operator’ or ‘period operator’. Here is how we would assign values to the members of book1. strcpy(book1.title,”BASIC”); strcpy(book1.author,”Balagurusamy”);
- 158. book1.pages = 250; book1.price = 28.50; We can also give the values through the keyboard. gets(book1.title); gets(book1.author); printf(“%d”,book1.pages); printf(“%f”,book1.price); Structure Initialization : void main( ) { struct st_record { char name[20]; int weight; float height; }; static struct st_record student1 = {“Suresh”, 60, 180.75}; static struct st_record student2 = {“Umesh”, 53, 170.60}; } Structures and Functions We can write programs with structures by using modular programming. We can write a function that returns the structure. While writing the function, you should indicate the type of structure that is returned by the function. The return statement should return the structure using a variable. It is possible to pass a structure as an argument. We can modify a member of the structure by passing the structure as an argument. The changes in the member made by the function are retained in the called module. This is not against
- 159. the principle of call by value because we are not modifying the structure variable, but are instead modifying the members of the structure. Program 11.4 To Illustrate the concept of structures and functions struct student { name char[30]; marks float; }; main ( ) { struct student student1; student1 = read_student ( ); print_student( student1); read_student_p(student1); print_student (student1); } struct student read_student( ) { struct student student2; gets(student2.name); scanf("%d",&student2.marks); return (student2); } void print_student (struct student student2) { printf( "name is %sn", student2.name); printf( "marks are%dn", student2.marks); } void read_student_p(struct student student2) { gets(student2.name); scanf("%d",&student2.marks); } Explanation 1. The function read_student reads values in structures and returns the structure. 2. The function print_student takes the structure variable as input and prints the content in the structure. 3. The function read_student_p reads the data in the structure similarly to read_student. It takes the structure student as an argument and puts the data in the structure. Since the data of a member of the structure is modified, you need not pass the structure as a pointer even though structure members are modified. Here you are not modifying the structure, but you are modifying the structure members through the structure. Self Assessment Questions
- 160. i) State true or false: We cannot write a function that returns the structure. ii) State true or false: We can modify a member of the structure by passing the structure as an argument. Arrays of Structures We can use structures to describe the format of a number of related variables. For example, in analyzing the marks obtained by a class of students, we may use a template to describe student name and marks obtained in various subjects and then declare all the students as structure variables. In such cases, we may declare an array of structures, each element of the array representing a structure variable. e.g, struct stclass student[100]; defines an array called student, that consists of 100 elements. Each element is defined to be of the type struct stclass. Consider the following declaration : struct marks { int subject1; int subject2; int subject3; }; main( ) { static struct marks student[3]={{45,68,81},{75,53,69},{57,36,71}}; } This declares the student as an array of three elements student[0], student[1] and student[2] and initializes their members as follows: student[0].subject1 = 45; student[0].subject2 = 68; ……..
- 161. student[2].subject3 = 71; Program 11.5 To process employee details using structures #include<conio.h> #include<stdio.h> struct employee { int empno; char name[30]; int basic; int hra; }; void main() { int i,j,n,net[50]; float avg; employee e[50]; printf(”nEnter the number of employees:”); scanf(“%d”, &n); printf(“nEnter Empno.tNametBasictHra of each employee:n”); for(i=0;i<n;i++) { scanf(“%d”,&e[i].empno); gets(e[i].name);
- 162. scanf(“%d”,&e[i].basic); scanf(%d”,&e[i].hra); net[i]= e[i].basic+e[i].hra; avg=avg+net[i]; } avg=avg/n; printf(”nEmpno.tNametNetpayn”); for(i=0;i<n;i++) { if(net[i]>avg) { printf(e[i].empnot)”; printf(e[i].namet)”; printf(net[i]n”); } } getch(); } Program 11.6 To process student details using structures #include<conio.h> #include<stdio.h> struct student {
- 163. int rollno; char name[30]; int marks1; int marks2; int marks3; }; void main() { int i,j,n,tot[50],t; student s[50],temp; printf(”nEnter the number of students:”); scanf(“%d”,&n); printf(”nEnter Rollno.tNametMarks1tMarks2tMarks3 of each student:n”); for(i=0;i<n;i++) { scanf(“%d”,&s[i].rollno); gets(s[i].name); scanf(“%d”,&s[i].marks1); scanf(“%d”,&s[i].marks2); scanf(“%d”,&s[i].marks3); tot[i]= s[i].marks1+s[i].marks2+s[i].marks3; } for(i=0;i<n-1;i++)
- 164. { for(j=i+1;j<n;j++) { if(tot[i]<tot[j]) { temp=s[i]; s[i]=s[j]; s[j]=temp; t=tot[i]; tot[i]=tot[j]; tot[j]=t; } } } printf(”nRollno.tNametTotal marks in decreasing order of total marks is:n”); for(i=0;i<n;i++) { printf(“%dt”,s[i].rollno); printf(“%st”,s[i].name); printf(“%dt”,s[i].tot); } getch(); }
- 165. Unions Unions look similar to structures. They have identical declaration syntax and member access, but they serve a very different purpose. union Utype { int ival; float fval; char *sval; }; union Utype x, y, z; Accessing members of a union is via “.” member operator or, for pointers to unions, the - > operator. A union holds the value of one-variable at a time. The compiler allocates storage for the biggest member of the union. The type retrieved from the union must be the type most recently stored. Otherwise, the result is implementation dependent. union Utype x; x.fval = 56.4; /* x holds type float. */ printf(”%fn”, x.fval); /* OK. */ printf(”%dn”, x.ival); /* Implementation dependent. */ Unions are used to store one of a set of different types. These are commonly used to implement a “variant” array. (This is a form of generic programming.) There are other uses also, but they are quite advanced (e.g., concern the alignment properties of unions). Self Assessment Questions i) A __________ holds the value of one-variable at a time. ii) State true or false: The compiler allocates storage for the smallest member of the union. Summary
- 166. A pointer is a variable that points at, or refers to, another variable. A structure is a convenient tool for handling a group of logically related data items. Structure members need to be linked to the structure variables in order to make them meaningful members. We can write programs with structures by using modular programming. We can use structures to describe the format of a number of related variables. Unions have identical declaration syntax and member access, but they serve a very different purpose. A union holds the value of one-variable at a time. The compiler allocates storage for the biggest member of the union. Terminal Questions 1. State whether true or false Structure is a method for packing data of different types. 2. The link between a member and a variable is established using the member operator ______________. 3. Describe the output generated by the following program. Distinguish between meaningful and meaningless output. #include <stdio.h> main() { union { int i; float f; double d; } u; printf(“%dn”, sizeof(u)); u.i= 100; printf(“%d %f %fn”, u.i, u.f, u.d);
- 167. u.f=0.5; printf(“%d %f %fn”, u.i, u.f, u.d); u.d = 0.0166667; printf(“%d %f %fn”, u.i, u.f, u.d); } 4. Declare a pointer to a floating point quantity and a double precision quantity Answers to Self Assessment Questions 11.1 i. It is the content of operator, *, that is used to get the content of a memory location pointed to by a pointer. ii. True iii. Incorrect 11.2 i) structure ii) true iii) false iv) false 11.3 i) false ii) true 11.5 i) union ii) false Answers to Terminal Questions 1. true 2. dot(.) 3. 8
- 168. 100 0.000000 -0.000000 0 0.500000 -0.000000 -25098 391364288.000000 0.016667 The first line displays the size of the union (8 bytes, to accommodate double data). In the second line , only the first value(100) is meaningful. In the third line , only the second value(0.500000) is meaningful. In the last line, only the last value(0.016667) is meaningful.. 4. float *fptr; double *dptr; Exercises 1. What is a structure? How does a structure differ from an array? 2. What is a member? What is the relationship between a member and a structure? 3. Describe what is wrong in the following structure declaration: struct { int number; float price; } main() { ……………. ……………… } 4. Describe Array of structures with an example program. 5. Define a structure called cricket that will describe the following information:
- 169. (i) player name (ii) team name (iii) batting average Using cricket , declare an array player with 50 elements and write a program to read the information about all the 50 players and print a team-wise list containing names of players and print a team-wise list containing names of players with their batting average. 6. Write a program to find the number of characters in a string using pointers. References 1. E. Balagurusamy, “Programming with ANSI C”, Tata McGraw-Hill Publishers, New Delhi. 2. Byron S. Gottfried, Schaum’s Outline Series, “ Theory and Problems of Programming wiith C”, ata McGraw-Hill Publishers, New Delhi. 3. Stephen C. Kochan, “ Programming in C”, CBS Publishers, Revised Edition, New Delhi. 4. Brian W. Kernighan and Dennis M. Ritchie, “ The C Programming Language”, Second Edition, Prentice-Hall of India, New Delhi.