Report on-the-logic-gates

Records of demonstration experiments

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S.No. Contents Page No.
I. Introduction 1
II. Principle 2
III. Basic Gates 3
IV. OR Gate 4
V. AND Gate 5
VI. NOT Gate 6
VII. NOR Gate 7
VIII. NAND Gate 8
IX. EX-OR Gate 9
X EX-NOR Gate 10
XI Step-Down Transformer 13
XII Step-Up Transformer 14
XIII Construction 15
XIV Theory 16
XV Energy Losses 17
XVI Bibliography 18

Samyak Sau

A gate is defined as a digital circuit which follows some
logical relationship between the input and output voltages.
It is a digital circuit which either allows a signal to pass
through as stop, it is called a gate.
The logic gates are building blocks at digital
electronics. They are used in digital electronics to change
on voltage level (input voltage) into another (output
voltage) according to some logical statement relating them.
A logic gate may have one or more inputs, but it has only
one output. The relationship between the possible values of
input and output voltage is expressed in the form of a table
called truth table or table of combinations.
Truth table of a Logic Gates is a table that shows all the
input and output possibilities for the logic gate.
George Boole in 1980 invented a different kind of algebra
based on binary nature at the logic, this algebra of logic
called BOOLEAN ALGEBRA. A logical statement can have
only two values, such as HIGH/LOW, ON/OFF,
CLOSED/OPEN, YES/NO, RIGHT/WRONG, TRUE/FALSE,
CONDUCTING/NON-CONDUCTING etc. The two values of
logic statements one denoted by the binary number 1 and 0.
The binary number 1 is used to denote the high value. The
logical statements that logic gates follow are called Boolean
expressions.
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Any Boolean algebra operation can be associated
with inputs and outputs represent the statements of
Boolean algebra. Although these circuits may be
complex, they may all be constructed from three basic
devices. We have three different types of logic gates
.These are the AND gate, the OR gate and the NOT
gate.
LOGIC STATES
1 0
HIGH LOW
+v Ov
ON OFF
CLOSE OPEN
RIGHT WRONG
TRUE FALSE
YES NO

Samyak Sau

(a) THE OR GATE is a device that combines A with B to give Y as the
result.
The OR gate has two or more inputs and one output. The logic gate of
OR gate with A and B input and Y output is shown below:

In Boolean algebra, addition symbol (+) is referred as the OR. The
Boolean expression:
A+B=Y, indicates Y equals A OR B.

(b) THE AND GATE is a device that combines A with B to give Y as the
result.
The AND gate has two or more inputs and one output. The logic gate
of AND gate with A and B input and Y output is shown below:

In Boolean algebra, multiplication sign (either x or.) is referred as the
AND. The Boolean expression:
A.B=Y, indicates Y equals A AND B.

(c) THE NOT GATE is a device that inverts the inputs. The NOT is a one
input and one output. The logic gate of NOT gate with A and Y
output is shown below:

_
In Boolean algebra, bar symbol ( ) is referred as the NOT. The Boolean
expression:
Ã =Y, indicates Y equals NOT A.
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Aim:
TO DESIGN AND SIMULATE THE OR GATE CIRCUIT.

Components:
Two ideal p-n junction diode (D1 and D2).

Theory and Construction:
An OR gate can be realize by the electronic circuit, making use of two diodes D1 and
D2 as shown in the figure.
Here the negative terminal of the battery is grounded and corresponds to the 0 level, and
the positive terminal of the battery (i.e. voltage 5V in the present case) corresponds to
level 1. The output Y is voltage at C w.r.t. earth.

The following interference can be easily drawn from the working of electrical circuit is:
a) If switch A & B are open lamp do not glow (A=0, B=0), hence Y=0.
b) If Switch A open B closed then (A=0, B=1) Lamp glow, hence Y=1.
c) If switch A closed B open then (A=1, B=0) Lamp glow, hence Y=1.
d) If switch A & B are closed then (A=1, B=1) Lamp glow, hence Y=1.

Truth Table:
Input A Input B Output Y
0 0 0
1 0 1
0 1 1
1 1 1

Samyak Sau

Aim:
TO DESIGN AND SIMULATE THE AND GATE CIRCUIT.

Components:
Two ideal p-n junction diode (D1 and D2), a resistance R.

An AND gate can be realize by the electronic circuit, making use of two diodes D1
and D2 as shown in the figure. The resistance R is connected to the positive terminal of a
5V battery permanently.
Here the negative terminal of the battery is grounded and corresponds to the 0 level, and
the positive terminal of the battery (i.e. voltage 5V in the present case) corresponds to
level 1. The output Y is voltage at C w.r.t. earth.

The following conclusions can be easily drawn from the working of electrical circuit:
a) If both switches A&B are open (A=0, B=0) then lamp will not glow, hence Y=0.
b) If Switch A closed & B open (A=1, B=0) then Lamp will not glow, hence Y=0.
c) If switch A open & B closed (A=0, B=1) then Lamp will not glow, hence Y=0.
d) If switch A & B both closed (A=1, B=1) then Lamp will glow, hence Y=1.

Truth Table:
0 0 0
1 0 0
0 1 0
1 1 1
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Aim:
TO DESIGN AND SIMULATE THE NOT GATE CIRCUIT.

Components:
An ideal n-p-n transistor.

A NOT gate cannot be realized by using diodes. However an electronic circuit of NOT
gate can be realized by making use of a n-p-n transistor as shown in the figure.
The base B of the transistor is connected to the input A through a resistance R b and the
emitter E is earthed. The collector is connected to 5V battery. The output Y is voltage at C
w.r.t. earth.

The following conclusion can be easily drawn from the working of the electrical circuit:

a) If switch A is open (i.e. A=0), the lump will glow, hence Y=1.
b) If Switch A is closed (i.e. A=1), the lump will not glow, hence Y=0.

Truth Table:
Input A Output Y
0 1
1 0

Samyak Sau

Aim:
TO DESIGN AND SIMULATE THE NOR GATE CIRCUIT.

Components:
Two ideal p-n junction diode (D1 and D2), an ideal n-p-n transistor.

If we connect the output Y’ of OR gate to the input of a NOT gate the gate obtained
is called NOR.
The output Y is voltage at C w.r.t. earth.

In Boolean expression, the NOR gate is expressed as Y=A+B, and is being read as ‘A OR B
negated’. The following interference can be easily drawn from the working of electrical
circuit is:
a) If Switch A & B open (A=0, B=0) then Lamp will glow, hence Y=1.
c) If Switch A open & B close (A=0, B=1) then Lamp will not glow, hence Y=0.
d) If switch A & B are closed then (A=1, B=1) Lamp will not glow, hence Y=0.

Truth Table:
0 0 1
1 0 0
0 1 0
1 1 0

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Aim:
TO DESIGN AND SIMULATE THE NAND GATE CIRCUIT.

Components:
Two ideal p-n junction diode (D1 and D2), a resistance R, an ideal n-p-n transistor.

If we connect the output Y’ of AND gate to the input of a NOT gate the gate obtained
is called NAND.
The output Y is voltage at C w.r.t. earth.

In Boolean expression, the NAND gate is expressed as Y=A.B, and is being read as ‘A AND B
negated’. The following interference can be easily drawn from the working of electrical
circuit:

Truth Table:
0 0 1
1 0 1
0 1 1
1 1 0

Samyak Sau

Aim:
TO DESIGN AND SIMULATE THE EX OR GATE CIRCUIT.

Components:
Two AND gate, an OR gate, two NOT gate.

The operation EXOR checks for the exclusivity in the value of the two signals A and
B. It means if A and B are not identical (i.e. if A=0 and B=1 or vice versa), the output Y=1,
and if both are identical, then the output Y=0. This operation is also called exclusive OR
gate, designated EXOR.

In Boolean expression, the EX OR gate is expressed as
Y=A.B + A.B =
The following interference can be easily drawn from the working of electrical circuit:
a) If both switches A&B are open (A=0, B=0) then lamp will not glow, hence Y=0.

Truth Table:
0 0 0
1 0 1
0 1 1
1 1 0

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Aim:
TO DESIGN AND SIMULATE THE EX NOR GATE CIRCUIT.

Components:
Two AND gate, an OR gate, three NOT gate.

The operation EXNOR checks for the exclusivity in the value of the two signals A and
B. It means if A and B are not identical (i.e. if A=0 and B=1 or vice versa), the output Y=0,
and if both are identical, then the output Y=1. This operation is also called exclusive NOR
gate, designated EXNOR.

In Boolean expression, the EX NOR gate is expressed as
Y=A.B + A.B =
The following interference can be easily drawn from the working of electrical circuit:
c) If Switch A open & B close (A=0, B=1) then Lamp will not glow, hence Y=0.
d) If switch A & B both closed (A=1, B=1) then Lamp will glow, hence Y=1.

Truth Table:
0 0 1
1 0 0
0 1 0
1 1 1

Samyak Sau

The transformer is a device used for converting

a low alternating voltage to a high alternating

voltage or a high alternating voltage into a low

alternating voltage.

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It is based on the principle of mutual induction that

is if a varying current is set-up in a circuit induced

e.m.f. is produced in the neighbouring circuit. The

varying current in a circuit produce varying

magnetic flux which induces e.m.f. in the

neighbouring circuit.

Samyak Sau

In this step-down transformer is used:
This transformer converts high voltage at alternating current into low
voltage alternating current. In step-down transformer the number of
turns in primary coil remains large as compare to secondary coil.

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In this step-up transformer is used:
This transformer converts low voltage at alternating current into high
voltage alternating current. In step-up transformer the number of
turns in secondary coil remains large as compare to primary coil.

Samyak Sau

The transformer consists of two coils. They are insulated

with each other by insulated material and wound on a

common core. For operation at low frequency, we may have

a soft iron. The soft iron core is insulating by joining thin

iron strips coated with varnish to insulate them to reduce

energy losses by eddy currents.

The input circuit is called primary. And the output circuit is

called secondary.

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Suppose, the number of turns in the primary coil is NP and
that in the secondary coil is NS. The resistance of the coil is
assumed to be zero. Let dq /dt be the rate of change of flux
in each turn of the primary coil. If Ep be the e.m.f. in the
primary circuit then.
EP = –NP (1)
We suppose that there is no loss of flux between the
primary and secondary coils. Then, the induced e.m.f. in the
secondary coil will be:
ES = –NS (2)
From equations (i) and (ii), we find:
Ns/Np = K
is called transformer ratio or turn ratio.
For step up transformer K > 1
For step down transformer K < 1
That is for step-up transformer NS > NP, therefore ES>EP.
For the step down transformer NS < NP therefore ES < EP.

Efficiency: The efficiency of the transformer is given by:
If Ip and Is be the currents in the primary and secondary
circuits. For ideal transformer = 1 = 100%. Therefore
ES|IS = EP|IP
Therefore, for step up, transformer current in the
secondary is less than in the primary (IS < IP). And in a step
down transformer we have IS > IP.

Samyak Sau

In practice, the output energy of a transformer is always less
than the input energy, because energy losses occur due to a
number of reasons as explained below.

1. Loss of Magnetic Flux: The coupling between the
coils is seldom perfect. So, whole of the magnetic flux
produced by the primary coil is not linked up with the
secondary coil.
2.
3. Iron Loss: In actual iron cores in spite of lamination,
Eddy currents are produced. The magnitude of eddy
current may, however be small. And a part of energy is
lost as the heat produced in the iron core.
4.
3. Copper Loss: In practice, the coils of the transformer
possess resistance. So a part of the energy is lost due to the
heat produced in the resistance of the coil.

5. Hysteresis Loss: The alternating current in the coil
tapes the iron core through complete cycle of
magnetization. So Energy is lost due to hysteresis.
6.
5. Magneto restriction: The alternating current in the
Transformer may be set its parts in to vibrations and sound
may be produced. It is called humming. Thus, a part of
energy may be lost due to humming.

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Encarta Encyclopaedia.

Britannica Encyclopaedia.

www.wikipedia.com.

www.answers.com.

www.google.co.in.

Samyak Sau

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