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Finding: Surface Area of
Triangular Prism 3
- Mr Kim
Please view:
Surface Area of Triangular Prism 1 & 2
Before you view this lesson
10 m
12 m
17 m
10 m
12 m
Find the Area of all 5 Faces
of this Prism
17 m
17 m
10 m
12 m
Front Area is
17 m
10 m
12 m
Front Area is

2
1
17 m
10 m
12 m
Front Area is
12
2
1

17 m
10 m
Front Area is
?12
2
1

?
12 m
17 m
10 m
?12
2
1

?
We have to find
that length
12 m
17 m
10 m
?12
2
1

We will call that
unknown length x
x
12 m
17 m
10 m
?12
2
1

To find x we need to use
Pythagoras theorem
x
12 m
17 m
10 m
12 m
?12
2
1

x
17 m
10 m
12 m
?12
2
1

x
Focus on this Triangle here
17 m
10 m
12 m
?12
2
1

x
We need this
length
17 m
10 m
12 m
?12
2
1

x
And this length
17 m
10 m
12 m
?12
2
1

x
Now if it’s 10 m
here
17 m
10 m
12 m
?12
2
1

x
10 m
It’s 10 m there as
well
17 m
10 m
12 m
?12
2
1

x
10 m
Now this length
17 m
10 m
12 m
?12
2
1

x
10 m
This length is half of…
17 m
10 m
12 m
?12
2
1

x
10 m
12 m
This whole length
17 m
10 m
12 m
?12
2
1

x
10 m
12 m
This whole length
17 m
10 m
12 m
?12
2
1

x
10 m
12 m
So 12 ÷ 2 =
17 m
10 m
12 m
?12
2
1

x
10 m
12 m
So 12 ÷ 2 = 6 m
6 m
17 m
10 m
12 m
?12
2
1

x
10 m
6 m
Now if we use Pythagoras
theorem we will get…
17 m
10 m
12 m
?12
2
1

x
10 m
6 m
x
x
Now if we use Pythagoras
theorem we will get…
17 m
10 m
12 m
?12
2
1

x
10 m
6 m
x
2
x
squared
17 m
10 m
12 m
?12
2
1

x
10 m
6 m
x
2
x
Equals
17 m
10 m
12 m
?12
2
1

x
6 m
x
10 m
22
10x
10²
17 m
10 m
12 m
?12
2
1

x
6 m
x
10 m
22
10x
The Hypotenuse
(10 m) must be written first
17 m
10 m
12 m
?12
2
1

x
6 m
x
10 m
22
10x
The Hypotenuse
(10 m) must be written first
not 6
17 m
10 m
12 m
?12
2
1

x
6 m
x
10 m
22
10x
10 m
Now x is not the longest
side of the triangle
17 m
10 m
12 m
?12
2
1

x
6 m
x
10 m
22
10x
10 m
This side is.
17 m
10 m
12 m
?12
2
1

x
6 m
x
10 m10 m
 22
10x
So we MINUS
17 m
10 m
12 m
?12
2
1

xx
10 m10 m
6 m
6²
222
610 x
17 m
10 m
12 m
?12
2
1

xx
10 m10 m
6 m
222
610 x
so x equals…
x
17 m
10 m
12 m
?12
2
1

xx
10 m10 m
6 m
222
610 x
so x equals…
22
610 x
17 m
10 m
12 m
?12
2
1

xx
10 m10 m
6 m
222
610 x
22
610 x
Putting this in the
calculator gives…
17 m
10 m
12 m
?12
2
1

xx
10 m10 m
6 m
222
610 x
22
610 x
8
17 m
10 m
12 m
?12
2
1

xx
10 m10 m
6 m
222
610 x
22
610 x
8
17 m
10 m
12 m
xx
10 m10 m
6 m
222
610 x
22
610 x
8
812
2
1

17 m
10 m
812
2
1

10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
17 m
10 m
812
2
1

10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
So this is the area of
the Front face
17 m
10 m
812
2
1

10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
Now the Back is the
same as the Front…
17 m
10 m
2812
2
1

10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
So times by 2
17 m
10 m
2812
2
1

10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
Now find the area of
the Right Side
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
Add that on
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
The Right Side is a
Rectangle
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
The Right Side is a
Rectangle
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
The Right Side is a
Rectangle
1710
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
1710
Now find the area of
the Left Side
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
1710
The Left Side is the
same as the Right Side
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
21710 
So times by 2
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
21710 
And finally find the
Bottom Area
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
 21710
Add that on
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
 21710
Bottom Area
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
 21710
Bottom Area
1712
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
 21710
1712
Putting this altogether in
the calculator gives…
17 m
10 m
 2812
2
1
10 m
6 m
12 m
22
610 x
222
610 x
8
8 m
 21710
1712
2
640m
Our Final Answer!
Putting this altogether in
the calculator gives…

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Surface Area of Triangular Prism 3