14.5.6 Example 1 Part 3

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This document calculates the capacitive reactance and capacitance value needed for a reactive power of 1.754 kVAR at 240V. It shows that the capacitive reactance is 32.845 ohms and the required capacitance is 80.761 microfarads.

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14.5.6 Example 1 Part 3

Reactive power
(1.754 kVAR)

Q = Voltage² (V) dived by reactance (X)
V2
Q=
XC
V²
Q= Transposed for XC
XC
V²
XC =
Q
240²
X= = 32.845 Ω
1754

Xc = 1 .

2πfC

C= 1 .
2 π f Xc

C= 1
2 π x 60 x 32.845

= 0.00008076

= 80.761 μF

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14.5.6 Example 1 Part 3

2. Reactive power (1.754 kVAR)

3. Q = Voltage² (V) dived by reactance (X) V2 Q= XC V² Q= Transposed for XC XC V² XC = Q 240² X= = 32.845 Ω 1754

4. Xc = 1 . 2πfC C= 1 . 2 π f Xc C= 1 2 π x 60 x 32.845 = 0.00008076 = 80.761 μF