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AP Calculus
   Derivative f’ (a) for specific values of a
   Function f’ (x)
  Domain of f’ (x) is all values of x in domain of
f (x) for which the limit exists.
 F’ (x) is differentiable on (a, b) if f ‘(x) exists
   for all x in (a, b).
 If f’ (x) exists for all x, then f (x) is
   differentiable.
   Prove that f (x) = x3 – 12x is differentiable.
    Compute f ‘(x) and write the equation of the
    tangent line at x = -3.
   F ‘(x) = 3x2 – 12
   Equation of tangent line at x = -3
    y = 15x + 54
   Calculate the derivative of y = x-2. Find the
    domain of y and y’
   Solution: y’ = -2x-3
   Domain of y: {x| x ≠ 0}
   Domain of y’ : {x| x ≠ 0}
   The function is differentiable.
   Another notation for writing the derivative:



   Read “dy dx”
   For the last example y = x-2, the solution could
    have been written this way:
   For all exponents n,
3.2 Derivative as a Function
   Calculate the derivative of the function below
   Solution:
Assume that f and g are differentiable
 functions.
 Sum Rule: the function f + g is differentiable
                 (f + g)’ = f’ + g’

   Constant Multiple Rule: For any constant c,
    cf is differentiable and
                        (cf)’ = cf’
   Find the points on the graph of
    f(t) = t3 – 12t + 4 where the tangent line(s) is
    horizontal.
   Solution:
   How is the graph of f(x) = x3 – 12x related to
    the graph of f’(x) = 3x2 – 12 ?
f(x) = x3 – 12 x        Decreasing on (-2, 2)
                                                     Increasing on (2, ∞)

 Increasing on (-∞, -2)


                                                              What happens
                                                              to f(x) at x = -2
 f’(x) = 3x2 - 12                                             and x = 2??
Graph of f’(x) positive     f’(x) is negative     f’(x) is positive on (2, ∞)
on (-∞, -2)                  on (-2,2)




                             Zeros at -2, 2
   Differentiability Implies Continuity
     If f is differentiable at x = c, then f is continuous at
      x = c.
   Show that f(x) = |x| is continuous but not
    differentiable at x = 0.
   The function is continuous at x = 0 because
   The one-sided limits are not equal:




   The function is not differentiable at x = 0
   Local Linearity
   f(x) = x3 – 12x
   g(x) = |x|
   Show that f(x) = x 1/3 is not differentiable at
    x = 0.
The limit at x = 0 is infinite
f’(0) =




  The slope of the tangent line is
  infinite – vertical tangent line

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3.2 Derivative as a Function

  • 2. Derivative f’ (a) for specific values of a
  • 3. Function f’ (x)
  • 4.  Domain of f’ (x) is all values of x in domain of f (x) for which the limit exists.  F’ (x) is differentiable on (a, b) if f ‘(x) exists for all x in (a, b).  If f’ (x) exists for all x, then f (x) is differentiable.
  • 5. Prove that f (x) = x3 – 12x is differentiable. Compute f ‘(x) and write the equation of the tangent line at x = -3.
  • 6. F ‘(x) = 3x2 – 12  Equation of tangent line at x = -3 y = 15x + 54
  • 7. Calculate the derivative of y = x-2. Find the domain of y and y’
  • 8. Solution: y’ = -2x-3  Domain of y: {x| x ≠ 0}  Domain of y’ : {x| x ≠ 0}  The function is differentiable.
  • 9. Another notation for writing the derivative:  Read “dy dx”  For the last example y = x-2, the solution could have been written this way:
  • 10. For all exponents n,
  • 12. Calculate the derivative of the function below
  • 13. Solution:
  • 14. Assume that f and g are differentiable functions.  Sum Rule: the function f + g is differentiable (f + g)’ = f’ + g’  Constant Multiple Rule: For any constant c, cf is differentiable and (cf)’ = cf’
  • 15. Find the points on the graph of f(t) = t3 – 12t + 4 where the tangent line(s) is horizontal.
  • 16. Solution:
  • 17. How is the graph of f(x) = x3 – 12x related to the graph of f’(x) = 3x2 – 12 ?
  • 18. f(x) = x3 – 12 x Decreasing on (-2, 2) Increasing on (2, ∞) Increasing on (-∞, -2) What happens to f(x) at x = -2 f’(x) = 3x2 - 12 and x = 2?? Graph of f’(x) positive f’(x) is negative f’(x) is positive on (2, ∞) on (-∞, -2) on (-2,2) Zeros at -2, 2
  • 19. Differentiability Implies Continuity  If f is differentiable at x = c, then f is continuous at x = c.
  • 20. Show that f(x) = |x| is continuous but not differentiable at x = 0.
  • 21. The function is continuous at x = 0 because
  • 22. The one-sided limits are not equal:  The function is not differentiable at x = 0
  • 23. Local Linearity  f(x) = x3 – 12x
  • 24. g(x) = |x|
  • 25. Show that f(x) = x 1/3 is not differentiable at x = 0.
  • 26. The limit at x = 0 is infinite f’(0) = The slope of the tangent line is infinite – vertical tangent line