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PROJECTILE MOTION
COURSE : PHYSICS
TOPIC
: TWO-DIMENSIONAL MOTION
GRADE / SEM : XI / 1
ALLOCATED TIME
: 2 HOURS

SMA NEGERI 1 JEPARA
STANDARD COMPETENCY


Analyze nature phenomenon and it’s regularity in
coverage of particle’s.
BASE COMPETENCY


Analyze
linier
motion
(2
Dimensional
motion), Circular motion, and Parabolic motion
using vector
INDICATOR
Analyze fundamental quantities in linier motion
using vector.
 Apply vector’s analysis to solve Two Dimensional
Motion’s problem (including parabolic motion).
 Analyze the relationship of the quantities in Two
Dimensional Motion.
 Analyze fundamental quantities in circular motion
using vector.
 Apply vector’s analysis to solve Circular Motion’s
Problem.

LEARNING MATERIAL
Constant velocity motion
 Constant acceleration motion
 Two-Dimensional linier motion
 Parabolic Motion
 Circular Motion

LEARNING METHODE
Discussion
 Experiment
 Class/Lecture

 Material
 Simulations
 Applications

1
 Applications 2
 Applications 3
 Applications 4
 Applications 5
 Applications 6
CONCLUSSION
1. Projectile motion is motion with a constant
horizontal velocity combined with a constant
vertical acceleration
2. The projectile moves along a parabola
3. Trajectory parabola, open down

a. Total time 44.  t 

2 v i sin 
g
v i sin 2
2

b. Horizontal range

X 

g

v i sin 
2

c. Max height

h max 

2

g
4. Trajectory Half-Parabola, open down

a. Total time 44. x  v i

b. Horizontal range
c. Final velocity

2h
g

vf 

vf 

2

v i  2 gh
2

v i  2 gh
SAMPLE PROBLEM
1. A bullet is shot at initial of velocity 40 m/s, and
0
elevation angle of 60
from a flat ground, ait friction
neglected and gravitasional acceleration g = 10 m/
2
. Determined:
s
a. The time needed by the bullet to reach the
highest point H?
b. The maximum height reached by the bullet?
c. The greatest distance reached by the bullet?
Solution
v 0 = 40 m/s
α = 60 0
g = 10m/s 2
a.

tH 

v 0 sin 



40 sin 60

g

40 .

0

1

3

2
10



10

 2 3s

thus, the time to reach the highest point H is
2

3 sec onds .

b. The maximum height reached by the bullet
v 0 sin 
2

yH 

2

2



40 sin

2g

2

60

1600 .

0

4  60 m .



2 . 10

3

20

c. The greatest distance reached by the bullet
v 0 sin 2
2

x

g

2



40 sin 2 . 60
10

1600 .

0



1

2
10

3
 40 3 m .
EXERCISE
1. An object is thrown at initial of velocity of 20 m/s from
0
30
point A to the ground with elevation angle
if gravitational acceleration g = 10 m / s 2 and air
friction neglected,determined:
a. the initial velocity component in horizontal and
vertical direction.
b. the object velocity after 0,5 s.
c. the object position after 0,5 s.
2. An object is thrown from the top of a building of which
the height is 40 m. The initial velocity of the object is
0
20 m/s and the elevation angle is
.
30
Determined the greatest distance in horizontal
direction counted from the base of building?.
3. A bullet is shot from a horizontal ground at an
elevation angle of 60 0. After 50 seconds, it falls to
the ground 4000 m away from where it was
2
thrown. Given g=10 m/ s , calculate the initial
velocity of the bullet?.
4. A soccer ball is kicked at an initial velocity of 25
m/s and form an angle of 45 degrees against
horizontal direction. Determined the time the ball
flies, the horizontal distance, and the highest point
reached by the ball?
5. Someone wants o shoot a bird on a tree which is
100 m away from the shooter. The bird is 80 m
high from the ground. If the shooter directs his gun
0
to form an angle of
to the horizontal direction,
45
then the initial velocity of the bullet to hit the bird
is?.
THANKS FOR ATTENTION
AND………
SEE YOU NEXT TIME

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Projectil motion

  • 1. PROJECTILE MOTION COURSE : PHYSICS TOPIC : TWO-DIMENSIONAL MOTION GRADE / SEM : XI / 1 ALLOCATED TIME : 2 HOURS SMA NEGERI 1 JEPARA
  • 2. STANDARD COMPETENCY  Analyze nature phenomenon and it’s regularity in coverage of particle’s.
  • 4. INDICATOR Analyze fundamental quantities in linier motion using vector.  Apply vector’s analysis to solve Two Dimensional Motion’s problem (including parabolic motion).  Analyze the relationship of the quantities in Two Dimensional Motion.  Analyze fundamental quantities in circular motion using vector.  Apply vector’s analysis to solve Circular Motion’s Problem. 
  • 5. LEARNING MATERIAL Constant velocity motion  Constant acceleration motion  Two-Dimensional linier motion  Parabolic Motion  Circular Motion 
  • 7.  Material  Simulations  Applications 1  Applications 2  Applications 3  Applications 4  Applications 5  Applications 6
  • 8. CONCLUSSION 1. Projectile motion is motion with a constant horizontal velocity combined with a constant vertical acceleration 2. The projectile moves along a parabola 3. Trajectory parabola, open down a. Total time 44.  t  2 v i sin  g v i sin 2 2 b. Horizontal range X  g v i sin  2 c. Max height h max  2 g
  • 9. 4. Trajectory Half-Parabola, open down  a. Total time 44. x  v i b. Horizontal range c. Final velocity 2h g vf  vf  2 v i  2 gh 2 v i  2 gh
  • 10. SAMPLE PROBLEM 1. A bullet is shot at initial of velocity 40 m/s, and 0 elevation angle of 60 from a flat ground, ait friction neglected and gravitasional acceleration g = 10 m/ 2 . Determined: s a. The time needed by the bullet to reach the highest point H? b. The maximum height reached by the bullet? c. The greatest distance reached by the bullet? Solution v 0 = 40 m/s α = 60 0 g = 10m/s 2
  • 11. a. tH  v 0 sin   40 sin 60 g 40 . 0 1 3 2 10  10  2 3s thus, the time to reach the highest point H is 2 3 sec onds . b. The maximum height reached by the bullet v 0 sin  2 yH  2 2  40 sin 2g 2 60 1600 . 0 4  60 m .  2 . 10 3 20 c. The greatest distance reached by the bullet v 0 sin 2 2 x g 2  40 sin 2 . 60 10 1600 . 0  1 2 10 3  40 3 m .
  • 12. EXERCISE 1. An object is thrown at initial of velocity of 20 m/s from 0 30 point A to the ground with elevation angle if gravitational acceleration g = 10 m / s 2 and air friction neglected,determined: a. the initial velocity component in horizontal and vertical direction. b. the object velocity after 0,5 s. c. the object position after 0,5 s. 2. An object is thrown from the top of a building of which the height is 40 m. The initial velocity of the object is 0 20 m/s and the elevation angle is . 30 Determined the greatest distance in horizontal direction counted from the base of building?.
  • 13. 3. A bullet is shot from a horizontal ground at an elevation angle of 60 0. After 50 seconds, it falls to the ground 4000 m away from where it was 2 thrown. Given g=10 m/ s , calculate the initial velocity of the bullet?. 4. A soccer ball is kicked at an initial velocity of 25 m/s and form an angle of 45 degrees against horizontal direction. Determined the time the ball flies, the horizontal distance, and the highest point reached by the ball? 5. Someone wants o shoot a bird on a tree which is 100 m away from the shooter. The bird is 80 m high from the ground. If the shooter directs his gun 0 to form an angle of to the horizontal direction, 45 then the initial velocity of the bullet to hit the bird is?.