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Amplitude Modulation
                                 m(t)




                                 s(t)
                          AM waveform with
                              ka m ( t ) < 1




                                 s(t)
                       Over-modulated waveform
                             ka m ( t ) > 1




Amplitude Modulation                             1
Amplitude Modulation

The sinusoidal carrier wave :      c ( t ) = Ac cos ( 2π f c t )

The AM waveform, DSB-LC :

 s ( t ) = Ac ⎡1 + ka m ( t ) ⎤ cos ( 2π f c t )
              ⎣               ⎦
            Ac                                     ka Ac
 S( f )=        ⎡δ ( f − f c ) + δ ( f + f c ) ⎤ +
                ⎣                                ⎦       ⎡ M ( f − f c ) + M ( f + f c )⎤
             2                                       2 ⎣                                ⎦

In AM, information pertaining to the message signal m(t) resides solely in the
envelope, which is defined as th amplitude of the modulated wave s(t).
    l      hi h i d fi d the         lit d f th      d l t d         ()
The carrier frequency fc is much greater than the highest frequency component W
of the message signal m(t).

Suppose the message signal m(t) is bandlimited to the interval −W ≤ f ≤ W, as
shown in Fig. 3.2a.


                                Amplitude Modulation                                    2
Amplitude Modulation



The
Th message signal has a
            i lh
bandwidth W Hz.




                                                 2W


                          Amplitude Modulation        3
Amplitude Modulation

Example 3.1             Single-Tone Modulation

      m ( t ) = Am cos ( 2π f m t )

where        fm is its frequency, and
             Am is the amplitude of the sinusoidal modulating wave
    s ( t ) = Ac ⎡1 + μ cos ( 2π f m t ) ⎤ cos ( 2π f c t )
                 ⎣                       ⎦
where μ = ka Am ; Amax = Ac [1 + μ ] ; Amin = Ac [1 − μ ]
         Amax Ac (1 + μ )
and          =            ⇒             Amax Ac − μ Amax Ac = Amin Ac + μ Amin Ac
         Amin Ac (1 − μ )
       Amax − μ Amax = Amin + μ Amin        ⇒     Amax − Amin = μ Amax + μ Amin


                                      Amax − Amin Peak DSB-SC Amplitude
The modulation factor, μ =                        =
                                      Amax + Amin   Peak Carrier A lit d
                                                    P k C i Amplitude
                               Amplitude Modulation                                 4
Amplitude Modulation

    s ( t ) = Ac ⎡1 + μ cos ( 2π f m t ) ⎤ cos ( 2π f c t )
                 ⎣                       ⎦
where μ = ka Am ; Amax = Ac [1 + μ ] ; Amin = Ac [1 − μ ]


            Amax − Amin Peak DSB-SC Amplitude Am
With μ =                =                        =
            Amax + Amin                  p
                          Peak Carrier Amplitude   Ac


                          ⎡ Am ⎤
Amax   = Ac [1 + μ ] = Ac ⎢1 + ⎥ = Ac + Am
                          ⎢ Ac ⎥
                          ⎣    ⎦
                          ⎡ Am ⎤
Amin   = Ac [1 − μ ] = Ac ⎢1 − ⎥ = Ac − Am
                          ⎢ Ac ⎥
                          ⎣    ⎦
   Amax − Amin ( Ac + Am ) − ( Ac − Am ) 2 Am Am
μ=            =                         =    =
   Amax + Amin ( Ac + Am ) + ( Ac − Am ) 2 Ac Ac
                       Amplitude Modulation                   5
Amplitude Modulation, DSB-LC
           p                 ,
3
                                                               Amax

2


                                                               Amin
1



0                                                               0

-1



-2



-3
     0      0.5
            05         1      1.5
                              15       2      2.5
                                              25           3
                                                       -3
                                                    x 10


                  Amax − Amin 2.8 − 1.2 1.6
           μ=                =         =    = 0.4
                  Amax + Amin 2 8 + 1.2 4
                               2.8 1 2

                      Amplitude Modulation                            6
Amplitude Modulation




   Amplitude Modulation   7
Amplitude Modulation, DSB-LC

Example 3.1            Single-Tone Modulation (continued)

 s ( t ) = Ac ⎡1 + μ cos ( 2π f m t ) ⎤ cos ( 2π f c t )
              ⎣                       ⎦
         = Ac cos ( 2π f c t ) + μ Ac cos ( 2π f m t ) cos ( 2π f c t )
                               1                                 1
        = Ac cos ( 2π f c t ) + μ Ac cos ⎡ 2π ( f c + f m )t ⎤ + μ Ac cos ⎡ 2π ( f c − f m )t ⎤
                                         ⎣                   ⎦ 2          ⎣                   ⎦
                               2
          1
S ( f ) = Ac ⎡δ ( f − f c ) + δ ( f + f c ) ⎤
          2 ⎣                               ⎦
          1
          4
                   {
        + μ Ac δ ⎡ f − ( f c + f m ) ⎤ + δ ⎡ f + ( f c + f m ) ⎤
                     ⎣                ⎦      ⎣                  ⎦         }
          1
          4
                   {
        + μ Ac δ ⎡ f − ( f c − f m ) ⎤ + δ ⎡ f + ( f c − f m ) ⎤
                     ⎣                ⎦      ⎣                  ⎦         }
  Can you identify each component in Fig. 3.3c from the above expression?


                                     Amplitude Modulation                                 8
Amplitude Modulation, DSB-LC

Example 3.1             Single-Tone Modulation (continued)

s ( t ) = Ac ⎡1 + μ cos ( 2π f m t ) ⎤ cos ( 2π f c t )
             ⎣                       ⎦
        = Ac cos ( 2π f c t ) + μ Ac cos ( 2π f m t ) cos ( 2π f c t )
The mean square value or time averaged value:
s 2 ( t ) = Ac 2 cos 2 ( 2π f c t ) + μ 2 Ac 2 cos 2 ( 2π f m t ) cos 2 ( 2π f c t )
                     1                                      1 1 1 1    1
Since cos 2 A =         (1 + cos 2 A ) ⇒ cos 2 A = + cos 2 A = + × 0 =
                     2                                      2 2 2 2    2
                           1
Ac 2 cos 2 ( 2π f c t ) = Ac 2 = Carrier Power
                           2
                                                           1 1
μ 2 Ac 2 cos 2 ( 2π f m t ) cos 2 ( 2π f c t ) = μ 2 Ac 2 × ×
                                                           2 2
                         1
                     = μ 2 Ac 2 = Sidebands Power=USB Power + LSB Power
                         4
                                       Amplitude Modulation                            9
Amplitude Modulation, DSB-LC

Example 3.1         Single-Tone Modulation (continued)

                     1 2
Sidebands power =      Ac
                     2
                       1                                1
Upper sideband power = μ 2 Ac 2 ; Lower sideband power = μ 2 Ac 2
                       8                                8
                       1 2 2 1 2 2          1 2
Total sidebands power 8
                         μ Ac + μ Ac         μ       μ2
                     =           8     = 4        =
     Total power        1 2 1 2 2         1 1 2 2 + μ2
                          Ac + μ Ac        + μ
                        2       4         2 4
                         1 2 1 2 2
Total power =   s ( t ) = Ac + μ Ac
                2

                         2    4



                             Amplitude Modulation                   10
Amplitude Modulation, DSB-LC




        Amplitude Modulation   11
Envelope Detection




  Amplitude Modulation   12
Envelope Detection
         An envelope detector is used to detect the
         envelope of the modulated waveform. Any
         circuit whose output follows the envelope of the
         input signal waveform will serve as an envelope
         detector.
         The simplest form of an envelope detector is a
         nonlinear charging circuit with a fast charge
         time and a slow discharge time.
         On the positive half cycles of the input signal,
         the diode is forwarded-biased and the capacitor
                      forwarded biased
         C charges to the peak value of the input signal
         waveform. As the input signal falls below this
         value, the diode is turned off. The capacitor
         slowly discharges through the resistor R until the
         next positive half-cycle. When the input signal
         becomes greater than the capacitor voltage and
         the diode will conduct again and the process is
         repeated.
         repeated

Amplitude Modulation                                      13
Double Sideband-Suppressed Carrier, DSB-SC




                                     m (t )                                    s (t )



                                              c ( t ) = A c cos ( 2π f c t )




              Amplitude Modulation                                                      14
Double Sideband-Suppressed Carrier, DSB-SC

Product modulator is used to generate DSB-SC modulated wave. The
modulated signal s(t) undergoes a phrase reversal whenever the message signal
m(t) crosses zero, as indicated in Fig. 3-10b. The envelope of a DSB-SC
                                          3 10b.                    DSB SC
modulated signal is therefore different from the message signal m(t), which
means that envelope detection is not applicable to retrieve m(t).




                            Amplitude Modulation                                15
Double Sideband-Suppressed Carrier, DSB-SC

s ( t ) = c ( t ) m ( t ) = A c cos ( 2π f c t ) m ( t )
                           1
ℑ{s ( t )} = S ( f ) =       A c ⎡ M ( f − f c ) + M ( f + f c )⎦
                                 ⎣
                                                                ⎤
                           2
The message signal m(t) has a bandwidth of W. The modulation process
translates the spectrum of the message signal by fc to the right and by –fc to the
                                                                         f
left. The transmission bandwidth required by DSB-SC modulation is the same
as that for amplitude modulation, 2W.

The only advantage for DSB-SC is saving transmitted power. The Amplitude
modulation is using DSB-LC. The demodulator is more complex for DSB-SC
than the envelope detector for DSB-LC.




                                          Amplitude Modulation                       16
Coherent Detection
The demodulation of a DSB-SC signal is under the assumption that the local
oscillator of the receiver is exactly coherent or synchronized, in both
frequency and phase, with the modulated signal.




                           Amplitude Modulation                              17
Coherent Detection

If there is a small frequency error, ∆ f, and a phase error, φ, in the local oscillator
of the receiver.
 ν (t )
 = s ( t ) Ac′ cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ m ( t )
                   ⎣                        ⎦                where         s ( t ) = Ac cos ( 2π f c t )

 = Ac Ac′ cos ( 2π f c t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ m ( t )
                               ⎣                        ⎦
                               {
 = Ac Ac′m ( t ) cos ( 2π f c t ) cos ⎡ 2π ( f c + Δ f ) t ⎤ cos φ − sin ⎡ 2π ( f c + Δ f )t ⎤ sin φ
                                      ⎣                    ⎦             ⎣                   ⎦       }
 = A A ′m ( t ) cos ( 2π f t ) {cos ⎣ 2π ( f + Δ f ) t ⎦ cos φ − cos ( 2π f t ) sin ⎣ 2π ( f + Δ f ) t ⎦ sin φ }
      c       c               c     ⎡               c   ⎤                           c   ⎡           c       ⎤

 = A A ′m ( t ) cos ( 2π f t ) ⎡cos ( 2π f t ) cos ( 2π Δ f t ) − sin ( 2π f t ) sin ( 2π Δ f t ) ⎤ cos φ
      c       c               c⎣                c                               c                 ⎦
   − A A ′m ( t ) cos ( 2π f t ) ⎡sin ( 2π f t ) cos ( 2π Δ f t ) − cos ( 2π f t ) sin ( 2π Δ f t ) ⎤ sin φ
          c       c              ⎣c                 c                                   c            ⎦
 = A A ′m ( t ) {cos ( 2π f t ) cos ( 2π Δ f t ) cos φ − cos ( 2π f t ) sin ( 2π f t ) sin ( 2π Δ f t ) cos φ }
      c       c
                        2
                                  c                                    c                    c


   − A A ′m ( t ) {cos ( 2π f t ) sin ( 2π f t ) cos ( 2π Δ f t ) sin φ − cos ( 2π f t ) sin ( 2π Δ f t ) sin φ }
          c       c                   c             c
                                                                                    2
                                                                                                c




                                             Amplitude Modulation                                            18
Coherent Detection
ν ( t ) = Ac Ac′m ( t ) cos 2 ( 2π f c t ) ⎡cos ( 2π Δ f t ) cos φ − sin ( 2π Δ f t ) sin φ ⎤
                                           ⎣                                                ⎦
          − Ac Ac′m ( t ) cos ( 2π f c t ) sin ( 2π f c t ) ⎡sin ( 2π Δ f t ) cos φ + cos ( 2π Δ f t ) sin φ ⎤
                                                            ⎣                                                ⎦
      = Ac Ac′m ( t ) cos 2 ( 2π f c t ) ⎡cos ( 2π Δ f t ) cos φ − sin ( 2π Δ f t ) sin φ ⎤
                                         ⎣                                                ⎦
          − Ac Ac′m ( t ) cos ( 2π f c t ) sin ( 2π f c t ) ⎡sin ( 2π Δ f t ) cos φ + cos ( 2π Δ f t ) sin φ ⎤
                                                            ⎣                                                ⎦
      = Ac Ac′m ( t ) cos 2 ( 2π f c t ) cos ( 2π Δ f t+ φ ) − Ac Ac′m ( t ) cos ( 2π f c t ) sin ( 2π f c t ) sin ( 2π Δ f t+ φ )
                                                                                               i                i
                                                                                 1
With sin ( A + A ) = sin 2 A = 2 cos A sin A ⇒ cos A sin A = sin 2 A, then
                                                                                 2
                                                                               sin ( 4π f c t )
ν ( t ) = Ac Ac′m ( t ) cos 2 ( 2π f c t ) cos ( 2π Δ f t+ φ ) − Ac Ac′m ( t )                  sin ( 2π Δ f t+ φ )
                                                                                      2
                                                                    A A′
       = Ac Ac ′m ( t ) ⎡1 + cos 4π f c t ⎤ cos ( 2π Δ f t + φ ) − c c m ( t ) sin ( 4π f c t ) sin ( 2π Δ f t + φ )
                        ⎢        2          ⎥                         2
                        ⎣                   ⎦
           Ac Ac′                                      Ac Ac′
      =               m ( t ) cos ( 2π Δ f t + φ ) +            m ( t ) cos ( 4π f c t ) cos ( 2π Δ f t + φ )
              2                                          2
              Ac Ac′
          −            m ( t ) sin ( 4π f c t ) sin ( 2π Δ f t + φ )
                  2
                                                   Amplitude Modulation                                                  19
Coherent Detection

           Ac Ac′                                        Ac Ac′
ν (t ) =      m ( t ) cos ( 4π f c t + 2π Δ f t + φ ) +   m ( t ) cos ( 2π Δ f t + φ )
          2                                             2
The first term is centered at ± 2 f c + Δ f and can be filtered out by the LPF.

                                                                                  Ac Ac′
Unless both ∆ f and φ are zero, otherwise v(t) is not equal to                             m (t ).
                                                                                     2
                              Ac Ac′
If ∆ f = 0, then ν ( t ) =             m ( t ) cos φ .
                                 2

This phase error in the local carrier causes an attenuation of the output signal
proportional to the cosine of the phase error, φ.

                             Ac Ac′
If φ = 0, then ν ( t ) =
       0                              m ( t ) cos 2π Δ f t.
                                2

If φ = 90º, the received signal will be wiped out, v(t) = 0.


                                     Amplitude Modulation                                            20
Coherent Detection
The second term can be expressed as:
             Ac Ac′
ν 0 (t ) =            m ( t ) cos ( 2π Δ f t + φ )
                2
             1
        =      Ac Ac′m ( t ) ⎡ cos ( 2π Δ f t ) cos φ − sin ( 2π Δ f t ) sin φ ⎤
                             ⎣                                                 ⎦
             2

 This phase error in the local carrier causes an attenuation of the output signal
 proportional to the cosine of the phase error φ, and Δ f is usually within ± 2%
 of the carrier frequency.
                                       Ac Ac′
 If φ = 0, then ν 0 ( t ) =
        0                                       m ( t ) cos 2π Δ f t.
                                          2
 If φ = 90º, the received signal will be wiped out, v0 (t) ≈ 0.
 I general, th phase error φ i not constant. It i necessary t synchronize th
 In       l the h              is t       t t is            to    h i the
 local oscillator in the receiver in both frequency and phase with the carrier
 wave to generate the DSB-SC modulated signal in the transmitter.


                                              Amplitude Modulation                  21
Coherent Detection




             Ac Ac′
ν 0 (t ) =            m ( t ) cos 2π Δ f t.
               2




                   Amplitude Modulation       22
Costas Receiver




 Amplitude Modulation   23
Costas Receiver
This receiver consists of two coherent detectors supplied with the same
input signal, Ac cos (2π fc t) m(t), but with two local oscillator signals that
are in phase quadrature with respect to each other.
Suppose the local oscillator drifts from its proper value by a small angle φ
radians. The I-channel output is proportional to cos φ and cos φ ≈ 1 for
small φ. The Q-channel output will have the same polarity as the I-channel
output for one direction of local oscillator phase driftφ and the opposite
polarity for the opposite direction of φ.
By combining the I- and Q-channel outputs in a phase discriminator (which
consists of a multiplier followed by a time-averaging unit), a dc control
signal proportional to the phase drift φ is generated. With negative feedback
acting around the Costas receiver, the control signal tends to automatically
correct for the local phase error φ in the voltage-controlled oscillator.
                                           voltage controlled




                             Amplitude Modulation                                 24
Single-Sideband Modulation, SSB

Modulating signal: m ( t ) = Am cos ( 2π f m t )
Carrier signal:
          g               c ( t ) = Ac cos ( 2π f c t )
S DSB − SC ( t ) = c ( t ) m ( t ) = Ac Am cos ( 2π f c t ) cos ( 2π f m t )
                  1                                    1
                =   Ac Am cos ⎡ 2π ( f c + f m ) t ⎤ + Ac Am cos ⎡ 2π ( f c − f m ) t ⎤
                              ⎣                    ⎦ 2             ⎣                   ⎦
                  2
                  1
S SSB + ( t )   =   Ac Am cos ⎡ 2π ( f c + f m ) t ⎤
                              ⎣                    ⎦
                  2
                  1                                          1
                =   Ac Am cos ( 2π f c t ) cos ( 2π f m t ) − Ac Am sin ( 2π f c t ) sin ( 2π f m t )
                  2                                          2
                  1
S SSB − ( t )   =   Ac Am cos ⎡ 2π ( f c − f m ) t ⎤
                              ⎣                    ⎦
                  2
                  1                                          1
                =   Ac Am cos ( 2π f c t ) cos ( 2π f m t ) + Ac Am sin ( 2π f c t ) sin ( 2π f m t )
                  2                                          2
                  1                                          1
S SSB ± ( t )   =   Ac Am cos ( 2π f c t ) cos ( 2π f m t ) ∓ Ac Am sin ( 2π f c t ) sin ( 2π f m t )
                  2                                          2

                                       Amplitude Modulation                                             25
Single-Sideband Modulation, SSB

                    1                                           1
S SSB ± ( t )   =     Ac Am cos ( 2π f c t ) cos ( 2π f m t ) ∓ Ac Am sin ( 2π f c t ) sin ( 2π f m t )
                    2                                           2
                    1                              1
                =     Ac m ( t ) cos ( 2π f c t ) ∓ Ac m ( t ) sin ( 2π f c t )
                    2                              2


 where m(t) can b d i d from m(t) simply by shifting the phase of each
   h     ()     be derived f  ( ) i l b hif i         h h       f    h
 frequency component by −90º.
 The signal m(t) is the Hilbert transform of the signal m(t) .




                                     Amplitude Modulation                                                 26
Hilbert Transform

The transfer function of a Hilbert transform is defined by:
The signum function, sgn(f) is defined as:
                                                     sgn ( t )

                ⎧+1 t > 0
                ⎪
    sgn ( t ) = ⎨ 0 t = 0
                ⎪
                ⎩−1 t < 0



The Hilbert transformer is a wide-band phase-shifter, the frequency response is
characterized in two parts:
The magnitude response is unity for all frequencies, both positive and negative.
       g           p           y           q              p              g
The phase response is +90º for negative frequencies -90º for positive frequencies.




                              Amplitude Modulation                               27
Frequency Discrimination Method for SSB
The SSB modulator of Fig. 3.19 consists of two components: product
modulator followed by a band-pass filter (BPF). The product modulator
produces a DSB-SC modulated wave with an upper sideband and a lower
sideband. The BPF is designed to transmit one of these two sidebands,
depending on whether the USB or LSB is the desired modulation.
                                                     M(f)




                                                                                                                     f
                                                               fa   fb                         fc
                                                      S( f )




                                                                                                                     f
                                                                                               fc + f a   f c + fb
                                                      S( f )




                                                                                                                     f
                                                                           fc − fb   fc − fa

        Figure 3.18 (a) Spectrum of a message signal m(t) with energy gay centered around zero frequency.
        Corresponding spectra of SSB modulated waves using (b) upper sideband, and (c) lower sideband. In parts (b)
                                   SSB-modulated
        and (c), the spectra are only shown for positive frequencies.


                                          Amplitude Modulation                                                           28
Frequency Discrimination Method for SSB




For the design of the BPF to be practically feasible, there must be a certain
separation between the two sidebands that is wide enough to accommodate the
transition band of the BPF. The separation is equal to 2fa, where fa is the lowest
frequency component of the message signal, as shown in Fig. 3.18. This
requirement limits the applicability of SSB modulation to speech signals for
which fa ≈ 100 Hz.
                             Amplitude Modulation                                    29
Coherent Detection of SSB




The coherent detection requires synchronization of a local oscillator in the
receiver with the oscillator responsible for generating the carrier in the
transmitter. The synchronization requirement has to be in both phase and
frequency.

                             Amplitude Modulation                              30
Vestigial Sideband (VSB) Modulation
SSB modulation works well with speech signal that has an energy gap centered
around zero frequency. For wideband signal like television transmission signal
will benefit by not using double sidebands, and SSB will make it impossible to
implement.

The television transmission, 525 lines of video information are sent in 1/30 (30
frames per second) of a second (that is, 15,750 lines per second – the
horizontal trace frequency). Allowing time for retrace and synchronization, this
requires a minimum video bandwidth of 4 MHz to transmit an array of picture
elements. The transfer function of a Hilbert transform is defined by:
The signum function sgn(f) is defined as:
             function,

                        ⎧ + 1,      t >0
                        ⎪
            sgn ( t ) = ⎨ 0,        t =0
                        ⎪ −1,       t<0
                        ⎩



                                 Amplitude Modulation                              31
Vestigial Sideband (VSB) Modulation
VSB modulation overcomes two of the difficulties present in SSB modulation.
By allowing a portion of the unwanted sideband to appear at the output of an
SSB modulator, the design of the sideband filter is simplified since the sharp
cut-off at the carrier frequency is not required. The bandwidth of a VSB
modulated signal is defined by BT = fv + W      where fv is the vestigial
bandwidth and W is the message bandwidth. The VSB bandwidth BT
compromises between the SSB bandwidth W and DSB-SC bandwidth 2W
                               bandwidth, W,     DSB SC bandwidth, 2W.




                             Amplitude Modulation                                32
Sideband Shaping Filter
In VSB modulation, only a portion of one sideband is transmitted in such a
way that the demodulation process reproduces the original signal. The partial
suppression of one sideband reduces the required bandwidth from that required
for DSB but does not match the spectrum efficiency of SSB. The spectrum
shaping is defined by the transfer function of the filter, which is denoted by
H( f ). The only requirement that the sideband shaping performed by H( f )
must satisfy is that the transmitted vestige compensates for the spectral portion
missing from the other sideband.
The sideband shaping filter must satisfy the following condition:

          H ( f + fc ) + H ( f − fc ) = 1      for − W ≤ f ≤ W
where
          fc is the carrier frequency.
The term H( f + fc ) is the positive-frequency part of the band-pass transfer
function H( f ) shifted to the left by fc, and H( f − fc ) is the negative-frequency
p
part of H( f ) shifted to the right by fc.
         (                      g    y

                                Amplitude Modulation                                   33
Sideband Shaping Filter
The transfer function of the sideband shaping filter is anti-symmetric about the
carrier frequency, fc.
The transfer function is required to satisfy the odd symmetry only for the
frequency interval, −W ≤ f ≤ W, where W is the message bandwidth.




                                                                  f
                    − fc                              fc




                                                                  f




                                                                  f




                               Amplitude Modulation                                34
Demodulation of SSB signals (1 of 5)
For demodulation, the spectral density of the SSB signal must be translated
back to f = 0. Multiplication of the SSB signal by cos(2π fc t) translates half of
each spectral density up in frequency by fc and half down by the same amount..


                                                                                          e0 ( t )
                                     S SSB ± ( t )



                                                       cos ( 2π f c t )




                                                                                                                                       f
                                                                  − fm            fm

                                                                          S SSB + ( t )


                                                                                                                                       f
                         − ( fc + fm )    fc                                                         fc   fc + fm




                                                                                                                                       f
− ( 2 fc + f m ) 2 fc                                             − fm            fm                                2 fc 2 fc + f m




                                                     Amplitude Modulation                                                             35
Demodulation of SSB signals (2 of 5)
With the frequency and phase errors in the demodulation process:
         S SSB ∓ ( t ) = f ( t ) cos ( 2π f c t ) ± f ( t ) sin ( 2π f c t )

Let the locally generated carrier signal be cos ⎡ 2π ( f c + Δ f ) t + φ ⎦
                                                ⎣                        ⎤                           where
Δ f is the frequency error and φ is the phase error.

S SSB ∓ ( t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤
                  ⎣                        ⎦
= ⎡ f ( t ) cos ( 2π f c t ) ± f ( t ) sin ( 2π f c t ) ⎤ cos ⎡ 2π ( f c + Δ f ) t + φ ⎤
  ⎣                                                     ⎦     ⎣                        ⎦
= f ( t ) cos ( 2π f c t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ ± f ( t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ sin ( 2π f c t )
                               ⎣                        ⎦               ⎣                        ⎦

The first term can be expressed as:                   ⎡ Note: 2 cos A cos B = cos ( A + B ) + cos ( A − B ) ⎤
                                                      ⎣                                                     ⎦
f ( t ) cos ( 2π f c t ) cos ⎣ 2π ( f c + Δ f ) t + φ ⎦
                             ⎡                        ⎤
 1                                                    1
=  f ( t ) cos ⎡ 2π f c t + 2π ( f c + Δ f ) t + φ ⎤ + f ( t ) cos ⎡ 2π f c t − 2π ( f c + Δ f ) t + φ ⎤
               ⎣                                   ⎦ 2             ⎣                                   ⎦
 2
 1                                            1
= f ( t ) cos [ 4π f c t + 2π Δ f t + φ ] + f ( t ) cos [ 2π Δ f t + φ ]
 2                                            2
                                             Amplitude Modulation                                                     36
Demodulation of SSB signals (3 of 5)
The seond term can be expressed as:                   ⎡ Note: 2 cos A sin B = sin ( A + B ) − sin ( A − B ) ⎤
                                                      ⎣                                                     ⎦
f ( t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ sin ( 2π f c t )
            ⎣                        ⎦
 1                                                    1
=  f ( t ) sin ⎡ 2π ( f c + Δ f ) t + φ + 2π f c t ⎤ − f ( t ) sin ⎡ 2π ( f c + Δ f ) t + φ − 2π f c t ⎤
               ⎣                                   ⎦ 2             ⎣                                   ⎦
 2
 1                                         1
= f ( t ) sin [ 4π f c t + 2π Δf t + φ ] − f ( t ) sin [ 2π Δ f t + φ ]
 2                                         2
Now, S SSB ∓ ( t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤
                       ⎣                        ⎦
= f ( t ) cos ( 2π f c t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ ± f ( t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ sin ( 2π f c t )
                               ⎣                        ⎦               ⎣                        ⎦
 1
=  f ( t ) {cos [ 4π f c t + 2π Δ f t + φ ] + cos [ 2π Δ f t + φ ]}
 2
             1
            ± f ( t ) {sin [ 4π f c t + 2π Δf t + φ ] − sin [ 2π Δ f t + φ ]}
             2                         Filtered out
 1
= f ( t ) {cos [ 4π f c t + 2π Δ f t + φ ] + cos [ 2π Δ f t + φ ]}
 2                                                                     Filtered out
             1
            ∓ f ( t ) {sin [ 2π Δ f t + φ ] − sin [ 4π f c t + 2π Δf t + φ ]}
                          i                       i
             2
                                           Amplitude Modulation                                                       37
Demodulation of SSB signals (4 of 5)
The LPF in the SSB demodulator will filter out the higher frequencies
component. Thus the output
                      1                               1
         e0 ( t ) =     f ( t ) cos [ 2π Δ f t + φ ] ∓ f ( t ) sin [ 2π Δ f t + φ ]
                                                                i
                      2                               2
                                               1
If Δ f = 0, and φ = 0, then e0 ( t ) =           f (t ).
                                               2
                                               1                1
If Δ f = 0, and φ ≠ 0, then e0 ( t ) =           f ( t ) cos φ ∓ f ( t ) sin φ .
                                               2                2

This give phase distortion in the receiver output. The SSB-SC demodulation is
quite tolerate for voice communication.

                                                1                          1
If φ = 0 and Δ f ≠ 0 then e0 ( t ) =
       0,          0,                             f ( t ) cos ( 2π Δf t ) ∓ f ( t ) sin ( 2π Δf t ) .
                                                                                     i
                                                2                          2
This frequency errors give rise to spectral shifts as well as to phase distortion
in the demodulation output. If Δ f is small, these spectral shifts can be tolerated
                       p                   ,        p
in voice communications.
                                        Amplitude Modulation                                            38
Demodulation of SSB signals                                   (5 of 5)


If the frequency error, Δf = fm , then the spectrum is inverted. The high
frequency spectral components will become the low frequency components and
vice versa.
This spectral inversion scrambles the speech quite unintelligible and this can be
used as a low-level speech scramblers to ensure communication privacy

     f (t )

                                                                                 fc        fc + fm
              cos2π ( fc + fm ) t




                                                                                                       f
                                                     − fm                   fm
                                                                                                 fc
                                                            S SSB + ( t )


                                                                                                       f
                           − ( fc + fm )   fc                                         fc    fc + fm
                                                            S SSB − ( t )                    fc + fm



                                                                                                       f
                           − ( fc + fm )   fc                                         fc    fc + fm
                                                Amplitude Modulation                                   39
Superheterodyne Receiver
Heterodyning means the translating or shifting in frequency. In the heterodyne
receiver the incoming modulated signal is translated in frequency, thus
occupying an equal bandwidth centered about a new frequency. This new
frequency is known as an intermediate frequency (IF) which is fixed and is not
dependent on the received signal frequency. The signal is amplified at the IF
before demodulation. If the IF is lower than the received carrier frequency but
above the final output signal frequency it is called a superheterodyne receiver
                              frequency,                               receiver.




                             Amplitude Modulation                                  40
Superheterodyne Receiver
The intermediate frequency (IF) for most common AM broadcast receivers is
455 KHz. AM band is from 540 KHz ~ 1600 KHz.
The required frequency translation to the IF is accomplished by mixing the
incoming signal with a locally generated signal which differs from the
incoming carrier by the IF (455 KHz). The received signal now translated to a
fixed IF, and it can be easily be amplified, filterer and demodulated. All the
amplification and filtering is performed at a fixed frequency regardless of
station selection.
The locally generated frequency is chosen to be 455 KHz higher than the
incoming signal, because it is easier to build oscillators which are reasonably
linear within 1~2 MHz range than 0.1~1 MHz range (455 KHz lower than the
incoming signal).
                          AM band: 540 KH ~ 1600 KH
                             b d       KHz       KHz
455 KHz higher than the incoming signal: ( 540 + 455) KHz ~ (1600 + 455) KHz
455 KHz lower than the incoming signal: (540 − 455) KHz ~ (1600 – 455) KHz


                               Amplitude Modulation                               41
Superheterodyne Receiver


                                f IF                      f IF                                            f IF                f IF
                                                                                                                                                                   f
           − ( f c + 2 f IF )                                         − fc                           fc                                   f c + 2 f IF

                        fc                                       fc                                  fc                              fc



                                                                                                                                                                   f
                                       − ( f c + f IF )                                                          f c + f IF




                                                                                                                                                                   f
 − ( 2 f c + f IF )                                                          − f IF           f IF                                                 2 f c + f IF




If there is another station broadcasting at ( fc+2fIF ) KHz the signal will also be
                                                        KHz,
mapped into the IF band. This signal is called the image frequency which is not the
desired signal. This is the only drawback in superheterodyne receiver.



                                                                              Amplitude Modulation                                                                42
Dual Conversion Receiver




A telemetry receiver is designed to receive satellite transmissions at 136 MHz.
The receiver uses two heterodyne operations with intermediate frequencies of
30 MHz and 10 MHz The first local oscillator is designed to operate below the
                 MHz.
incoming carrier frequency; the second one, above the first (30 MHz)
intermediate frequency. What possible input frequencies could result in images
for both mixers if the filters were not ideal?


                             Amplitude Modulation                                 43
Dual Conversion Receiver

The first local oscillator is operating at 136 MHz − 30 MHz = 106 MHz.
The other frequency of transmission @ 106 MHz − 30 MHz = 76 MHz will
 also map to IF1.
The second local oscillator is operating at 30 MHz +10 MHz = 40 MHz.
If 40 MHz +10 MHz = 50 MHz is not attenuated significantly after passing
  IF1, then the 50 MHz will also map to IF2. Then the possible image
  frequencies are:
 106 − 40 = 56 MHz ; 106 − 30 = 76 MHz ; 106 + 50 = 156 MHz
Check:
• LO1=106 MHz, 106 −56 = 50 MHz. If this 50 MHz appears at the output of
  IF1, it will also map to IF2. 50 −40 = 10 MHz.
                                    40      MHz
• LO1=106 MHz, 106 −76 = 30 MHz. (IF1=30 MHz)
• LO1=106 MHz, 156 −106 = 50 MHz. If this 50 MHz appears at the output
  of IF1, it will also map to IF2, for 50 −40 = 10 MHz.

                           Amplitude Modulation                            44
Stereo Multiplex System

l (t )   +
             ∑
                   bg bg ×
                  l t −r t

             −
                                                                         +
r (t )
                            cos2π fc t
                                           38 KHz         19 KHz   +
                                                                          ∑
                                                                                  bg
                                                                                xb t
                                                    ÷2
                                                                         +
             +

         +   ∑ l bt g + r bt g




         0                   15 KHz 23 KHz                             53 KHz
                                                                                       f
                                  19 KHz                 38 KHz




                                           Amplitude Modulation                            45
Time-Averaged Noise Representations

Suppose n(t) is a noise voltage or current (assume a 1-ohm resistive load):

                                                          1
1. Mean value, n ( t ) :                     n ( t ) = lim    n ( t ) dt
                                                     T →∞ T ∫
             ,
                                                            T

   This is often referred to as the dc or average, value of n(t).

2. Mean-square value,      n 2( t ):         n 2( t ) = lim
                                                             1
                                                                 n ( t ) dt
                                                                        2

                                                        T →∞ T ∫
                                                               T

   The square root of n 2( t ) is called the root-mean-square (rms) value of n(t).

3. AC component, σ(t) :
                            σ (t ) ≈ n (t ) − n (t ) ⇒ n (t ) = n (t ) + σ (t )
                                          1                  1                 2
                           n ( t ) = lim ∫ n ( t ) dt = lim ∫ n ( t ) + σ ( t ) dt
                             2                    2

                                     T →∞ T             T →∞ T
                                            T                  T

                                          1       2          1
                                   = lim ∫ n ( t ) dt + lim ∫ σ ( t ) dt
                                                                     2

                                     T →∞ T             T →∞ T
                                            T                  T

                                 Amplitude Modulation                                46
Time-Averaged Noise Representations

The ac, or fluctuation, component of n(t) is that component which remains
after the mean value, n ( t ) , had been taken out.

                     1                  1                 2
      n ( t ) = lim ∫ n ( t ) dt = lim ∫ n ( t ) + σ ( t ) dt
        2                    2

                T →∞ T             T →∞ T
                       T                  T

                    1       2          1
             = lim ∫ n ( t ) dt + lim ∫ σ ( t ) dt
                                               2

               T →∞ T             T →∞ T
                      T                  T


The term on the left-hand side of the above equation is the time-averaged
power in n(t) across a 1 ohm resistor The first term on the right hand side is
                        1-ohm resistor.                          right-hand
the dc power and the second term, the ac power in n(t). The rms value of n(t)
is equal to the rms value of σ(t) only if the mean value n ( t ) is zero.




                              Amplitude Modulation                               47
Time-Averaged Noise Representations

Example:
Compute the (a) average value, (b) ac power, and © rms value of the periodic
waveform v ( t ) = 1 + cos 2π f 0 t .
    f

                  1
a)     v (t ) =     ∫ (1 + cos 2π f0 t )dt = 1
                  TT

                  1                       1 1                         1
b) σ 2( t ) =       ∫ ( cos 2π f0 t ) dt = ∫ (1 + cos 4π f 0 t ) dt =
                                     2

                  TT                      TT2                         2


c) v 2( t ) = 1 ∫ (1 + cos 2π f 0 t )2 dt = 1 ∫ (1 + cos 4π f 0 t + cos 2 2π f 0 t ) dt = 1 + 1 = 3
                  T   T
                                                 T   T
                                                                                            2    2

                             3
     vrms = v 2( t ) =         = true rms value
                             2




                                         Amplitude Modulation                                         48

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7 amplitude modulation

  • 1. Amplitude Modulation m(t) s(t) AM waveform with ka m ( t ) < 1 s(t) Over-modulated waveform ka m ( t ) > 1 Amplitude Modulation 1
  • 2. Amplitude Modulation The sinusoidal carrier wave : c ( t ) = Ac cos ( 2π f c t ) The AM waveform, DSB-LC : s ( t ) = Ac ⎡1 + ka m ( t ) ⎤ cos ( 2π f c t ) ⎣ ⎦ Ac ka Ac S( f )= ⎡δ ( f − f c ) + δ ( f + f c ) ⎤ + ⎣ ⎦ ⎡ M ( f − f c ) + M ( f + f c )⎤ 2 2 ⎣ ⎦ In AM, information pertaining to the message signal m(t) resides solely in the envelope, which is defined as th amplitude of the modulated wave s(t). l hi h i d fi d the lit d f th d l t d () The carrier frequency fc is much greater than the highest frequency component W of the message signal m(t). Suppose the message signal m(t) is bandlimited to the interval −W ≤ f ≤ W, as shown in Fig. 3.2a. Amplitude Modulation 2
  • 3. Amplitude Modulation The Th message signal has a i lh bandwidth W Hz. 2W Amplitude Modulation 3
  • 4. Amplitude Modulation Example 3.1 Single-Tone Modulation m ( t ) = Am cos ( 2π f m t ) where fm is its frequency, and Am is the amplitude of the sinusoidal modulating wave s ( t ) = Ac ⎡1 + μ cos ( 2π f m t ) ⎤ cos ( 2π f c t ) ⎣ ⎦ where μ = ka Am ; Amax = Ac [1 + μ ] ; Amin = Ac [1 − μ ] Amax Ac (1 + μ ) and = ⇒ Amax Ac − μ Amax Ac = Amin Ac + μ Amin Ac Amin Ac (1 − μ ) Amax − μ Amax = Amin + μ Amin ⇒ Amax − Amin = μ Amax + μ Amin Amax − Amin Peak DSB-SC Amplitude The modulation factor, μ = = Amax + Amin Peak Carrier A lit d P k C i Amplitude Amplitude Modulation 4
  • 5. Amplitude Modulation s ( t ) = Ac ⎡1 + μ cos ( 2π f m t ) ⎤ cos ( 2π f c t ) ⎣ ⎦ where μ = ka Am ; Amax = Ac [1 + μ ] ; Amin = Ac [1 − μ ] Amax − Amin Peak DSB-SC Amplitude Am With μ = = = Amax + Amin p Peak Carrier Amplitude Ac ⎡ Am ⎤ Amax = Ac [1 + μ ] = Ac ⎢1 + ⎥ = Ac + Am ⎢ Ac ⎥ ⎣ ⎦ ⎡ Am ⎤ Amin = Ac [1 − μ ] = Ac ⎢1 − ⎥ = Ac − Am ⎢ Ac ⎥ ⎣ ⎦ Amax − Amin ( Ac + Am ) − ( Ac − Am ) 2 Am Am μ= = = = Amax + Amin ( Ac + Am ) + ( Ac − Am ) 2 Ac Ac Amplitude Modulation 5
  • 6. Amplitude Modulation, DSB-LC p , 3 Amax 2 Amin 1 0 0 -1 -2 -3 0 0.5 05 1 1.5 15 2 2.5 25 3 -3 x 10 Amax − Amin 2.8 − 1.2 1.6 μ= = = = 0.4 Amax + Amin 2 8 + 1.2 4 2.8 1 2 Amplitude Modulation 6
  • 7. Amplitude Modulation Amplitude Modulation 7
  • 8. Amplitude Modulation, DSB-LC Example 3.1 Single-Tone Modulation (continued) s ( t ) = Ac ⎡1 + μ cos ( 2π f m t ) ⎤ cos ( 2π f c t ) ⎣ ⎦ = Ac cos ( 2π f c t ) + μ Ac cos ( 2π f m t ) cos ( 2π f c t ) 1 1 = Ac cos ( 2π f c t ) + μ Ac cos ⎡ 2π ( f c + f m )t ⎤ + μ Ac cos ⎡ 2π ( f c − f m )t ⎤ ⎣ ⎦ 2 ⎣ ⎦ 2 1 S ( f ) = Ac ⎡δ ( f − f c ) + δ ( f + f c ) ⎤ 2 ⎣ ⎦ 1 4 { + μ Ac δ ⎡ f − ( f c + f m ) ⎤ + δ ⎡ f + ( f c + f m ) ⎤ ⎣ ⎦ ⎣ ⎦ } 1 4 { + μ Ac δ ⎡ f − ( f c − f m ) ⎤ + δ ⎡ f + ( f c − f m ) ⎤ ⎣ ⎦ ⎣ ⎦ } Can you identify each component in Fig. 3.3c from the above expression? Amplitude Modulation 8
  • 9. Amplitude Modulation, DSB-LC Example 3.1 Single-Tone Modulation (continued) s ( t ) = Ac ⎡1 + μ cos ( 2π f m t ) ⎤ cos ( 2π f c t ) ⎣ ⎦ = Ac cos ( 2π f c t ) + μ Ac cos ( 2π f m t ) cos ( 2π f c t ) The mean square value or time averaged value: s 2 ( t ) = Ac 2 cos 2 ( 2π f c t ) + μ 2 Ac 2 cos 2 ( 2π f m t ) cos 2 ( 2π f c t ) 1 1 1 1 1 1 Since cos 2 A = (1 + cos 2 A ) ⇒ cos 2 A = + cos 2 A = + × 0 = 2 2 2 2 2 2 1 Ac 2 cos 2 ( 2π f c t ) = Ac 2 = Carrier Power 2 1 1 μ 2 Ac 2 cos 2 ( 2π f m t ) cos 2 ( 2π f c t ) = μ 2 Ac 2 × × 2 2 1 = μ 2 Ac 2 = Sidebands Power=USB Power + LSB Power 4 Amplitude Modulation 9
  • 10. Amplitude Modulation, DSB-LC Example 3.1 Single-Tone Modulation (continued) 1 2 Sidebands power = Ac 2 1 1 Upper sideband power = μ 2 Ac 2 ; Lower sideband power = μ 2 Ac 2 8 8 1 2 2 1 2 2 1 2 Total sidebands power 8 μ Ac + μ Ac μ μ2 = 8 = 4 = Total power 1 2 1 2 2 1 1 2 2 + μ2 Ac + μ Ac + μ 2 4 2 4 1 2 1 2 2 Total power = s ( t ) = Ac + μ Ac 2 2 4 Amplitude Modulation 10
  • 11. Amplitude Modulation, DSB-LC Amplitude Modulation 11
  • 12. Envelope Detection Amplitude Modulation 12
  • 13. Envelope Detection An envelope detector is used to detect the envelope of the modulated waveform. Any circuit whose output follows the envelope of the input signal waveform will serve as an envelope detector. The simplest form of an envelope detector is a nonlinear charging circuit with a fast charge time and a slow discharge time. On the positive half cycles of the input signal, the diode is forwarded-biased and the capacitor forwarded biased C charges to the peak value of the input signal waveform. As the input signal falls below this value, the diode is turned off. The capacitor slowly discharges through the resistor R until the next positive half-cycle. When the input signal becomes greater than the capacitor voltage and the diode will conduct again and the process is repeated. repeated Amplitude Modulation 13
  • 14. Double Sideband-Suppressed Carrier, DSB-SC m (t ) s (t ) c ( t ) = A c cos ( 2π f c t ) Amplitude Modulation 14
  • 15. Double Sideband-Suppressed Carrier, DSB-SC Product modulator is used to generate DSB-SC modulated wave. The modulated signal s(t) undergoes a phrase reversal whenever the message signal m(t) crosses zero, as indicated in Fig. 3-10b. The envelope of a DSB-SC 3 10b. DSB SC modulated signal is therefore different from the message signal m(t), which means that envelope detection is not applicable to retrieve m(t). Amplitude Modulation 15
  • 16. Double Sideband-Suppressed Carrier, DSB-SC s ( t ) = c ( t ) m ( t ) = A c cos ( 2π f c t ) m ( t ) 1 ℑ{s ( t )} = S ( f ) = A c ⎡ M ( f − f c ) + M ( f + f c )⎦ ⎣ ⎤ 2 The message signal m(t) has a bandwidth of W. The modulation process translates the spectrum of the message signal by fc to the right and by –fc to the f left. The transmission bandwidth required by DSB-SC modulation is the same as that for amplitude modulation, 2W. The only advantage for DSB-SC is saving transmitted power. The Amplitude modulation is using DSB-LC. The demodulator is more complex for DSB-SC than the envelope detector for DSB-LC. Amplitude Modulation 16
  • 17. Coherent Detection The demodulation of a DSB-SC signal is under the assumption that the local oscillator of the receiver is exactly coherent or synchronized, in both frequency and phase, with the modulated signal. Amplitude Modulation 17
  • 18. Coherent Detection If there is a small frequency error, ∆ f, and a phase error, φ, in the local oscillator of the receiver. ν (t ) = s ( t ) Ac′ cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ m ( t ) ⎣ ⎦ where s ( t ) = Ac cos ( 2π f c t ) = Ac Ac′ cos ( 2π f c t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ m ( t ) ⎣ ⎦ { = Ac Ac′m ( t ) cos ( 2π f c t ) cos ⎡ 2π ( f c + Δ f ) t ⎤ cos φ − sin ⎡ 2π ( f c + Δ f )t ⎤ sin φ ⎣ ⎦ ⎣ ⎦ } = A A ′m ( t ) cos ( 2π f t ) {cos ⎣ 2π ( f + Δ f ) t ⎦ cos φ − cos ( 2π f t ) sin ⎣ 2π ( f + Δ f ) t ⎦ sin φ } c c c ⎡ c ⎤ c ⎡ c ⎤ = A A ′m ( t ) cos ( 2π f t ) ⎡cos ( 2π f t ) cos ( 2π Δ f t ) − sin ( 2π f t ) sin ( 2π Δ f t ) ⎤ cos φ c c c⎣ c c ⎦ − A A ′m ( t ) cos ( 2π f t ) ⎡sin ( 2π f t ) cos ( 2π Δ f t ) − cos ( 2π f t ) sin ( 2π Δ f t ) ⎤ sin φ c c ⎣c c c ⎦ = A A ′m ( t ) {cos ( 2π f t ) cos ( 2π Δ f t ) cos φ − cos ( 2π f t ) sin ( 2π f t ) sin ( 2π Δ f t ) cos φ } c c 2 c c c − A A ′m ( t ) {cos ( 2π f t ) sin ( 2π f t ) cos ( 2π Δ f t ) sin φ − cos ( 2π f t ) sin ( 2π Δ f t ) sin φ } c c c c 2 c Amplitude Modulation 18
  • 19. Coherent Detection ν ( t ) = Ac Ac′m ( t ) cos 2 ( 2π f c t ) ⎡cos ( 2π Δ f t ) cos φ − sin ( 2π Δ f t ) sin φ ⎤ ⎣ ⎦ − Ac Ac′m ( t ) cos ( 2π f c t ) sin ( 2π f c t ) ⎡sin ( 2π Δ f t ) cos φ + cos ( 2π Δ f t ) sin φ ⎤ ⎣ ⎦ = Ac Ac′m ( t ) cos 2 ( 2π f c t ) ⎡cos ( 2π Δ f t ) cos φ − sin ( 2π Δ f t ) sin φ ⎤ ⎣ ⎦ − Ac Ac′m ( t ) cos ( 2π f c t ) sin ( 2π f c t ) ⎡sin ( 2π Δ f t ) cos φ + cos ( 2π Δ f t ) sin φ ⎤ ⎣ ⎦ = Ac Ac′m ( t ) cos 2 ( 2π f c t ) cos ( 2π Δ f t+ φ ) − Ac Ac′m ( t ) cos ( 2π f c t ) sin ( 2π f c t ) sin ( 2π Δ f t+ φ ) i i 1 With sin ( A + A ) = sin 2 A = 2 cos A sin A ⇒ cos A sin A = sin 2 A, then 2 sin ( 4π f c t ) ν ( t ) = Ac Ac′m ( t ) cos 2 ( 2π f c t ) cos ( 2π Δ f t+ φ ) − Ac Ac′m ( t ) sin ( 2π Δ f t+ φ ) 2 A A′ = Ac Ac ′m ( t ) ⎡1 + cos 4π f c t ⎤ cos ( 2π Δ f t + φ ) − c c m ( t ) sin ( 4π f c t ) sin ( 2π Δ f t + φ ) ⎢ 2 ⎥ 2 ⎣ ⎦ Ac Ac′ Ac Ac′ = m ( t ) cos ( 2π Δ f t + φ ) + m ( t ) cos ( 4π f c t ) cos ( 2π Δ f t + φ ) 2 2 Ac Ac′ − m ( t ) sin ( 4π f c t ) sin ( 2π Δ f t + φ ) 2 Amplitude Modulation 19
  • 20. Coherent Detection Ac Ac′ Ac Ac′ ν (t ) = m ( t ) cos ( 4π f c t + 2π Δ f t + φ ) + m ( t ) cos ( 2π Δ f t + φ ) 2 2 The first term is centered at ± 2 f c + Δ f and can be filtered out by the LPF. Ac Ac′ Unless both ∆ f and φ are zero, otherwise v(t) is not equal to m (t ). 2 Ac Ac′ If ∆ f = 0, then ν ( t ) = m ( t ) cos φ . 2 This phase error in the local carrier causes an attenuation of the output signal proportional to the cosine of the phase error, φ. Ac Ac′ If φ = 0, then ν ( t ) = 0 m ( t ) cos 2π Δ f t. 2 If φ = 90º, the received signal will be wiped out, v(t) = 0. Amplitude Modulation 20
  • 21. Coherent Detection The second term can be expressed as: Ac Ac′ ν 0 (t ) = m ( t ) cos ( 2π Δ f t + φ ) 2 1 = Ac Ac′m ( t ) ⎡ cos ( 2π Δ f t ) cos φ − sin ( 2π Δ f t ) sin φ ⎤ ⎣ ⎦ 2 This phase error in the local carrier causes an attenuation of the output signal proportional to the cosine of the phase error φ, and Δ f is usually within ± 2% of the carrier frequency. Ac Ac′ If φ = 0, then ν 0 ( t ) = 0 m ( t ) cos 2π Δ f t. 2 If φ = 90º, the received signal will be wiped out, v0 (t) ≈ 0. I general, th phase error φ i not constant. It i necessary t synchronize th In l the h is t t t is to h i the local oscillator in the receiver in both frequency and phase with the carrier wave to generate the DSB-SC modulated signal in the transmitter. Amplitude Modulation 21
  • 22. Coherent Detection Ac Ac′ ν 0 (t ) = m ( t ) cos 2π Δ f t. 2 Amplitude Modulation 22
  • 23. Costas Receiver Amplitude Modulation 23
  • 24. Costas Receiver This receiver consists of two coherent detectors supplied with the same input signal, Ac cos (2π fc t) m(t), but with two local oscillator signals that are in phase quadrature with respect to each other. Suppose the local oscillator drifts from its proper value by a small angle φ radians. The I-channel output is proportional to cos φ and cos φ ≈ 1 for small φ. The Q-channel output will have the same polarity as the I-channel output for one direction of local oscillator phase driftφ and the opposite polarity for the opposite direction of φ. By combining the I- and Q-channel outputs in a phase discriminator (which consists of a multiplier followed by a time-averaging unit), a dc control signal proportional to the phase drift φ is generated. With negative feedback acting around the Costas receiver, the control signal tends to automatically correct for the local phase error φ in the voltage-controlled oscillator. voltage controlled Amplitude Modulation 24
  • 25. Single-Sideband Modulation, SSB Modulating signal: m ( t ) = Am cos ( 2π f m t ) Carrier signal: g c ( t ) = Ac cos ( 2π f c t ) S DSB − SC ( t ) = c ( t ) m ( t ) = Ac Am cos ( 2π f c t ) cos ( 2π f m t ) 1 1 = Ac Am cos ⎡ 2π ( f c + f m ) t ⎤ + Ac Am cos ⎡ 2π ( f c − f m ) t ⎤ ⎣ ⎦ 2 ⎣ ⎦ 2 1 S SSB + ( t ) = Ac Am cos ⎡ 2π ( f c + f m ) t ⎤ ⎣ ⎦ 2 1 1 = Ac Am cos ( 2π f c t ) cos ( 2π f m t ) − Ac Am sin ( 2π f c t ) sin ( 2π f m t ) 2 2 1 S SSB − ( t ) = Ac Am cos ⎡ 2π ( f c − f m ) t ⎤ ⎣ ⎦ 2 1 1 = Ac Am cos ( 2π f c t ) cos ( 2π f m t ) + Ac Am sin ( 2π f c t ) sin ( 2π f m t ) 2 2 1 1 S SSB ± ( t ) = Ac Am cos ( 2π f c t ) cos ( 2π f m t ) ∓ Ac Am sin ( 2π f c t ) sin ( 2π f m t ) 2 2 Amplitude Modulation 25
  • 26. Single-Sideband Modulation, SSB 1 1 S SSB ± ( t ) = Ac Am cos ( 2π f c t ) cos ( 2π f m t ) ∓ Ac Am sin ( 2π f c t ) sin ( 2π f m t ) 2 2 1 1 = Ac m ( t ) cos ( 2π f c t ) ∓ Ac m ( t ) sin ( 2π f c t ) 2 2 where m(t) can b d i d from m(t) simply by shifting the phase of each h () be derived f ( ) i l b hif i h h f h frequency component by −90º. The signal m(t) is the Hilbert transform of the signal m(t) . Amplitude Modulation 26
  • 27. Hilbert Transform The transfer function of a Hilbert transform is defined by: The signum function, sgn(f) is defined as: sgn ( t ) ⎧+1 t > 0 ⎪ sgn ( t ) = ⎨ 0 t = 0 ⎪ ⎩−1 t < 0 The Hilbert transformer is a wide-band phase-shifter, the frequency response is characterized in two parts: The magnitude response is unity for all frequencies, both positive and negative. g p y q p g The phase response is +90º for negative frequencies -90º for positive frequencies. Amplitude Modulation 27
  • 28. Frequency Discrimination Method for SSB The SSB modulator of Fig. 3.19 consists of two components: product modulator followed by a band-pass filter (BPF). The product modulator produces a DSB-SC modulated wave with an upper sideband and a lower sideband. The BPF is designed to transmit one of these two sidebands, depending on whether the USB or LSB is the desired modulation. M(f) f fa fb fc S( f ) f fc + f a f c + fb S( f ) f fc − fb fc − fa Figure 3.18 (a) Spectrum of a message signal m(t) with energy gay centered around zero frequency. Corresponding spectra of SSB modulated waves using (b) upper sideband, and (c) lower sideband. In parts (b) SSB-modulated and (c), the spectra are only shown for positive frequencies. Amplitude Modulation 28
  • 29. Frequency Discrimination Method for SSB For the design of the BPF to be practically feasible, there must be a certain separation between the two sidebands that is wide enough to accommodate the transition band of the BPF. The separation is equal to 2fa, where fa is the lowest frequency component of the message signal, as shown in Fig. 3.18. This requirement limits the applicability of SSB modulation to speech signals for which fa ≈ 100 Hz. Amplitude Modulation 29
  • 30. Coherent Detection of SSB The coherent detection requires synchronization of a local oscillator in the receiver with the oscillator responsible for generating the carrier in the transmitter. The synchronization requirement has to be in both phase and frequency. Amplitude Modulation 30
  • 31. Vestigial Sideband (VSB) Modulation SSB modulation works well with speech signal that has an energy gap centered around zero frequency. For wideband signal like television transmission signal will benefit by not using double sidebands, and SSB will make it impossible to implement. The television transmission, 525 lines of video information are sent in 1/30 (30 frames per second) of a second (that is, 15,750 lines per second – the horizontal trace frequency). Allowing time for retrace and synchronization, this requires a minimum video bandwidth of 4 MHz to transmit an array of picture elements. The transfer function of a Hilbert transform is defined by: The signum function sgn(f) is defined as: function, ⎧ + 1, t >0 ⎪ sgn ( t ) = ⎨ 0, t =0 ⎪ −1, t<0 ⎩ Amplitude Modulation 31
  • 32. Vestigial Sideband (VSB) Modulation VSB modulation overcomes two of the difficulties present in SSB modulation. By allowing a portion of the unwanted sideband to appear at the output of an SSB modulator, the design of the sideband filter is simplified since the sharp cut-off at the carrier frequency is not required. The bandwidth of a VSB modulated signal is defined by BT = fv + W where fv is the vestigial bandwidth and W is the message bandwidth. The VSB bandwidth BT compromises between the SSB bandwidth W and DSB-SC bandwidth 2W bandwidth, W, DSB SC bandwidth, 2W. Amplitude Modulation 32
  • 33. Sideband Shaping Filter In VSB modulation, only a portion of one sideband is transmitted in such a way that the demodulation process reproduces the original signal. The partial suppression of one sideband reduces the required bandwidth from that required for DSB but does not match the spectrum efficiency of SSB. The spectrum shaping is defined by the transfer function of the filter, which is denoted by H( f ). The only requirement that the sideband shaping performed by H( f ) must satisfy is that the transmitted vestige compensates for the spectral portion missing from the other sideband. The sideband shaping filter must satisfy the following condition: H ( f + fc ) + H ( f − fc ) = 1 for − W ≤ f ≤ W where fc is the carrier frequency. The term H( f + fc ) is the positive-frequency part of the band-pass transfer function H( f ) shifted to the left by fc, and H( f − fc ) is the negative-frequency p part of H( f ) shifted to the right by fc. ( g y Amplitude Modulation 33
  • 34. Sideband Shaping Filter The transfer function of the sideband shaping filter is anti-symmetric about the carrier frequency, fc. The transfer function is required to satisfy the odd symmetry only for the frequency interval, −W ≤ f ≤ W, where W is the message bandwidth. f − fc fc f f Amplitude Modulation 34
  • 35. Demodulation of SSB signals (1 of 5) For demodulation, the spectral density of the SSB signal must be translated back to f = 0. Multiplication of the SSB signal by cos(2π fc t) translates half of each spectral density up in frequency by fc and half down by the same amount.. e0 ( t ) S SSB ± ( t ) cos ( 2π f c t ) f − fm fm S SSB + ( t ) f − ( fc + fm ) fc fc fc + fm f − ( 2 fc + f m ) 2 fc − fm fm 2 fc 2 fc + f m Amplitude Modulation 35
  • 36. Demodulation of SSB signals (2 of 5) With the frequency and phase errors in the demodulation process: S SSB ∓ ( t ) = f ( t ) cos ( 2π f c t ) ± f ( t ) sin ( 2π f c t ) Let the locally generated carrier signal be cos ⎡ 2π ( f c + Δ f ) t + φ ⎦ ⎣ ⎤ where Δ f is the frequency error and φ is the phase error. S SSB ∓ ( t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ ⎣ ⎦ = ⎡ f ( t ) cos ( 2π f c t ) ± f ( t ) sin ( 2π f c t ) ⎤ cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ ⎣ ⎦ ⎣ ⎦ = f ( t ) cos ( 2π f c t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ ± f ( t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ sin ( 2π f c t ) ⎣ ⎦ ⎣ ⎦ The first term can be expressed as: ⎡ Note: 2 cos A cos B = cos ( A + B ) + cos ( A − B ) ⎤ ⎣ ⎦ f ( t ) cos ( 2π f c t ) cos ⎣ 2π ( f c + Δ f ) t + φ ⎦ ⎡ ⎤ 1 1 = f ( t ) cos ⎡ 2π f c t + 2π ( f c + Δ f ) t + φ ⎤ + f ( t ) cos ⎡ 2π f c t − 2π ( f c + Δ f ) t + φ ⎤ ⎣ ⎦ 2 ⎣ ⎦ 2 1 1 = f ( t ) cos [ 4π f c t + 2π Δ f t + φ ] + f ( t ) cos [ 2π Δ f t + φ ] 2 2 Amplitude Modulation 36
  • 37. Demodulation of SSB signals (3 of 5) The seond term can be expressed as: ⎡ Note: 2 cos A sin B = sin ( A + B ) − sin ( A − B ) ⎤ ⎣ ⎦ f ( t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ sin ( 2π f c t ) ⎣ ⎦ 1 1 = f ( t ) sin ⎡ 2π ( f c + Δ f ) t + φ + 2π f c t ⎤ − f ( t ) sin ⎡ 2π ( f c + Δ f ) t + φ − 2π f c t ⎤ ⎣ ⎦ 2 ⎣ ⎦ 2 1 1 = f ( t ) sin [ 4π f c t + 2π Δf t + φ ] − f ( t ) sin [ 2π Δ f t + φ ] 2 2 Now, S SSB ∓ ( t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ ⎣ ⎦ = f ( t ) cos ( 2π f c t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ ± f ( t ) cos ⎡ 2π ( f c + Δ f ) t + φ ⎤ sin ( 2π f c t ) ⎣ ⎦ ⎣ ⎦ 1 = f ( t ) {cos [ 4π f c t + 2π Δ f t + φ ] + cos [ 2π Δ f t + φ ]} 2 1 ± f ( t ) {sin [ 4π f c t + 2π Δf t + φ ] − sin [ 2π Δ f t + φ ]} 2 Filtered out 1 = f ( t ) {cos [ 4π f c t + 2π Δ f t + φ ] + cos [ 2π Δ f t + φ ]} 2 Filtered out 1 ∓ f ( t ) {sin [ 2π Δ f t + φ ] − sin [ 4π f c t + 2π Δf t + φ ]} i i 2 Amplitude Modulation 37
  • 38. Demodulation of SSB signals (4 of 5) The LPF in the SSB demodulator will filter out the higher frequencies component. Thus the output 1 1 e0 ( t ) = f ( t ) cos [ 2π Δ f t + φ ] ∓ f ( t ) sin [ 2π Δ f t + φ ] i 2 2 1 If Δ f = 0, and φ = 0, then e0 ( t ) = f (t ). 2 1 1 If Δ f = 0, and φ ≠ 0, then e0 ( t ) = f ( t ) cos φ ∓ f ( t ) sin φ . 2 2 This give phase distortion in the receiver output. The SSB-SC demodulation is quite tolerate for voice communication. 1 1 If φ = 0 and Δ f ≠ 0 then e0 ( t ) = 0, 0, f ( t ) cos ( 2π Δf t ) ∓ f ( t ) sin ( 2π Δf t ) . i 2 2 This frequency errors give rise to spectral shifts as well as to phase distortion in the demodulation output. If Δ f is small, these spectral shifts can be tolerated p , p in voice communications. Amplitude Modulation 38
  • 39. Demodulation of SSB signals (5 of 5) If the frequency error, Δf = fm , then the spectrum is inverted. The high frequency spectral components will become the low frequency components and vice versa. This spectral inversion scrambles the speech quite unintelligible and this can be used as a low-level speech scramblers to ensure communication privacy f (t ) fc fc + fm cos2π ( fc + fm ) t f − fm fm fc S SSB + ( t ) f − ( fc + fm ) fc fc fc + fm S SSB − ( t ) fc + fm f − ( fc + fm ) fc fc fc + fm Amplitude Modulation 39
  • 40. Superheterodyne Receiver Heterodyning means the translating or shifting in frequency. In the heterodyne receiver the incoming modulated signal is translated in frequency, thus occupying an equal bandwidth centered about a new frequency. This new frequency is known as an intermediate frequency (IF) which is fixed and is not dependent on the received signal frequency. The signal is amplified at the IF before demodulation. If the IF is lower than the received carrier frequency but above the final output signal frequency it is called a superheterodyne receiver frequency, receiver. Amplitude Modulation 40
  • 41. Superheterodyne Receiver The intermediate frequency (IF) for most common AM broadcast receivers is 455 KHz. AM band is from 540 KHz ~ 1600 KHz. The required frequency translation to the IF is accomplished by mixing the incoming signal with a locally generated signal which differs from the incoming carrier by the IF (455 KHz). The received signal now translated to a fixed IF, and it can be easily be amplified, filterer and demodulated. All the amplification and filtering is performed at a fixed frequency regardless of station selection. The locally generated frequency is chosen to be 455 KHz higher than the incoming signal, because it is easier to build oscillators which are reasonably linear within 1~2 MHz range than 0.1~1 MHz range (455 KHz lower than the incoming signal). AM band: 540 KH ~ 1600 KH b d KHz KHz 455 KHz higher than the incoming signal: ( 540 + 455) KHz ~ (1600 + 455) KHz 455 KHz lower than the incoming signal: (540 − 455) KHz ~ (1600 – 455) KHz Amplitude Modulation 41
  • 42. Superheterodyne Receiver f IF f IF f IF f IF f − ( f c + 2 f IF ) − fc fc f c + 2 f IF fc fc fc fc f − ( f c + f IF ) f c + f IF f − ( 2 f c + f IF ) − f IF f IF 2 f c + f IF If there is another station broadcasting at ( fc+2fIF ) KHz the signal will also be KHz, mapped into the IF band. This signal is called the image frequency which is not the desired signal. This is the only drawback in superheterodyne receiver. Amplitude Modulation 42
  • 43. Dual Conversion Receiver A telemetry receiver is designed to receive satellite transmissions at 136 MHz. The receiver uses two heterodyne operations with intermediate frequencies of 30 MHz and 10 MHz The first local oscillator is designed to operate below the MHz. incoming carrier frequency; the second one, above the first (30 MHz) intermediate frequency. What possible input frequencies could result in images for both mixers if the filters were not ideal? Amplitude Modulation 43
  • 44. Dual Conversion Receiver The first local oscillator is operating at 136 MHz − 30 MHz = 106 MHz. The other frequency of transmission @ 106 MHz − 30 MHz = 76 MHz will also map to IF1. The second local oscillator is operating at 30 MHz +10 MHz = 40 MHz. If 40 MHz +10 MHz = 50 MHz is not attenuated significantly after passing IF1, then the 50 MHz will also map to IF2. Then the possible image frequencies are: 106 − 40 = 56 MHz ; 106 − 30 = 76 MHz ; 106 + 50 = 156 MHz Check: • LO1=106 MHz, 106 −56 = 50 MHz. If this 50 MHz appears at the output of IF1, it will also map to IF2. 50 −40 = 10 MHz. 40 MHz • LO1=106 MHz, 106 −76 = 30 MHz. (IF1=30 MHz) • LO1=106 MHz, 156 −106 = 50 MHz. If this 50 MHz appears at the output of IF1, it will also map to IF2, for 50 −40 = 10 MHz. Amplitude Modulation 44
  • 45. Stereo Multiplex System l (t ) + ∑ bg bg × l t −r t − + r (t ) cos2π fc t 38 KHz 19 KHz + ∑ bg xb t ÷2 + + + ∑ l bt g + r bt g 0 15 KHz 23 KHz 53 KHz f 19 KHz 38 KHz Amplitude Modulation 45
  • 46. Time-Averaged Noise Representations Suppose n(t) is a noise voltage or current (assume a 1-ohm resistive load): 1 1. Mean value, n ( t ) : n ( t ) = lim n ( t ) dt T →∞ T ∫ , T This is often referred to as the dc or average, value of n(t). 2. Mean-square value, n 2( t ): n 2( t ) = lim 1 n ( t ) dt 2 T →∞ T ∫ T The square root of n 2( t ) is called the root-mean-square (rms) value of n(t). 3. AC component, σ(t) : σ (t ) ≈ n (t ) − n (t ) ⇒ n (t ) = n (t ) + σ (t ) 1 1 2 n ( t ) = lim ∫ n ( t ) dt = lim ∫ n ( t ) + σ ( t ) dt 2 2 T →∞ T T →∞ T T T 1 2 1 = lim ∫ n ( t ) dt + lim ∫ σ ( t ) dt 2 T →∞ T T →∞ T T T Amplitude Modulation 46
  • 47. Time-Averaged Noise Representations The ac, or fluctuation, component of n(t) is that component which remains after the mean value, n ( t ) , had been taken out. 1 1 2 n ( t ) = lim ∫ n ( t ) dt = lim ∫ n ( t ) + σ ( t ) dt 2 2 T →∞ T T →∞ T T T 1 2 1 = lim ∫ n ( t ) dt + lim ∫ σ ( t ) dt 2 T →∞ T T →∞ T T T The term on the left-hand side of the above equation is the time-averaged power in n(t) across a 1 ohm resistor The first term on the right hand side is 1-ohm resistor. right-hand the dc power and the second term, the ac power in n(t). The rms value of n(t) is equal to the rms value of σ(t) only if the mean value n ( t ) is zero. Amplitude Modulation 47
  • 48. Time-Averaged Noise Representations Example: Compute the (a) average value, (b) ac power, and © rms value of the periodic waveform v ( t ) = 1 + cos 2π f 0 t . f 1 a) v (t ) = ∫ (1 + cos 2π f0 t )dt = 1 TT 1 1 1 1 b) σ 2( t ) = ∫ ( cos 2π f0 t ) dt = ∫ (1 + cos 4π f 0 t ) dt = 2 TT TT2 2 c) v 2( t ) = 1 ∫ (1 + cos 2π f 0 t )2 dt = 1 ∫ (1 + cos 4π f 0 t + cos 2 2π f 0 t ) dt = 1 + 1 = 3 T T T T 2 2 3 vrms = v 2( t ) = = true rms value 2 Amplitude Modulation 48