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Use of summation notation
Use of summation notation (∑)
First to understand
= + +
= + + =
Formula For Mean
=
∑
Example-1. A data set contains the observations
2, 1, 3, 2, 3 find:
(a).
(b).
(c).
(d). ∑( − 3)
Solution:
(a) = 2 + 1 + 3 + 2 + 3 = 11
(b) = (2)2
+ (1)2
+ (3)2
+ (2)2
+ (3)2
= 27
(c) = (2 – 3) + (1 – 3) + (3 – 3) + (2 – 3) + (3 – 3)
= –1 –2 + 0 –1 + 0 = – 4
(d) ∑( − 3) = (2 − 3) + (1 − 3) + (3 − 3) + (2 − 3) + (3 − 3)
∑( − 3) = 1 + 4 + 0 + 1 + 0 = 6
Do yourself
(1) A data set contains the observations5, 1, 3, 2, 1 find
a. (Ans.12)
b. ( Ans.40)
c. ( Ans.7)
d. ( Ans.21)
e. (∑x)2
(Ans.144)
(2) If X1 = 11, X2 = 3, X3 = 4, X4 = 5, Evaluate.
{Answers: a(13),b(51), c(3.25), d(0), e(8.75)}
Example-2
Find given that
Solution:
As shown in given question n = 20
̅ =
∑
=
226
20
= 11.3
Example-3 Find given that
METHOD - I
Solution:
As shown in given question n = 20
( − 100) = 226
− (20)(100) = 226
− 2000 = 226
= 226 + 2000
= 2226
=
∑
=
2226
20
= 111.3
METHOD - II
Solution:
As shown in given question n = 20
( − 100) = 226
Let
( − ) =
By compairing
= 100 = 226
We know that
= +
∑
= 100 +
= 100 + 11.3
= 111.3

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Use of summation notation

  • 2. Use of summation notation (∑) First to understand = + + = + + = Formula For Mean = ∑ Example-1. A data set contains the observations 2, 1, 3, 2, 3 find: (a). (b). (c). (d). ∑( − 3) Solution: (a) = 2 + 1 + 3 + 2 + 3 = 11 (b) = (2)2 + (1)2 + (3)2 + (2)2 + (3)2 = 27 (c) = (2 – 3) + (1 – 3) + (3 – 3) + (2 – 3) + (3 – 3) = –1 –2 + 0 –1 + 0 = – 4
  • 3. (d) ∑( − 3) = (2 − 3) + (1 − 3) + (3 − 3) + (2 − 3) + (3 − 3) ∑( − 3) = 1 + 4 + 0 + 1 + 0 = 6 Do yourself (1) A data set contains the observations5, 1, 3, 2, 1 find a. (Ans.12) b. ( Ans.40) c. ( Ans.7) d. ( Ans.21) e. (∑x)2 (Ans.144) (2) If X1 = 11, X2 = 3, X3 = 4, X4 = 5, Evaluate. {Answers: a(13),b(51), c(3.25), d(0), e(8.75)}
  • 4. Example-2 Find given that Solution: As shown in given question n = 20 ̅ = ∑ = 226 20 = 11.3 Example-3 Find given that METHOD - I Solution: As shown in given question n = 20 ( − 100) = 226 − (20)(100) = 226 − 2000 = 226 = 226 + 2000 = 2226 = ∑ = 2226 20 = 111.3
  • 5. METHOD - II Solution: As shown in given question n = 20 ( − 100) = 226 Let ( − ) = By compairing = 100 = 226 We know that = + ∑ = 100 + = 100 + 11.3 = 111.3