Basic Electric Circuits Session 5 Homework problems
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This document contains examples of homework problems and their solutions related to basic electric circuits. It includes 4 sample circuit problems where the key values like voltage (vx) and current (ix) are calculated. The document provides the circuit diagrams and step-by-step working to find the requested values. It also lists the power absorbed by different components like a resistor in one of the circuits. References for circuit textbooks are listed at the end.
Basic Electric Circuits Session 5 Homework problems
- 1. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com
- 2. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com Home Work Problems with Solutions
- 3. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com 3 S5_HW_Problem_1 Find vx and ix : Note: This is Practice problem 3.2 on page 43, Figure 3.7 in the Ref 1 book (by Hayt) -4 V and -400 mA 3 + 1 + vx = 0 vx = -4 V ix = -400 mA Start from the node A and move in the clockwise direction till reaching A again ix = vx / 10 = -4/10 A
- 4. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com 4 S5_HW_Problem_2 Find vx : 8 V Note: This is Example problem is 3.4 on page 45, Figure 3.10 in the Ref 1 book (by Hayt) -60 + v8 + v10 = 0 v8 = 5 * 8 = 40 V -60 + 40 + v10 = 0 v10 = 20 V -v10 + v4 + vx = 0 -20 + 12 + vx = 0 vx = 8 V i10 = v10 /10 i10 = 20 /10 i10 = 2 A i10 + i4 = 5 A i4 = 5 – 2 = 3 A v4 = 3 * 4 = 12 V
- 5. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com 5 S5_HW_Problem_3 Find vx : 12.8 V Note: This is Practice problem is 3.4 on page 46, Figure 3.11 in the Ref 1 book (by Hayt) -30 + v8 + v10 = 0 v8 = 2 * 8 = 16 V -30 + 16 + v10 = 0 v10 = 14 V -v10 + v2 + vx = 0 -14 + 1.2 + vx = 0 vx = 12.8 V i10 = v10 /10 i10 = 14/10 i10 = 1.4 A i10 + i2 = 2 A i2 = 2 – 1.4 = 0.6 A v2 = 0.6 * 2 = 1.2 V v10 v8 vx i2 i10 v2+ + + + - - --
- 6. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com 6 S5_HW_Problem_4 Power absorbed by 4vx: -3.072 W Note: This is Practice problem 3.6 on page 48, Figure 3.14 in the Ref 1 book (by Hayt) -vx - 12 + v8 + v7 + 4vx = 0 vx = -30 * i = -30 i v8 + v7 + 3vx = 12 i v8 = 8 * i = 8 i v7 = 7 * i = 7 i8i+ 7i-90i= 12 -75i= 12, i = -0.16 A P30 = i2 * 30 = (0.16)2 * 30 = 0.768 W P12V = v* i = (12 * 0.16)= 1.92 W P8 = i2 * 8 = (0.16)2 * 8= 0.2048 W P7 = i2 * 7 = (0.16)2 * 7= 0.1792 W P4vx = 4 vx * i = -30*4*0.16* 0.16 = -3.072 W
- 7. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com 7 References Ref 1 Ref 2