Basic Electric Circuits Tutorial 6
Download as PPTX, PDF0 likes57 views
This document discusses solving circuits using supermesh analysis. It provides an example problem of finding the currents i1 and the power supplied by a 1V source in a circuit containing 3 meshes. The document sets up three equations relating the mesh currents using Kirchhoff's voltage law (KVL) and combines two meshes into a supermesh. It then solves the two equations simultaneously to find i1 = 19A and the power supplied by the 1V source as 19W.
Basic Electric Circuits Tutorial 6
- 1. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com
- 2. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com 2 Tutorial 6: Focus Nodal Analysis One problem - Supermesh
- 3. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com 3 T6_Problem 1: Supermesh Note: This is problem 48 on page 118, Figure 4.73 in the Ref 1 book (by Hayt) Find i1 and Power supplied by 1V: - 1+ 4i1 + 3(i1 -i2) + 1(i1 -i3) = 0 3(i2 - i1) – 8 + 2i3 + 1(i3 - i1) = 0 8i1 - 3i2 - i3 = 1 KVL for the mesh with i1 : supermesh combining i2 and i3 : -4i1 + 3i2+ 3i3 = 8 5i1= i2 – i3 How many meshes are there? 3 What is 5i1 in terms of mesh currents? 5i1= i2 – i3 i3= i2 – 5i1 8i1 - 3i2 – (i2 – 5i1)= 1 8i1 - 4i2 + 5i1 = 1 13i1 - 4i2 = 1 -4i1 + 3i2+ 3(i2 – 5i1) = 8 -19i1 + 6i2 = 8
- 4. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com 4 T6_Problem 1: Supermesh Note: This is problem 48 on page 118, Figure 4.73 in the Ref 1 book (by Hayt) Find i1 and Power supplied by 1V: Solving these two equations: i1 = 19 A P1V = (i1 * 1) = 19 W 13i1 - 4i2 = 1 -19i1 + 6i2 = 8 ---- (2) ---- (1) -38 i1 + 12 i2 = 8(1) * 2 (2) * 3 39 i1 - 12 i2 = 3 i1 = 19 A P1V = 19 W
- 5. Basic Electric Circuits – © 2020 Mouli Sankaran Email: mouli.sankaran@yahoo.com 5 References Ref 1 Ref 2